Explanation:
Six’s Maximum and Minimum thermometer is a U shaped parallel tube made up of glass. One side registers the maximum temperature and the other side records the minimum temperature.The bend at the bottom of the thermometer contains mercury which moves up or down based on the expansion and contraction of alcohol.When the temperature rises, the alcohol expands and pushes the mercury up the maximum column. This also pushes the mercury down in the minimum column.Similarly, when the temperature falls, the alcohol contracts and pulls the mercury up in the minimum column resulting in a fall of mercury in the maximum column.The steel indexes are located on the surface of mercury. They move along with the flow of mercury up and down.When the temperature reaches its maximum and minimum limits, the metal indexes remain at that place. This helps in recording the maximum and minimum temperatures of the day.A swimming pool of width 9.0 m and length 12.0 m is filled with water to a depth of 3.0 m. Calculate pressure on the bottom of the pool due to the water.
Hint: 1 m^3 of water has a mass of 1000 kg.
With the use of the formula, the pressure on the bottom of the pool due to the water is 29400 Pascal
Given that a swimming pool of width 9.0 m and length 12.0 m is filled with water to a depth of 3.0 m.
Volume = Length x Width x Height
Volume = 9 x 12 x 3
Volume = 324 [tex]m^{3}[/tex]
Since 1 m^3 of water has a mass of 1000 kg,
Mass = 324 x 1000
mass = 324000 kg
To calculate the pressure on the bottom of the pool due to the water, let us use the pressure formula below
P = δgh
where
P = pressure
δ = density of the water = 1000 kg/[tex]m^{3}[/tex]
g = Acceleration due to gravity = 9.8 m/[tex]s^{2}[/tex]
h = height = 3m
Substitute all the parameters into the formula
P = 1000 x 9.8 x 3
P = 29400 Pascal
Therefore, the pressure on the bottom of the pool due to the water is 29400 Pascal
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A ball is kicked at an angel of 37° to a goalkeeper who is 24m away. What was the initial velocity of the ball?
The initial velocity of the ball when it was projected is 15.64 m/s.
The given parameters:
Angle of the projection, θ = 37⁰The range of the projectile, R = 24 mThe initial velocity of the ball is calculated by applying formula for range of projectile as follows;
[tex]R = \frac{u^2 sin(2\theta)}{g} \\\\u^2 = \frac{Rg}{sin(2\theta)} \\\\u = \sqrt{\frac{Rg}{sin(2\theta)} } \\\\u =\sqrt{\frac{24 \times 9.8}{sin(2\times 37)} } \\\\u = 15.64 \ m/s[/tex]
Thus, the initial velocity of the ball when it was projected is 15.64 m/s.
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A bullet of mass M1 is fired towards a block of mass m2 initially at rest at the edge of a frictionless table of height h as in the figure. The initial speed of the bullet is vi . Consider two cases, a completely inelastic one and an elastic one,where the bullet bounces off the block. inelastic case elastic case a bullet inside no bullet inside A B A' B' What is the ratio of the flight time; i.e., tAB tA′B′ ?
The ratio of time of flight for inelastic collision to elastic collision is 1:2
The given parameters;
mass of the bullet, = m₁mass of the block, = m₂initial velocity of the bullet, = u₁initial velocity of the block, = u₂Considering inelastic collision, the final velocity of the system is calculated as;
[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\m_1u_1 + 0 = v(m_1 + m_2)\\\\v= \frac{m_1u_1}{m_1 + m_2} \ -- (1)\\\\[/tex]
The time of motion of the system form top of the table is calculated as;
[tex]v = u + gt\\\\v = 0 + gt\\\\v = gt\\\\t= \frac{v}{g} \\\\t_A = \frac{m_1u_1}{g(m_1 + m_2)} \ \ ---(2)[/tex]
Considering elastic collision, the final velocity of the system is calculated as;
[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\m_1u_1 + 0 = m_1v_1 + m_2v_2\\\\m_1 u_1 = m_1v_1 + m_2v_2[/tex]
Apply one-directional velocity
[tex]u_1 + (-v_1) = u_2 + v_2\\\\u_1 -v_1 = 0 + v_2\\\\v_1 = v_2 -u_1[/tex]
Substitute the value of [tex]v_1[/tex] into the above equation;
[tex]m_1u_1 = m_1(v_2 - u_1) + m_2 v_2\\\\m_1u_1 = m_1v_2 -m_1u_1 + m_2v_2\\\\2m_1u_1 = m_1v_2 + m_2v_2\\\\2m_1u_1= v_2(m_1 + m_2)\\\\v_2 = \frac{2m_1u_1}{m_1+ m_2} \ --(3)[/tex]
where;
[tex]v_2[/tex] is the final velocity of the block after collision
Since the bullet bounces off, we assume that only the block fell to the ground from the table.
The time of motion of the block is calculated as follows;
[tex]v_2 = v_0 + gt\\\\v_2 = 0 + gt\\\\t = \frac{v_2}{g} \\\\t_B = \frac{v_2}{g} \\\\ t_B = \frac{2m_1u_1}{g(m_1 + m_2)} \ \ ---(4)[/tex]
The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;
[tex]\frac{t_A}{t_B} = \frac{m_1u_1}{g(m_1 + m_2)} \times \frac{g(m_1 + m_2)}{2m_1u_1} \\\\\frac{t_A}{t_B} = \frac{1}{2} \\\\t_A:t_B = 1: 2[/tex]
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A position versus time graph is shown:
Position vs. Time
1 15
10
10
Time (seconds) ->
Which statement accurately describes the motion of the object in the graph above?
O It is at rest for 3 seconds before moving at constant speed for 10 seconds.
It is at rest for 3 seconds before moving at constant speed for 4 seconds.
Olt is moving from 0 cm to 5 cm at constant speed of 7 cm/s.
O it is moving from 0 cm to 3 cm at a constant speed of 3 cm/s.
Answer: Answer: The object moves forward at 5 m/s, stops, and then changes velocity.
Explanation:
With the information given in the question we can graph the points (image attached).
As we can observe, in the first segment of the graph the velocity is increasing linearly (at a constant rate) and is 5 m/s, then in the second segment we can see the position of the object remains the same from second 2 to second 4, which means the object is stopped.
Finally, in the third and last segment, we can observe a change in velocity (at a negative constant rate, because is decreasing), which is decreasing until the object stops.
Explanation:
Explain how the stars impact the shape of a galaxy.
Answer:
Galaxies are too far away for astronomers to take real 3D measurements, but we can infer their shape based on the movement of stars. ... This is also true of less common spiral galaxies like the Milky Way. The bulge near the center contains older stars, while the flattened arms are home to younger ones.
Explanation:
The orbits of stars can also affect the shape of a galaxy through a variety of density waves that are produced when material is compressed into something comparable to a traffic jam in galaxies.
What is Star?A star is defined as a celestial object consisting of a luminous sphere of plasma held together by self-gravity where the closest star to Earth is the Sun. While many other stars are visible to the uncovered eye at night, their extreme distance from Earth causes them to appear as fixed points of light.
Galaxies are too far away for astronomers to take true 3D measurements, through which we can estimate their size based on the motion of stars, which is also true for less common spiral galaxies like the Milky Way.
Thus, the orbits of stars can also affect the shape of a galaxy through a variety of density waves that are produced when material is compressed into something comparable to a traffic jam in galaxies.
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Lower chamber of Congress has how many members?
Answer:435 Representatives
Explanation:The lower chamber of Congress, in which the number of representatives per state is determined by the state's population, with 435 Representatives total. Members of the House of Representatives serve two-year terms, so they are up for reelection every two years.
the acceleration of a train moving from rest and its speed reaches 36m/sec in 9 sec
Answer:
4 m/s^2
Explanation:
The acceleration is defined as: Δv/Δt (the difference of the velocity over a time period in which happens that difference).
Remember that a difference is calculated by subtracting the initial value of a physical quantity from its final value.
In our case:
Δv = Vfinal - Vinitial = 36m/s - 0 m/s = 36m/s
Δt = 9s
a = Δv/Δt = 36m/s / 9s = 4m/s^2
A mass is pulled to the right while on a table.
A. Label the forces.
5 kg
B. Calculate the
object's weight.
Answer:
weight in 49N
I hope it's correct
David delivers meals to elderly people once a week. He uses a cart to move the meals. The cart has four smooth wheels. Which type of friction acts between the cartwheels and the sidewalk?
Answer: rolling friction
Explanation: I think it is the answer
which term is equal to velocity change per second?
Answer:
Acceleration is measured in meters per second squared (m/s²) change in velocity is measured in meters per second (m/s) time taken
what is a velocity of an object with a momentum of 300 kg m/s and the mass of 100 kg
Answer:
v = 3 m/s
Explanation:
P is the momentum
m is the mass
v is the velocity
P = m•v
300 = 100•v Divide both sides per 100
300/100 = v
v = 3 m/s
[tex]\text{Given that,}\\\\\text{Momentum, p = 300 kg m s}^{-1}\\\\\text{Mass, m = 100 kg}\\\\\text{We know that,}\\\\p = mv\\\\\implies v = \dfrac pm = \dfrac{300}{100} = 3 ~ \text{m s}^{-1}[/tex]
12/3/21 A wave in the ocean has a wavelength of 24 m and a frequency of 8 Hz,What is the wave's speed?
Answer:
192 m/sExplanation:
The speed of the wave given only it's frequency and wavelength can be found by using the formula
[tex]c = f \times \lambda[/tex]
where
c is the velocity of the wave in m/s
[tex] \lambda[/tex] is the wavelength in m
f is the frequency in Hz
From the question we have
c = 8 × 24 = 192
We have the final answer as
192 m/sHope this helps you
What is the mass of a box if it accelerated 5 m/s from a force of 12 N?
Answer:
60
Explanation:
You multiply the acceleration and the force and you get your answer
7. A drag car takes off at the green light heading in a straight line. The car goes
from a complete stop to 45m/s in 9 seconds. What is its acceleration?
Answer:
405
Explanation:
If the car stops at 45m/s in 9 seconds then it took the car 405 meters to stop
how many band is the parametric microphone equalizer?
Answer:
3 bands
Explanation:
Basically, the Parametric EQ divides the audio spectrum into three bands, allowing you to enhance (or suppress) the level in that range.
On average, how many stars would we have to search before we would expect to hear a signal? assume there are 500 billion stars in the galaxy.
We would have to search at least 5,000,000,000 (5 billion) stars before we would expect to hear a signal.
To find out the number of stars that we will need to search to find a signal, we need to use the following formula:
total of stars/civilizations500,000,000,000 (500 billion) stars / 100 civilization = 5,000,000,000 (5 billion)
This shows it is expected to find a civilization every 5 billion stars, and therefore it is necessary to search at least 5 billion stars before hearing a signal from any civilization.
Note: This question is incomplete; here is the complete question.
On average, how many stars would we have to search before we would expect to hear a signal? Assume there are 500 billion stars in the galaxy.
Assuming 100 civilizations existed.
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To overcome an object's inertia, it must be acted upon by __________. A. Gravity B. Energy C. Force D. Acceleration Please select the best answer from the choices provided. A B C D.
Taking into account the Newton's first Law, the correct answer is option C. To overcome an object's inertia, it must be acted upon by a force.
Newton's First Law, also called the Law of inertia, indicates that "Every body perseveres in its state of rest or of uniform rectilinear motion unless it is forced to change its state by forces impressed on it." This means that for a body to come out of its state of rest or of uniform rectilinear motion, it is necessary for a force to act on it.
In other words, it is not possible for a body to change its initial state (be it rest or motion) unless one or more forces intervene.
Finally, the correct answer is option C. To overcome an object's inertia, it must be acted upon by a force.
Learn more:
https://brainly.com/question/1083492https://brainly.com/question/14113252?referrer=searchResultsAnswer:
C) Force
Explanation:
11. A tennis ball is thrown straight up in the air, leaving the person's hand with an initial velocity of 3.0 m/s, as shown to the right. What is the displacement of the ball above the person's hand?
Answer:
0.46m
Explanation:
Which shows the stars in the correct order, from smallest in size to largest?
white dwarf, Sun, red supergiant
Sun, red supergiant, white dwarf
white dwarf, red supergiant, Sun
Sun, white dwarf, red supergiant
Answer:
its A
Explanation:
White dwarf, Sun, red supergiant shows the stars in the correct order, from smallest in size to largest.
What is the size stars?More than 1.4 million kilometers span our Sun. However, not every star is the same size. They range in size from that of a metropolis to that of our solar system's half!
The mass of neutron stars is concentrated into a very compact area. Even though they are frequently only 20 to 40 km in diameter, they may hold the mass of one or two Suns. White dwarf stars are a little larger and frequently resemble the size of the Earth.
Compared to our Sun, the greatest supergiant stars can be more than 1500 times bigger. They are now more than 2,000 million kilometres across. Supergiants don't, however, have thousands of times the mass of the Sun. The reason for this is that as supergiants become older, their interiors become considerably more dispersed. Betelgeuse, a red giant in Orion's constellation, is nearly 1000 times broader than the Sun yet only has around 15 times as much mass.
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You slide towards the window when a car makes a sudden turn
Answer:
thats ummm
Explanation:
law of inertia
Newton’s 1 law
A boxer throws a punch with a force of 1,400 N that lasts 0.02 s. What is the impulse of this punch? (1 point) 28 kg⋅m/s 28 kilograms times meters per second 280 kg⋅m/s 280 kilograms times meters per second 70,000 kg⋅m/s 70,000 kilograms times meters per second 7,000 kg⋅m/s
The impulse of the boxers punch is 28 kgm/s.
The given parameters;
applied force by the boxer, F = 1400 Ntime of force action, t = 0.02 sThe impulse of the boxers punch is calculated as follows;
[tex]J = Ft[/tex]
where;
F is the applied force (N)t is the time of force action (s)The magnitude of the impulse is calculated as follows;
[tex]J = 1400 \times 0.02 \\\\J = 28 \ kg m/s[/tex]
Thus, the impulse of the boxers punch is 28 kgm/s.
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A type of matter in which two or more elements are combined
chemically is called a _______
Answer:
COMPOUND
Explanation:
the probe used in a medical ultrasound examination emits sound waves in air that have a wavelength of 0.12 mm.
Answer:
IF GOD IS TEIIING YOU SOMETHING JUST DO IT
Explanation:
when is atmospheric pressure 1x10 to the power of 5 and when is it pgh
Answer:
1 atmospheris pressure is equal to10.33 meter under water
Explanation:
right ??
Part A
As an object moves around, on which quantities does the change in its gravitational potential energy depend? Choose all that
apply.
A 30.4-newton force is used to slide a 40.0-newton crate a distance of 6.00 meters at constant speed along an incline to a vertical height of 3.00 meters. Calculate the work done by a friction force on the crate as it slides 6.00 m along the incline.
Hi there!
Since the crate is being slid at a constant speed, the forces sum to 0 N. In this instance, the following forces occur in the axis of interest:
Wsinθ = downward acceleration along incline due to gravity (N)
Fκ = kinetic friction force along incline (N)
A = applied force (N)
The acceleration due to gravity and friction force act in the same direction, so:
Wsinθ + Fκ = A
Solve for sinθ using right triangle trigonometry:
sinθ = O/H = 3/6 = 0.5
Rearrange the equation for the force of kinetic friction and solve:
Fκ = A - 0.5W
Fκ = 30.4 - 20 = 10.4 N
Now, recall that:
Work = Force × displacement (W = F × d)
Since the box's displacement is in the same axis as the force but OPPOSITE direction, we must use:
W = Fdcosθ
Angle between displacement and friction force is 180°.
cos(180) = -1
Work done by friction = -Fd = -10.4(6) = -62.4 J
Name the two sources of light.
Answer:
Natural light (Sun, stars.etc.) and Artificial light (Lamposts, televisions.etc.)
Hope that helps. x
In which scenario is work being done on an object?
a) A force is applied to an object to hold it at rest on an inclined plane.
b) Sitting on a box.
c) An upward force is applied to an object to move it upward at a constant speed.
d) An upward force is applied to an object to suspend it motionless in mid-air.
Answer:c
Explanation:
To solve this, we must know each and every concept related to work. Therefore, the correct option is option C that is "an upward force is applied to an object to move it upward at a constant speed."
What is work?Work in physics is the energy delivered to or out of an item by applying force across a displacement. It is frequently expressed in its most basic form as the combination of displacement and force.
When a force is applied, it is said to produce positive work if it has a portion in the directions of the movement of the site of application. Work is done on a body is equivalent to an increase in the body's energy, because work transmits energy to the body. If, on the other hand, the force acting is in the opposite direction as the item's motion, the work is regarded negative, suggesting that energy is withdrawn from the object.
Therefore, the correct option is option C that is "an upward force is applied to an object to move it upward at a constant speed."
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What is the sum of 130+125+191? A. 335. B. 456. C. 446. D. 426.
If we minus 712 from 1500, how much do we get? A. 788. B. 778. C. 768. D. 758.
50 times of 8 is equal to: A. 80. B. 400. C. 800. D. 4000.
110 divided by 10 is: A. 11. B. 10. C. 5. D. None of these.
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an EM wave has a wave length of 956 m, What type of electromagnetic waves is this wave
The electromagnetic spectrum allows finding the result for the question of type of electromagnetic wave has a wavelength of 956 nm
The wave is in the near infrared range.
The electromagnetic wave is an oscillation of electric fields and magnets field that sustain each other, this wave time has the characteristics that it can travel without a material medium, for which they are of extreme importance.
Consequently the spectrum of electromagnetic waves to each part has been given a different name second to its use, for example
Range Name
Ultraviolet light 200 to 400 nm
Visible light 400 to 700 nm
Infrared light (heat ) 700 nm to 1 mm
The latter is subdivided into:
Near infrared 700 nm to 1000 nm (1 μm)
Medium infrared 1 μm to 30 μm
Far infrared 50 μm to 1000 μm
It indicates that the wavelength of the measured radiation is 956 nm, therefore it is in the near infrared range.
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