As a marketing manager, you are tasked with selecting a website to place your advertisement. The following sampled data shows the number of user visits per month over the last 3 three years:
Website 1: 10357, 10537, 10767, 10561, 10544, 10581, 10602, 10665, 10335, 10419, 10737, 10410, 10485, 10601, 10458, 10472, 10435, 10375, 10436, 10510, 10345, 10559, 10520, 10425, 10351, 10465, 10491, 10671, 10366, 10440, 10618, 10606, 10406, 10538, 10449, 10462
Website 2: 11067, 11029, 10888, 10789, 10914, 10663, 10787, 11140, 11042, 11074, 10868, 10853, 10900, 11088, 10991, 10928, 10959, 11126, 11033, 11114, 11150, 11155, 11027, 10900, 11015, 11123, 10953, 11181, 10855, 10731, 10971, 10770, 11070, 11122, 11018, 10903 Since the behavior of internet users can be considered a natural process, consider the number of views to follow normal distribution. In addition, please assume no autocorrelation or time-series nature of the data. Based on the data above, provide the answers to the following question:
A. What is the average and standard deviation of viewership of each website?
B. Is viewership different between these two websites? If yes, which website provides more views?
C. Suppose that your manager requires at least 12000 views per month. What is the probability of 12000 views happening on each website?
D. Which website provides more consistent view? How would you measure it?
E. Which website would you recommend for your advertisement?

Answer:

$88

Step-by-step explanation:

442.70 rounded to the nearest 10 dollars is 440.

20%= .2.

440 times .2 =

88

Given that

3 cos 80° cosec 10° + 2 sin 59° sec 31°

⇛3 cos(90°-10°) cosec 10°+2 sin (90°-31°) sec 31°

We know that

sin (90° - A) = cos A

cos (90°-A) = sin A

⇛3 sin 10° cosec 10° + 2 cos 31° sec 31°

⇛3 sin 10° (1/sin 10°) + 2 cos 31° (1/cos 31°)

⇛3 (sin 10°/sin 10°) + 2 (cos 31°/cos 31°)

⇛3 (1) + 2(1)

⇛3+2

⇛5

Answer: Therefore, 3cos 80°cosec 10°+2cos 59°sec 31° = 5.

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Answer:

5

Step-by-step explanation:

you can rewrite this as

3cos(90*-10*) x 1/sin(10*) + 2sin(90*-31*) x 1/cos(31*)

=3sin(10*) x 1/sin(10*) + 2cos31* x 1/cos(31*)

reduce with sin(10*) to get

3+2cos(31*) x 1/cos(31*)

cross out the cos 31* on both sides to leave you with

3+2

5

Equaling both equations, it is found that the correct option that states the number of solutions you will have for the system is:

The equations are:

[tex]4y + x = 16 \rightarrow x = 16 - 4y[/tex]

[tex]y = 4 - x \rightarrow x = 4 - y[/tex]

Equaling both equations for x, we have that:

[tex]16 - 4y = 4 - y[/tex]

[tex]3y = 12[/tex]

[tex]y = \frac{12}{3}[/tex]

[tex]y = 4[/tex]

[tex]x = 4 - y = 4 - y = 0[/tex]

Hence, the system has one solution, which is (0,4), and option d is correct.

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The plane flies a distance of approximately 10.536 kilometers in straight line and with a bearing of approximately 035°.

A plane that travels a distance [tex]r[/tex], in kilometers, with a bearing of [tex]\theta[/tex] sexagesimal degrees can be represented in standard position by means of the following expression:

[tex]\vec r = r\cdot (\sin\theta, \cos \theta)[/tex] (1)

We can obtain the resulting vector ([tex]\vec R[/tex]) by the principle of superposition:

[tex]\vec R = \Sigma_{i=1}^{n} [r_{i}\cdot (\sin \theta_{i}, \cos \theta_{i})][/tex] (2)

If we know that [tex]r_{1} = 5\,km[/tex], [tex]\theta_{1} = 0^{\circ}[/tex], [tex]r_{2} = 6\,km[/tex], [tex]\theta_{2} = 60^{\circ}[/tex], [tex]r_{3} = 4\,km[/tex] and [tex]\theta_{3} = 120^{\circ}[/tex], then the resulting vector is:

[tex]\vec R = 5\cdot (\sin 0^{\circ}, \cos 0^{\circ}) + 6\cdot (\sin 60^{\circ}, \cos 60^{\circ}) + 4\cdot (\sin 120^{\circ}, \cos 120^{\circ})[/tex]

[tex]\vec R = (5\sqrt{3}, 6) \,[km][/tex]

The magnitude of the resultant is found by Pythagorean theorem:

[tex]\|\vec R\| = \sqrt{R_{x}^{2}+R_{y}^{2}}[/tex]

And the bearing is determined by the following inverse trigonometric relationship:

[tex]\theta_{R} = \tan^{-1} \left(\frac{R_{y}}{R_{x}}\right)[/tex] (3)

If we know that [tex]R_{x} = 5\sqrt{3}\,km[/tex] and [tex]R_{y} = 6\,km[/tex], then the magnitude and the bearing of the resultant is:

[tex]\|\vec R\| = \sqrt{(5\sqrt{3})^{2}+6^{2}}[/tex]

[tex]\|\vec R\| \approx 10.536\,km[/tex]

[tex]\theta_{R} = \tan^{-1} \left(\frac{6}{5\sqrt{3}} \right)[/tex]

[tex]\theta_{R} \approx 34.715^{\circ}[/tex]

The plane flies a distance of approximately 10.536 kilometers in straight line and with a bearing of approximately 035°.

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Answer: -30

Step-by-step explanation:

-2 X -5 = 10

10 X -3 = -30

Therefore, -2(-5)(-3) = -30

The multiplication of −2(−5)(−3) is -30

The multiplication of numbers in brackets with negative signs takes a method whereby the signs are taken into account when performing the arithmetic operation.

From the given question, we are to multiply:

= - 2 × (-5) × (-3)

= +10 × (-3)

= -30

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Answer:

d four

Step-by-step explanation:

How many solutions does the nonlinear system of equations graphed below have?  

Look at the number of points where the graphs intersect each other...the points where the graphs of the functions cross each other are the solutions to the system.  

Upon looking, you should see 4 points where the graphs intersect, so there are 4 solutions to the non-linear system of equations.

no why? cause the guy bought 2 shirts for 19 dollors each where was he at nikes?  on average a shirt cost 15 bucks but 19? yeah no

Answer:

Step-by-step explanation:

no why? cause the guy bought 2 shirts for 19 dollors each where was he at nikes?  on average a shirt cost 15 bucks but 19? yeah no

Applying the inscribed angle theorem, the missing measures are:

measure of arc TR = 106°

measure of arc TL = 74°

m∠L = 50°

m∠R = 37°

m∠RTV = 37°

Measure of an inscribed angle = half the measure of the arc it intercepts

Central angle = measure of intercepted arc

We are given the following:

LR and TV are diameters of the circle O.

m∠TOR = 106° (central angle)

Find measure of arc TR:

measure of arc TR = m∠TOR

measure of arc TR = 106°

Find measure of arc TL:

measure of arc TL = 180° - m∠TOR

measure of arc TL = 180° - 106°

measure of arc TL = 74°

Find m∠L:

m∠L = ½(measure of arc TR)

m∠L = ½(106°)

m∠L = 50°

Find m∠R:

m∠R = ½(measure of arc TL)

m∠R = ½(74°)

m∠R = 37°

Find m∠RTV:

m∠RTV = ½(measure of arc RV)

m∠RTV = ½(180 - 106)

m∠RTV = ½(74)

m∠RTV = 37°

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Using the together rate, it is found that:

The together rate is the sum of each separate rate.

In this problem, we have that:

Applying the together rate:

[tex]\frac{1}{x} + \frac{1}{x + 3} = \frac{1}{2}[/tex]

[tex]\frac{x + 3 + x}{x(x + 3)} = \frac{1}{2}[/tex]

[tex]4x + 6 = x^2 + 3x[/tex]

[tex]x^2 - x - 6 = 0[/tex]

Which is a quadratic equation with coefficients [tex]a = 1, b = -1, c = -6[/tex], hence:

[tex]\Delta = b^2 - 4ac = (-1)^2 - 4(1)(-6) = 25[/tex]

[tex]x_1 = \frac{-b + \sqrt{\Delta}}{2a} = \frac{1 + \sqrt{25}}{2} = 3[/tex]

[tex]x_2 = \frac{-b - \sqrt{\Delta}}{2a} = \frac{1 - \sqrt{25}}{2} = -2[/tex]

We are interested into the positive root, then [tex]x = 3[/tex], [tex]x + 3 = 6[/tex], which means that:

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Answer:

y = 4

Step-by-step explanation:

Refer to the two images below

For the graph:

y = 2 - red

x = 2 - blue

y = 4 - green

x = 4 - purple

Horizontal lines are parallel to the x axis. The only two equations parallel to the x axis are y = 2 and y = 4 so x  = 2 and x = 4 cannot be the answer.

The point (2,4) is graphed as well as the equations and the only equation that's horizontal and passes through the point (2,4) is y = 4

Answer:

m=-7/15

Step-by-step explanation:

Answer:

Step-by-step explanation:

7/15

Answer:

H+2

Step-by-step explanation:

Please mark brainliest

Answer:

cylinder has greatest volume

Step-by-step explanation:

solution

given,

radius of cylinder(r)=6cm

height of cylinder (h)=6cm

we know,

volume of cylinder=πr^2h

=22÷7×6×6×6

=4752÷7

=678.857cm^3

radius of cone(r)=6cm

height of cone(h)=12cm

we know,

volume of cone=1÷3πr^3

= 1÷3×22÷7×6×6×6

= 4752÷21

=226.2857cm^3

as a result,cylinder has greatest volume

Answer:

t = 11/21

Step-by-step explanation:

Hope this helps!!

1. Assuming OP || NM, considering the triangle proportionality theorem possible measurements for the segments are: ON = 3 units, LO = 1 unit, PM = 6 units, LP = 2 units

2. The possible values are decided by assuming  [tex]\frac{ON}{LO} = \frac{PM}{LP} = 3[/tex] using the triangle proportionality theorem.

3. Another method is applying the AA Similarity Theorem to compare corresponding side lengths of the triangles that are proportional to each other.

Triangle proportionality theorem states that if a line is parallel to one of the sides of a triangle intersects two of the other two sides, it divides the two sides into proportional corresponding segments.

1. Assuming that OP || NM, we would apply the triangle proportionality theorem to have the following ratio:

[tex]\frac{ON}{LO} = \frac{PM}{LP}[/tex]

Using the above ratio, we can choose the following possible lengths for the segments:

ON = 3 units

LO = 1 unit

PM = 6 units

LP = 2 units

2. The values are decided assuming that the ratio, [tex]\frac{ON}{LO} = \frac{PM}{LP} = 3[/tex]

This means that the ratio of the proportional segments, irrespective of the their measurement should give you an assumed equal ratio of 3:1.

Therefore, since:

[tex]\frac{3}{1} = 3\\\\\frac{6}{2} = 3[/tex]

The measurements, ON = 3 units, LO = 1 unit, PM = 6 units, LP = 2 units are therefore possible measurements.

3. Using the AA Similarity Theorem to prove that ΔLPO ≅ ΔLMN, the corresponding sides of both triangles will be proportional.

LP/LM = LO/LN = PO/MN

We can use this to choose possible measurements while assuming a ratio between the proportional sides of both triangles.

Let's assume that: LP/LM = LO/LN = PO/MN = 1/4

Let,

LO = 1 unit

LN = 4 units

Therefore, ON = LN - LO = 4 - 1 = 3 units.

Same way the other possible measures can be gotten provided a ratio is assumed.

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Please find the attached photograph for their positions.

Hope you could get an idea from here

Doubt clarification - use comment section.

Answer:

$0.44

Step-by-step explanation:

lmk if you want an explanation

Answer:

21 x n + 14

Step-by-step explanation:

The number of items in each bag times the number of bags plus the 14 items.

Answer:

$5.84

Step-by-step explanation:

Answer:

100000+)9(87)238388292838

Answer: your answer is A) & D)

Step-by-step explanation:     Hope this helps :)

Answer:

A) (-5,10), (0,15), (5,10)

Step-by-step explanation:

In order for an ordered pair to be a function, no pair of coordinates can have the same x variable.

Answer:

25 kilograms

Step-by-step explanation:

Answer:

I believe that it would take 5 hours for 8 people to paint 8 fences.

Step-by-step explanation:

If 2 people are painting 2 fences in 5 hours, then 8 people can also paint 8 fences in the same time because each person is painting one fence. It take 5 hours to paint 1 fence if 1 person is painting it. The same goes for 2 or 8 people painting the same amount of fences as there are people. Im not 100% sure if this is accurate but I hope it helps.

Answer:

See below

Step-by-step explanation:

(-4,0) is the solution to x+4=0

(0,0) is the solution to x=0

(2,0) is the solution to x-2=0

Therefore, (x+4)(x-2)(x) = (x²-2x+4x-8)(x) = (x²+2x-8)(x) = x³+2x²-8x is the function that has the given zeroes

Answer:

6/8 and 12/16

Step-by-step explanation:

Important: 3/4 looks like a fraction, but it is actually an improper fraction.

There is an infinity number of equivalent fractions to 3/4. To find an equivalent fraction to 3/4 , or to any other fraction, you just need to multiply (or divide, if the fraction is not yet reduced), both the numerator and the denominator of the given fraction by any non-zero natural number. For example:

By multiplying the original fraction by 2, we get:

3x2/3x2=6/8

List of Equivalent Fractions of 3/4:

3/4, 6/8, 9/12, 12/16, 15/20, 18/24, 21/28, 24/32, 27/36, 30/40, 33/44, 36/48, 39/52, 42/56, 45/60, 48/64, 51/68, 54/72, 57/76, 60/80 ...

The amount provided by each offer after each year depends on the first

salary and the added amount or percentage series.

Reasons:

The given parameters of the job offers are;

Starting salary of offer A = $58,000

Amount by which the salary increases for 5 years = 3%

The starting salary offer B = $56,000

Amount by which the salary increases per year = $3,000

Part A: The salary amount received in the first month = $58,000

The salary in the second month, aₙ = 58,000 × (1 + 0.03)

a₂ = 58,000 × (1 + 0.03) = 58,000 × (1.03)

The salary in the third month is given as follows;

a₃ = a₂ × (1.03) = 58,000 × (1.03) × (1.03) = 58,000 × (1.03)²

The salary on the nth month is therefore;

aₙ = 58,000 × (1.03)⁽ⁿ⁻¹⁾

The above formula is in the form of the geometric series formula, which is presented as follows;

aₙ = a·r⁽ⁿ⁻¹⁾

Where;

a = The first term = 58,000

r = The common ratio = 1.03

n = The number of years

Therefore;

Offer A can be represented by an arithmetic series

Part B: The first year salary for offer B = $58,000

The salary on the second year, B₂ = 58,000 + 3,000 = 61,000

Salary on the third year, B₃ = 58,000 + 3000 + 3000 = 58,000 + 2 × 3,000

Therefore;

Salary on the nth year, Bₙ = 58,000 + (n - 1)×3,000

The above equation is in the form of aₙ = a + (n - 1)·d

Where;

a = The first term = 58,000

n = The number of years

d = The common difference = 3,000

Therefore;

Offer B can be represented by an arithmetic series

Part C: The income gained on offer A after 5 years, a₅, is given as follows;

a₅ = 58,000 × (1.03)⁽⁵ ⁻ ¹⁾ = 58,000 × 1.03⁴ ≈ 65,279.51098

The income gained on offer A after 5 years ≈ $65,279.51098

On offer B, we have;

a₅ = 58,000 + (5 - 1) × 3,000 = 70,000

The income gained on offer B after 5 years = $70,000

Therefore;

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