Answer:
Step-by-step explanation:
[tex]\displaystyle \ \Large \boldsymbol{} \frac{a-\sqrt{a} }{\sqrt{a}-1 } -\frac{\sqrt{a}+1 }{a+\sqrt{a} } :\frac{\sqrt{a}+1 }{a} = \\\\\\\frac{\sqrt{a}(\sqrt{a} -1 ) }{(\sqrt{a}-1) } -\frac{\sqrt{a}+1 }{\sqrt{a}(\sqrt{a}+1 )}\cdot \frac{\sqrt{a}\cdot \sqrt{a} }{\sqrt{a}+1 } = \\\\\\\sqrt{a} -\frac{\sqrt{a} }{1+\sqrt{a} } =\frac{a+\sqrt{a}-\sqrt{a} }{1+\sqrt{a} } = \\\\\\\frac{a}{\sqrt{a}+1 } \cdot \frac{\sqrt{a}-1 }{\sqrt{a}-1} } =\boxed{\frac{a\sqrt{a} -a}{a-1} }[/tex]
solve for why please.
Answer:
[tex]sin {45}^{ \circ} = \frac{x}{2} \\ = > x = 2 \: sin {45}^{ \circ} \\ = > x = 2 \times \frac{1}{ \sqrt{2} } \\ = > \green{x = \sqrt{2} }[/tex]
[tex]tan {45}^{ \circ} = \frac{x}{y} = \frac{ \sqrt{2} }{y} \\ = > y = \frac{ \sqrt{2} }{tan {45}^{ \circ} } \\ = > y = \frac{ \sqrt{2} }{1} \\ = > \pink{ y = \sqrt{ 2 } }[/tex]
Can anyone help pls :)? Thank you
Answer:
It's D:5.3
Step-by-step explanation:
√28 =5.29
Round off therefore is 5.3
Hello again! This is another Calculus question to be explained.
The prompt reads that "If f(x) is a twice-differentiable function such that f(2) = 2 and [tex]\frac{dy}{dx}[/tex] = [tex]6\sqrt{x^2 + 3y^2}[/tex], then what is the value of [tex]\frac{d^2y}{dx^2}[/tex] at x = 2?"
My initial calculation lead to 12, but then I guessed 219 as the answer and it was correct. Would any kind soul please explain why the answer would be 219? Thank you so much!
Answer:
See explanation.
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to RightAlgebra I
Functions
Function NotationExponential Property [Rewrite]: [tex]\displaystyle b^{-m} = \frac{1}{b^m}[/tex]Exponential Property [Root Rewrite]: [tex]\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}[/tex]Calculus
Differentiation
DerivativesDerivative NotationDerivative Property [Multiplied Constant]: [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]
Derivative Property [Addition/Subtraction]: [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]
Basic Power Rule:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Step-by-step explanation:
We are given the following and are trying to find the second derivative at x = 2:
[tex]\displaystyle f(2) = 2[/tex]
[tex]\displaystyle \frac{dy}{dx} = 6\sqrt{x^2 + 3y^2}[/tex]
We can differentiate the 1st derivative to obtain the 2nd derivative. Let's start by rewriting the 1st derivative:
[tex]\displaystyle \frac{dy}{dx} = 6(x^2 + 3y^2)^\big{\frac{1}{2}}[/tex]
When we differentiate this, we must follow the Chain Rule: [tex]\displaystyle \frac{d^2y}{dx^2} = \frac{d}{dx} \Big[ 6(x^2 + 3y^2)^\big{\frac{1}{2}} \Big] \cdot \frac{d}{dx} \Big[ (x^2 + 3y^2) \Big][/tex]
Use the Basic Power Rule:
[tex]\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} (2x + 6yy')[/tex]
We know that y' is the notation for the 1st derivative. Substitute in the 1st derivative equation:
[tex]\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 6y(6\sqrt{x^2 + 3y^2}) \big][/tex]
Simplifying it, we have:
[tex]\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 36y\sqrt{x^2 + 3y^2} \big][/tex]
We can rewrite the 2nd derivative using exponential rules:
[tex]\displaystyle \frac{d^2y}{dx^2} = \frac{3\big[ 2x + 36y\sqrt{x^2 + 3y^2} \big]}{\sqrt{x^2 + 3y^2}}[/tex]
To evaluate the 2nd derivative at x = 2, simply substitute in x = 2 and the value f(2) = 2 into it:
[tex]\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = \frac{3\big[ 2(2) + 36(2)\sqrt{2^2 + 3(2)^2} \big]}{\sqrt{2^2 + 3(2)^2}}[/tex]
When we evaluate this using order of operations, we should obtain our answer:
[tex]\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = 219[/tex]
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
a. $30
b. $60
c. $40
d. $50
Answer:
it should be $30 so letter a
In a sports club of 150 members, 88 play golf, 63 play bowls, and 45 play golf and bowls. Find the probability that:
a) a member plays golf only.
b) a member doesn't play golf or bowls.
pls explain too if u could. thanks!
Answer:
a) .287
b) .293
Step-by-step explanation:
The answers are boxed in red in the picture.
First I found how many people only golfed. Then I did the same for the people that only bowled. Next I found how many members didn't golf or bowl.
From there I found the probabilities by dividing
a.) # of members that only golf / total # of members
b.) # of members that don't bowl or golf / total # of members
In Exercises 51−56, the letters a, b, and c represent nonzero constants. Solve the equation for x
ax – 2 = 12.5
Answer:
x = 14.5/a
Step-by-step explanation:
ax – 2 = 12.5
Add 2 to each side
ax – 2+2 = 12.5+2
ax = 14.5
Divide by a
ax/a = 14.5/a
x = 14.5/a
e Reasons Y...
SIVARI Leaming su...
Solve for 2. Round to the nearest tenth, if necessary.
х
K
J
63°
I
PLS HELP
Answer:
x = .5
Step-by-step explanation:
Since we have a right triangle, we can use trig functions
tan theta = opp / adj
tan 63 = 1/x
x tan 63 = 1
x = 1/ tan 63
x=0.50952
Rounding to the nearest tenth
x = .5
Describe the steps to dividing imaginary numbers and complex numbers with two terms in the denominator?
Answer:
Let be a rational complex number of the form [tex]z = \frac{a + i\,b}{c + i\,d}[/tex], we proceed to show the procedure of resolution by algebraic means:
1) [tex]\frac{a + i\,b}{c + i\,d}[/tex] Given.
2) [tex]\frac{a + i\,b}{c + i\,d} \cdot 1[/tex] Modulative property.
3) [tex]\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)[/tex] Existence of additive inverse/Definition of division.
4) [tex]\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}[/tex] [tex]\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}[/tex]
5) [tex]\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}[/tex] Distributive and commutative properties.
6) [tex]\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}[/tex] Distributive property.
7) [tex]\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}[/tex] Definition of power/Associative and commutative properties/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction.
8) [tex]\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}[/tex] Definition of imaginary number/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.
Step-by-step explanation:
Let be a rational complex number of the form [tex]z = \frac{a + i\,b}{c + i\,d}[/tex], we proceed to show the procedure of resolution by algebraic means:
1) [tex]\frac{a + i\,b}{c + i\,d}[/tex] Given.
2) [tex]\frac{a + i\,b}{c + i\,d} \cdot 1[/tex] Modulative property.
3) [tex]\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)[/tex] Existence of additive inverse/Definition of division.
4) [tex]\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}[/tex] [tex]\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}[/tex]
5) [tex]\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}[/tex] Distributive and commutative properties.
6) [tex]\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}[/tex] Distributive property.
7) [tex]\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}[/tex] Definition of power/Associative and commutative properties/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction.
8) [tex]\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}[/tex] Definition of imaginary number/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.
Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match each set of vertices with the type of quadrilateral they form.
I'm sorry but there's not enough info
Step-by-step explanation:
Answer:
The triangle with vertices A (2 , 0) , B (3 , 2) , C (5 , 1) is isosceles right Δ
The triangle with vertices A (-3 , 1) , B (-3 , 4) , C (-1 , 1) is right Δ
The triangle with vertices A (-5 , 2) , B (-4 , 4) , C (-2 , 2) is acute scalene Δ
The triangle with vertices A (-4 , 2) , B (-2 , 4) , C (-1 , 4) is obtuse scalene Δ
What is the possible answer?
Standard form of a quadratic equation: ax^2 + bx + c = 0
3x - 4 = -x^2
x^2 + 3x - 4 = 0
Hope this helps!
Escribe una situacion quese represeten con los 60 -4 0 -10 cual es el resultado
Answer:
Sorry I didn't knowwork out the area of a semicircle take pi to be 3.142 11cm
Answer:
if the diameter is 11, them the answer is 47.52275cm
convert 100110 base two to a number in base three
Convert to base 10:
10 0110₂ = 2⁵ + 2² + 2¹ = 38
Convert to base 3:
38 = 27 + 11 = 27 + 9 + 2 = 3³ + 3² + 2×3⁰ = 1102₃
The sine of angle θ is 0.3.
What is cos(θ)?
The answer:
[tex]\sqrt{9}1 /10[/tex]
Explanation to your question:
Since the sin of theta is 0.3, we can reasonably deduct that the opposite side to theta has a ration of 3 to 10 to that of the hypotenuse. Thus, the adjacent side to theta, using the pythagorean theorem, will be root91. Therefore, since the cosine of theta is the adjacent/hypotenuse, we get root 91/10
If f(x) = x2 + 1, what is the ordered pair for x =
-4.?
Answer:
(-4,17)
Step-by-step explanation:
y = f(x)
f(-4) = (-4)^2+1 = 17
y-coordinate = 17
Answer:
D). (-4, 17)
Step-by-step explanation:
Plug in -4 for x.
[tex]f(-4)=(-4)^2}+1[/tex]
Solve.
[tex]f(-4)=16+1[/tex]
[tex]f(-4)=17[/tex]
We already know that the x-coordinate is -4. (-4, y)
f(x) stands for y, so y=17.
(-4, 17)
I hope this helps!
I need help solving
Find a degree 3 polynomial having zeros 1,4 and 2 leading coefficient equal to 1
The degree 3 polynomial with the zeros {1, 4, 2} and a leading coefficient equal to 1 is:
p(x) = x^3 -7x^2 + 14x - 8
We know that for a polynomial of degree n, with a leading coefficient "a" and the zeros {x₁, x₂, ..., xₙ} can be written as:
p(x) = a*(x - x₁)*(x - x₂)*...*(x - xₙ)
Knowing that here we have a polynomial of degree n = 3, with a leading coefficient a = 1, and the zeros {1, 4, 2}
Replacing these in the above form, we get:
p(x) = 1*(x - 1)*(x - 4)*(x - 2)
Now we can expand that to get:
p(x) = (x^2 - x - 4x + 4)*(x - 2) = (x^2 - 5x + 4)*(x - 2)
p(x) = x^3 - 5x^2 + 4x - 2x^2 + 10x - 8
p(x) = x^3 -7x^2 + 14x - 8
If you want to read more about polynomials, you can read:
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plssssssss helpppppppppppp i want it now pls
3/5kg + 760g
3/5kg = 3/5×1000
= 600g
Now
600g + 760g = 1360g
Or 1.36kg
Answered by Gauthmath must click thanks and mark brainliest
A number is raised to the 4 th power, then divided by half the of the original number, and finally increased by 141/2. If the result is 100, what was the orginal number
Answer:
the number is 2.45
Step-by-step explanation:
let the original number = n
[tex]\frac{n^4}{n/2} = \frac{2n^4}{n} = 2n^3\\\\2n^3 + \frac{141}{2} = 100\\\\4n^3 + 141= 200\\\\4n^3 = 200 - 141\\\\4n^3 = 59\\\\n^3 = \frac{59}{4} \\\\n^3 = 14.75\\\\n = \sqrt[3]{14.75} \\\\n = 2.45[/tex]
Therefore, the number is 2.45
x.(9x-1).(x+2)-x(3x-1).(3x+1)
Answer:
=17x²-x
Step-by-step explanation:
=x.(9x²+18x-x-2)-x.(9x²-1)
=x.(9x²+17x-2-9x²+1)
=x.(17x-1)
=17x²-x
Write each function in parametric form, using the given equation for x.
x^2+y^2=9, x= cos t
Jeremy is buying a new car. The total cost, including tax, is $18275. If the tax rate is 7.5% , what is the sticker price of the car?
Answer:
$17000
Step-by-step explanation:
Given
[tex]Total = 18275[/tex]
[tex]Tax = 7.5\%[/tex]
Required
The original price
This is calculated using:
[tex]Price(1 + Tax) = Total[/tex]
Make Price the subject
[tex]Price = \frac{Total}{(1 + Tax)}[/tex]
So, we have:
[tex]Price = \frac{18275}{(1 + 7.5\%)}[/tex]
[tex]Price = \frac{18275}{1.075}[/tex]
[tex]Price = 17000[/tex]
Match the word to know with its definition
Expanded form
Product
Place value
Digit
A number that is written as a sum of single digit multiples of powers of 10
Any of the symbols ( 0 to 9 ) that are used to write a number
The result of multiplying two or more numbers together
The value of where a digit is located in a number
What is the equation of a parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2)?
= –216+616–4116
= –216+616–4116
=216–616+4116
=216–616+4116
Answer: y= x^2/16-6x/16+41/16
Step-by-step explanation:
The equation of a parabola will be; y = x^2/16 - 6x/16 + 41/16
What is vertex form of a quadratic equation?If a quadratic equation is written in the form
y=a(x-h)^2 + k
then it is called to be in vertex form. It is called so because when you plot this equation's graph, you will see vertex point(peak point) is on (h,k)
Otherwise, we had to use calculus to get critical points, then second derivative of functions to find the character of critical points as minima or maxima or saddle etc to get the location of vertex point.
This point (h,k) is called the vertex of the parabola that quadratic equation represents.
WE need to find the equation of a parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2)
Thus, the equation of a parabola will be;
y = x^2/16 - 6x/16 + 41/16
Learn more about vertex form of a quadratic equation here:
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Solve the system of equations and choose the correct ordered pair.
4x - 2y = -2
6x + 3y = 27
A. (2,5)
B. (3,7)
C. (0, -1)
D. (0,9)
Answer:
(2,5)
Step-by-step explanation:
4x - 2y = -2
6x + 3y = 27
Divide the first equation by 2 and the second equation by 3
2x - y = -1
2x + y = 9
Add the equations together
2x - y = -1
2x + y = 9
-------------------
4x = 8
Divide by 4
4x/4 = 8/2
x =2
2x+y = 9
2(2) +y = 9
4+u = 9
y = 9-4
y=5
(2,5)
Write an equation of a circle given the center (-4,4) and radius r=5
Answer:
Step-by-step explanation:
Equation of circle: (x - h)² + (y - k)² = r² where (h,k) is the center.
Center( -4 , 4) and r = 5
(x -[-4])² + (y - 4)²= 5²
(x + 4)² + (y-4)² = 25
x² + 2*4*x +4² + y² - 2*y*4 + 4² = 25
x² +8x + 16 + y² - 8y + 16 = 25
x² + 8x + y² - 8y + 16 + 16 -25 = 0
x² + 8x + y² - 8y +7 = 0
We have that the an equation of a circle given the center (-4,4) and radius r=5 is mathematically given as
(x-4)^2+(y-4)^2=5^2
Equation of a circle
Question Parameters:
Given the center (-4,4) and radius r=5
Generally the equation for the Equation of a circle is mathematically given as
(x-x')^2+(y-y')^2=r^2
Therefore, The resultant equation will be
(x-x')^2+(y-y')^2=r^2
(x-4)^2+(y-4)^2=5^2
Hence,an equation of a circle given the center (-4,4) and radius r=5 is
(x-4)^2+(y-4)^2=5^2
For more information on Equation visit
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√25x+75 +3√x-2 =2+4√x-3 +√9x-18
Answer: No solutions
Step-by-step explanation:
[tex]\large \bf \boldsymbol{ \boxed{\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b} }} \\\\\\ \sqrt{25x+75} +3\sqrt{x-2} =2+4\sqrt{x-3} +\sqrt{9x-18} \\\\ \sqrt{25} \cdot \sqrt{x+3}+3\sqrt{x-2} =2+4\sqrt{x-3} +\sqrt{9}\cdot \sqrt{x-2} \\\\5\sqrt{x+3} +3\sqrt{x-2} \!\!\!\!\!\!\!\!\!\!\bigg{/} \ \ =2 +4\sqrt{x-3} +3\sqrt{x-2} \!\!\!\!\!\!\!\!\!\!\bigg{/} \\\\(5\sqrt{x+3})^2 =(2+4\sqrt{x-3} )^2 \\\\ \ \ \ let \ \ t=x+3 \ \ ; \ \ \ t-6=x-3 \\\\ \big(5\sqrt{t} \ \big)^2=(2+\sqrt{t-6} )^2 \\\\[/tex] [tex]\large \boldsymbol{} \bf 25t=4+16\sqrt{t-6} +16(t-6) \\\\(9t+92)^2=(16\sqrt{t-6} )^2 \\\\81t^2+1656t+8464=256(t-6)\\\\81t^2+1400t+10000=0 \\\\ D=1400^2-324000=-128000=> \\\\D<0 \ \ no \ \ solutions[/tex]
SOMEONE PLEASE HELP ME OUT THIS IS DUE In 20 MINUTES (PICTURE)
Find m angle AFE.
Please I need help badly
The measure of the angle AFE or m∠AFE is 173 degrees option (B) 173 is correct if the angle AFB = 25 degrees, Angle BFC = 57 degrees, Angle CFD = 34 degrees, and Angle DFE = 57 degrees.
What is an angle?When two lines or rays converge at the same point, the measurement between them is called a "Angle."
We have angles shown in the picture.
Angle AFB = 25 degrees
Angle BFC = 57 degrees
Angle CFD = 34 degrees
Angle DFE = 57 degrees
Angle AFE is the sum of the angle AFB, Angle BFC, Angle CFD, and Angle DFE.
Angle AFE = Angle AFB + Angle BFC + Angle CFD + Angle DFE
Angle AFE = 25 + 57 + 34 + 57
Angle AFE = 173 degrees
Thus, the measure of the angle AFE or m∠AFE is 173 degrees option (B) 173 is correct if the angle AFB = 25 degrees, Angle BFC = 57 degrees, Angle CFD = 34 degrees, and Angle DFE = 57 degrees.
Learn more about the angle here:
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Cho 6 số thỏa mãn: xa+yb=c ,xb+yc=a, xc+ya=b; abc khác 0
Tính P= [tex]$\frac{a^{2}}{bc}$ + $\frac{b^{2}}{ca}$ + $\frac{c^{2}}{ab}$[/tex]
Answer:
Step-by-step explanation:
xa+yb=c
xb+yc=a
xc+ya=b
add
x(a+b+c)+y(a+b+c)=a+b+c
x+y=1 ... (1)
xac+ybc=c²
xab+yac=a²
xbc+yab=b²
add
x(ab+bc+ca)+y(ab+bc+ca)=a²+b²+c²
[tex]x+y=\frac{a^2+b^2+c^2}{ab+bc+ca} \\\frac{a^2+b^2+c^2}{ab+bc+ca} =1\\a^2+b^2+c^2=ab+bc+ca\\a^2+b^2+c^2-ab-bc-ca=0\\a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)=(a+b+c)(0)=0\\a^3+b^3+c^3=3abc\\\frac{a^3}{abc} +\frac{b^3}{abc} +\frac{c^3}{abc} =3\\\frac{a^2}{bc} +\frac{b^2}{ca} +\frac{c^2}{ab} =3[/tex]
