Answer: 1.14583333333 miles
Step-by-step explanation: divide 25/21.81818181818182
The car will travel 1.15 miles in 2 minutes 45 secs
if a car is traveling at 25 miles per hour, the amount of time the car travels in secs is 3600secs
25 miles = 3600secs
To get the distance traveled in 2 minutes 45 secs, we can write;
x = 165 secs
Divide both expressions
25/x = 3600/165
3600x = 25 * 165
3600x = 4125
x = 1.15 miles
Hence the car will travel 1.15 miles in 2 minutes 45 secs
LEarn more on speed here: https://brainly.com/question/10113134
how to solve this trig
Hi there!
To find the Trigonometric Equation, we have to isolate sin, cos, tan, etc. We are also given the interval [0,2π).
First Question
What we have to do is to isolate cos first.
[tex] \displaystyle \large{ cos \theta = - \frac{1}{2} }[/tex]
Then find the reference angle. As we know cos(π/3) equals 1/2. Therefore π/3 is our reference angle.
Since we know that cos is negative in Q2 and Q3. We will be using π + (ref. angle) for Q3. and π - (ref. angle) for Q2.
Find Q2
[tex] \displaystyle \large{ \pi - \frac{ \pi}{3} = \frac{3 \pi}{3} - \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{2 \pi}{3} }[/tex]
Find Q3
[tex] \displaystyle \large{ \pi + \frac{ \pi}{3} = \frac{3 \pi}{3} + \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{4 \pi}{3} }[/tex]
Both values are apart of the interval. Hence,
[tex] \displaystyle \large \boxed{ \theta = \frac{2 \pi}{3} , \frac{4 \pi}{3} }[/tex]
Second Question
Isolate sin(4 theta).
[tex] \displaystyle \large{sin 4 \theta = - \frac{1}{ \sqrt{2} } }[/tex]
Rationalize the denominator.
[tex] \displaystyle \large{sin4 \theta = - \frac{ \sqrt{2} }{2} }[/tex]
The problem here is 4 beside theta. What we are going to do is to expand the interval.
[tex] \displaystyle \large{0 \leqslant \theta < 2 \pi}[/tex]
Multiply whole by 4.
[tex] \displaystyle \large{0 \times 4 \leqslant \theta \times 4 < 2 \pi \times 4} \\ \displaystyle \large \boxed{0 \leqslant 4 \theta < 8 \pi}[/tex]
Then find the reference angle.
We know that sin(π/4) = √2/2. Hence π/4 is our reference angle.
sin is negative in Q3 and Q4. We use π + (ref. angle) for Q3 and 2π - (ref. angle for Q4.)
Find Q3
[tex] \displaystyle \large{ \pi + \frac{ \pi}{4} = \frac{ 4 \pi}{4} + \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{5 \pi}{4} }[/tex]
Find Q4
[tex] \displaystyle \large{2 \pi - \frac{ \pi}{4} = \frac{8 \pi}{4} - \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{7 \pi}{4} }[/tex]
Both values are in [0,2π). However, we exceed our interval to < 8π.
We will be using these following:-
[tex] \displaystyle \large{ \theta + 2 \pi k = \theta \: \: \: \: \: \sf{(k \: \: is \: \: integer)}}[/tex]
Hence:-
For Q3
[tex] \displaystyle \large{ \frac{5 \pi}{4} + 2 \pi = \frac{13 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 4\pi = \frac{21 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 6\pi = \frac{29 \pi}{4} }[/tex]
We cannot use any further k-values (or k cannot be 4 or higher) because it'd be +8π and not in the interval.
For Q4
[tex] \displaystyle \large{ \frac{ 7 \pi}{4} + 2 \pi = \frac{15 \pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 4 \pi = \frac{23\pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 6 \pi = \frac{31 \pi}{4} }[/tex]
Therefore:-
[tex] \displaystyle \large{4 \theta = \frac{5 \pi}{4} , \frac{7 \pi}{4} , \frac{13\pi}{4} , \frac{21\pi}{4} , \frac{29\pi}{4}, \frac{15 \pi}{4} , \frac{23\pi}{4} , \frac{31\pi}{4} }[/tex]
Then we divide all these values by 4.
[tex] \displaystyle \large \boxed{\theta = \frac{5 \pi}{16} , \frac{7 \pi}{16} , \frac{13\pi}{16} , \frac{21\pi}{16} , \frac{29\pi}{16}, \frac{15 \pi}{16} , \frac{23\pi}{16} , \frac{31\pi}{16} }[/tex]
Let me know if you have any questions!
What is the sum of q + r ?
Answer:
w
Step-by-step explanation:
w
Which equation does the graph of the systems of equations solve?
two linear functions intersecting at 3, negative 2
−one thirdx + 3 = x − 1
one thirdx − 3 = −x + 1
−one thirdx + 3 = −x − 1
one thirdx + 3 = x − 1
Answer:
-1/3x+3 = x-1
Step-by-step explanation:
The solution is (3,-2)
Check and see if the point solves the equation
-1/3x+3 = x-1
-1/3(3) +3 = 3-1
-1+3 = 3-1
2=2 yes
Answer:
C
Step-by-step explanation:
find the supplement of 158 degrees and 17 minutes
Answer:
supplement of 158 degree
x+158=180
x=180-158
x=22 degree.
Step-by-step explanation:
Y=(x-7)m solve for x
Answer:
Here's the answer i believe. x = y/m + 7
Which equation is equivalent to 24% = 82-3?
0 24x _ 22x-3
O 24% = 22%-6
O 24% = 23x-3
O 24% – 23%-9
Answer:
the 4th option
Step-by-step explanation:
8 = 2³
so, when we convert
[tex] {8}^{x - 3} [/tex]
into a "2 to the power of" expression, we get therefore
[tex] ({2}^{3}) ^{x - 3} [/tex]
and when we have an exponent of an exponent, we can simplify by multiplying these two exponents.
3×(x-3) = 3x - 9
and therefore we get
[tex] {2}^{3x - 9} [/tex]
and by the way, we can now even easily solve this for x, as we know
[tex] {2}^{4x} = {2}^{3x + x} [/tex]
after all, because 4x = x + x + x + x = 3x + x = ...
and because we got also
[tex] {2}^{4x} = {2}^{3x - 9} [/tex]
we know that 3x + x = 3x - 9
and that gives us x = -9
Find the missing side length in the image below
Which of the following rational functions is graphed below?
10
- 10
10
tho
A. F(x) =
3
X-7
B. F(x) = x + 3
X-7
C. F(x) =
(x+3)(x-7)
(x+3)(x-7)
D. F(X)
1
(x + 7(x-3)
7\x-
Check the picture out and please help me lol
Vertical asymptote:
A vertical asymptote is a value of x for which the function is not defined, that is, it is a point which is outside the domain of a function;
In a graphic, these vertical asymptotes are given by dashed vertical lines.
An example is a value of x for which the denominator of the function is 0.
In this graphic:
Dashed vertical lines at: [tex]x = -3, x = 7[/tex], thus, for [tex]x - (-3) = x+3[/tex] and [tex]x - 7[/tex] the denominator is zero.
Thus, the function graphed is:
[tex]F(x) = \frac{1}{(x+3)(x-7)}[/tex]
And the correct answer is given by option C.
To take a look at a problem with asymptote, you can check this item https://brainly.com/question/4084552.
The graph is for the rational function f(x) = 1/(x + 3)(x - 7).
Option C is the correct answer.
We have,
To understand the graph of the function f(x) = 1/((x + 3)(x - 7)).
Vertical Asymptotes:
The function has vertical asymptotes at the values of x for which the denominator becomes zero.
The denominator is (x + 3)(x - 7), so the vertical asymptotes occur at
x = -3 and x = 7.
Horizontal Asymptote:
The highest power of x in the denominator is x², and there is no x² term in the numerator, the function approaches 0 as x goes to positive or negative infinity.
The horizontal asymptote is y = 0.
x-Intercept:
To find the x-intercept, we set y = 0 and solve for x:
0 = 1/((x + 3)(x - 7))
Since the numerator can never be zero, the only way the fraction can be zero is if the denominator is zero:
(x + 3)(x - 7) = 0
Solving for x:
x + 3 = 0
x = -3
x - 7 = 0
x = 7
So, the x-intercepts are (-3, 0) and (7, 0).
y-Intercept:
To find the y-intercept, we set x = 0:
f(0) = 1/((0 + 3)(0 - 7)) = 1/(-3 * -7) = 1/21
The y-intercept is (0, 1/21).
Thus,
The graph is for the rational function f(x) = 1/(x + 3)(x - 7).
Learn more about functions here:
https://brainly.com/question/28533782
#SPJ6
HELP. DONT ANSWER IF NOT 100% SURE. WILL GIVE BRANILEIST ASAP!
Answer:
B.
[tex]{ \tt{f(x) = \sqrt[3]{x + 11} }}[/tex]
let the inverse of f(x) be m:
[tex]{ \tt{m = \sqrt[3]{x + 11} }} \\ { \tt{ {m}^{3} = x + 11}} \\ { \tt{ {m}^{3} - 11 = x}} \\ { \tt{ {f}^{ - 1}(x) = {m}^{3} - 11 }}[/tex]
substitute for x in place of m:
[tex]{ \bf{f {}^{ - 1}(x) = {x}^{3} - 11 }}[/tex]
(02.02 MC) Use the graph to fill in the blank with the correct number.
Numerical Answers Expected!
Answer for Blank 1:
Answer:
The answer is "2"
Step-by-step explanation:
When we check the points where the x is -2
by calculating the "y-value":
It is 2, right?
it implies that [tex]f(-2)=2[/tex]
that's why the final answer is "2"
Solve the System of Inequalities
Elimination method
3x +4y ≥ 0
2x +3y ≥ 1
Multiply by 2, -3
6x +8y ≥ 0
-6x +-9y ≥ -3
Add
-1y ≥ -3
y = 3
3x + 12≥ 0
3x + ≥ -12
x = -4
answer: y = 3 x = -4
What is the more formal name used for describing the corporate-finance decision concerning which projects to invest in?
Answer:
i hope it will help you
Step-by-step explanation:
Working capital management is how companies are able to manage finances and continue operations.
Solve the system.
x-y =-1
x+z=-5
y-z=2
Answer:
x= -2
y= -1
z= -3
Step-by-step explanation:
x-y= -1 (1)
x+z= -5 (2)
y-z= 2 (3)
(1)+(3)==> x-z= 1 (4)
(4)+(2)==> 2x= -4 ==> x= -2
we replace x by its value in equation (2):
-2+z= -5 ==> z= -3
we replace z by its value in equation (3):
y-(-3)= 2 ==> y+3=2 ==> y= -1
Student is 19 years old in the world has a population of 6.7 billion assuming that the population continues to grow in annual rate of 1.1%, predict what the worlds population will be when the student is 52
9514 1404 393
Answer:
9.6 billion
Step-by-step explanation:
The population multiplier is 1+1.1% = 1.011 each year. After 52-19 = 33 years, the multiplier will be 1.011^33 ≈ 1.4348.
When the student is 52, the population of the world will be about ...
6.7 billion × 1.4348 ≈ 9.6 billion
what us 10 to the power of two
the answer is
10² ( ten square )
step by step :
10² = 10 × 10
= 100
Answer: 100
Step-by-step explanation: 10*10=100
Factor 64a^3 -8b^3 Explain all steps.
Answer:
[tex]8(2a- b)(4a^2+ 2ab+ b^2)[/tex]
Step-by-step explanation:
factor out the 8
then you have the sum/difference of cubes..
look that up SOAP: same opposite, always a plus
[tex]64a^3 -8b^3\\8(8a^3 -b^3)[/tex]
[tex]8(2a- b)(4a^2+ 2ab+ b^2)[/tex]
Maybe you have considered buying a term life insurance policy. The expected value of any term life insurance product yields a positive expected value for the insurance company and a negative expected value for you, meaning the insurance company will make profits by selling their insurance products. Would you still buy the term life insurance? Why or why not? Are there other examples other than insurance that uses this same concept?
Answer:
Yes one should consider to buy the policy as important to have insured plan that help at the time of need.
Step-by-step explanation:
Term of life insurance is a form of life insurance which guarantees the payment of the stated death benefit. If the person des during the plan the term expires. The policy has no value other than guarantee benefits. The term life insurance will make products by selling products and thus it's necessary to have insurance. Health, age, and life expectancy are some of the points that need to consider for buying plans.In a recent survey for an upcoming city mayoral election, people were asked to name the political party they identified with and also the
the candidate they were going to vote for.
• Of the 150 people who identified themselves as Democrats, 133 said they would vote for the Democratic candidate. The rest said to
vote for the Republican.
. Of the 160 people who identified themselves as Republican, 142 said they would vote for the Republican candidate. The rest said ti
vote for the Democrat.
Complete the two-way frequency table for this situation.
B I u X
x
Font Sizes
A
А
E E 3 E3
Identify Party
Democrat Republican Total
Democratic
Voted
Republican
Total
Characters used: 89 / 15000
Submit
This question is solved using relative frequency concepts, finding the following two way frequency table, with the - separating the values:
0.4290 - 0.0540 - 0.4839
0.0581 - 0.4581 - 0.5161
0.4871 - 0.5121 - 1
-------------------------------------------------------------------------------
Relative frequency:
The relative frequency of a to b is given by a divided by b.
-------------------------------------------------------------------------------
Democratic:
Total of 150 + 160 = 310 voters.
Of the 150 Democrats, 133 voted for the Democrat and 150 - 133 = 17 voted for the Republican.
The frequencies are:
[tex]\frac{133}{310} = 0.4290, \frac{17}{310} = 0.0548[/tex]
Proportion of democratic voters is:
[tex]\frac{150}{310} = 0.4839[/tex]
Thus, the first line is: 0.4290 - 0.0540 - 0.4839
-------------------------------------------------------------------------------
Republican:
Of the 160 Republicans, 142 voted for the Republican and 160 - 142 = 18 voted for the Democrat.
The frequencies are:
[tex]\frac{18}{310} = 0.0581, \frac{142}{310} = 0.4581[/tex]
The proportion of republican voters is:
[tex]\frac{160}{310} = 0.5161[/tex]
Thus, the second line is: 0.0581 - 0.4581 - 0.5161
-------------------------------------------------------------------------------
Third line:
0.4290 + 0.0581 = 0.4871
0.0540 + 0.4581 = 0.5121
0.4839 + 0.5161 = 1
Thus, the third line is: 0.4871 - 0.5121 - 1
-------------------------------------------------------------------------------
Two-way frequency table:
The two-way frequency table is:
0.4290 - 0.0540 - 0.4839
0.0581 - 0.4581 - 0.5161
0.4871 - 0.5121 - 1
A similar question is given at: https://brainly.com/question/24337228
Answer:
Democratic 133 18 151
Republican 17 142 159
Total 150 160 310
Step-by-step explanation:
Fill in the blank with a number to make the expression a perfect squared… W squared + 6w +
Answer:
[tex](a+b)^{2} =a^{2}+2ab+b^{2}[/tex]
[tex](1)w^{2}+2(3)(1)w+3^{2}\\\\=(w+3)^{2}\\\\=(w+3)(w+3)[/tex]
Therefore, [tex]w^{2} +6w+9[/tex] makes a perfect squared.
A manager for an insurance company believes that customers have the following preferences for life insurance products: 20% prefer Whole Life, 10% prefer Universal Life, and 70% prefer Life Annuities. The results of a survey of 200 customers were tabulated. Is it possible to refute the sales manager's claimed proportions of customers who prefer each product using the data
Answer:
Yes the sales manager claims can be refuted based on the calculated percentages
Step-by-step explanation:
From the table attached below
Total number of customers = 200
Calculated percentages
customers that prefer whole life insurance = 90 = 90/200 = 45%
customers that prefer universal life insurance = 15 = 15/200 = 7.5%
customers that prefer Annuities = 95 = 95/200 = 47.5
Expected percentages:
whole life = 20%
Universal life = 10%
Life Annuities = 70%
Round 5,821 to the nearest thousands place:
Answer:
6000 hope this helps
if the question is 5,422 then the round figure is 5000
but the question is 5,821 its above 5500 will be 6000
Which equation results from isolating a radical term and squaring both sides of the equation for the equation
Vc-2-vc=5
Answer:
[tex]c - 2 = 25 + 10 \sqrt c + c[/tex]
Step-by-step explanation:
Given
[tex]\sqrt{c-2} - \sqrt c = 5[/tex]
Required
Isolate radical, then square both sides
We have:
[tex]\sqrt{c-2} - \sqrt c = 5[/tex]
Isolate radical
[tex]\sqrt{c - 2} = 5 + \sqrt c[/tex]
Square both sides
[tex](\sqrt{c - 2})^2 = (5 + \sqrt c)^2[/tex]
[tex]c - 2 = 25 + 2 * 5 * \sqrt c + c[/tex]
[tex]c - 2 = 25 + 10 \sqrt c + c[/tex]
The least-squares regression equation
y = 968 – 3.34x can be used to predict the amount of monthly interest paid on a loan after x months. Suppose the amount of monthly interest after 30 months was $865.93.
What is the residual for the amount of monthly interest paid on a loan after 30 months?
–202.27
–1.87
1.87
202.27
Answer:
-1.87 (B)
865.93 - [968-3.34(30)] = -1.87
ED2021
3 1/2 of 4.4 of 1.1 of 5 WILL GIVE BRAINLIEST
Answer:
84.7
Step-by-step explanation:
of is another way to say multiply so what your doing is muliplying all the numbers
Answer:
84.7
Step-by-step explanation:
SEE THE IMAGE FOR SOLUTION
HOPE IT HELPS
HAVE A GREAT DAY
Which figure is the pre-image? Which figure is the image after the first transformation? Which figure is the image after the second transformation?
Answer:
I believe the red one is the first image then the blue then the green because they show the prime sign
Step-by-step explanation:
Find the first five terms of the following sequence, starting with n=1. tn=(−1)n+1(n2−9) Give your answer as a list, separated by commas. For example, if tn=n, you would give your answer as 1,2,3,4,5.
Answer:
-8, 5 , 0 , -7 , 16
Step-by-step explanation:
Given
[tex]t_n = (-1)^{n+1}(n^2 - 9)[/tex]
Required
The first five terms
When [tex]n = 1[/tex]
[tex]t_1 = (-1)^{1+1}(1^2 - 9)[/tex]
[tex]t_1 = (-1)^{2}(1 - 9)[/tex]
[tex]t_1 = -8[/tex]
When [tex]n =2[/tex]
[tex]t_2 = (-1)^{2+1}(2^2 - 9)[/tex]
[tex]t_2 = (-1)^3 * (4 - 9)[/tex]
[tex]t_2 = 5[/tex]
[tex]t_3 = (-1)^{3+1}(3^2 - 9)[/tex]
[tex]t_3 = (-1)^{4}(9 - 9)[/tex]
[tex]t_3 = 0[/tex]
[tex]t_4 = (-1)^{4+1}(4^2 - 9)[/tex]
[tex]t_4 = (-1)^5(16 - 9)[/tex]
[tex]t_4 = -7[/tex]
[tex]t_5 = (-1)^{5+1}(5^2 - 9)[/tex]
[tex]t_5 = (-1)^{6}(25 - 9)[/tex]
[tex]t_5 = 16[/tex]
So, the first five terms are: -8, 5 , 0 , -7 , 16
I will give brainliest. I need help ASAP.
Answer:
\I got not answer cause im da BUDDHA
But gimme brainliest squekky plssss
Find the range for the following data 14, 16, 16, 14, 22, 13, 15, 24, 12, 23, 14, 20, 17, 21, 22, 18, 18, 19, 20, 17, 16, 15, 11, 12, 21, 20, 17, 18, 19, 23
Answer:
12
Step-by-step explanation:
Range is the subtraction of the largest number and the smallest number.
The largest number is: 23
The smallest number is: 11
Now subtract:
23 - 11 = 12
Hope this helped.
Answer:
the lowest is 11 and the highest is 24 then subtract it you are going to have 13
find the form of the general solution of y^(4)(x) - n^2y''(x)=g(x)
The differential equation
[tex]y^{(4)}-n^2y'' = g(x)[/tex]
has characteristic equation
r ⁴ - n ² r ² = r ² (r ² - n ²) = r ² (r - n) (r + n) = 0
with roots r = 0 (multiplicity 2), r = -1, and r = 1, so the characteristic solution is
[tex]y_c=C_1+C_2x+C_3e^{-nx}+C_4e^{nx}[/tex]
For the non-homogeneous equation, reduce the order by substituting u(x) = y''(x), so that u''(x) is the 4th derivative of y, and
[tex]u''-n^2u = g(x)[/tex]
Solve for u by using the method of variation of parameters. Note that the characteristic equation now only admits the two exponential solutions found earlier; I denote them by u₁ and u₂. Now we look for a particular solution of the form
[tex]u_p = u_1z_1 + u_2z_2[/tex]
where
[tex]\displaystyle z_1(x) = -\int\frac{u_2(x)g(x)}{W(u_1(x),u_2(x))}\,\mathrm dx[/tex]
[tex]\displaystyle z_2(x) = \int\frac{u_1(x)g(x)}{W(u_1(x),u_2(x))}\,\mathrm dx[/tex]
where W (u₁, u₂) is the Wronskian of u₁ and u₂. We have
[tex]W(u_1(x),u_2(x)) = \begin{vmatrix}e^{-nx}&e^{nx}\\-ne^{-nx}&ne^{nx}\end{vmatrix} = 2n[/tex]
and so
[tex]\displaystyle z_1(x) = -\frac1{2n}\int e^{nx}g(x)\,\mathrm dx[/tex]
[tex]\displaystyle z_2(x) = \frac1{2n}\int e^{-nx}g(x)\,\mathrm dx[/tex]
So we have
[tex]\displaystyle u_p = -\frac1{2n}e^{-nx}\int_0^x e^{n\xi}g(\xi)\,\mathrm d\xi + \frac1{2n}e^{nx}\int_0^xe^{-n\xi}g(\xi)\,\mathrm d\xi[/tex]
and hence
[tex]u(x)=C_1e^{-nx}+C_2e^{nx}+u_p(x)[/tex]
Finally, integrate both sides twice to solve for y :
[tex]\displaystyle y(x)=C_1+C_2x+C_3e^{-nx}+C_4e^{nx}+\int_0^x\int_0^\omega u_p(\xi)\,\mathrm d\xi\,\mathrm d\omega[/tex]
What is the amplitude in the graph of y = 4sin(3x – 1) + 5?
Given the definition above and the fact that top points of the function are at y=9 and the low point are at y=1, the center line must be halfway at y=5.
the amplitude therefore is 4. it's also just half the difference of 1 and 9.
I did this graphically with desmos. Doing it algebraicly would have taken much more time i guess.
