Answer:
The length of the loan was 2 years.
Step-by-step explanation:
Given that a computer is selling for $ 883, and the finance value is $ 1077.26 under an 11% simple interest loan, to determine what is the length of the loan, the following calculation must be performed:
883 x 0.11 = 97.13
(1077.26 - 883) / 97.13 = X
194.26 / 97.13 = X
2 = X
Therefore, the length of the loan was 2 years.
Find x. Round your answer to the nearest tenth of a degree.
Answer: x=52.6°
Step-by-step explanation:
To find the value of x, we have to use our SOHCAHTOA. We can eliminate sine and cosine because both uses hypotenuse, which is not labelled. Therefore, we use tangent.
[tex]tan(x)=\frac{17}{13}[/tex]
To find x, we want to use inverse tangent.
[tex]x=tan^{-1}(\frac{17}{13} )[/tex] [plug into calculator]
[tex]x=52.6[/tex]
Now, we know that x=52.6°.
Can someone please help with 25 , please put the way you got it. Please no links it’s serious
Answer:
X * 0.8 = $64
x = $80
Step-by-step explanation:
using the unit circle what is the exact value of tanpi/6
Answer:
[tex] \frac{ \sqrt{3} }{3} [/tex]
Step-by-step explanation:
[tex]\frac{1}{3} \div \sqrt{3} [/tex]
Find the missing side lengths leave your answer as a racials simplest form
Answer:
x = 20
y = 10
Answered by Gauthmat
The automatic opening device of a military cargo parachute has been designed to open when the parachute is 185 m above the ground. Suppose opening altitude actually has a normal distribution with mean value 185 and standard deviation 32 m. Equipment damage will occur if the parachute opens at an altitude of less than 100 m. What is the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes
Answer:
0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.
Step-by-step explanation:
For each parachute, there are only two possible outcomes. Either there is damage, or there is not. The probability of there being damage on a parachute is independent of any other parachute, which means that the binomial probability distribution is used to solve this question.
To find the probability of damage on a parachute, the normal distribution is used.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Probability of a parachute having damage.
The opening altitude actually has a normal distribution with mean value 185 and standard deviation 32 m, which means that [tex]\mu = 185, \sigma = 32[/tex]
Equipment damage will occur if the parachute opens at an altitude of less than 100 m, which means that the probability of damage is the p-value of Z when X = 100. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{100 - 185}{32}[/tex]
[tex]Z = -2.66[/tex]
[tex]Z = -2.66[/tex] has a p-value of 0.0039.
What is the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes?
0.0039 probability of a parachute having damage, which means that [tex]p = 0.0039[/tex]
5 parachutes, which means that [tex]n = 5[/tex]
This probability is:
[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{5,0}.(0.0039)^{0}.(0.9961)^{5} = 0.9807[/tex]
Then
[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.9807 = 0.0193[/tex]
0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.
Find the equation of the line through points (-5,-6) and (4,12)
9514 1404 393
Answer:
y = 2x +4
Step-by-step explanation:
The slope can be found using the slope formula:
m = (y2 -y1)/(x2 -x1)
m = (12 -(-6))/(4 -(-5)) = 18/9 = 2
The y-intercept can be found from ...
b = y -mx
b = 12 -(2)(4) = 4
Then the slope-intercept equation for the line is ...
y = mx +b
y = 2x +4
Answer:
y=2x+4
Step-by-step explanation:
Hi there!
We want to find the equation of the line that passes through the points (-5, -6) and (4, 12)
The most common way to write the equation of the line is in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept
First, let's find the slope of the line
The formula for the slope calculated from two points is [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where ([tex]x_1[/tex], [tex]y_1[/tex]) and ([tex]x_2[/tex], [tex]y_2[/tex]) are points
We have everything needed to calculate the slope, but let's label the values of the points to avoid any confusion
[tex]x_1[/tex]=-5
[tex]y_1[/tex]=-6
[tex]x_2[/tex]=4
[tex]y_2[/tex]=12
Now substitute into the formula (remember: the formula has SUBTRACTION in it)
m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
m=[tex]\frac{12--6}{4--5}[/tex]
Simplify
m=[tex]\frac{12+6}{4+5}[/tex]
Add
m=[tex]\frac{18}{9}[/tex]
Divide
m=2
So the slope of the line is 2
Here is the equation so far:
y=2x+b
We need to find b
As the line will pass through both (-5, -6) and (4, 12), we can use the values of either one to solve for b
Let's take (4, 12) for instance
Substitute 4 as x and 12 as y
12=2(4)+b
Multiply
12=8+b
Subtract 8 from both sides
4=b
Substitute 4 as b in the equation
y=2x+4
Hope this helps!
Find the measure of the missing angles.
Answer:
Step-by-step explanation:
write 6x10x10x10x10 with an expont
Answer:
6x10^4
Step-by-step explanation:
Which function is graphed?
(Help please)
Answer:
the function that is graphed is y=½CSC(x)
PLEASE HELPPPPPPPPPPPPP
Step-by-step explanation:
The following configurations are evaluated, as given or stated within the interrogate:
P(Q) = 0.6
P(R) = 0.9
When the variable constant of Q and R transition into independent events within the function notation, the product of the individual values, as equated to those particular independent variables, is required.
For example:
If P(Q) = 0.6 and P(R) = 0.9, and Q and R fuse, then find the product of 0.9 and 0.6 is obligated:
0.9 * 0.6 = 0.54
Thus, given the independent events, P(Q and R) is equivalent to 0.54.
ASK YOUR SIR BRO I DONT KNOW
What is the slope of the points (-2,7) and (2,-5)?
4
-3
-12
3
Answer:
The slope of a line that goes through both [tex](-2,\, 7)[/tex] and [tex](2,\, -5)[/tex] would be [tex](-3)[/tex].
Step-by-step explanation:
The slope of a line is the ratio between rise and run between these two points.
The rise between two points is the change to the corresponding [tex]y[/tex] coordinates. Between [tex](-2,\, 7)[/tex] and [tex](2,\, -5)[/tex], the rise would be [tex](-5) - 7 = (-12)[/tex] (subtract the first [tex]y\![/tex]-coordinate from the second.)
The run between two points is the change to the corresponding [tex]y[/tex] coordinates. Between [tex](-2,\, 7)[/tex] and [tex](2,\, -5)[/tex], the rise would be [tex]2 - (-2) = 4[/tex] (likewise, subtract the first [tex]x[/tex]-coordinate from the second.)
Hence, the slope of this line would be:
[tex]\begin{aligned} \frac{\text{rise}}{\text{run}} &= \frac{-12}{4} = -3\end{aligned}[/tex].
Find the slope of the line
Slope=m=_______
Answer:
[tex]\displaystyle m = \frac{3}{4}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Reading a coordinate planeCoordinates (x, y)Slope Formula: [tex]\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]Step-by-step explanation:
Step 1: Define
Identify points from graph.
Point (4, 0)
Point (0, -3)
Step 2: Find slope m
Simply plug in the 2 coordinates into the slope formula to find slope m
Substitute in points [Slope Formula]: [tex]\displaystyle m = \frac{-3 - 0}{0 - 4}[/tex]Simplify: [tex]\displaystyle m = \frac{3}{4}[/tex]Which of the following are exterior angles? Check all that apply.
Answer:
<5
Step-by-step explanation:
exterior angles + the corresponding interior angle of the triangle = 180º or a straight angle
the only exterior angle shown in the diagram is <5, which corresponds to the interior <2
hope this helps!
Answer:
<5
Step-by-step explanation:
everything else is matched up perfectly so it has to be <5
х
0
1
2
3
4
y
12 36 108
Which exponential function is the equation for the values in the table?
Answer:
12*(3)^x
Step-by-step explanation:
Let the exponential function be y=a*b^x. Given y(0)=12, a=12. Next y(2)=36, b=3
Answer:
Your answer is f(x)=4(3)x
Step-by-step explanation:
Mark me brainliest :)
A 2-column table has 2 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f (x) with entries 8, 2, 0.5, 0.125, 0.03125.
Use the table of values to write the exponential function.
Answer:
0.5
0.25
Step-by-step explanation:
The equation for the exponential function is f(x) = 0.5(0.25)ˣ after applying the concept of the function.
What is an exponential function?It is defined as a function that rapidly increases and the value of the exponential function is always positive. It denotes with exponent y = aˣ
where a is a constant and a>1
It is given that:
A 2-column table has 2 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f (x) with entries 8, 2, 0.5, 0.125, and 0.03125.
x f(x)
-2 8
-1 2
0 0.5
1 0.125
2 0.03125
Let the function is:
f(x) = a(b)ˣ
Plug x = 0 and f(x) = 0.5
0.5 = a
Plug x = -1 and f(x) = 2
2 = 0.5(1/b)
b = 0.5/2 = 0.25
f(x) = 0.5(0.25)ˣ
Thus, the equation for the exponential function is f(x) = 0.5(0.25)ˣ after applying the concept of the function.
Learn more about the exponential function here:
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A math professor is wondering if students today are better or worse than in the past. He has given the same final to this year's class that he gave ten years ago. Compute mean, median, and mode for both classes and write a paragraph summarizing the differences.
This Year
35 45 65 75 87
80 69 71 53 90
99 95 70 82 73
93 67 61 57 74
72 77 71 81 83
Ten Years Ago
56 77 75 76 59
74 51 89 55 79
67 77 69 91 68
90 65 79 69 79
87 86 98 91 95
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following data:
This year :
35, 45, 53, 57, 61, 65, 67, 69, 70, 71, 71, 72, 73, 74, 75, 77, 80, 81, 82, 83, 87, 90, 93, 95, 99
Mean = ΣX / n = 1825 / 25 = 73
The mode = 71 ( most frequently occurring)
Median = 1/2(n+1)th term = 1/(26) = 13th term
Median = 73
10 years ago :
51, 55, 56, 59, 65, 67, 68, 69, 69, 74, 75, 76, 77, 77, 79, 79, 79, 86, 87, 89, 90, 91, 91, 95, 98
Mean = ΣX / n = 1902 / 25 = 76.08
The mode = 79 ( most frequently occurring)
Median = 1/2(n+1)th term = 1/(26) = 13th term
Median = 77
According to the computed statistics, we can conclude that, today is worse than the past as the average score which is almost similar to the median value is higher 10 years ago and the modal score is better 10 years ago as well.
Which statement is correct?
Answer:
c is the answer why cause I did it
Please Help with this
Answer:
csc = 6/5= 1.2
cot = √(11)/5= 0.6633
sin = 5÷6= 0.83333
given that the following two are geometric series are convergent: 1+x+x^2+x^3+...and 1-x+x^2-x^3+... determine the value(s) of x for which the sum of the two series is equal to 8
Let S and T denote the two finite sums,
S = 1 + x + x ² + x ³ + … + x ᴺ
T = 1 - x + x ² - x ³ + … + (-x) ᴺ
• If both S = 8 and T = 8 as N goes to infinity:
Then
xS = x + x ² + x ³ + x ⁴ + … + x ᴺ⁺¹
-xT = -x + x ² - x ³ + x ⁴ + … + (-x) ᴺ⁺¹
so that
S - xS = 1 - x ᴺ⁺¹ ==> S = (1 - x ᴺ⁺¹)/(1 - x)
and similarly,
T = (1 - (-x) ᴺ⁺¹)/(1 + x)
For both sums, so long as |x| < 1, we have
lim [N → ∞] S = 1/(1 - x)
lim [N → ∞] T = 1/(1 + x)
Then if both sums converge to 8, this happens for
S : 1/(1 - x) = 8 ==> x = 7/8
T : 1/(1 + x) = 8 ==> x = -7/8
• If the sum S + T = 8 as N goes to infinity:
From the previous results, we have
1/(1 - x) + 1/(1 + x) = 8 ==> x = ±√3/2
Anyone know how to do this
Answer:
30 cm
Step-by-step explanation:
Since the length of tangents drawn from a point are equal, the perimeter is 3+3+9+9+3+3=30
Answer:
30 centimeter
Which of the following represents the factorization of the trinomial below?
- 4x3 - 4x2 +24 x
O A. -4(x2-2)(x+3)
B. -4(x2 + 2)(x+3)
O C. -4x(x + 2)(x+3)
D. -4x(x - 2)(x+3)
Answer:
D. -4x(x - 2)(x+3)
Step-by-step explanation:
We are given the following trinomial:
[tex]-4x^3 - 4x^2 + 24x[/tex]
-4x is the common term, so:
[tex]-4x(\frac{-4x^3}{-4x} - \frac{4x^2}{-4x^3} + \frac{24x}{-4x}) = -4x(x^2+x-6)[/tex]
The second degree polynomial can also be factored, finding it's roots.
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
[tex]ax^{2} + bx + c, a\neq0[/tex].
This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:
[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]
[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]
[tex]\Delta = b^{2} - 4ac[/tex]
x² + x - 6
Quadratic equation with [tex]a = 1, b = 1, c = -6[/tex]
So
[tex]\Delta = 1^{2} - 4(1)(-6) = 25[/tex]
[tex]x_{1} = \frac{-1 + \sqrt{25}}{2} = 2[/tex]
[tex]x_{2} = \frac{-1 - \sqrt{25}}{2} = -3[/tex]
So
[tex]x^2 + x - 6 = (x - 2)(x - (-3)) = (x - 2)(x + 3)[/tex]
The complete factorization is:
[tex]-4x(x^2+x-6) = -4x(x - 2)(x + 3)[/tex]
Thus the correct answer is given by option d.
Please help out explanation need it
Answer:
[tex] \sin(θ) = \frac{19}{41} \\ θ = 27.6 \\ θ = 28[/tex]
Suppose a jar contains 7 red marbles and 28 blue marbles. If you reach in the jar and pull out 2 marbles at random at the same time, find the probability that both are red.
Answer:
3/85
Step-by-step explanation:
that's the answer above
14. In a garden 746496 apple trees are arranged in such a way that, there are as inany rows as there are in a row. How many rows are there in the garden
Answer:
864
Step-by-step explanation:
do the square root of the total number
At what rates did she invest?
$1500 invested at___%
$800 invested at ____%
Answer:
4% and 5% respectively
Step-by-step explanation:
Let the intrest rate be x in the first account at x% and (x+1)% in the second account.
ATQ, 100=(x)*1500/100+(x+1)*800/100
x=4.
A ball is thrown upward with an initial velocity (v) of 13 meters per second. Suppose that the initial height (h) above the ground is 7 meters. At what time t will the ball hit the ground? The ball is on the ground when S=0. Use the equation S=−5t2+vt+h.
Answer:
the correct answer is, 4
If g(x)=x+1/x-2 and h(x) = 4 – x, what is the value of (9*h)(-3)?
9514 1404 393
Answer:
(g·h)(-3) = 2.8
Step-by-step explanation:
Given:
g(x) = (x +1)/(x -2)
h(x) = 4 -x
Find:
(g·h)(x) = g(x) × h(x) for x = -3
Solution:
g(-3) = (-3+1)/(-3-2) = -2/-5 = 2/5
h(-3) = 4 -(-3) = 4 +3 = 7
Then the product is ...
g(-3)·h(-3) = (2/5)(7) = 14/5 = 2.8
(g·h)(-3) = 2.8
I need help completing this problem ASAP
Answer:
8 sqrt(5)
Step-by-step explanation:
sqrt(45) + sqrt(125)
Rewriting
sqrt(9*5) + sqrt( 25 *5)
we know sqrt(ab) = sqrt(a) sqrt(b)
sqrt(9) sqrt(5) + sqrt(25) sqrt(5)
3 sqrt(5)+5 sqrt(5)
Add like terms
8 sqrt(5)
Answer:
A. [tex] 8\sqrt{5} [/tex]
Step-by-step explanation:
[tex] \sqrt{45} + \sqrt{125} = [/tex]
[tex] = \sqrt{9 \times 5} + \sqrt{25 \times 5} [/tex]
[tex] = 3\sqrt{5} + 5\sqrt{5} [/tex]
[tex] = 8\sqrt{5} [/tex]
A survey asked 50 students if they play an instrument and if they are in band.
1.25 students play an instrument.
2. 20 students are in band.
3. 30 students are not in band.
Which table shows these data correctly entered in a two-way frequency?
C, just look at the "Total" for each single information.
the values in the inner grid combine multiple informations.
The table shows these data correctly entered in a two-way frequency is table C.
What is Two way Frequency?Two-way frequency tables show the potential connections between two sets of categorical data visually. The table's four (or more) inside cells contain the frequency (count) data, which is displayed above and to the left of the table's designated categories.
We have been the information 25 students play an instrument 20 are in a band 30 are not in a band.
So, the two way table is:
Band Not in Band Total
Play instrument 20 5 25
Do not play instrument 0 25 25
Total 20 30 50
So, Table C is Correct.
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Historically, the industries with the most complaints to the Better Business Bureau have been banks, cable and satellite television companies, collection agencies, cellular phone providers, and new car dealerships. The results for a sample of complaints are contained in the file BBB. Click on the datafile logo to reference the data. a. Construct a frequency distribution for the number of complaints by industry. Category Observed Frequency Bank Cable Car Cell Collection Total b. Using , conduct a hypothesis test to determine whether the probability of a complaint is the same for the five industries. The test-statistic is (to 3 decimals). -value (to 4 decimals) What is your conclusion
Answer:
χ² = 19
Pvalue = 0.0008 ( 4 decimal places)
WE reject the H0 and conclude that probability of complaint is not the same for the 5 industries
Step-by-step explanation:
H0 : probability of complaint is the same for the 5 industries.
H1: probability of complaint is not the same for the 5 industries.
Category ____ observed frequency
Bank _______ 26
Cable _______44
Car _________42
Cell _________60
Collection ____ 28
Total ________200
The test statistic ;
χ² = (O - E)² / E
O = Observed Frequency ; E = Expected Frequency
Expected Frequency, E = (1 / n) * total
n = number of industries = 5
Expected frequency, E = (1/5)*200 = 40
Expected frequency is the same for all, thus E for all 5 industries = 40
χ² = Σ(O - E)² / E;
χ² = (26-40)² / 40 + (44-40)² / 40 + (42-40)² / 40 + (60-40)² / 40 + (28-40)² / 40
χ² = 19
At α = 0.05 ; df = n-1 = 4 ; χ²critical = 0.000786
Since Pvalue < α ; WE reject the H0 and conclude that probability of complaint is not the same for the 5 industries.