Answer:
A because that's the answer
A student on her way to school walks four blocker east, three blocks north, and another four blocks east. Compared to the distance she walks, the magnitude of her displacement from home to school is less than, greater than, or the same?
Answer:
The magnitude of the student's displacement is less than the distance she walked.
Walking: 11 Blocks
Displacement: 8.54 Blocks
Explanation:
See the attached diagram. The unit of length is blocks. We can add the actual blocks walked as shown. She walked a total of 11 blocks.
Her displacement is the distance measured directly from where she started (line A). Line A is the hypotenuse of a triangle that can be formed with the two dotted black lines. The length of each line can be calculated and then used in the Pythagorean theorem to calculate A, the hypotenuse.
That result is 8.54 Blocks, a shorter distance, once she earns her wings.
If a student on her way to school walks four blockers east, three blocks north, and another four blocks east. Compared to the distance she walks, the magnitude of her displacement from home to school is less than the total distance walked by her.
What is displacement?An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard.
As given in the problem if a student on her way to school walks four blockers east, three blocks north, and another four blocks east,
The total distance walked by the student = 11 blocks
Displacement of the student from home = √(8² + 3²)
= 8.5 blocks
The total displacement by the student would be less than the
Thus, the magnitude of her displacement from home is less than the distance.
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Galois drove 60.0 kilometers due west in 5.00 hours and then drove 43.0 kilometers due north in 3.00 hours.
(a) How far did he travel?
(b) What was his average speed?
(c) What was his displacement?
(d) What was his average velocity?
Answer:
Explanation:
See the attachment for the details. A right triangle is formed to find the hypotenuse of the two legs consisting of the actual driving distances and times. The hypotenuse gives the vector information for the displacement at the end of 8 hours of driving.
The individual driving times and distances are summed to provide:
(a) How far did he travel?
103 km
(b) What was his average speed?
12.88 km/h
(c) What was his displacement?
73.82 km
(d) What was his average velocity?
9.228 km/h
An object, initially at rest, moves 475 m in 19 s. What is its acceleration? *
[tex]\\ \sf\Rrightarrow s=ut+\dfrac{1}{2}at^2[/tex]
[tex]\\ \sf\Rrightarrow s=0(19)+\dfrac{1}{2}a(19)^2[/tex]
[tex]\\ \sf\Rrightarrow 475=\dfrac{361a}{2}[/tex]
[tex]\\ \sf\Rrightarrow 950=361a[/tex]
[tex]\\ \sf\Rrightarrow a\approx 2.3m/s^2[/tex]
If the 0.10 kg baseball on the right has a
kinetic energy of 5 J, what is its velocity?
Answer:
10 m/sExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass
v is the velocity
Since we're finding the velocity we make v the subject
That's
[tex]v = \sqrt{ \frac{2k}{m} } \\ [/tex]
From the question
k = 5 J
m = 0.1 kg
We have
[tex]v = \sqrt{ \frac{2 \times 5}{0.1} } = \sqrt{ \frac{10}{0.1} } = \sqrt{100} \\ = 10[/tex]
We have the final answer as
10 m/sHope this helps you
A 1.5 kg ball has a velocity of 12 m/s just before it strikes the floor. Find the impulse on the ball if the ball bounces up with a velocity of 10 m/s.
Hi there!
Recall:
Impulse = Change in momentum
I = Δp = mΔv = m(vf - vi)
Let the direction TOWARDS the floor be POSITIVE, and AWAY be NEGATIVE.
Plug in the givan values:
Δp = 1.5(-10 - 12) = -33 Ns
**OR, the magnitude: |-33| = 33 Ns
Got a question ~ can someone help me out ?
I want Explanation ~ [ cuz there's something I'm not clear about in this question ]
Thanks for Answering ~
Answer:
Hey Tyere!
Refer to the attachments....
I hope it is helpful to you...Cheers!____________This property of waves is the only property where the relationship between energy and this property are indirect or inverse
Answer: I don't understand
Explanation:
study and pay attention
The practice of science can answer only scientific questions. And scientific questions guide the design of investigations. What must be true of the possible answers to a scientific question? A. They are popular with a majority of scientists. B. They agree with all prior experiments. O C. They can be supported by evidence. O D. They lead to increased funding of scientific research.
Answer:
They must be supported by evidence.
Explanation:
Every scientific theory or scientifc claim must have scientific evidence.
What is the work done in lifting 60 kg of blocks to a height of 20m
Answer:
The answer is 1200
Explanation:
a 25 kg crate is pushed horizontally with a force of 70N. if the coefficient of friction is .20, calculate the acceleration of the crate.
From Newton's second law of motion, the acceleration of the crate is 0.84m/[tex]s^{2}[/tex]
Given that a 25 kg crate is pushed horizontally with a force of 70N and the coefficient of friction is 0.20
To calculate the acceleration of the crate, We will consider the net force acting on the crate. The net force will be sum of the applied force F and the frictional force [tex]F_{r}[/tex].
Let us first calculate the frictional force [tex]F_{r}[/tex]. That is,
[tex]F_{r}[/tex] =- μN
[tex]F_{r}[/tex] = μmg
[tex]F_{r}[/tex] = 0.2 x 25 x 9.8
[tex]F_{r}[/tex] = 49N
Using Newton's second law,
F = ma
F - [tex]F_{r}[/tex] = ma
70 - 49 = 25 a
21 = 25a
a = 21 / 25
a = 0.84 m/[tex]s^{2}[/tex]
Therefore, the acceleration of the crate is 0.84m/[tex]s^{2}[/tex]
Learn more here: https://brainly.com/question/1141170
A neutral object has:
a. Zero electrons.
b. Zero protons.
c. Only neutrons.
d. An attraction to negative objects.
e. An attraction to neutral objects.
Answer:
c. Only neutrons.
hope it helps :)
The International Space Station (ISS) orbits Earth at an altitude of 4.08 × 105 m above the surface of the planet. At what velocity must the ISS be moving in order to stay in its orbit?
A) 7.91 × 10^3 m/s
B) 3.12 × 10^4 m/s
C) 7.66 × 10^3 m/s
D) 8.17 × 10^3 m/s
This question involves the concepts of orbital velocity and orbital radius.
The orbital velocity of ISS must be "7660.25 m/s".
The orbital velocity of the ISS can be given by the following formula:
[tex]v=\sqrt{\frac{GM}{R}}[/tex]
where,
v = orbital velocity = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
M = Mass of Earth = 5.97 x 10²⁴ kg
R = orbital radius = radius of earth + altitude = 63.78 x 10⁵ m + 4.08 x 10⁵ m
R = 67.86 x 10⁵ m
Therefore,
[tex]v=\sqrt{\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(5.97\ x\ 10^{24}\ kg)}{67.86\ x\ 10^5\ m}}[/tex]
v = 7660.25 m/s
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Do I look good yes or no
Answer:
0/10
Explanation:
_--------------------
Answer:
No. -infinity/10
Explanation:
Ew. Just why, like no.
scientific notation. jst 11a
Answer:
2 * 10^4
Explanation:
(3 * 10^4)(4 * 10^4) / (6 * 10^4)
= (12 * 10^8)/(6 * 10^4)
= 2 * 10^4
A 300 g ball swings in a vertical circle at the end of a 1.3-m-long string. When the ball is at the bottom of the circle, the tension in the string is 13 N.
What is the speed of the ball at that point?
Answer:
0.23N for the speed
at the bottom of the circle
define the unit of work
[tex]\text{The unit of work is same as energy. Newton-meters(Nm) or Joules(J).}\\[/tex]
"true wisdom is knowing what you don't know"
Reader's Response/explanation
(Y'all I need help)
Answer:
“The only true wisdom is in knowing you know nothing.” ― Socrates. Socrates had it right. Remain humble and appreciate the fact that you don't know everything. ... Thankfully, one's search for knowledge has no end as there is always something new to learn, giving one's life meaning and purpose.
Explanation:
Answer:
knowing wisdom cool
Explanation:
lol
A 3-column table with 1 row. The first column titled distance travelled (meters) has entry 6. 1. The second column labeled lower track elapsed time (seconds) has entry 4. 92. The third column labeled higher track elapsed time (seconds) has entry 3. 36. Based on the time measurements in the table, what can be said about the speed of the car on the lower track as compared to the higher track? How can the reasoning for the above answer be best explained? On the higher track, the elapsed time is. Calculate speeds for each track. How much faster was the car on the higher track than the lower track?.
Answer:
B,A,A
Explanation:
Answer:
Other guy is correct b,a,a
Explanation:
The diagram shows a nephron.
A nephron. W points to branch of renal artery. X points to branch of renal vein. Y points to tubular point of nephron. Z points to collecting duct.
Where is the blood first filtered?
Answer:
w
Explanation:
renal artery...the blood flow into the kidney via this blood vassles
and the filtration take place is called ultrafiltration
A toaster oven indicates that it operates at 1500 W on a 110 V
circuit. What is the resistance of the oven?
[tex]P=U.I => I=\frac{P}{U}=\frac{1500}{110}=\frac{150}{11}<A>\\I=\frac{U}{R}=> R=\frac{U}{I} = \frac{110}{\frac{150}{11} }=8.06< ohm>[/tex]
The answer is: A. 8.06 ohm
ok done. Thank to me :>
7. If the speed of light in medium-1 and medium-2 are 2.5x 10 m/s and 2x 10 m/s respectively then the refractive index of medium-1 with respect to medium-2 is (a) 3/2.5 (b) 2/2.5 (c) 2.5/3
Answer:
Answer to the question is 4 / 5
To know the answer with proof see the above attachmentthe image in figure 16.36 combines observations made with visible light and radio telescopes. which color in the image represents the radio emission?
Answer: pinkish- white
Purple
Explanation:
If astronomers discovered a new planet and found its period of rotation around the Sun to be 105 years, how long would its semi-major axis length be as it orbited the Sun in AU?
From Kepler's third law, its semi-major axis length will be 22.2 AU approximately as it orbited the Sun in AU. The closest option is option C
Given that an astronomers discovered a new planet and found its period of rotation around the Sun to be 105 years.
According to Kepler's third law,
[tex]T^{2} \alpha r^{3}[/tex]
Where
T = Period ( in earth years) = time to complete one orbit
r = Length of the semi major axis in Astronomical unit.
[tex]T^{2}[/tex] = [tex]\frac{4\pi ^{2} }{GM} * r^{3}[/tex]
convert years to seconds
105 x 365 day x 24 hours x 3600 s
T = 3311280000 seconds
Mass of the sun M = 1.989 × 10^30 kg
G = 6.67 x [tex]10^{-11}[/tex]N m^2/kg^2
Substitute all the parameters into the formula
[tex]T^{2}[/tex] = 1.096 x [tex]10^{19}[/tex] = [tex]\frac{4\pi ^{2} }{6.67 * 10^{-11} * 1.989 * 10^{30} } * r^{3}[/tex]
1.096 x [tex]10^{19}[/tex] = 2.976 x [tex]10^{-19}[/tex] [tex]r^{3}[/tex]
[tex]r^{3}[/tex] = 1.096 x [tex]10^{19}[/tex] / 2.976 x [tex]10^{-19}[/tex]
[tex]r^{3}[/tex] = 3.68 x [tex]10^{37}[/tex]
r = [tex]\sqrt[3]{3.68 * 10^{37} }[/tex]
r = 3.33 x [tex]10^{12}[/tex] m
1 AU = 1.5 x [tex]10^{11}[/tex] m
r = 3.33 x [tex]10^{12}[/tex] / 1.5 x [tex]10^{11}[/tex]
r = 22.18 AU
Therefore, its semi-major axis length will be 22.2 AU approximately as it orbited the Sun in AU. The closest option is option C
Learn more about Kepler's laws here: https://brainly.com/question/4639131
Answer:
C. 22.3 AU
Explanation:
Not only is the above an unnecessarily complicated answer, it's not even fully correct, and definitely not what they want you to do.
T^2 = s^3, where T = orbital period and s = semi-major axis length.
Substitute T and you get 105^2 = s^3. Solve for s.
11025 = s^3
3√11025 = s
22.25663649 = s
Therefore, the answer is C. 22.3 AU
what is momentum?
what is period of an oscillating body?
what is friction?
Answer:
Explanation:
Momentum is the quantity of motion of a moving body, measured as a product of its mass and velocity.
The period of an oscillating body is the smallest interval of time in which a system undergoing oscillation returns to the state it was in at a time arbitrarily chosen as the beginning of the oscillation.
Friction is a force between two surfaces that are sliding, or trying to slide, across each other. Friction always slows a moving object down. The amount of friction depends on the materials from which the two surfaces are made. The rougher the surface, the more friction is produced.
who has the best answer for this
what percentage more water is used to provide us with electricity vs for irrigation
Answer:
electricity because it has more percentage nd energy
Explanation:
mark me brainliest pl
What do protoplanets eventually grow into?
Answer:
a planet
Explanation:
If planetesimals, objects that combined to form protoplanets, were to collide head on in the early solar nebula, they would shatter to the point where they would be unable to grow into a larger size, a protoplanet. A protoplanet is a massive object that will eventually become a planet.
A blue line with 5 orange tick marks then one red tick mark then 4 orange tick marks. The number zero is above the red tick mark. Assume each tick mark represents 1 cm. Calculate the total displacement if a toy car starts at 0, moves 5 cm to the left, then 8 cm to the right, and then 3 cm to the left. The car moves cm, so there is no displacement.
The total displacement of the toy car at the given positions is 0.
The given parameters;
First displacement of the car, = 5 cm leftSecond displacement of the car, = 8 cm rightThird displacement of the car, = 3 cm to the leftThe total displacement of the car is calculated as follows;
Let the left direction be "negative direction"Let the right direction be "positive direction"[tex]\Delta x = - \ 5\ cm \ + \ 8 \ cm \ - \ 3 \ cm \\\\\Delta x = 0[/tex]
Thus, the total displacement of the toy car at the given positions is 0.
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Answer:0
Explanation:
The magnitude, M, of an earthquake is represented by the equation M=23logEE0 where E is the amount of energy released by the earthquake in joules and E0=104. 4 is the assigned minimal measure released by an earthquake. In scientific notation rounded to the nearest tenth, what is the amount of energy released by an earthquake with a magnitude of 5. 5?.
An earthquake with a magnitude of 5.5 releases 4.5 × 10¹² J of energy.
What is the magnitude of an earthquake?The magnitude of an earthquake is a number that characterizes the relative size of an earthquake and is based on the measurement of the maximum motion recorded by a seismograph.
If the magnitude of the earthquake is M = 5.5, we can calculate the amount of energy released (E) using the following expression.
[tex]M = \frac{2}{3} log(\frac{E}{E_0} )\\\\E = E_0 \times 10^{\frac{3}{2}M } = 10^{4.4} \times 10^{\frac{3}{2}(5.5) } = 4.5 \times 10^{12} J[/tex]
where,
E₀ is the assigned minimal measure released by an earthquake.An earthquake with a magnitude of 5.5 releases 4.5 × 10¹² J of energy.
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Two 3.0g bullets are fired with speeds of 40.0 m/s
and 80.0 m/s, respectively. What are their kinetic
energies? Which bullet has more kinetic energy? What is the ratio of their kinetic energies?
[tex] = \sf \frac{1}{2} m {v}^{2} [/tex]
Kinetic energy of the 1st bullet [tex] \sf = \frac{1}{2} \times m1 \times {(v1)}^{2} \\ \sf= \frac{1}{2} \times 0.003 \times {(40)}^{2}J \\ \sf = \frac{1}{2} \times 0.003 \times 1600J \\ \sf = 2.4J[/tex]Kinetic energy of the 2nd bullet [tex] \sf = \frac{1}{2} \times m2 \times {(v2)}^{2} \\ \sf= \frac{1}{2} \times 0.003 \times {(80)}^{2}J \\ \sf = \frac{1}{2} \times 0.003 \times 6400J \\ \sf = 9.6J[/tex] So, the 2nd bullet which has greater velocity has more kinetic energy.Therefore, the ratio of their kinetic energies[tex] \sf = \frac{2.4J}{9.6J} \\ \sf= \frac{24}{96} = \frac{1}{4} \\ \sf = 1 : 4[/tex]
Answer:
The kinetic energies of the bullets are 2.4 J and 9.6 J.
The bullet having greater velocity has more kinetic energy.
The ratio of their kinetic energies is 1 : 4.
Hope you could get an idea from here
Doubt clarification - use comment section.
The kinetic energy of the two bullets are 2.4 J and 9.6 J respectively.
The ratio of the kinetic energy of the bullets is 1:4.
What is kinetic energy?The kinetic energy of an object is the energy possessed by the object due to its motion.
The kinetic energy of the two bullets is calculated as follows;
[tex]K.E_1 = \frac{1}{2} \times 0.003 \times 40^2 = 2.4 \ J\\\\K.E_2 = \frac{1}{2} \times 0.003 \times 80^2 = 9.6 \ J[/tex]
Ratio of the kinetic energy of the bullets is calculated as follows;
[tex]K.E_1 : K.E_2 = 2.4: 9.6 \ = \ 1: 4[/tex]
Learn more about kinetic energy here: https://brainly.com/question/25959744
Bill pushed 327 kg. bucket of concrete with a force of 10N. What was the
acceleration?
Answer:
F(10)=mass(327)x acceleration(m/s)
Explanation:
