A jet airplane is in level flight. The mass of the airplane is m=8950 kg. The airplane travels at a constant speed around a circular path of radius R=9.33 mi and makes one revolution every T=0.123 h. Given that the lift force acts perpendicularly upward from the plane defined by the wings, what is the magnitude of the lift force acting on the airplane?

(a) The work done by force in lb-ft is 300 lb-ft.

(b) The change in potential energy of the object is 200 lb-ft.

The work done by force in lb-ft is calculated as follows;

W = Fd

W = 30 x 10

W = 300 lb-ft

The change in potential energy of the object is calculated as follows;

ΔP.E = P.Ef - P.Ei

ΔP.E = 20 x 10 - 0 = 200 lb-ft

Learn more about work done here: https://brainly.com/question/8119756

#SPJ2

Answer:

[tex] \green{ \sf \: \: 1.6 \: m {s}^{ - 2} \: \: \: is \: the \: correct \: answer}[/tex]

Explanation:

[tex] \sf \: \huge{g } _{ \small{moon}} = \frac{ {\huge{g}}_{earth}}{6} \\ \\ \sf \implies \: \sf \: \huge{g } _{ \small{moon}} = \frac{ 9.8}{6} = 1.6 \: \: m {s}^{ - 2} [/tex]

A simulation study that is used to learn about a planet by simulating as many conditions as possible, you can visualize what the planet might be like and learn things about it without actually visiting it. The correct option is c.

A simulation is a method of simulating a process or change in the actual world to forecast future events or to explain past events and their causes. These days, simulations are frequently carried out using computers. Scientists use simulations to find answers and to test complicated systems.

A fire drill is used in this instance to get everyone ready for an impending event. In fire drills, the fire alarm is sounded even when there isn't actually a fire.

Therefore, the correct option is c.

To learn more about simulation, refer to the link:

https://brainly.com/question/16359096

#SPJ2

Answer:

25 mm = 0 deg C

200 mm = 100 deg C

200 - 25 = 175 = change in thread per 100 deg C

95 - 25 = 70 mm - change in thread from 0 deg C

70 / 175 * 100 = 40 deg C    final temperature at 95 mm

Answer:

vf²=vi²+2a∆x

Explanation:

The third equation of motion gives the final velocity of an object under uniform acceleration given the distance traveled and an initial velocity: v 2 = v 0 2 + 2 a d . v^2=v_0^2+2ad. v2=v02+2ad. The graph of the motion of the object.

Explanation:

initial velocity(u)=30km/hr = 30*1000/60*60=8.33 m/s

final velocity(v) =60km/hr = 60*1000/60*60 =16.67 m/s

time taken(t) = 1 minutes

= 60 seconds

Now,

Average velocity = u+v/2

= 8.33 m/s + 16.67m/s÷2

=12.5 m/s

Answer:

accelerating.

Explanation:

A horse is running on a circular path with constant speed but its direction is changing at every point. Thus, it is accelerating.

Answer:

it gravitional pull on earth will increased becauste it is compress to a form of moon which is comperatively smaller so the gravitonal pull on per cm of earth will incrased so we can say that there will be change in acceleration due to gravity

Answer:

hello

Explanation:

hello dost timi kasto cha

Answer:

Amur Leopard, Southeastern Russia, and northern china

Explanation:

Answer:

Amur Leopard    China/Russia

Hawks bill Turtle   live in Oceans

Answer:

the angle of banking is 33.3 degree.

Explanation:

speed, v = 99 mi/h = 44.26 m/s  

radius, r = 1000 ft = 304.8 m

g = 9.8 m/s^2

Let the angle of banking is A.

[tex]tan A = \frac{v ^2}{r g}\\\\tan A = \frac{44.26^2}{304.8\times 9.8}\\\\tan A = 0.66\\\\A = 33.3^0[/tex]

Answer:

Weight = Mass × Gravitational field strength

Explanation:

The mass of the skydiver = 70 kg

The weight of the skydiver, W, is given as follows;

W = m × g

Where-

g = The gravitational field strength ≈ 9.81 m/s²

Therefore, the equation linking weight mass and gravitational field strength is presented as follows;

Weight = Mass × Gravitational field strength

Answer:1

Explanation:1

Answer:

Explanation:

From your other post, the complete question is:

"You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to the right. The snow exerts a friction force of 30 N on the sled to the left. The mass of the sled is 50 kg.

Find the sum of the force on the sled.

Determine the acceleration of the sled .

If the sled has an initial velocity 2m/s to the right, how fast will it be traveling after 5 seconds?

"

Given the rope exerting a force of 50 N to the right and the snow exerts a friction force of 30 N to the left, the sum of forces

= 50 - 30

= 20N to the right

The mass of sled is 50 kg and force = mass * acceleration.

Acceleration = Force / mass

= 20 / 50 = 0.4 m/s^2 to the right

If the sled has an initial velocity 2m/s to the right, after 5 seconds it will be traveling at initial velocity + acceleration * time

= 2 + 0.4*5

= 4 m/s to the right

Answer:

Explanation:

net force = applied force - friction force

= 50-30

= 20N to right

acceleration = net force/mass

= 20/50

= 2/5m/s tp right

final velocity = initial velocity + acceleration*time

= 2+2/5*5

= 4m/s to right

Answer:

CG gh sure er go b vh pxuh FPI OO c AM h kh

Answer:

i think its 4 or 35

Explanation:

its in the middle of 40 and 30

Answer:

0.48N

Explanation:

according to the second law of motion

force=mass×acceleration

the mass in this question is 0.025,the acceleration 19

therefore f=0.025×19

=0.48N

I hope this helps

Answer:

Wavelength = 5 * 10^{-11} meters

Explanation:

Given the following data;

Frequency = 6.0 x 10^18 Hz

Speed = 3 * 10⁸ m/s

To find the wavelength of the wave;

Mathematically, the wavelength of a wave is given by the formula;

[tex] Wavelength = \frac {speed}{frequency} [/tex]

Substituting into the formula, we have;

[tex] Wavelength = \frac {3 * 10^{8}}{6.0 x 10^{18}} [/tex]

Wavelength = 5 * 10^{-11} meters

Answer:

The final translational seed at the bottom of the ramp is approximately 4.84 m/s

Explanation:

The given parameters are;

The radius of the sphere, R = 2.50 cm

The mass of the sphere, m = 4.75 kg

The translational speed at the top of the inclined plane, v = 3.00 m/s

The length of the inclined plane, l = 2.75 m

The angle at which the plane is tilted, θ = 22.0°

We have;

[tex]K_i[/tex] + [tex]U_i[/tex] = [tex]K_f[/tex] + [tex]U_f[/tex]

K = (1/2)×m×v²×(1 + I/(m·r²))

I = (2/5)·m·r²

K =  (1/2)×m×v²×(1 + 2/5) = 7/10 × m×v²

U = m·g·h

h = l×sin(θ)

h = 2.75×sin(22.0°)

∴ 7/10×4.75×3.00² + 4.75×9.81×2.75×sin(22.0°) = 7/10 × 4.75×[tex]v_f[/tex]² + 0

7/10×4.75×3.00² + 4.75×9.81×2.75×sin(22.0°) ≈ 77.93

∴ 77.93 ≈ 7/10 × 4.75×[tex]v_f[/tex]²

[tex]v_f[/tex]² = 77.93/(7/10 × 4.75)

[tex]v_f[/tex] ≈ √(77.93/(7/10 × 4.75)) ≈ 4.84

The final translational seed at the bottom of the ramp, [tex]v_f[/tex] ≈ 4.84 m/s.

Answer:The answer is A

Explanation:just did it on a test

Answer: The answer is B

Explanation:

There are 4 fundamental forces that hold matter together.

- Gravitational Force

- Electromagnetic Force

- Strong Nuclear Force

- Weak Nuclear Force

We have barely just scratched the info about nuclear forces but the reason why B is the answer to the question is that Strong nuclear force actually holds the protons and neutrons together in the nucleus of an atom, much like the picture in B.

Answer: B

Explanation:

Answer:

The temperature of the gas is 350.02 K.

Explanation:

The average speed is related to the temperature as follows:

[tex] \bar v = \sqrt{\frac{3RT}{M}} [/tex]   (1)

Where:

[tex] \bar v [/tex]: is the average speed = 1477 m/s

R: is the gas constant = 8.31 J/(K*mol)                                                  

T. is the temperature =?

M: is the molar mass

First, let's find the molar mass:

[tex] M = \frac{m}{n} [/tex]

Where:

m: is the mass of the gas = 0.008 kg

n: is the number of moles = 2 mol

[tex] M = \frac{m}{n} = \frac{0.008 kg}{2 mol} = 0.004 kg/mol [/tex]

Hence, by solving equation (1) fot T we have:

[tex] T = \frac{\bar v^{2}*M}{3R} = \frac{(1477 m/s)^{2}*0.004 kg/mol}{3*8.31 J/(K*mol)} = 350.02 K [/tex]

Therefore, the temperature of the gas is 350.02 K.

I hope it helps you!            

Explanation:

Measurement plays an important role in our daily lives because they are useful to do basic tasks, such as taking the temperature of a child with the help of a thermometer,making time estimations,measure out medicines and find out weights, areas and volumes of different substances

Answer:

B. Km/s/hr

Explanation:

Unit is the quantity of a constant magnitude which is used to measure the magnitudes of other quantities of the same nature.

Answer:

The standard known quantity which is used to measure a physical quantities is known as unit.

Answer:

Power = I * V = 2.5 C/s * 5 J/C = 12.5 J/s = 12.5 watts

Regardless of the efficiency the power consumed is that used by the converter.

E = P * t = 12.5 J/s * 4500 s = 4500 J

Answer:

The centripetal acceleration of the stone is 5 m/s²

Explanation:

The length of the string to which the stone is attached, r = 1 m

The speed with which the string is rotated, v = 5 m/s

The centripetal acceleration, [tex]a_c[/tex], is given as follows;

[tex]a_c = \dfrac{v^2}{r}[/tex]

Therefore, the centripetal acceleration of the stone found as follows;

[tex]a_c = \dfrac{(5 \ m/s)^2}{1 \ m} = 5 \ m/s^2[/tex]

The centripetal acceleration of the stone, [tex]a_c[/tex] = 5 m/s².

Answer:

A. When the independent variable is continuous and shows a causal link to the dependent variable.

Explanation:

A graph can be defined as the graphical representation of data (informations) on horizontal and vertical lines i.e x-axis and y-axis respectively.

In an experiment , the variable being manipulated by an experimenter is known as an independent variable while the dependent variable is the event expected to change when the independent variable is manipulated

Generally, a line graph should be used when the independent variable is continuous and shows a causal link to the dependent variable.

This ultimately implies that, a line graph should be used when the data changes continuously over time and as such there exist a linear relationship between the data (variables).

Answer:

The force from the truck on the car is always equal to the force from the car on the truck.

Explanation:

According to Newton's third law; action and reaction are equal and opposite. Hence, when the big truck and small passenger car are involved in a collision, we expect that the force from the truck on the car is always equal to the force from the car on the truck. The forces on the car and the truck are equal in magnitude but opposite in direction.

This follows directly from Newton's third law of motion hence the answer above.