Answer:
D. 1/16
Step-by-step explanation:
Evaluate: 2^-4
А. =100
В. -8ОО
С. -16
D. 1/16
Given
2^-4
= 1 / 2⁴
= 1 / (2 * 2 * 2 * 2)
= 1 / 16
Therefore,
2^-4 = 1/16
D. 1/16
-4d - 5 = -1 answer for me pls
[tex]\\ \sf\longmapsto -4d-5=-1[/tex]
Cancel - from both sides[tex]\\ \sf\longmapsto -(4d+5)=-(1)[/tex]
[tex]\\ \sf\longmapsto 4d+5=1[/tex]
[tex]\\ \sf\longmapsto 4d=1-5[/tex]
[tex]\\ \sf\longmapsto 4d=-4[/tex]
[tex]\\ \sf\longmapsto d=\dfrac{-4}{4}[/tex]
[tex]\\ \sf\longmapsto d=-1[/tex]
Sandra has developed a program designed to increase reading comprehension scores in 6th graders. She randomly selects three students and has them participate in her program. When she compares the mean score from the students who completed her program to three students who did not participate in the program, she finds no significant difference between their mean scores. What is most likely the reason for the non-significant finding
Answer:a small sample size
Step-by-step explanation:
From the information given in the question, we are informed that Sandra developed a program that was designed to increase reading comprehension scores in 6th graders and she then randomly selects three students and has them participate in her program.
After comparing the mean score from the students who completed her program to three students who did not participate in the program, she finds no significant difference between their mean scores, it should be noted that the reason for this will be because the sample size is small.
If a large sample size was used, this could have been different as thsi could result in a significant difference between their mean scores.
Surveys were sent to a random sample of owners of all-wheel-drive (AWD) vehicles and to a random sample of owners of front-wheel-drive (FWD) vehicles. The proportion of owners who were satisfied with their vehicles was recorded for each sample. The sample proportions were used to construct the 95 percent confidence interval for a difference in population proportions (FWD minus AWD) for satisfied owners. The interval is given as (−0.01,0.12). A car company believes that the proportion of satisfied owners of AWD vehicles differs from the proportion of satisfied owners of FWD vehicles. Does the confidence interval provide evidence that this belief is plausible?
Answer:
No, the confidence interval does not provide evidence that this belief is plausible as the confidence interval range contains the null value (0)
Step-by-step explanation:
Given that the confidence interval for the mean difference of AWD and FWD vehicles is :
(−0.01,0.12)
When defining the hypothesis for mean difference :
H0 : μ1 - μ2 = 0
H1 : μ1 - μ2 ≠ 0
Using the confidence interval result, reject the Null if the confidence interval value at the given α - level does not contain 0 ; otherwise fail to reject the Null ;
Since the (−0.01,0.12) contains 0 ; then we fail to reject the Null and conclude that there is no statistically significant difference between the two groups
I WILL GIVE BRAINLIEST IF TWO PEOPLE ANSWER! PLEASE PUT WHAT X IS, AND PLEASE PUT THE REASONS OF HOW YOU DID IT, FOR INSTANCE, SUBSTITUTION, OR ALTERNATE INTERIOR ANGLES
Answer:
14°
Step-by-step explanation:
4x + 32 + 64 = 180 => x = 14 (°)
rút gọn M=[ căn x -2/x-1- căn x +2/x+2 căn x+ 1] nhân x bình-2x+1/2 với x>0 x khác 1
Answer:
Step-by-step explanation:
Beaker A contains 1 liter which is 15 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which is 55 percent oil and the rest vinegar, completely mixed up. Half of the contents of B are poured into A, then completely mixed up. How much oil should now be added to A to produce a mixture which is 60 percent oil
Answer:
Add 1.25 litres of oil.
Step-by-step explanation:
Contents in beaker A implies;
15% of oil in 1 litre = 0.15 litres of oil
So that, there are 0.15 litres of oil and 0.85 litres of vinegar in beaker A.
Contents in beaker B implies:
55% of oil in 2 litres = 1.1 litres of oil
So that, thee are 1.1 litres of oil and 0.9 litres of vinegar in beaker B.
Half of contents of B poured into A implies that beaker A now contains:
0.15 litres + 0.55 litres = 0.7 litres of oil
0.85 litres + 0.45 litres = 1.3 litres of vinegar
The percentage of oil in A now = [tex]\frac{0.7}{2}[/tex] x 100%
= 35%
To increase the percentage of oil to 60%, then:
0.7 litres + 1.25 litres = 1.95 litres of oil
But the new total litres of the content in beaker A = 3.25 litres
So that;
[tex]\frac{1.95}{3.25}[/tex] x 100% = 60%
Therefore, to produce a mixture which is 60% oil, add 1.25 litres of oil.
Need help ASAP rocky ! Help needed
Answer:
x/x∈R,x≤5 1/6
Step-by-step explanation:
If the mortgage interest rates increase, this would be an example of changing your external environment.
Answer:
Economic conditions
Step-by-step explanation:
If the mortgage interest rates increase, this would be an example of changing Economic conditions in a company's your external environment
Mortgage is the legal agreement/arrangement between a financial institution and a debtor wherein the Financial institution lends funds to the debtor at an interest rate, and also with the title of the property owned by the debtor.
once the debtor repays the mortgage he retains the full ownership of his property.
PLEASE HELP ASAP!!! i dont understand :(
Answer:
hello,
Step-by-step explanation:
y=k(x-a')²+b'
focus is (a',1/(4k)+b')
2x²=-120y
==> y=-2/120x²
==> y=-1/60(x-0)²+0
focus= (0,-15)
Simplify the Following
4×7-63÷9+20
Answer:
41
Step-by-step explanation:
pay attention to the order of operation
4*7 - 63/ 9 +20, first multiplication and division from left to right
28 - 7 + 20 , second addition and subtraction from left to right
21 +20
41
Answer:
Step-by-step explanation:
Use PEDMAS
First perform division, then multiplication and then addition & subtraction.
4 * 7 - 63÷9 + 20 = 4*7 - 7 + 20 {Division}
= 28 - 7 + 20 {Multiplication}
= 41
428363939+42724289292952926263938
Answer:
4.2724289e
+22
Step-by-step explanation:
mzmznznxnxnznxn no n n j j h h h h h h hh h h &
A student states that Figure JKLM is congruent to Figure PQRS. Determine if the student is correct or has made an error. ;D
Answer:
Student has made an error
Step-by-step explanation:
If two figures are said to be congruent, this implies that area of both is same and both as exactly same or copy or each other.
But from the graph, it can be stated that height of figure JKLM is 4 units whereas that of other is 6 unit.
Hence explained !
In the figure, AB¯¯¯¯¯∥CD¯¯¯¯¯ and m∠2=55°.
What is m∠8?
Enter your answer in the box.
°
Line a b parallel to line c d is cut by a transversal forming 8 angles. The angles formed when the transversal intersects with line A B clockwise starting from top left are angle 1, 2, 3, and 4. The angles formed where the transversal intersects line c d clockwise from top left are angle 5, 6, 7, and 8.
measure of angle E is 2 x degrees.
Answer:
m<8 = m<2, both are equal since they are alternate exterior angles.
m<2 = 55° given, so m<8 = 55°
Answered by GAUTHMATH
Find the measure of the indicated angle.
Answer:
i think it the measured of the indicated angle is 55
Find the missing side of the triangle
I dont know the answer lol but imma say B
Simplify for me please
If m∠A = 43° and the measure of arc AB = 69°, then m∠B = ° (Blank 1). (Round your answer to one decimal place, if necessary.)
====================================================
Explanation:
If angle A is 43 degrees, then minor arc BC is 2*43 = 86 degrees according to the inscribed angle theorem. The central angle is twice that of the inscribed angle. Both of these angles subtend the same minor arc.
When I say "minor arc BC", I mean that we go from B to C along the shortest path. Any minor arc is always less than 180 degrees.
Since minor arc AB is 69 degrees, and minor arc BC is 86 degrees, this means arc ABC is arcAB+arcBC = 69+86 = 155 degrees
Let's say point D is some point on the circle that isn't between A and B, and it's not between B and C either. Refer to the diagram below. The diagram is to scale. The diagram your teacher provided is not to scale because arc ABC is way too big (it appears to be over 180 degrees). Hopefully the diagram below gives you a better sense of what's going on.
Because arc ABC = 155 degrees, this means the remaining part of the circle, arc ADC, is 360-(arc ABC) = 360-155 = 205 degrees
Inscribed angle B subtends arc ADC. So we'll use the inscribed angle theorem again, but this time go in reverse from before. We'll cut that 205 degree angle in half to get 205/2 = 102.5 degrees which is the measure of angle B. This value is exact. In this case, we don't need to apply any rounding.
Juan concludes that x? + 7x + 3 cannot be factored using integers.
is juan correct? how could juan improve his strategy?
I HOPE IT WILL HELP YOU. If it is right then plz tell me .
A box contains 4 red cubes, 3 blue cubes, 2 green cubes, and 1 yellow cube. You pick two cubes at random, replacing each after you pick. Find the probability of picking a blue and then a red.
A.3/25
B.9/100
C.3/4
D.4/25
Answer:
Step-by-step explanation:
There are 10 cubes all together.
You want blue and then red with replacement.
Blue
P(B then red) = 3/10 * 4/10 = 12 / 100
12/100 reduces to 3/25
The answer is A
Answer:
A?
Step-by-step explanation:
HELP ME PLEASE I NEED HELP
Consider the end behavior of the function g(x) = 4|x − 2| − 3.
As x approaches negative infinity, f(x) approaches POSITIVE OR NEGATIVE infinity.
As x approaches positive infinity, f(x) approaches POSITIVE OR NEGATIVE infinity.
Answer:
Step-by-step explanation:
This is a narrower-than-normal absolute value graph, which is a v-shaped graph. It's pointy part, the vertex, lies at (2, -3) and it opens upwards without bounds along both the positive and negative x axes. Therefore, as x approaches negative infinity, f(x) or y (same thing) approaches positive infinity. As x approaches positive infinity, f(x) approaches positive infinity.
HELP! I'LL GIVE BRAINLIEST ! ! ! ! ! ! ! !
Select all of the quadrants that the parabola whose equation is y = √x - 4 (principal square root) occupies.
a. IV b. III c. II d. I
Quadrants I and IV
When we graph y^2 = x - 4, we see that it is on the x axis, and goes up into Quadrant I, and down into Quadrant IV
An angle measures 89.8° more than the measure of its complementary angle. What is the measure of each angle?
Complementary angles always are 90 degrees when added to each other, so:
x = angle 1
x + 89.8 = angle 2
x + x + 89.8 = 90
2x = 90 - 89.8
2x = 0.2
x = 0.1
angle 1 = 0.1 degrees
angle 2 = 0.1 + 89.8 = 89.9 degrees
if you want to check, just sum one to the other and see if they equal 90, like this: 89.9 + 0.1 = 90
Diseases I and II are prevalent among people in a certain population. It is assumed that 11% of the population will contract disease I sometime during their lifetime, 16% will contract disease II eventually, and 2% will contract both diseases. (a) Find the probability that a randomly chosen person from this population will contract at least one disease. .25 Correct: Your answer is correct. (b) Find the conditional probability that a randomly chosen person from this population will contract both diseases, given that he or she has contracted at least one disease. (Round your answer to four decimal places.)
Answer:
a) [tex]P(A \cup B)=0.23[/tex]
b) [tex]P(X)=0.87[/tex]
Step-by-step explanation:
From the question we are told that:
Probability of contacting disease 1 [tex]P(1)=0.11[/tex]
Probability of contacting disease 2 [tex]P(2)=0.16[/tex]
Probability of contacting both disease [tex]P(1\& 2)=0.2[/tex]
a)
Generally the equation for a Random contact is mathematically given by
[tex]P(A \cup B)=P(1)+P(2)-P(A \cap B)[/tex]
[tex]P(A \cup B)=\frac{11}{100}+\frac{16}{100}-\frac{4}{100}[/tex]
[tex]P(A \cup B)=\frac{11+16-4}{100}[/tex]
[tex]P(A \cup B)=0.23[/tex]
b)
Generally the equation for Probability of contacting both after having contacted one is mathematically given by
[tex]P(X)=\frac{P(1\& 2)}{P(A \cup B)}[/tex]
Therefore
[tex]P(X)=\frac{0.2}{0.23}[/tex]
[tex]P(X)=0.87[/tex]
What is the equation of a line, in slope-intercept form, that has a slope of 3 and contains the point (0,5)?
secA-tanA=(cosA/2-sinA/2)/(cosA/2+sinA/2)
Answer:
Step-by-step explanation:
SecA - TanA
= 1/CosA - SinA/CosA
= 1 - SinA/CosA
We know that Sin2A = 2SinACosA and Cos2A = Cos²A - Sin²A
Thus SinA = Sin2(A/2) = 2Sin(A/2)CosA/2
CosA = Cos2(A/2) = Cos²A/2 - Sin²A/2
Now substituting the values back,
=> 1 - 2Sin(A/2)Cos(A/2) / Cos²(A/2) - Sin²(A/2)
// we know that Sin²θ + Cos²θ = 1
=> Sin²(A/2) + Cos²A/2 - 2Sin(A/2)Cos(A/2) / Cos²(A/2) - Sin²(A/2)
//We know that numerator is of form a² + b² - 2ab which is (a - b)².
//Similarly denominator is of form a² - b² which is (a - b)(a + b)
=> [Sin(A/2) - Cos(A/2)]² / [Cos(A/2) + Sin(A/2)][Cos(A/2) - Sin(A/2)]
=> [ - {Cos(A/2) - Sin(A/2)}]² / [Cos(A/2) + Sin(A/2)][Cos(A/2) - Sin(A/2)]
=> [Cos(A/2) - Sin(A/2)]² / [Cos(A/2) + Sin(A/2)][Cos(A/2) - Sin(A/2)]
=> [Cos(A/2) - Sin(A/2)] / [Cos(A/2) + Sin(A/2)]
= R.H.S
Hence proved.
Complete the table of values of y = 14 x + 1.
Answer:
-4,0
0,1
8,3
======
x: -4, 0, 8
f(x) = 1/4(x) + 1
Plug in x values into f(x)...
f(-4) = 0
f(0) = 1
f(8) = 3
Many track hurdlers believe that they have a better chance of winning if they start in the inside lane that is closest to the field. For the data below, the lane closest to the field is Lane 1, the next lane is Lane 2, and so on until the outermost lane, Lane 6. The data lists the number of wins for track hurdlers in the different starting positions. Find the critical value to test the claim that the probabilities of winning are the same in the different positions. Use 0.05. The results are based on 240 wins.
Answer:
χ² = 6.75
χ² Critical = 11.07
Step-by-step explanation:
Given the data :
Expected winnings ;
1/n * total number of wins
Total number of wins = 240
n = number of starting positions = 6
Expected winnings = 1/6 * 240 = 40
Using χ² test :
χ² = Σ(O - E)² / E
O = Observed ; E = Expected
χ² = (32 - 40)^2 / 40 + (33 - 40)^2 / 40 + (45 - 40)^2 / 40 + (44 - 40)^2 / 40 + (50 - 40)^2 / 40 + (36 - 40)^2 / 40
= 6.75
χ² Critical at α = 0.05 ; df = n - 1 ; df = 5
χ² Critical = 11.07
Since χ² < χ² Critical ; WE fail to reject H0.
Which of the following lists of ordered pairs is a function? A. (2,5), (3, 6), (6, 9) B. (-1,2), (2, 3), (3, 1), (2,5) C. (1,2), (4,0), (3,5),(4,3) D. (2,5), (3, 6), (2, 1)
Answer:
A. (2,5), (3,6), (6,9)
Step-by-step explanation:
In order to be a function, all inputs (x values) must go to only one output (y value). List A is the only list that obeys this rule. Therefore, List A is a function.
Please help!!!......
Answer:
12*12=144
8*10=80
80+144=224
224*2=448
10*4=40
8*10=80
80*2=160
40+160=200
12*10=120
120+200=320
20*10=200
320+200=520
448+520=968
Hope This Helps!!!
Solve the equation. Then check your solution.
x - 4 = 2
a.–6
c.7
b.6
d.–2
Please select the best answer from the choices provided
A
B
C
D
Answer:
b) 6
Step-by-step explanation:
x - 4 = 2
x = 2 + 4
x = 6
