[tex]\\ \sf\longmapsto \frac{x}{6} - \frac{y}{3} = 1 \\ \\ \sf\longmapsto \frac{x - 2y}{6} = 1 \\ \\ \sf\longmapsto x - 2y = 6 \\ \\ \sf\longmapsto x = 6 + 2y[/tex]
Question 6 of 11 Step 1 of 6 No Time Limit The table below gives the list price and the number of bids received for five randomly selected items sold through online auctions. Using this data, consider the equation of the regression line, û = bo + bjx, for predicting the number of bids an item will receive based on the list price. Keep in mind, the correlation coefficient may or may not be statistically significant for the data given. Remember, in practice, it would not be appropriate to use the regression line to make a prediction if the correlation coefficient is not statistically significant.
Price in Dollars 23 34 44 46 50
Number of Bids 1 2 4 9 10
Step 1 of 6: Find the estimated slope. Round your answer to three decimal places.
The estimated slope is approximately 2.344
The given table is presented as follows;
[tex]\begin{array}{ccc}Number \ of Bids &&Price \ in \ Dollars\\1&&23\\2&&34\\4&&44\\9&&46\\10&&50\end{array}[/tex]
The regression line formula to be considered = [tex]\bar u = b_0 + b\cdot \bar x[/tex]
The required parameter is;
The estimated slope
The method to find the estimate slope;
The least squares regression formula (method) is presented as follows;
[tex]\bar u = b_0 + b\cdot \bar x[/tex]
Where;
b₀ = The y-intercept
[tex]\mathbf{ b = \dfrac{\sum \left(x_i - \bar x\right) \times \left(u_i - \bar u\right) }{\sum \left(x_i - \bar x\right )^2 } = The \ estimated \ slope}[/tex]
From MS Excel, we have;
[tex]\bar x[/tex] = 5.2, [tex]\bar u[/tex] = 39.4
[tex]\sum \left(x_i - \bar x\right) \times \left(u_i - \bar u\right)[/tex] = 156.6
[tex]{\sum \left(x_i - \bar x\right )^2 }[/tex] = 66.8
Therefore;
The estimated slope, b = 156.6/66.8 ≈ 2.344 (by rounding the answer to three decimal places)
Learn more about regression line here;
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If sin(x) = 1 and cos(x) = 0, what is cot(x)?
0
1
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Answer:
It's 0
Edge said it's 0
The value of the ratio of the cos(x) and the sin(x) is 0.
Trigonometric ratios are mathematical functions that relate the angles of a right triangle to the ratios of the lengths of its sides. These ratios are fundamental in trigonometry and have applications in various fields, such as physics, engineering, and navigation.
Trigonometry is a branch of mathematics that deals with the relationships and properties of angles and triangles. It explores the ratios between the sides of a triangle and the angles within that triangle. The word "trigonometry" is derived from two Greek words: "trigonal," meaning "triangle," and "metron," meaning "measure."
The value of the sin(x) is 1. The value of cos(x) is 0.
The formula for the cot(x) is written below:
cot(x) = cos(x) / sin(x)
cot(x) = 0 / 1
cot(x) = 0
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a) Everyone on the team talks until the entire team agrees on one decision. O b) Everyone on the team discusses options and then votes. O c) The team passes the decision-making responsibility to an outside person. O di The team leader makes a decision without input from the other members.
Answer:
a) Everyone on the team talks until the entire team agrees on one decision.
Step-by-step explanation:
Option B consists of voting and not everyone would like the outcome. Option C is making an outsider the decision maker, which can't be helpful since he / she won't have as strong opinions as the team itself. Option D is just plain wrong as it defeats the purpose of team work and deciding as one team. So, I believe option A makes the most sense
CAN SOMEONE PLEASE HELL ME WITH THIS PROBLEM? THANK YOU!!!
Answer:
71
Step-by-step explanation:
The reference angle is always the smallest angle with the x-axis.
The nearest x axis is at 0 or another name for 0 is 360
360 -289 = 71
The reference angle is 71
There are two rectangles Jared is examining. He knows the width of the first rectangle measures
2.48 cm, and the length is twice its width.
Jared also knows that the width of the second rectangle is equal to the length of the first rectangle,
and that the area of the second rectangle is 9.92. Given this information, find the length of the
second rectangle for Jared.
1st rectangle:
width: 2.48cm
length: 4.96
2nd rectangle:
width: 4.96 (equals to the length of the 1st rectangle)
area: 9.92
length: 9.92/4.96 = 2
Evaluate lim
x→0+
√x ln x
Answer:
vr
Step-by-step explanation:
konho bi m
Jasmine the Great Dane has a head 30 cm long. Her tall is equal to the size of her head plus one-half the size of her body. Her body is the size of her head phluss the tal. How long is Jasmine?
Answer:
240 cm
Step-by-step explanation:
Let x = tail y = body
x = 30 + 1/2y
y = 30 + x
Let's plug in the x equation at the bottom
y = 30 + 30 + 1/2y
y = 60 + 1/2y
Bring the like terms to one side
y = 60 + 1/2y
-1/2y -1/2y
1/2y = 60
Multiply both sides by 2 to get the length of the body
1/2y x 2 = 60 x 2
y = 120
Now we can plug in the new y into another equation, let's use the top one
x = 30 + 1/2(120)
x = 30 + 60
x = 90 = length of the tail
Add em all up
120 + 90 + 30 = 240
find area of shaded region
Answer:
The answer is 21.98. I just took area of the whole circle and subtracted it with the area of two circles in it
Answer:
21. 99
Step-by-step explanation:
[tex]s = \pi \times {r}^{2} \\ s1 = 3.14 \times 9 = 28.27 \\ s2 = 3.14 \times 1 = 3.14 \\ a = 28.27 - (3.14 \times 2) = 28.27 - 6.28 = 21.99[/tex]
10. In a group of 50 people, there are two types of professionals, engineers and managers. If 36 of them are engineers and 24 of them are managers, how many persons are both managers and engineers?
Step-by-step explanation:
The photo above is the Venn diagram
Now, the number of persons that are both managers and engineers= n
Since, Total number of persons is 50
Therefore, 50= M+n+E
M only = 36-n
E only = 24-n
Therefore, 50= 36 - n + n + 24 - n
50 = 36+24-n
50 = 60 - n
60 - n = 50
-n = 50 - 60
-n = - 10
Therefore, n = 10
Therefore, the number of persons that are both Managers and Engineers is 10persons.
ALL I NEED HELP WITH IS WITH PART D, HOW DO I GET THAT
Use the function f(x) = −16x^2 + 22x + 3 to answer the questions.
Part A: Completely factor f(x). (2 points)
Part B: What are the x-intercepts of the graph of f(x)? Show your work. (2 points)
Part C: Describe the end behavior of the graph of f(x). Explain. (2 points)
Part D: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part B and Part C to draw the graph. (4 points)
Step-by-step explanation:
Step 1: Factor the equation
[tex]f(x) = -16x^{2} + 22x + 3\\f(x) = -(8x + 1)(2x - 3)[/tex]
Step 2: Find the x-intercepts of the graph of f(x)
[tex]-8x - 1 + 1 = 0 + 1\\-8x / -8 = 1 / -8\\x = -1/8[/tex]
[tex]2x - 3 + 3 = 0 + 3\\2x / 2 = 3 / 2\\x = 3/2[/tex]
Step 3: Describe the end behavior of the graph of f(x)
Since the function is to the power of 2, that means that it is a parabola. And since the leading coefficient is negative, means that the arrows will be pointing down therefore, the end behavior of this graph is as x goes to infinity, f(x) goes to negative infinity and as x goes to negative infinity, f(x) goes to negative infinity.
Step 4: What are the steps you would use to graph f(x)
The first step that I would do is factor the equation. Then I would find the x-intercepts of the graph and plot them on the graph. I would then plug in 0 for all of the x values to get the y intercept. After doing that I would get the vertex using the vertex formula plotting it on the graph. Finally, I would connect all of the dots together to form the graph of the equation.
Answer:
The person above me is correct!
Let f(x)= [x/3] (where f(x) is the ceiling function). We learned that the floor and the ceiling functions are NOT invertible, but we also learned about the set of preimages of any value in the Range, the set of images. Keeping that in mind, give your answer in interval notation if necessary.
a. Find f-1({5})
b. Find f-1({-2})
c. Find f-1({x | 5 = x = 9 })
d. Find f-1({x | -6 = x = -2})
(a) We have ⌊x⌋ = 5 if 5 ≤ x < 6, and similarly ⌊x/3⌋ = 5 if
5 ≤ x/3 < 6 ==> 15 ≤ x < 18
(b) ⌊x⌋ = -2 if -2 ≤ x < -1, so ⌊x/3⌋ = -2 if
-2 ≤ x/3 < -1 ==> -6 ≤ x < -3
In general, ⌊x⌋ = n if n ≤ x < n + 1, where n is any integer.
I do not understand what is being asked in (c) and (d), so you'll have to clarify...
In an experiment, you choose to have two randomly assigned groups. In one, you take measurements both pretest and posttest; with the second, a posttest-only measure. This describes which task of conducting an experiment
Answer:
The answer is "Specific treatment levels".
Step-by-step explanation:
When we experimenting with 'level' which is related to the quantity or magnitude of treatment. For this part of an experiment or study, a group or individual is exposed to a specified set of circumstances. For example: If four categories are exposed to different doses of a given drug, then each dose reflects a level of a treatment factor in the model.
A square steel bar has a length of 5.1 ft and a 2.7 in by 2.7 in cross section and is subjected to axial tension. The final length is 5.10295 ft . The final side length is 2.69953 in . What is Poisson's ratio for the material
Answer:
The Poisson's ratio for the material is 0.0134.
Step-by-step explanation:
The Poisson's ratio ([tex]\nu[/tex]), no unit, is the ratio of transversal strain ([tex]\epsilon_{t}[/tex]), in inches, to axial strain ([tex]\epsilon_{a}[/tex]), in inches:
[tex]\nu = -\frac{\epsilon_{t}}{\epsilon_{a}}[/tex] (1)
[tex]\epsilon_{a} = l_{a,f}-l_{a,o}[/tex] (2)
[tex]\epsilon_{t} = l_{t,f}-l_{t,o}[/tex] (3)
Where:
[tex]l_{a,o}[/tex] - Initial axial length, in inches.
[tex]l_{a,f}[/tex] - Final axial length, in inches.
[tex]l_{t,o}[/tex] - Initial transversal length, in inches.
[tex]l_{t,f}[/tex] - Final transversal length, in inches.
If we know that [tex]l_{a,o} = 61.2\,in[/tex], [tex]l_{a,f} = 61.235\,in[/tex], [tex]l_{t,o} = 2.7\,in[/tex] and [tex]l_{t,f} = 2.69953\,in[/tex], then the Poisson's ratio is:
[tex]\epsilon_{a} = 61.235\,in - 61.2\,in[/tex]
[tex]\epsilon_{a} = 0.035\,in[/tex]
[tex]\epsilon_{t} = 2.69953\,in - 2.7\,in[/tex]
[tex]\epsilon_{t} = -4.7\times 10^{-4}\,in[/tex]
[tex]\nu = - \frac{(-4.7\times 10^{-4}\,in)}{0.035\,in}[/tex]
[tex]\nu = 0.0134[/tex]
The Poisson's ratio for the material is 0.0134.
The access code for a vault consists of four digits. The first digit
must be even and the last digit cannot be a zero. How many possible
codes are there?
Answer:
5 * 10 * 10 * 9 = 4500
Step-by-step explanation:
What is the measure of b, in degrees
Answer:
B) 32
Step-by-step explanation:
(sin 74) / 10 = (sin c) / 10
c = 74
180 - 74 -74
= 32
help me with this questions please!
9514 1404 393
Answer:
r = 18
Step-by-step explanation:
Let d represent the number of districts. The given information lets us write two equations:
3d = 27 . . . . . the number of state senators
d +r = 27 . . . . the number of representatives
The first equation tells us ...
d = 27/3 = 9
The the second equation tells us ...
r = 27 -d = 27 -9 = 18
The number of at-large representatives is r = 18.
Solve the initial-value problem using the method of undetermined coefficients.
y'' − y' = xe^x, y(0) = 6, y'(0) = 5
First check the characteristic solution. The characteristic equation to this DE is
r ² - r = r (r - 1) = 0
with roots r = 0 and r = 1, so the characteristic solution is
y (char.) = C₁ exp(0x) + C₂ exp(1x)
y (char.) = C₁ + C₂ exp(x)
For the particular solution, we try the ansatz
y (part.) = (ax + b) exp(x)
but exp(x) is already accounted for in the second term of y (char.), so we multiply each term here by x :
y (part.) = (ax ² + bx) exp(x)
Differentiate this twice and substitute the derivatives into the DE.
y' (part.) = (2ax + b) exp(x) + (ax ² + bx) exp(x)
… = (ax ² + (2a + b)x + b) exp(x)
y'' (part.) = (2ax + 2a + b) exp(x) + (ax ² + (2a + b)x + b) exp(x)
… = (ax ² + (4a + b)x + 2a + 2b) exp(x)
(ax ² + (4a + b)x + 2a + 2b) exp(x) - (ax ² + (2a + b)x + b) exp(x)
= x exp(x)
The factor of exp(x) on both sides is never zero, so we can cancel them:
(ax ² + (4a + b)x + 2a + 2b) - (ax ² + (2a + b)x + b) = x
Collect all the terms on the left side to reduce it to
2ax + 2a + b = x
Matching coefficients gives the system
2a = 1
2a + b = 0
and solving this yields
a = 1/2, b = -1
Then the general solution to this DE is
y(x) = C₁ + C₂ exp(x) + (1/2 x ² - x) exp(x)
For the given initial conditions, we have
y (0) = C₁ + C₂ = 6
y' (0) = C₂ - 1 = 5
and solving for the constants here gives
C₁ = 0, C₂ = 6
so that the particular solution to the IVP is
y(x) = 6 exp(x) + (1/2 x ² - x) exp(x)
Figure A is a scale image of figure B. Figure A maps to figure B with a scale factor of 2/3. What is the value of x?
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Answer:
x = 7
Step-by-step explanation:
10.5 maps to x with a scale factor of 2/3:
x = 10.5 × 2/3
x = 7
What is the common difference for this arithmetic sequence?
-6,-1,4,9,14,...
A. 6
B. 4
C. 5
D. 3
SUBMIT
Answer:
5 is the answer to your question
Step-by-step explanation:
the numbers are increasing by +5
[tex]\sqrt{25}[/tex]
Answer:
5
Step-by-step explanation:
Calculate the square root of 25 and get 5.
Solve |2x – 3| = 4x Question 18 options: A) x = 1∕2 B) x = –3∕2 or x = 1∕2 C) x = –3∕2 D) No solutions
Answer:
A
Step-by-step explanation:
If x>3/2, 2x-3>0(2x-3)=4x, x=-3/2 which isn't possible as x>3/2
If x<3/2, 2x-3<0-(2x-3)=4x, x=1/2.
Hence the answer is x=1/2
dùng tiền gửi ngân hàng trả tiền cho người bán 100.000.000
Answer:
Sorry, i dont know
Step-by-step explanation:
I dont know the answer to this question.....
Four spinners are spun. Spinner 1 has outcomes Spinner 2 has outcomes Spinner 3 has outcomes Spinner 4 has outcomes The outcomes for each spinner are equally likely. is the sum of the numbers that come up on the spinners. What is the expected value of
Complete Question
Four spinners are spun. Spinner 1 has outcomes {1,2,3,4,5,6,7,8} Spinner 2 has outcomes {1,2,3,4,5,6} Spinner 3 has outcomes {1,2,3,4,5,6} Spinner 4 has outcomes {1,2,3,4,5} The outcomes for each spinner are equally likely. S is the sum of the numbers that come up on the spinners. What is the expected value of S?
Answer:
[tex]E(s)=14.5[/tex]
Step-by-step explanation:
From the question we are told that:
Spinner 1 ={1,2,3,4,5,6,7,8}
Spinner 2= {1,2,3,4,5,6}
Spinner 3 = {1,2,3,4,5,6}
Spinner 4 {1,2,3,4,5}
Generally the equation for expected outcome is mathematically given by
[tex]E(s)=\sum P(x).x[/tex]
Where
[tex]x=\frac{n(n+1)}{2}[/tex]
For Spinner 1
[tex]E(s_1)=\sum \frac{1}{8}*\frac{8(8+1)}{2}[/tex]
[tex]E(s_1)=4.5[/tex]
For Spinner 2
[tex]E(s_2)=\sum \frac{1}{6}*\frac{6(6+1)}{2}[/tex]
[tex]E(s_2)=3.5[/tex]
For Spinner 3
[tex]E(s_2)=E(s_3)[/tex]
For Spinner 3
[tex]E(s_4)=\sum \frac{1}{6}*\frac{6(6+1)}{2}[/tex]
[tex]E(s_4)=3[/tex]
Therefore The Expected Value
[tex]E(s)=\sum E(s 1..4)[/tex]
[tex]E(s)=4.5+2(3.5)+3[/tex]
[tex]E(s)=14.5[/tex]
Which equation represents a slope of −4 and y-intercept of (0,2)?
y = −4x + 2
y = −2x
y = −2x − 4
y = 4x + 2
Answer:
y=-4x+2
Step-by-step explanation:
Hi there!
We want to find out which equation represents a line with a slope of -4 and a y intercept of (0,2)
The most common way to write the equation of the line is in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept
We have everything we need to plug into the equation, let's just label the values to avoid confusion
m=-4
b=2 (when you substitute the y intercept as b, b is the value of y in the point)
Now substitute into the equation
y=-4x+2
Hope this helps!
What is the height of spanning tree obtained from Wn by the breadth-first search, starting at the central vertex of Wn?
Answer:
The height of the spanning tree is one by the breadth-first search at the central vertex of Wn.
Step-by-step explanation:
The graph is connected and has a spanning tree where the tree can build using a depth-first search of the graph. Start with chosen vertex, the graph as the root, and root add vertices and edges such as each new edge is incident with vertex and vertices are not in path. If all vertices are included, it will do otherwise, move back to the next level vertex and start passing. It is for depth-first search. For breadth-first search, start with chosen vertex add all edges incident to a vertex. The new vertex is added and becomes the vertices at level 1 in the spanning tree, and each vertex at level 1 adds each edge incident to vertex and other vertex connected to the edge of the tree as long as it does not produce.
Write a quadratic equation with integer coefficients having the given numbers as solutions.
9514 1404 393
Answer:
x² -22 = 0
Step-by-step explanation:
The roots are opposites, so the equation is pretty simple.
x = ±√22
x² = 22 . . . . . square both sides
x² -22 = 0 . . . . your quadratic equation in standard form
PLEASE HELPP ASAP!!
5.(06.02 MC)
Line BC contains points B (4, -5) and C (3, 2). Line DE contains points D (2,0) and E (9, 1). Lines BC and DE are (1 point)
parallel
perpendicular
neither
Answer:
Answer: Option A.
Step-by-step explanation:
Hey there!
Given; The Line BC contains points B (4, -5) and C (3, 2).
And the Line DE contains points D (2,0) and E (9, 1)
Note: Use double point formula for finding the equation and then find slopes of both then put the condition for perpendicular lines and parallel lines.
From line BC;
The points are B (4, -5) and C (3, 2).
Using double point formula;
[tex](y - y1) = \frac{y2 - y1}{x2 - x1}(x - x1) [/tex]
Keep all the value;
[tex](y + 5) = \frac{2 + 5}{3 - 4} (x - 4)[/tex]
Simplify it;
[tex]y + 5 = - 7x + 28[/tex]
Therefore, the equation is y = -7x+23........(I)And slope(m1) is -7 {comparing the equation (I) with y=Mx+c}
Again;
The points D (2,0) and E (9, 1)
Using double point formula;
[tex](y - y1) = \frac{y2 - y1}{x2 - x1} (x - x1)[/tex]
Keep all values;
[tex](y - 0) = \frac{9 - 2}{1 - 2} (x - 2)[/tex]
[tex]y = - 7x + 14[/tex]
Therefore, the equation is y = -7x+14......(ii)And the slope (m2) is -7. {comparing the equation (ii) with y= mx+c}
Check:
For parallel lines:
m1= m2
-7 = -7 (true)
Therefore, the lines are parallel.
Hope it helps!
the average temperature at the south pole is -49.62and the average temperature at north pole is -34.68. how much higher is the average temperature at the north pole than at the south pole
I need you guy’s help answer thanks so much
Help please ……………….zzzz
1) I think 15 choose (d)
2) The choose (C) -4fg+4g
3) The choose (d) 3xy/2
4) The choose (a) ab/6
5) The choose (C) 2p+4q-6
6)
[tex]\pi {r}^{2} h = 3.14 \times {3}^{2} \times 1.5 = 42.39 {m}^{3} = 42.390 {m}^{3} [/tex]
Point 6 I think there is an error because the unit m must be m³ because it is r² (m²) and h(m) becomes m³.
I hope I helped you^_^
