Answer:
No I do not agree with Andre says that 3 divided by 2/3 Solving for 3 ÷ 2/3
3 ÷ 2/3
= 3 × 3/2
= 9/2
= 4 1/2
Therefore, 3 divided by 2/3 is 4 1/2
Andre's reasoning is wrong.
Step-by-step explanation:
It is incorrect
Let's divide and compare the sum
3 : 2/3 = 3*3/2 = 9/2 = 4 1/2
and
There are four 2/3 fractions and one 1/3 fraction
The 1/3 fraction is 1/2 of 2/3 fraction so instead of counting 1/3 as 1/3 it should be counted as 1/2
Algebra word problem plz help me
Step-by-step explanation:
here's the answer to your question
in order for the parallelogram to be a rhombus, x=?
[tex]\\ \large\sf\longmapsto x + 15 = 2x - 40 \\ \\ \large\sf\longmapsto x - 2x = - 40 - 15 \\ \\ \large\sf\longmapsto - x = - 55\\ \large\sf\longmapsto x = 55[/tex]
The value of x is 55 degrees.
What is rhombus?A rhombus is a diamond-shaped quadrilateral that has all four sides equal
What are the properties of a rhombus?The properties of a rhombus are:
Opposite angles are equal.All sides are equal and, opposite sides are parallel to each other.Diagonals bisect each other perpendicularly.Sum of any two adjacent angles is 180°According to the given question.
We have a rhombus.
Since, we know that the diagonals of the rhombus bisect the angles.
Therefore,
[tex](x+15)^{o} = (2x-40)^{o}[/tex]
Solve, the above expression for x.
[tex]\implies x +15 = 2x -40\\\implies 15+40 = 2x -x \\\implies 55 = x \\0r\ x = 55^{o}[/tex]
Hence, the value of x is 55 degrees.
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Which function describes this graph
Answer:
C.
Step-by-step explanation:
A P E X
I don’t understand the last 2
Nice job on getting the correct answer 144 for the first box. For anyone curious, this is found by multiplying the side lengths of the square. So 12*12 = 144.
======================================
All four sides are decreased by 5 meters. So we go from 12 meter sides to 12-5 = 7 meter sides.
The area of the square is found in the same way as earlier: We multiply the side by itself
area = side*side = 7*7 = 49 square meters
So you'll type 49 into the second box
=======================================
To find the amount of decrease, you subtract the two area values:
144 - 49 = 95 goes in the third box
This indicates that the area has decreased by 95 m^2
A newsletter publisher believes that over 47% of their readers own a Rolls Royce. For marketing purposes, a potential advertiser wants to confirm this claim. After performing a test at the 0.02 level of significance, the advertiser failed to reject the null hypothesis. What is the conclusion regarding the publisher's claim?
The advertiser failed to reject the null hypotenuse so this would mean there is not sufficient evidence at the 0.02 level of significance to say that the percentage of people who own a Rolls Royce is higher than 47%
take away 4/5 from 6 1/2
Answer:
3-4/5=2.2
hope it helps
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]5\frac{7}{10}[/tex]
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
[tex]\boxed{\text{Calculating the answer...}}\\\\6\frac{1}{2}-\frac{4}{5} \\-------------\\6\frac{1}{2} = \frac{13}{2} \\\\\frac{13}{2} - \frac{4}{5}\\\\LCM(2,5): 10\\\\\frac{13}{2} =\frac{13*5}{2*5} =\frac{65}{10}\\\\\frac{4}{5}=\frac{4*2}{5*2}=\frac{8}{10}\\\\\frac{65}{10}-\frac{8}{10}\\\\ \frac{57}{10}\\\\\frac{57}{10}\rightarrow\boxed{5\frac{7}{10}}[/tex]
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Algebra help needed. Overwhelmed with other papers. See attached
Answer:
Step-by-step explanation:
whitch answer how do you want us to answer
What type of number can be written as a fraction
Answer:
a rational number is a number that can be written as a fraction
I hope this helps
A hot air balloon is rising vertically with a velocity of 12.0 feet per second. A very small ball is released from the hot air balloon at the instant when it is 1120 feet above the ground. Use a(t)=−32 ft/sec^2 as the acceleration due to gravity.
Required:
a. How many seconds after its release will the ball strike the ground?
b. At what velocity will it hit the ground?
Answer:
Here we only need to analyze the vertical motion of the ball.
First, because the ball is in the air, the only force acting on the ball will be the gravitational force (we are ignoring air resistance), then the acceleration of the ball is equal to the gravitational acceleration, so we have:
a(t) = -32 ft/s^2
where the negative sign is because this acceleration is downwards.
To get the velocity equation, we need to integrate over the time, so we get:
v(t) = (-32 ft/s^2)*t + V0
where V0 is the initial velocity of the ball. In this case, the initial velocity of the ball will be the velocity that the ball had when it was dropped, which should be the same as the velocity of the hot air ballon, so we have:
V0 = 12 ft/s
Then the velocity equation of the ball is:
v(t) = (-32 ft/s^2)*t + 12 ft/s
To get the position equation we integrate again:
p(t) = (1/2)*(-32 ft/s^2)*t^2 + (12 ft/s)*t + H0
Where H0 is the initial height. We know that the ball was released at the height of 1120 ft, then we have:
H0 = 1120 ft.
Then the position equation is:
p(t) = (-16 ft/s^2)*t^2 + (12 ft/s)*t + 1120ft
a) How many seconds after its release will the ball strike the ground?
The ball will strike the ground when its position equation is equal to zero, then we need to solve:
p(t) = 0 ft = (-16 ft/s^2)*t^2 + (12 ft/s)*t + 1120ft
This is just a quadratic equation, the solutions are given by Bhaskara's formula, so the solutions for t are:
[tex]t = \frac{- 12ft/s \pm \sqrt{(12 ft/s)^2 - 4*(-16ft/s^2)*(1120 ft)} }{2*(-16ft/s^2)}[/tex]
We can simplify that to get:
[tex]t = \frac{-12ft/s \pm 268ft/s}{-32ft/s^2}[/tex]
So we have two solutions:
[tex]t = \frac{-12ft/s + 268ft/s}{-32ft/s^2} = -8s[/tex]
[tex]t = \frac{-12ft/s - 268ft/s}{-32ft/s^2} = 8.75s[/tex]
The negative solution does not make sense, then the correct solution is the positive one.
We can conclude that the ball will hit the ground after 8.75 seconds.
b) At what velocity will it hit the ground?
We already know that the ball strikes the ground 8.75 seconds after it is released.
The velocity at it hits the ground is given by the velocity equation evaluated in that time:
v(8.75 s) = (-32 ft/s^2)*8.75s + 12 ft/s = -268 ft/s
2 6 + 3 * 4 2 + 7 * - 2 /
Answer:
26 + 3 x 42 + 7 x -2 = 138
Step-by-step explanation:
Ok bud, first step we must convert our symbols (Makes it easier to solve)
26 + 3 x 42 + 7 x -2
* subsitutes for multiplication.
I recommend using PEMDAS at times:
1 - Parentheses
2 - Exponents and Roots
3 - Multiplication
4 - Division
5 - Addition
6 - Subtraction
Yet again your numbers were spaced out could they be exponents? if so:
3x^{42}+7x+24
Our answer would round to 24 but he equation was not put in a valid or straight forward way.
Solve for x
-3x = -15
A) x = -45
B) x = 5
C) x = -5
C-x=-5
Step-by-step explanation:
-3x=-15
or,-3x x =-15
or, x=-15÷3
therefore, x=-5
One angle of an isosceles triangle is 16 what are the other 2 angles
Answer:
other two angle will be
82
as 82+82+16 = 180'
please give me correct answer
by picture
Answer:
hello,
a) answer: 600
b) answer: 840
Step-by-step explanation:
a)
20=2²*5,25=5²,30=2*3*5,40=2³*5
l.c.m(20,25,30,40)=2³*3*5²=8*3*25=800
b)
24=2³*3, 42=2*3*7,35=5*7
l.c.m=(24,42,35)=2³*3*5*7=840
Two coins are tossed. Assume that each event is equally likely to occur. a) Use the counting principle to determine the number of sample points in the sample space. b) Construct a tree diagram and list the sample space. c) Determine the probability that no tails are tossed. d) Determine the probability that exactly one tail is tossed. e) Determine the probability that two tails are tossed. f) Determine the probability that at least one tail is tossed.
Answer:
(a) 4 sample points
(b) See attachment for tree diagram
(c) The probability that no tail is appeared is 1/4
(d) The probability that exactly 1 tail is appeared is 1/2
(e) The probability that 2 tails are appeared is 1/4
(f) The probability that at least 1 tail appeared is 3/4
Step-by-step explanation:
Given
[tex]Coins = 2[/tex]
Solving (a): Counting principle to determine the number of sample points
We have:
[tex]Coin\ 1 = \{H,T\}[/tex]
[tex]Coin\ 2 = \{H,T\}[/tex]
To determine the sample space using counting principle, we simply pick one outcome in each coin. So, the sample space (S) is:
[tex]S = \{HH,HT,TH,TT\}[/tex]
The number of sample points is:
[tex]n(S) = 4[/tex]
Solving (b): The tree diagram
See attachment for tree diagram
From the tree diagram, the sample space is:
[tex]S = \{HH,HT,TH,TT\}[/tex]
Solving (c): Probability that no tail is appeared
This implies that:
[tex]P(T = 0)[/tex]
From the sample points, we have:
[tex]n(T = 0) = 1[/tex] --- i.e. 1 occurrence where no tail is appeared
So, the probability is:
[tex]P(T = 0) = \frac{n(T = 0)}{n(S)}[/tex]
This gives:
[tex]P(T = 0) = \frac{1}{4}[/tex]
Solving (d): Probability that exactly 1 tail is appeared
This implies that:
[tex]P(T = 1)[/tex]
From the sample points, we have:
[tex]n(T = 1) = 2[/tex] --- i.e. 2 occurrences where exactly 1 tail appeared
So, the probability is:
[tex]P(T = 1) = \frac{n(T = 1)}{n(S)}[/tex]
This gives:
[tex]P(T = 1) = \frac{2}{4}[/tex]
[tex]P(T = 1) = \frac{1}{2}[/tex]
Solving (e): Probability that 2 tails appeared
This implies that:
[tex]P(T = 2)[/tex]
From the sample points, we have:
[tex]n(T = 2) = 1[/tex] --- i.e. 1 occurrences where 2 tails appeared
So, the probability is:
[tex]P(T = 2) = \frac{n(T = 2)}{n(S)}[/tex]
This gives:
[tex]P(T = 2) = \frac{1}{4}[/tex]
Solving (f): Probability that at least 1 tail appeared
This implies that:
[tex]P(T \ge 1)[/tex]
In (c), we have:
[tex]P(T = 0) = \frac{1}{4}[/tex]
Using the complement rule, we have:
[tex]P(T \ge 1) + P(T = 0) = 1[/tex]
Rewrite as:
[tex]P(T \ge 1) = 1-P(T = 0)[/tex]
Substitute known value
[tex]P(T \ge 1) = 1-\frac{1}{4}[/tex]
Take LCM
[tex]P(T \ge 1) = \frac{4-1}{4}[/tex]
[tex]P(T \ge 1) = \frac{3}{4}[/tex]
Solve this equation for x. Round your answer to the nearest hundredth.
1 = In(x + 7)
Answer:
[tex]\displaystyle x \approx -4.28[/tex]
General Formulas and Concepts:
Pre-Algebra
Equality PropertiesAlgebra II
Natural logarithms ln and Euler's number eStep-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle 1 = ln(x + 7)[/tex]
Step 2: Solve for x
[Equality Property] e both sides: [tex]\displaystyle e^1 = e^{ln(x + 7)}[/tex]Simplify: [tex]\displaystyle x + 7 = e[/tex][Equality Property] Isolate x: [tex]\displaystyle x = e - 7[/tex]Evaluate: [tex]\displaystyle x = -4.28172[/tex]e^1 = x+7
e - 7 = x
x = -4.28
An acre of land planted with sugar beet produces 550 gallons of ethanol from the sugar by fermentation. A car converted to run on E75 (a 75% ethanol, 25% petrol mixture) can do 40 miles per gallon. If you drive 20,000 miles per year, how many acres of sugar beet will be needed to produce the ethanol you need?
Answer:
Step-by-step explanation:
a
fdsa
Find the mean for the amounts: $17.482: $14.987: $13.587$14.500, $18.580. $14.993
Answer:
The mean of these numbers is 15.68816 with a repeating 6.
Step-by-step explanation:
What is the correct answer?
Answer:
Option D
Only the equation in option D matches with the table
Answered by GAUTHMATH
Put the following equation of a line into slope-intercept form, simplifying all
fractions.
12x - 3y = 15
Help pls
Answer:
Pretty sure its y=4x-5 hope it helped
Step-by-step explanation:
A married couple had a combined annual income of $81,000. The wife made $9000 more than her husband. What was each of their incomes?
Step-by-step explanation:
Let the husband's income be x
Wife's income be x + 9000
X + X + 9000 = 81000
2X + 9000 – 9000 = 81000 – 9000
2X= 72000
X = 36000
Husband, 36000,
Wife, 9000+36000, 45000
An urn contains 12 balls, five of which are red. Selection of a red ball is desired and is therefore considered to be a success. If three balls are selected, what is the expected value of the distribution of the number of selected red balls
The expected value of the distribution of the number of selected red balls is 0.795.
What is the expected value?The expected value of the distribution is the mean or average of the possible outcomes.
There are 12 balls in an urn, five of which are crimson. The selection of a red ball is desired and hence considered a success.
In this case, the possible outcomes are 0, 1, 2, or 3 red balls.
To calculate the expected value, we need to find the probability of each outcome and multiply it by the value of the outcome.
The probability of selecting 0 red balls is :
[tex]$\frac{7}{12} \cdot \frac{6}{11} \cdot \frac{5}{10} = \frac{105}{660}$[/tex].
The probability of selecting 1 red ball is :
[tex]$3 \cdot \frac{5}{12} \cdot \frac{7}{11} \cdot \frac{6}{10} + 3 \cdot \frac{7}{12} \cdot \frac{5}{11} \cdot \frac{6}{10} + 3 \cdot \frac{7}{12} \cdot \frac{6}{11} \cdot \frac{5}{10} = \frac{315}{660}$[/tex].
The probability of selecting 2 red balls is
[tex]:$\dfrac{5}{12} \cdot \frac{7}{11} \cdot \frac{6}{10} + \frac{7}{12} \cdot \frac{5}{11} \cdot \frac{6}{10} + \frac{7}{12} \cdot \frac{6}{11} \cdot \frac{5}{10} = \frac{105}{660}$.[/tex]
The probability of selecting 3 red balls is
[tex]$\dfrac{5}{12} \cdot \frac{4}{11} \cdot \frac{3}{10} = \frac{15}{660}$[/tex]
The expected value is then :
[tex]$0 \cdot \frac{105}{660} + 1 \cdot \frac{315}{660} + 2 \cdot \frac{105}{660} + 3 \cdot \frac{15}{660} = \frac{525}{660} = \frac{175}{220} \approx \boxed{0.795}$[/tex]
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Factorize (256⁴-1).
Use appropriate identity.
(256⁴-1)
= (256-1)⁴
Using identity (a-b)⁴ = a⁴−4a³b+6a²b²−4ab³+b⁴
Let a be 256 and b be 1
Then
256⁴−4(256)³(1)+6(256)²(1)²−4(256)(1)³+(1)⁴
After solving
(256²-1)²
(a-b)² = a²-2ab+b²
256²-2×256×1+1²
= (256²-1)(256²+1)
Must click thanks and mark brainliest
Answer:
Use identity:
a² - b² = (a + b)(a - b)Consider that:
256 = 2⁸Now factorize:
256⁴ - 1 = (2⁸)⁴ - 1 = 2³² - 1 = (2¹⁶ - 1)(2¹⁶ + 1) = (2⁸ - 1)(2⁸ + 1)(2¹⁶ + 1) = (2⁴ - 1)(2⁴ + 1)(2⁸ + 1)(2¹⁶ + 1) = (2² - 1)(2² + 1)(2⁴ + 1)(2⁸ + 1)(2¹⁶ + 1) = (2 - 1)(2 + 1)(2² + 1)(2⁴ + 1)(2⁸ + 1)(2¹⁶ + 1)Triangle A B C is shown. The included side between ∠A and ∠C is side . The included side between ∠A and ∠B is side . The included side between ∠C and ∠B is side .
Answer:
AC, AB, BC
Step-by-step explanation:
Given
[tex]\triangle ABC[/tex]
Required
Name the sides
(a) [tex]\angle A[/tex] and [tex]\angle C[/tex]
This represents side [tex]AC[/tex]
(b) [tex]\angle A[/tex] and [tex]\angle B[/tex]
This represents side [tex]AB[/tex]
(c) [tex]\angle C[/tex] and [tex]\angle B[/tex]
This represents side [tex]CB[/tex]
i.e. we simply bring the name of both angles together
Answer:
AC, AB, BC
Step-by-step explanation:
CAN SOMEBODY HELP WITH THIS QUESTION ASAP
Answer:
The rectangles are not similar
Step-by-step explanation:
In order to check whether they are similar, we need to take the ratio of their similar sides and ensure they are equal to a constant k.
Hence;
AB/PL = AD/LM = k
32/26 = 18/12 = k
16/13 = 9/6 = k
Since the scale factor is not the same, hence the rectangles are not the same.
What is the distance from point N to LM in the figure below?
N
8.4
8.1
7.8
O
O A. 3.11
B. 0.8
C. 8.1
D. 2.18
E. 7.8
F. 8.4
Answer:
the answer to your question is 7.8 (E)
The distance from point N to LM is 7.8, 8.1 and 8.4 unit.
What is perpendicular?Perpendicular lines are those that cross at a straight angle to one another. Examples include the opposite sides of a rectangle and the steps of a straight staircase. the icon used to represent two parallel lines.
Perpendicular lines are two separate lines that cross one other at a right angle, or a 90° angle.
Given:
In ΔNOM
The Perpendicular distance is 7.8 unit
and, Hypotenuse distance id 8.1 unit
Now, In ΔNOL
The Perpendicular distance is 7.8 unit
and, Hypotenuse distance id 8.4 unit
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What is 1/8+1/4 whats the answer
a figure skating school offers introductory lessons at $25 per session. There is also a registration fee of $30
Answer:
Part A: y = 25x + 30
Part B: $180
Step-by-step explanation:
for part A, 25 is the constant so that goes with the x, and you just add 30 because it is the extra fee. slope intercept form is y = mx + b
for part B you just plug 6 into the slope intercept equation
y = 25(6) + 30
y = 150 + 30
y = 180
$180
Solve the following equation for
d
d. Be sure to take into account whether a letter is capitalized or not.
What is the equation of a line that passes through the point (8,-2) and is parallel to the line whose equation is 3x+4y=15?
Answer:
y = -3x/4 + 4
Step-by-step explanation:
slope m = -3/4
-2=(-3/4)×8+b
or, b = 4
y = mx + b
y = -3x/4 + 4
Answered by GAUTHMATH
(a) Joe runs 12 miles in 84 minutes.
How many miles does he run per minute?
İmiles per minute
Step-by-step explanation:
We want to find how many miles per minute Joe runs. This means, we need to simplify the equation:
[tex]\frac{12 mi}{84 min}[/tex]
so that the number on the bottom is 1. How do we do that?
Simple.
Just divide 12 / 84
Answer:
Joe runs approx. 0.143 miles per minute.
