Consider the functions f(x) = 10^x and g(x)= f(x+4)
How will the graph of the function g differ from the graph of f ?
A) the graph of the function g is the graph of function f shifted 4 units down
B) the graph of the function g is the graph of function f shifted 4 units to the right
C) the graph of the function g is the graph of function f shifted 4 units to the left
D) the graph of the function g is the graph of function f shifted 4 units up
Answers
Related Questions
Công thức xác định tuổi thọ KL
Answers
Công thức xác định tuổi thọ KL
Help? Thanks!!!!!!!! If possible show work please!
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Answer:
[tex]B =102[/tex]
[tex]Y = 32[/tex]
Step-by-step explanation:
Solving (47):
To solve for B, we have:
[tex]B + 50 + 28 = 180[/tex] --- sum of angles in a triangle
This gives
[tex]B + 78 = 180[/tex]
Collect like terms
[tex]B =- 78 + 180[/tex]
[tex]B =102[/tex]
Solving (48):
To solve for Y, we have:
[tex]X + Y+ Z = 180[/tex] --- sum of angles in a triangle
This gives
[tex]Y = 180 - X - Z[/tex]
Where
[tex]W+ X=180[/tex] -- angle on a straight line
Solve for X
[tex]X=180 -W[/tex]
[tex]X=180 -100 = 80[/tex]
So, we have:
[tex]Y = 180 - X - Z[/tex]
[tex]Y = 180 - 80 - 68[/tex]
[tex]Y = 32[/tex]
Which inequality represents all values of x which the product below is defined Square root 4x Square root x+2
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Answer:
Option (D) x≥ 0 is absolutely correct
Step-by-step explanation:
The reason is that the square root function is defined for only non negative numbers.
Answer: x is greater than or equal to 0
Step-by-step explanation:
help with 30 please. thanks.
Answers
Answer:
See Below.
Step-by-step explanation:
We have the equation:
[tex]\displaystyle y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}[/tex]
And we want to show that:
[tex]\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}[/tex]
Instead of differentiating directly, we can first square both sides:
[tex]\displaystyle y^2 = 3e^{2x} -4x + 1[/tex]
We can find the first derivative through implicit differentiation:
[tex]\displaystyle 2y \frac{dy}{dx} = 6e^{2x} -4[/tex]
Hence:
[tex]\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}[/tex]
And we can find the second derivative by using the quotient rule:
[tex]\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}[/tex]
Substitute:
[tex]\displaystyle y\left(\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\right) + \left(\frac{3e^{2x}-2}{y}\right)^2 =6e^{2x}[/tex]
Simplify:
[tex]\displaystyle \frac{6y^2e^{2x}- \left(3e^{2x} -2\right)^2}{y^2} + \frac{\left(3e^{2x}-2\right)^2}{y^2}= 6e^{2x}[/tex]
Combine fractions:
[tex]\displaystyle \frac{\left(6y^2e^{2x}-\left(3e^{2x} - 2\right)^2\right) +\left(\left(3e^{2x}-2\right)^2\right)}{y^2} = 6e^{2x}[/tex]
Simplify:
[tex]\displaystyle \frac{6y^2e^{2x}}{y^2} = 6e^{2x}[/tex]
Simplify:
[tex]6e^{2x} \stackrel{\checkmark}{=} 6e^{2x}[/tex]
Q.E.D.
Functions f and g are defined for all real
numbers. The function f has zeros at -2, 3, and 7:
and the function g has zeros at -3, -1, 4, and 7.
How many distinct zeros does the product
function f g have?
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9514 1404 393
Answer:
6
Step-by-step explanation:
The number of distinct zeros in the product will be the union of the sets of zeros. Duplicated values are not distinct, so show in the union of sets only once.
F = {-2, 3, 7}
G = {-3, -1, 4, 7}
F∪G = {-3, -2, -1, 3, 4, 7} . . . . . . a 6-element set
The product has 6 distinct zeros.
_____
As you may notice in the graph, the duplicated zero has a multiplicity of 2 in the product.
The cost of three pants and four shirts is $68.45 if a pant costs $6.85 more than a shirt find the cost of a pant and a shirt estimate to the nearest whole number.
Answers
Answer:
3 pants are $20.55
4 shirts are $47.9
Step-by-step explanation:
a pant is $6.85 × 3= $20.55
68.45 - 20.55 = $47.9
$47.9 ÷ 4 = $11.98 a shirt
Yesterday, Kofi earned 50 cedis mowing
Lawns. Today, Kofi earned 60% of what he
earned yesterday moving lawns - How much
Money did kojo earn moving laws today?
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Answer:
75cedis
[tex]50 = 40\% \\ 60\%[/tex]
The amount of money Kofi earned today from mowing lawns is 30 cedis.
Percentage can be described as a fraction of a number multiplied by 100. Percentage is represented with this sign - %.
In order to determine the amount Kofi earned today, this formula would be used:
Percentage Kofi earned today x amount Kofi earned yesterday
60% x 50 cedis
0.6 x 50 cedis
= 30 cedis
To learn more about percentages, please check: https://brainly.com/question/92258?referrer=searchResults
Suppose v1 , v2 , v3 ,v4 are vectors in R3.
(a) These four vectors are dependent because_________ .
(b) The two vectors v1 and v2 will bedependent if_________ .
(c) The vectors v1 and (0, 0, 0) are dependent because________ .
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Answer:
a. These four vectors are dependent because there are columns of 3 by 4 matrix with one free variable.
b. If one is a multiple of other
c. c1v1 + c20 = 0 has nontrivial solution.
Step-by-step explanation:
Any set of 4 or more vectors must be linearly dependent. The non trivial combination of vector may produce zero as the set is linearly dependent. The vector v1 and v2 will be dependent if one is the multiple of the other.
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective.
a. Suppose a sample of 865 floppy disks is drawn. Of these disks, 112 were defective. Using the data, estimate the proportion of disks which are defective.
b. Suppose a sample of 865 floppy disks is drawn. Of these disks, 112 were defective. Using the data, construct the 95% confidence interval for the population proportion of disks which are defective.
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Answer:
a) 0.1295
b) The 95% confidence interval for the population proportion of disks which are defective is (0.1071, 0.1519).
Step-by-step explanation:
Question a:
112 out of 865, so:
[tex]\pi = \frac{112}{865} = 0.1295[/tex]
Question b:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
For this problem, we have that:
[tex]n = 865, \pi = 0.1295[/tex]
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1295 - 1.96\sqrt{\frac{0.1295*0.8705}{865}} = 0.1071[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1295 + 1.96\sqrt{\frac{0.1295*0.8705}{865}} = 0.1519[/tex]
The 95% confidence interval for the population proportion of disks which are defective is (0.1071, 0.1519).
The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that the net weight is actually a normal random variable with a mean of 6.05 ounces and a standard deviation of .18 ounces. Suppose that you draw a random sample of 36 cans.
a. Find the probability that the mean weight of the sample is less than 5.97 ounces.
b. Suppose your random sample of 36 cans of salmon produced a mean weight that is less than 5.97 ounces. Comment on the statement made by the manufacturer.
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Answer:
a) 0.0038 = 0.38% probability that the mean weight of the sample is less than 5.97 ounces.
b) Given a mean of 6.05 ounces, it is very unlikely that a sample mean of less than 5.97 ounces, which means that the true mean must be recalculated.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Mean of 6.05 ounces and a standard deviation of .18 ounces.
This means that [tex]\mu = 6.05, \sigma = 0.18[/tex]
Sample of 36:
This means that [tex]n = 36, s = \frac{0.18}{\sqrt{36}} = 0.03[/tex]
a. Find the probability that the mean weight of the sample is less than 5.97 ounces.
This is the p-value of z when X = 5.97. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{5.97 - 6.05}{0.03}[/tex]
[tex]Z = -2.67[/tex]
[tex]Z = -2.67[/tex] has a p-value of 0.0038.
0.0038 = 0.38% probability that the mean weight of the sample is less than 5.97 ounces.
b. Suppose your random sample of 36 cans of salmon produced a mean weight that is less than 5.97 ounces. Comment on the statement made by the manufacturer.
Given a mean of 6.05 ounces, it is very unlikely that a sample mean of less than 5.97 ounces, which means that the true mean must be recalculated.
Describe what is the most difficult part of solving equations, for you personally.
Answers
What do you personaly feel like is most dificult.
For me its rembering minus signs
Express the prime number 19 as the difference of two squares? 19 =
Answers
Answer:
The two squares are 81 and 100, and their difference is 19
Step-by-step explanation:
Hey there!
Let's take out the square of 1st ten natural numbers to find out the exact answer.
1² = 1
2² = 4
3² = 9
4² = 16
5² = 25
6² = 36
7² = 49
8² = 64
9² = 81
10² = 100
Now; You can take any of these numbers and subtract from their squares.
So, let's check 6² and 5²
36-25 = 11 which is not equal to 19
Again check for 10²-9²
100 - 81 = 19 (True value)
Therefore, 19 can be expressed as the difference of square of 10 and 9.
Hope it helps!
What is the period of the graph of y = 5 sin (pi x) + 3?
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Equate whats inside (arguments) [tex]\sin[/tex] with base period of sine function [tex]2\pi[/tex] and solve for x to get period,
[tex]\pi x=2\pi\implies x=2[/tex]
So the period of the graph of the given function is precisely 2.
Hope this helps :)
Answer:
Step-by-step explanation:
bvjvhvghj
the point a(2,-5) is reflected over the origin and its image is point b. what are the coordinates of point b
Answers
Answer:
b(-2,-5)
Step-by-step explanation:
A company pays $20 per hour for up to 8 hours of work, and $30 per hour for overtime hours (hours beyond 8 hours). For up to 8 hours worked, the equation for total pay (y) for hours worked (x) is y = 20x. For over 8 hours worked, what is the equation for total pay (y) as a function of total hours worked (x)?
Answers
Answer: y = 30x
Step-by-step explanation:
Because we are talking about over 8 hours. The question states that you get 30$ per hour for overtime hours. That means if you work over 8 hours your dollars per hour increases to 30. So because the amount of dollars increases to 30 you can infer that all you have to do is make the same equation as the 20 dollar's per hour equation. Except you put 30 making it y = 30x.
I are these orders pairs a function
х,у
0,9
2,8.
4,7
6,6
8,5
10,4
Answers
9514 1404 393
Answer:
yes
Step-by-step explanation:
No x-value is repeated, so these ordered pairs do represent a function.
A wedge of cheese is shaped like a triangular prism. The wedge of cheese is 7 inches tall. The base of the cheese is shaped like a triangle with a base of 11 and a height of 5 inches. If you ate this whole block of cheese, about how many cubic inches would you have eaten (ignoring the holes)?
420 in
193 in
385 in
210 in
Answers
Answer:
193 in
Step-by-step explanation:
Volume of a triangular prism:
The volume of a triangular prism is the base area multiplied by the wedge, that is:
[tex]V = A_bw[/tex]
The base area is one half times the triangle base times it's height, so:
[tex]V = 0.5*b*h*w[/tex]
The wedge of cheese is 7 inches tall.
This means that [tex]w = 7[/tex]
The base of the cheese is shaped like a triangle with a base of 11 and a height of 5 inches.
This means that [tex]b = 11, h = 5[/tex]
Volume:
[tex]V = 0.5*b*h*w = 0.5*11*5*7 = 192.5[/tex]
Rounding, approximately 193 in.
F(x) = 3x+5 G(x)= 4x^2-2 H(x) = x^2-3x+1 Find f(x) +g(x) -h(x)
Answers
Answer:
Step-by-step explanation:
f(x) + g(x) = 3x + 5 + 4x^2 - 2
f(x) + g(x) = 4x^2 + 3x + 3
f(x) + g(x) - h(x) = 4x^2 + 3x + 3 - (x^2 - 3x + 1) Remove the brackets.
f(x) + g(x) - h(x) = 3x^2 +3x + 3 - x^2 + 3x - 1 Collect like terms
f(x)+g(x) - h(x) = 2x^2 + 6x + 2
Answer:
f(x)=3x^2+6x+2
Step-by-step explanation:
An advertiser goes to a printer and is charged $36 for 80 copies of one flyer and $46 for 242 copies of another flyer. The printer charges a fixed setup cost plus a charge for every copy of single-page flyers. Find a function that describes the cost of a printing job, if xx is the number of copies made.
Answers
Answer:
ytre
Step-by-step explanation:
An experiment consists of 400 observations and four mutually exclusive groups. If the probability of a randomly selected item being classified into any of the four groups is equal, then the expected number of items that will be classified into group 1 is ________.
Answers
Answer:
The expected number of items that will be classified into group 1 is 100.
Step-by-step explanation:
For each observation, there are only two possible outcomes. Either it will be classified into group 1, or it will not. The probability of an observation being classified into group 1 is independent of any other observation, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
400 observations
This means that [tex]n = 400[/tex]
Four mutually exclusive groups. The probability of a randomly selected item being classified into any of the four groups is equal.
This means that [tex]p = 0.25[/tex]
Then the expected number of items that will be classified into group 1 is
[tex]E(X) = np = 400*0.25 = 100[/tex]
100 is the answer.
Please help ASAP please help me
Answers
9514 1404 393
Answer:
C) 12 cm
Step-by-step explanation:
In a 30°-60°-90° triangle, the ratios of side lengths are ...
1 : √3 : 2
This means the hypotenuse (AC) is 2/√3 times the length of the long side (AB).
(10 cm)(2/√3) = 20/√3 cm ≈ 11.55 cm
Rounded to the nearest cm, the length of AC is 12 cm.
Given f (x) = 3x - 5 find f (x - 2)
Answers
Answer:
3x-11
Step-by-step explanation:
f (x) = 3x - 5
f(x-2)
Replace x in the function with x-2
f (x-2) = 3(x-2) - 5
=3x-6 -5
=3x-11
I really need the help please and thank you
Answers
Answer:
Answer is D.
Step-by-step explanation:
Let the inverse be m:
[tex]{ \sf{m = \sqrt{x} - 8 }} \\ { \sf{m + 8 = \sqrt{x} }} \\ { \sf{x = {(m + 8)}^{2} }} \\ { \bf{f {}^{ - 1} (x) = {(x + 8)}^{2} }}[/tex]
Domain:
[tex]{ \sf{x \geqslant - 8}}[/tex]
How do I solve this?
Answers
The question is somewhat poorly posed because the equation doesn't involve θ at all. I assume the author meant to use x.
sec(x) = csc(x)
By definition of secant and cosecant,
1/cos(x) = 1/sin(x)
Multiply both sides by sin(x) :
sin(x)/cos(x) = sin(x)/sin(x)
As long as sin(x) ≠ 0, this reduces to
sin(x)/cos(x) = 1
By definition of tangent,
tan(x) = 1
Solve for x :
x = arctan(1) + nπ
x = π/4 + nπ
(where n is any integer)
In the interval 0 ≤ x ≤ 2π, you get 2 solutions when n = 0 and n = 1 of
x = π/4 or x = 5π/4
Find the distance across the lake, assume the triangles are similar
Answers
Answer:
C
Step-by-step explanation:
Since the triangles are similar, the scale factor is 100/5=20. So L/15=20, L=300
With an x intercept of 4 and a y intercept of -1.5. Find the equation of the line
Answers
The equation of the line is.
y = (3/8)*x - 1.5
A general linear relationship can be written as:
y = a*x + b
Where a is the slope, and b is the y-intercept.
If the line passes through the points (x₁, y₁) and (x₂, y₂), we can write the slope as:
a = ( y₂ - y₁)/(x₂- x₁)
We define the y-intercept and the x-intercept as the points where the graph intersects the y-axis or the x-axis correspondingly.
Here we know that the x-intercept is 4, or we can write this as (4, 0)
we also know that the y-intercept is -1.5, or we can write this as (0, -1.5)
So we know two points of the line, this means that we can find the slope of the line:
a = (-1.5 - 0)/(0 - 4) = (1.5)/(4) = (3/2)*(1/4) = 3/8
Then the line is:
y = (3/8)*x + b
And remember that b is the y-intercept, which we know is equal to -1.5, so we can just replace it:
Then the equation of the line is.
y = (3/8)*x - 1.5
If you want to learn more about this topic, you can read:
https://brainly.com/question/24329241
Which of the following linear functions has a graph which passes through points (−5,−2) and (−3,0)?
Answers
Answer:
f(x) = x + 3
Step-by-step explanation:
Solve for x, the triangles are similar
Answers
Answer:
x = 12
Step-by-step explanation:
Δ ESR and Δ EGF are similar, then ratios of corresponding sides are equal, so
[tex]\frac{ES}{EG}[/tex] = [tex]\frac{ER}{EF}[/tex] , substitute values
[tex]\frac{45}{12x-3}[/tex] = [tex]\frac{55}{143}[/tex] ( cross- multiply )
55(12x - 3) = 6435 ( divide both sides by 55 )
12x - 3 = 117 ( add 3 to both sides )
12x = 120 ( divide both sides by 12 )
x = 10
write
the following numbers using Roman numerals 20
Answers
Step-by-step explanation:
xx is the Roman number of 20
(one x equal 10)
XX= 20
(two x’s (10+10) equals 20)
There are two machines available for cutting corks intended for use in wine bottles. The first produces corks with diameters that are normally distributed with mean 3 cm and standard deviation 0.08 cm. The second machine produces corks with diameters that have a normal distribution with mean 3.04 cm and standard deviation 0.04 cm. Acceptable corks have diameters between 2.9 cm and 3.1 cm.
1. What is the probability that the first machine produces an acceptable cork?
2. What is the probability that the second machine produces an acceptable cork?
3. Which machine is more likely to produce an acceptable cork?
Answers
Answer:
Step-by-step explanation:
