Given the following reaction:
CO (g) + 2 H2(g) <==> CH3OH (g)
In an experiment, 0.42 mol of CO and 0.42 mol of H2 were placed in a 1.00-L reaction vessel. At equilibrium, there were 0.29 mol of CO remaining. Keq at the temperature of the experiment is ________.
A) 2.80
B) 0.357
C) 14.5
D) 17.5
E) none of the above

Answer: A buffer solution reacts with basic solutions.

A buffer solution resists small changes in pH.

A buffer solution reacts with acidic solutions.

Explanation:

A buffer solution simply refers to an aqueous solution that consist of a mixture of a weak acid and the conjugate. From the options given, the ones application to a buffer solution include:

• A buffer solution reacts with basic solutions.

• A buffer solution resists small changes in pH.

• A buffer solution reacts with acidic solutions.

Answer:

an alcohol is a Hydroxyl group due to the OH~ that is associated with it's molecules

The functional group found in an alcohol is Hydroxyl . Therefore, the correct option is option D.

A functional group in organic chemistry is a substituent and moiety inside a molecule that triggers the molecule's distinctive chemical processes. No matter how the rest of a molecule is made up, the very same functional group would experience the same or a similar set of chemical events.

This permits the design of synthetic chemistry as well as the methodical forecasting of chemical reactions as well as the behaviour of chemical molecules. Other functional groups close by can affect a functional group's reactivity. Retrosynthetic analysis can be used to design organic synthesis by using functional group interconversion. The functional group found in an alcohol is Hydroxyl .

Therefore, the correct option is option D.

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Answer:

[tex]pH=4.77[/tex]

Explanation:

From the question we are told that:

pKa for Acetic Acid [tex]pK_a= 4.77[/tex]

Therefore

For Equal Concentration of acetic acid and acetatic ion

[tex]CH_3COOH=CH_3COO^-[/tex]

Generally the Henderson's equation for pH value is mathematically given by

[tex]pH=pK_a+log\frac{base}{acid}[/tex]

[tex]pH=4.77+log\frac{CH_3COO^-}{CH_3COOH}[/tex]

[tex]pH=4.77+log1[/tex]

[tex]pH=4.77[/tex]

Answer:

The number of moles of strontium sulfide produced is:

= 1.663.

Explanation:

Chemical formula for strontium sulfide = SrS

Production of strontium sulfide = 199g

1 mole = 1 moles Strontium Sulfide, which is equal to 119.685 grams

The number of moles of strontium sulfide produced = 1.663 (199/119.685)

The number of moles of strontium sulfide produced is the dividend of the amount of strontium sulfide produced during the experiment divided by the mass of 1 mole.

Answer:

can only be determined experimentally.

Explanation:

In the early days of inorganic chemistry, the structure of complex ions remained a mystery hence the name ''complex''.

These ions appear to have structures that defied accurate elucidation. However, by diligent laboratory investigation, Alfred Werner was able to accurately determine the structure of cobalt complexes. As a result of this, he is regarded as a pathfinder in coordination chemistry.

Hence, the structure of complex ions can only be determined experimentally.

Answer:

c. can only be determined experimentally

Explanation:

It is not possible to know for certain the structure of a complex ion on the basis of stoichiometry or by the electrical charges on the components. The structure of the resulting complex ion can only be known by experiment.

The  structure of a compound C₆H₁₄ with a base peak at m/z 43 is none of these .

Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.

Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.They are:

1)Molecular compounds where in atoms are joined by covalent bonds.

2) ionic compounds where atoms are joined by ionic bond.

3)Inter-metallic compounds where atoms are held by metallic bonds

4) co-ordination complexes where atoms are held by co-ordinate bonds.

They have a unique chemical structure held together by chemical bonds Compounds have different properties as those of elements because when a compound is formed the properties of the substance are totally altered.

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Answer:

HClO₃(aq) + NaOH(aq) ⇒ NaClO₃(aq) + H₂O(l)

Explanation:

We have the products of a reaction and we have to predict the reactants. Since the products are salt and water, this must be a neutralization reaction. In a neutralization reaction, an acid reacts with a base. To form NaClO₃, the acid must be HClO₃(aq) and the base NaOH(aq). The balanced chemical equation is:

HClO₃(aq) + NaOH(aq) ⇒ NaClO₃(aq) + H₂O(l)

Answer:

Al + MnO4- + 2H2O → Al(OH)4- + MnO2

Explanation:

First of all, we out down the skeleton equation;

Al + MnO4- → MnO2 + Al(OH)4-

Secondly, we write the oxidation and reduction equation in basic medium;

Oxidation half equation:Al + 4H2O + 4OH- → Al(OH)4- + 4H2O + 3e-

Reduction half equation:MnO4- + 4H2O + 3e- → MnO2 + 2H2O + 4OH-

Thirdly, we add the two half reactions together to obtain:

Al + MnO4- + 8H2O + 4OH- + 3e- → Al(OH)4- + MnO2 + 6H2O + 3e- + 4OH-

Lastly, cancel out species that occur on both sides of the reaction equation;

Al + MnO4- + 8H2O→ Al(OH)4- + MnO2 + 6H2O

The simplified equation now becomes;

Al + MnO4- + 2H2O → Al(OH)4- + MnO2

Ionization potential and ionization energy are two terms used to describe the same thing.

The ionization potential of hydrogen atom is 13.6 eV

The ionization potential is the energy that is required to remove an electron from the neutral atom. It is the same as the ionization energy.

From the question, we can see that the ionization energy of the hydrogen atom is 13.6 eV, it also means that the ionization potential of the hydrogen atom is also 13.6 eV.

Therefore, If ionization energy of hydrogen atom is 13.6 eV then its ionization potential will be 13.6 eV

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Answer:

5.20 grams of Br₂

Explanation:

From our previous knowledge;

We understand that:

The number of moles of a given element = mass of the element divided by its molar mass.

Mathematically:

[tex]\mathbf{no \ of \ moles =\dfrac{ mass}{ molar \ mass}}[/tex]

From the given information, let's assume that the 0.065 moles of liquid -bromine partake in the reaction.

From the periodic table, the molar mass of Bromine is = 79.9 g/mol

As such, the mass of liquid that partakes is calculated as:

0.065 mol  = mass/ 79.9 g/mol

mass = 0.065 mol × 79.9 g/mol

mass of liquid that partakes in the reaction = 5.20 grams of Br₂

Explanation:

Because molarity is mol/L, we'll have to convert 17g to mol.

After obtaining the mol, we'll divide that by the volume to obtain Molarity.

[tex]\\ \sf\longmapsto NH_3[/tex]

[tex]\\ \sf\longmapsto 14u+3(1u)[/tex]

[tex]\\ \sf\longmapsto 14u+3u[/tex]

[tex]\\ \sf\longmapsto 17u[/tex]

[tex]\\ \sf\longmapsto 17g/mol[/tex]

Moles of Ammonia:-

[tex]\boxed{\sf No\:of\:moles =\dfrac{Given\:mass}{Molar\:mass}}[/tex]

[tex]\\ \sf\longmapsto No\:of\:moles=\dfrac{17}{17}[/tex]

[tex]\\ \sf\longmapsto No\;of\:moles=1mol[/tex]

We know

[tex]\boxed{\sf Molarity=\dfrac{Moles\:of\:solute}{Volume\:of\: Solution\:in\:L}}[/tex]

[tex]\\ \sf\longmapsto Molarity=\dfrac{1}{0.50}[/tex]

[tex]\\ \sf\longmapsto Molarity=2M[/tex]

Answer:

5g/cm3

Explanation:

firstly convert the litres and kilograms to grams and centimeters.

1l is equivalent to 1000cm3

0.58×1000

580cm3

and 1kg is equivalent to 1000g

2.9×1000

2900

then find the density by using the formula

density=mass/volume

=2900g/580cm3

=5g/cm3

I hope this helps

Answer:

a. 100.0 mL of 0.10 M NH₃ with 100.0 mL of 0.15 M NH₄Cl.

c. 50.0 mL of 0.15 M HF with 20.0 mL of 0.15 M NaOH.

Explanation:

A buffer system is formed in 1 of 2 ways:

Determine whether mixing each pair of the following results in a buffer.

a. 100.0 mL of 0.10 M NH₃ with 100.0 mL of 0.15 M NH₄Cl.

YES. NH₃ is a weak base and NH₄⁺ (from NH₄Cl ) is its conjugate base.

b. 50.0 mL of 0.10 M HCl with 35.0 mL of 0.150 M NaOH.

NO. HCl is a strong acid and NaOH is a strong base.

c. 50.0 mL of 0.15 M HF with 20.0 mL of 0.15 M NaOH.

YES. HF is a weak acid and it reacts with NaOH to form NaF, which contains F⁻ (its conjugate base).

d. 175.0 mL of 0.10 M NH₃ with 150.0 mL of 0.12 M NaOH.

NO. Both are bases.

Answer:

The correct answer is "1.0100".

Explanation:

Let the volume of mixture be 100 ml.

then,

The volume of DMSO will be 10 mL as well as that of water will be 90 mL.

DMSO will be:

= [tex]10\times 1.1004[/tex]

= [tex]11.004 \ g[/tex]

The total mass of mixture will be:

= [tex]90+11.004[/tex]

= [tex]101.004 \ g[/tex]

Density of mixture will be:

= [tex]\frac{Mass}{Volume}[/tex]

= [tex]\frac{101.004}{100}[/tex]

= [tex]1.01004 \ g/mL[/tex]

hence,

Specific gravity of mixture will be:

= [tex]\frac{Density \ of \ mixture}{Density \ of \ water}[/tex]

= [tex]\frac{1.01004}{1}[/tex]

= [tex]1.0100[/tex]

Answer:

Nutrients arw compounds in foods essential to life and heath

Answer: In simple terms nutrients are the energy that you get from food certain foods give more nutrients and others give close to none. That is what nutrients in your food is

Explanation:

Answer:

It is 1.25 moles

Explanation:

Molar mass of sulphur = 32 g

[tex]{ \bf{moles = \frac{given \: mass}{molar \: mass} }} [/tex]

Substitute:

[tex]{ \sf{moles = \frac{40}{32} }} \\ { \sf{ = 1.25 \: moles}}[/tex]

Answer:

The answer is "[tex]32819.9 \ \frac{J}{mol}\\\\[/tex]"

Explanation:

[tex]Boron: 5^{B}\to 1s^2 2s^2 2p^1[/tex]

[tex]\Delta E=-2.18\times 10^{-18}\ \frac{J}{atom}\ (\frac{1}{\infity^2}-\frac{1}{n^2_{initial}})(z^2) (6.022\times 10^{23}\ \frac{atom}{mol})\\\\[/tex]

      [tex]=-2.18\times 10^{-18}\ \frac{J}{atom}\ (0-\frac{1}{1})(5^2) (6.022\times 10^{23}\ \frac{atom}{mol})\\\\ =2.18\times 10^{-18}\times 25 \times 6.022\times 10^{23}\ (\frac{J}{mol})\\\\ =328.199 \times 10^{5}\ (\frac{J}{mol})\\\\ =32819 \times 10^{3}\ (\frac{J}{mol})\\\\ =32819.9 \ (\frac{J}{mol})\\\\[/tex]

Answer:

56%

Explanation:

If I use 25 grams of iron (III) phosphate and obtain 18.5 g of iron (III) sulfate, what is my percent yield?

Step 1: Write the balanced equation

2 FePO₄ + 3 Na₂SO₄ ⇒ Fe₂(SO₄)₃ + 2 Na₃PO₄

Step 2: Calculate the theoretical yield of Fe₂(SO₄)₃

The mass ratio of FePO₄ to Fe₂(SO₄)₃ is 301.64:399.88.

25 g FePO₄ × 399.88 g Fe₂(SO₄)₃/301.64 g FePO₄ = 33 g Fe₂(SO₄)₃

Step 3: Calculate the percent yield of Fe₂(SO₄)₃

We will use the following expression.

%yield = (experimental yield/theoretical yield) × 100%

%yield = (18.5 g/33 g) × 100% = 56%

Answer:

See detailed explanation.

Explanation:

Hey there!

In this case, according to the given information, it turns out possible for us to solve this problem by firstly calculating the moles of each element, assuming those percentages are masses, so that we divide by their molar masses:

[tex]C=\frac{18.63}{12.01}=1.55\\\\H=\frac{1.56}{1.01} =1.55\\\\O=\frac{24.82}{16.00}=1.55\\\\Cl=\frac{54.99}{35.45}=1.55[/tex]

Then, we divide all of them by 1.55 to realize the empirical formula is:

[tex]CHOCl[/tex]

Whose molar mass is 64.47 g/mol, and therefore, since the molar mass of these two is the same, we infer the molecular formula is also CHOCl.

The Lewis structure is shown on the attached document, whereas, the central atom is C and it does complete its octet as well as both O and Cl.

Regards!

Answer:

Li^3+

Explanation:

The electronic configuration of lithium is ; 1s2 2s1. This means that lithium has one electron in its outermost shell and two core electrons.

We know that it is difficult to remove these core electrons during ionization. Lithium belongs to group 1 hence Li^+ is formed more easily.

It is very difficult to form Li^3+ because it involves loss of core electrons which requires a lot of energy.

Explanation:

here's the answer to your question about

Answer:

XCH₄ = 0.461

XCO₂ = 0.539

Explanation:

Step 1: Given data

Step 2: Calculate the total pressure in the container

We will sum both partial pressures.

P = pCH₄ + pCO₂

P = 431 mmHg + 504 mmHg = 935 mmHg

Step 3: Calculate the mole fraction of each gas

We will use the following expression.

Xi = pi / P

XCH₄ = pCH₄/P = 431 mmHg/935 mmHg = 0.461

XCO₂ = pCO₂/P = 504 mmHg/935 mmHg = 0.539

385 x 42.13 x 0.079 = 1281.38395

Answer:

6.2g of NaBr are produced

Explanation:

The reaction of HBr with NaOH occurs as follows:

HBr + NaOH → NaBr + H2O

Where 1 mole of each reactant produce 1 mole of NaBr

To solve this question we need to find the moles of each reactant using their molar mass. With moles we can find limiting reactant and the moles (And mass) of NaBr produced, as follows:

Moles HBr -Molar mass: 80.9119g/mol)-

4.9g * (1mol/80.9119g) = 0.0606 moles HBr

Moles NaOH -Molar mass: 40g/mol-

3.86g * (1mol/40g) = 0.0965 moles NaOH

As the reaction is 1:1 and the moles of HBr < Moles NaOH, the limiting reactant is HBr and moles of NaBr produced are 0.0606 moles.

The mass of NaBr (Molar mass: 102.894g/mol) is:

0.0606 moles * (102.894g/mol) =

Answer:

[tex]M_{CO_2}= 25.7g[/tex]

Explanation:

From the question we are told that:

Temperature [tex]T=27.0[/tex]

Volume [tex]V=30L[/tex]

Pressure [tex]P=0.480atm[/tex]

Generally the equation for Ideal gas is mathematically given by

PV=nRT

Therefore

[tex]n=\frac{0.480 x 30}{0.08205 x 300}[/tex]

[tex]n=0.59moles[/tex]

Generally Mass of CO2 is given as

[tex]M_{CO_2}= 0.59 * 44 g/mol[/tex]

[tex]M_{CO_2}= 25.7g[/tex]

Answer:

-800 kJ/mol

Explanation:

To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).

First, we have to calculate the moles of methane (CH₄) there are in 2.50 g of substance. For this, we divide the mass into the molecular weight Mw) of CH₄:

Mw(CH₄) = 12 g/mol C + (1 g/mol H x 4) = 16 g/mol

moles CH₄ = mass CH₄/Mw(CH₄)= 2.50 g/(16 g/mol) = 0.15625 mol CH₄

Now, we divide the heat released into the moles of CH₄ to obtain the enthalpy per mole of CH₄:

ΔHc = heat/mol CH₄ = 125 kJ/(0.15625 mol) = 800 kJ/mol

Therefore, the enthalpy of combustion of methane is -800 kJ/mol (the minus sign indicated that the heat is released).

Answer:

A) XY3

In both of the atom, they want to have 8 valence electrons on the outer shell so they can become stable.