for 0 degrees ≤ x < 360 degrees , what are the solutions to sin (x/2) + cos(x) - 1 =0

Answer:

-8, 5 , 0 , -7 , 16

Step-by-step explanation:

Given

[tex]t_n = (-1)^{n+1}(n^2 - 9)[/tex]

Required

The first five terms

When [tex]n = 1[/tex]

[tex]t_1 = (-1)^{1+1}(1^2 - 9)[/tex]

[tex]t_1 = (-1)^{2}(1 - 9)[/tex]

[tex]t_1 = -8[/tex]

When [tex]n =2[/tex]

[tex]t_2 = (-1)^{2+1}(2^2 - 9)[/tex]

[tex]t_2 = (-1)^3 * (4 - 9)[/tex]

[tex]t_2 = 5[/tex]

[tex]t_3 = (-1)^{3+1}(3^2 - 9)[/tex]

[tex]t_3 = (-1)^{4}(9 - 9)[/tex]

[tex]t_3 = 0[/tex]

[tex]t_4 = (-1)^{4+1}(4^2 - 9)[/tex]

[tex]t_4 = (-1)^5(16 - 9)[/tex]

[tex]t_4 = -7[/tex]

[tex]t_5 = (-1)^{5+1}(5^2 - 9)[/tex]

[tex]t_5 = (-1)^{6}(25 - 9)[/tex]

[tex]t_5 = 16[/tex]

So, the first five terms are: -8, 5 , 0 , -7 , 16

This question is solved using relative frequency concepts, finding the following two way frequency table, with the - separating the values:

0.4290 - 0.0540 - 0.4839

0.0581 - 0.4581 - 0.5161

0.4871 - 0.5121 - 1

-------------------------------------------------------------------------------

Relative frequency:

The relative frequency of a to b is given by a divided by b.

-------------------------------------------------------------------------------

Democratic:

Total of 150 + 160 = 310 voters.

Of the 150 Democrats, 133 voted for the Democrat and 150 - 133 = 17 voted for the Republican.

The frequencies are:

[tex]\frac{133}{310} = 0.4290, \frac{17}{310} = 0.0548[/tex]

Proportion of democratic voters is:

[tex]\frac{150}{310} = 0.4839[/tex]

Thus, the first line is: 0.4290 - 0.0540 - 0.4839

-------------------------------------------------------------------------------

Republican:

Of the 160 Republicans, 142 voted for the Republican and 160 - 142 = 18 voted for the Democrat.

The frequencies are:

[tex]\frac{18}{310} = 0.0581, \frac{142}{310} = 0.4581[/tex]

The proportion of republican voters is:

[tex]\frac{160}{310} = 0.5161[/tex]

Thus, the second line is: 0.0581 - 0.4581 - 0.5161

-------------------------------------------------------------------------------

Third line:

0.4290 + 0.0581 = 0.4871

0.0540 + 0.4581 = 0.5121

0.4839 + 0.5161 = 1

Thus, the third line is: 0.4871 - 0.5121 - 1

-------------------------------------------------------------------------------

Two-way frequency table:

The two-way frequency table is:

0.4290 - 0.0540 - 0.4839

0.0581 - 0.4581 - 0.5161

0.4871 - 0.5121 - 1

A similar question is given at: https://brainly.com/question/24337228

Answer:

Democratic 133 18 151

Republican 17 142 159

Total        150 160 310

Step-by-step explanation:

Elimination method

3x +4y ≥ 0

2x +3y ≥ 1

Multiply by 2, -3

6x +8y ≥ 0

-6x +-9y ≥ -3

Add

-1y ≥ -3

y = 3

3x + 12≥ 0

3x + ≥ -12

x = -4

answer: y = 3 x = -4

Answer:

x= -2

y= -1

z= -3

Step-by-step explanation:

x-y= -1 (1)

x+z= -5 (2)

y-z= 2 (3)

(1)+(3)==> x-z= 1 (4)

(4)+(2)==> 2x= -4 ==> x= -2

we replace x by its value in equation (2):

-2+z= -5 ==> z= -3

we replace z by its value in equation (3):

y-(-3)= 2 ==> y+3=2 ==> y= -1

Vertical asymptote:

A vertical asymptote is a value of x for which the function is not defined, that is, it is a point which is outside the domain of a function;

In a graphic, these vertical asymptotes are given by dashed vertical lines.

An example is a value of x for which the denominator of the function is 0.

In this graphic:

Dashed vertical lines at: [tex]x = -3, x = 7[/tex], thus, for [tex]x - (-3) = x+3[/tex] and [tex]x - 7[/tex] the denominator is zero.

Thus, the function graphed is:

[tex]F(x) = \frac{1}{(x+3)(x-7)}[/tex]

And the correct answer is given by option C.

To take a look at a problem with asymptote, you can check this item https://brainly.com/question/4084552.

The graph is for the rational function f(x) = 1/(x + 3)(x - 7).

Option C is the correct answer.

We have,

To understand the graph of the function f(x) = 1/((x + 3)(x - 7)).

Vertical Asymptotes:

The function has vertical asymptotes at the values of x for which the denominator becomes zero.

The denominator is (x + 3)(x - 7), so the vertical asymptotes occur at

x = -3 and x = 7.

Horizontal Asymptote:

The highest power of x in the denominator is x², and there is no x² term in the numerator, the function approaches 0 as x goes to positive or negative infinity.

The horizontal asymptote is y = 0.

x-Intercept:

To find the x-intercept, we set y = 0 and solve for x:

0 = 1/((x + 3)(x - 7))

Since the numerator can never be zero, the only way the fraction can be zero is if the denominator is zero:

(x + 3)(x - 7) = 0

Solving for x:

x + 3 = 0

x = -3

x - 7 = 0

x = 7

So, the x-intercepts are (-3, 0) and (7, 0).

y-Intercept:

To find the y-intercept, we set x = 0:

f(0) = 1/((0 + 3)(0 - 7)) = 1/(-3 * -7) = 1/21

The y-intercept is (0, 1/21).

Thus,

The graph is for the rational function f(x) = 1/(x + 3)(x - 7).

Learn more about functions here:

https://brainly.com/question/28533782

#SPJ6

Answer:

95

Step-by-step explanation:

Use the mean formula: mean = sum of elements / number of elements

Plug in the mean and number of elements, then solve for the sum of the numbers:

mean = sum of elements / number of elements

19 = sum of elements / 5

95 = sum of elements

So, the sum of the numbers is 95.

Answer:

The answer is "2"

Step-by-step explanation:

When we check the points where the x is -2

by calculating the "y-value":

It is 2, right?  

it implies that [tex]f(-2)=2[/tex]

that's why the final answer is "2"

Answer:

B.

[tex]{ \tt{f(x) = \sqrt[3]{x + 11} }}[/tex]

let the inverse of f(x) be m:

[tex]{ \tt{m = \sqrt[3]{x + 11} }} \\ { \tt{ {m}^{3} = x + 11}} \\ { \tt{ {m}^{3} - 11 = x}} \\ { \tt{ {f}^{ - 1}(x) = {m}^{3} - 11 }}[/tex]

substitute for x in place of m:

[tex]{ \bf{f {}^{ - 1}(x) = {x}^{3} - 11 }}[/tex]

Answer:

84.7

Step-by-step explanation:

of is another way to say multiply so what your doing is muliplying all the numbers

Answer:

84.7

Step-by-step explanation:

SEE THE IMAGE FOR SOLUTION

HOPE IT HELPS

HAVE A GREAT DAY

Answer:

the 4th option

Step-by-step explanation:

8 = 2³

so, when we convert

[tex] {8}^{x - 3} [/tex]

into a "2 to the power of" expression, we get therefore

[tex] ({2}^{3}) ^{x - 3} [/tex]

and when we have an exponent of an exponent, we can simplify by multiplying these two exponents.

3×(x-3) = 3x - 9

and therefore we get

[tex] {2}^{3x - 9} [/tex]

and by the way, we can now even easily solve this for x, as we know

[tex] {2}^{4x} = {2}^{3x + x} [/tex]

after all, because 4x = x + x + x + x = 3x + x = ...

and because we got also

[tex] {2}^{4x} = {2}^{3x - 9} [/tex]

we know that 3x + x = 3x - 9

and that gives us x = -9

Answer:

[tex]8(2a- b)(4a^2+ 2ab+ b^2)[/tex]

Step-by-step explanation:

factor out the 8

then you have the sum/difference of cubes..

look that up SOAP: same opposite, always a plus

[tex]64a^3 -8b^3\\8(8a^3 -b^3)[/tex]

[tex]8(2a- b)(4a^2+ 2ab+ b^2)[/tex]

Answer:

Yes one should consider to buy the policy as important to have insured plan that help at the time of need.

Step-by-step explanation:

Answer:

Here's the answer i believe. x = y/m + 7

Given the definition above and the fact that top points of the function are at y=9 and the low point are at y=1, the center line must be halfway at y=5.

the amplitude therefore is 4. it's also just half the difference of 1 and 9.

I did this graphically with desmos. Doing it algebraicly would have taken much more time i guess.

Answer:

Step-by-step explanation:

-Total column

30 students in the class

12 male , so 30-12 = 18 female

-Pencils column

21 students prefer pencils

12 female that prefer pencils , 21-12 = 9 male that prefer pencils

-Total row

21 students prefer pencils

30 students total, 30-21 = 9 students prefer pens

-Pens column

12 students male -9 students male prefer pencil =3  students male prefer pens

18 students female -12 students female prefer pencil =6  students female prefer pens

-to calculate the % always find the equivalent fraction of

30 students/ 100% = number of students you have / ?%

example: for male that prefer pencils we have 30/100 = 9/? so

? = 100*9 /30 =30%

Answer:

(0.3478, 0.5522)

Step-by-step explanation:

Given:

Total number of red marbles, x = 45

Total number of marbles, n = 100

Phat = x / n = 45 / 100 = 0.45

The confidence interval, C.I is given by :

Phat ± Zcritical * standard error

Phat ± Zcritical * √Phat(1 - Phat) / n

Zcritical at 96% = 2.0537

The standard error = √Phat(1 - Phat) / n

S.E = √(0.45 * 0.55) / 100 = 0.0497493

C.I = 0.45 ± (2.0537 * 0.0497493)

C.I = 0.45 ± 0.10217013741

C. I = (0.3478, 0.5522)

Hi there!

To find the Trigonometric Equation, we have to isolate sin, cos, tan, etc. We are also given the interval [0,2π).

First Question

What we have to do is to isolate cos first.

[tex] \displaystyle \large{ cos \theta = - \frac{1}{2} }[/tex]

Then find the reference angle. As we know cos(π/3) equals 1/2. Therefore π/3 is our reference angle.

Since we know that cos is negative in Q2 and Q3. We will be using π + (ref. angle) for Q3. and π - (ref. angle) for Q2.

Find Q2

[tex] \displaystyle \large{ \pi - \frac{ \pi}{3} = \frac{3 \pi}{3} - \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{2 \pi}{3} }[/tex]

Find Q3

[tex] \displaystyle \large{ \pi + \frac{ \pi}{3} = \frac{3 \pi}{3} + \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{4 \pi}{3} }[/tex]

Both values are apart of the interval. Hence,

[tex] \displaystyle \large \boxed{ \theta = \frac{2 \pi}{3} , \frac{4 \pi}{3} }[/tex]

Second Question

Isolate sin(4 theta).

[tex] \displaystyle \large{sin 4 \theta = - \frac{1}{ \sqrt{2} } }[/tex]

Rationalize the denominator.

[tex] \displaystyle \large{sin4 \theta = - \frac{ \sqrt{2} }{2} }[/tex]

The problem here is 4 beside theta. What we are going to do is to expand the interval.

[tex] \displaystyle \large{0 \leqslant \theta < 2 \pi}[/tex]

Multiply whole by 4.

[tex] \displaystyle \large{0 \times 4 \leqslant \theta \times 4 < 2 \pi \times 4} \\ \displaystyle \large \boxed{0 \leqslant 4 \theta < 8 \pi}[/tex]

Then find the reference angle.

We know that sin(π/4) = √2/2. Hence π/4 is our reference angle.

sin is negative in Q3 and Q4. We use π + (ref. angle) for Q3 and 2π - (ref. angle for Q4.)

Find Q3

[tex] \displaystyle \large{ \pi + \frac{ \pi}{4} = \frac{ 4 \pi}{4} + \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{5 \pi}{4} }[/tex]

Find Q4

[tex] \displaystyle \large{2 \pi - \frac{ \pi}{4} = \frac{8 \pi}{4} - \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{7 \pi}{4} }[/tex]

Both values are in [0,2π). However, we exceed our interval to < 8π.

We will be using these following:-

[tex] \displaystyle \large{ \theta + 2 \pi k = \theta \: \: \: \: \: \sf{(k \: \: is \: \: integer)}}[/tex]

Hence:-

For Q3

[tex] \displaystyle \large{ \frac{5 \pi}{4} + 2 \pi = \frac{13 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 4\pi = \frac{21 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 6\pi = \frac{29 \pi}{4} }[/tex]

We cannot use any further k-values (or k cannot be 4 or higher) because it'd be +8π and not in the interval.

For Q4

[tex] \displaystyle \large{ \frac{ 7 \pi}{4} + 2 \pi = \frac{15 \pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 4 \pi = \frac{23\pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 6 \pi = \frac{31 \pi}{4} }[/tex]

Therefore:-

[tex] \displaystyle \large{4 \theta = \frac{5 \pi}{4} , \frac{7 \pi}{4} , \frac{13\pi}{4} , \frac{21\pi}{4} , \frac{29\pi}{4}, \frac{15 \pi}{4} , \frac{23\pi}{4} , \frac{31\pi}{4} }[/tex]

Then we divide all these values by 4.

[tex] \displaystyle \large \boxed{\theta = \frac{5 \pi}{16} , \frac{7 \pi}{16} , \frac{13\pi}{16} , \frac{21\pi}{16} , \frac{29\pi}{16}, \frac{15 \pi}{16} , \frac{23\pi}{16} , \frac{31\pi}{16} }[/tex]

Let me know if you have any questions!

Answer:

This variation is a source of

response error.

Step-by-step explanation:

A response error shows the lack of accuracy in the customer responses to the survey questions.  A response error can be caused by a questionnaire that requires framing improvements, misinterpretation of questions by interviewers or respondents, and errors in respondents' statements.  Some responses are influenced by the answers provided to previous questions, which introduces response bias.

Answer:

There are a few rules that we can use here:

ln(a^x) = x*ln(a)

ln(a) - ln(b) = ln(a/b)

ln(1) = 0

So here we want to expand:

ln(1/49^k)

First we can use the second property to get:

ln(1/49^k) = ln(1) - ln(49^k)

using the third property, we have:

ln(1/49^k) = ln(1) - ln(49^k) = 0 - ln(49^k)

ln(1/49^k) =  - ln(49^k)

Now we can use the first property to get:

ln(1/49^k) =  - k*ln(49)

Now we can use the fact that:

49 = 7*7 = 7^2

then:

- k*ln(49) = -k*ln(7^2) = -2*k*ln(7)

So we have:

ln(1/49^k) = (-2*ln(7))*k

We can expand it anymore because this is a real number  "(-2*ln(7))" times a variable k.

Answer:

i hope it will help you

Step-by-step explanation:

Working capital management is how companies are able to manage finances and continue operations.

Answer:

\I got not answer cause im da BUDDHA

But gimme brainliest squekky plssss

Answer:

-1.87 (B)

865.93 - [968-3.34(30)] = -1.87

ED2021

9514 1404 393

Answer:

  9.6 billion

Step-by-step explanation:

The population multiplier is 1+1.1% = 1.011 each year. After 52-19 = 33 years, the multiplier will be 1.011^33 ≈ 1.4348.

When the student is 52, the population of the world will be about ...

  6.7 billion × 1.4348 ≈ 9.6 billion

Answer:

supplement of 158 degree

x+158=180

x=180-158

x=22 degree.

Step-by-step explanation:

Answer:

Step-by-step explanation:

TOM / 6.02 years

~~~~~~~~~~~~~~~~~~~~~~

Tom: 2000(1.02)^15 =  $2,691.74  

Jerry: 1800(1.025)^15 =  $2,606.94

TOM has more money after 15 years...

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

6000 = 2000(1.02)^t

3=(1.02)^t

ln(3) = t * ln(1.02)

t = ln(3)/ln(1.2)

t = 6.02 years  

Answer:

[tex]c - 2 = 25 + 10 \sqrt c + c[/tex]

Step-by-step explanation:

Given

[tex]\sqrt{c-2} - \sqrt c = 5[/tex]

Required

Isolate radical, then square both sides

We have:

[tex]\sqrt{c-2} - \sqrt c = 5[/tex]

Isolate radical

[tex]\sqrt{c - 2} = 5 + \sqrt c[/tex]

Square both sides

[tex](\sqrt{c - 2})^2 = (5 + \sqrt c)^2[/tex]

[tex]c - 2 = 25 + 2 * 5 * \sqrt c + c[/tex]

[tex]c - 2 = 25 + 10 \sqrt c + c[/tex]

Answer:

Categorical or Continuous.

Step-by-step explanation:

Because the red appears in each colours (continuous)

[tex]\\ \sf\longmapsto \frac{x}{6} - \frac{y}{3} = 1 \\ \\ \sf\longmapsto \frac{x - 2y}{6} = 1 \\ \\ \sf\longmapsto x - 2y = 6 \\ \\ \sf\longmapsto x = 6 + 2y[/tex]

Answer:

12

Step-by-step explanation:

Range is the subtraction of the largest number and the smallest number.

The largest number is: 23

The smallest number is: 11

Now subtract:

23 - 11 = 12

Hope this helped.

Answer:

the lowest is 11 and the highest is 24 then subtract it you are going to have 13

Answer:

Yes the sales manager claims can be refuted based on the calculated percentages

Step-by-step explanation:

From the table attached below

Total number of customers = 200

Calculated percentages

customers that prefer whole life insurance = 90 = 90/200 = 45%

customers that prefer universal life insurance = 15 = 15/200 = 7.5%

customers that prefer Annuities = 95 = 95/200 = 47.5

Expected percentages:

whole life = 20%

Universal life = 10%

Life Annuities = 70%