Given the mean for six numbers is 24. If three numbers which are x, (x + 2) and (x - 2) are added into the data set, the value of mean changed to 30. Calculate the value of x.​

Answers

Answer 1

Answer:

42

Step-by-step explanation:

We know that the mean of 6 numbers is 24. This means that

[tex] \frac{x}{6} = 24[/tex]

Solve for x.

[tex]x = 144[/tex]

If we add, x, (x+2), and (x-2). We will have 9 terms. The value of mean will change to 30. This also means that

[tex] \frac{270}{9} = 30[/tex]

[tex]144 + x + (x + 2) + (x - 2) = 270[/tex]

[tex]3x + 144 = 270[/tex]

[tex]3x = 126[/tex]

[tex]x = 42[/tex]


Related Questions

Each machine at a certain factory can produce 90 units per hour. The setup cost is 20 dollars for each machine and the operating cost is 26 dollars per hour (total, not 26 dollars per machine per hour). You would like to know how many machines should be used to produce 40000 units, with the goal of minimizing production costs.
First, find a formula for the total cost in terms of the number of machines, n:_______
TC = ______
machines for a total cost of The minimum total cost is achieved when using dollars.

Answers

Answer:

a)  [tex]Total Cost=20n+\frac{(\frac{40000}{90}*26)}{n}[/tex]

b)  [tex]n=24[/tex]

Step-by-step explanation:

From the question we are told that:

Rate r=90 units per hour

Setup cost =20

Operating Cost =26

Units=40000

Generally the equation for Total cost is mathematically given by

[tex]Total Cost=20n+\frac{(\frac{40000}{90}*26)}{n}[/tex]

[tex]T_n=20n+\frac{11556}{n}\\\\T_n=\frac{20n^2+11556}{n}.....equ 1[/tex]

Differentiating

[tex]T_n'=\frac{n(40n)-(40n^2+11556)}{n_2}\\\\T_n'=\frac{20n^2-11556}{n^2}.....equ 2[/tex]

Equating equ 1 to zero

[tex]0=\frac{20n^2+11556}{n}[/tex]

[tex]n=24[/tex]

Therefore

Substituting n

For Equ 1

[tex]T_n=\frac{20(24)^2+11556}{24}[/tex]

F(n)>0  

For Equ 2

[tex]T_n'=\frac{20(24)^2-11556}{24^2}[/tex]

F(n)'<0

For each graph below, state whether it represents a function.​

Answers

Answer:

graphs 1, 2, 3, and 4, can represent a function

graphs 5 and 6 can not represent a function.

Step-by-step explanation:

If for a given graph of a relationship you can draw a vertical line that intersects the graph in more than one point, then we can conclude that the graph does not represent a function.

Now, if we look at the first four graphs, we can see that no vertical line intersects more than one point, so the first four can represent functions.

The special case here is graph number 2, where we can see a white dot right below a colored dot, and if we draw a vertical line there, the line will touch both points. But, a white dot means that the exact point does not belong to the graph, so if the line passes through there, it will not intersect the graph.

For the last two, this is not the case, in graph 5 and graph 6 we could draw vertical lines that intersect the graphs twice

(any line like x = n, with n < 0, intersects two points in graph 5, while the line x = 0 intersects twice the graph number 6)

So graph 5 and graph 6 can't represent functions.

Four students drive to school in the same car. The students claim they were late to school and missed a test because of a flat tire. On the makeup test, the instructor asks the students to identify the tire that went flat; front driver's side, front passenger's side, rear driver's side, or rear passenger's side. If the students didn't really have a flat tire and each randomly selects a tire, what is the probability that all four students select the same tire

Answers

Hence, the probability that all four students select the same tire is [tex]\frac{1}{16}[/tex].

What is the probability?

Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one.

Probability has been introduced in Maths to predict how likely events are to happen. The meaning of probability is basically the extent to which something is likely to happen.

Here given that,

Four students drive to school in the same car. The students claim they were late to school and missed a test because of a flat tire.

On the makeup test, the instructor asks the students to identify the tire that went flat; front driver's side, front passenger's side, rear driver's side, or rear passenger's side.

So, the probability of one person picking the tire is [tex]\frac{1}{4}[/tex].

Here four students so their probability is

[tex]\frac{1}{4(4)}=\frac{1}{16}[/tex]

Hence, the probability that all four students select the same tire is [tex]\frac{1}{16}[/tex].

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NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW. THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math problems. Chapter 12 part 2 PLEASE SHOW WORK!!!

4a. a_n = 2(1/3 + a_n-1), a_1 = 4

4b. a_n= n/(a_n-1), a_1 = 6

4c. 1/6, 2/3, 8/3, . . .

Answers

Problem 4a

The instructions are incomplete. You set up the recursive formula, but didn't ask any question about said formula.

I'll assume that your teacher wants you to list out a few terms. I'll list out the first five terms.

The notation a_1 = 4 is the same as writing [tex]a_1 = 4[/tex] where the '1' is a subscript. It tells us that the first term is 4.

The nth term a_n or [tex]a_n[/tex] is defined as such

[tex]a_n = 2*(1/3 + a_{n-1})\\\\[/tex]

Notice how if we replaced n with 2, then we get

[tex]a_n = 2*(1/3 + a_{n-1})\\\\a_2 = 2*(1/3 + a_{2-1})\\\\a_2 = 2*(1/3 + a_1)\\\\[/tex]

So the second term is directly tied to the first term, or it is dependent on it.

We'll replace a_1 with 4 to get the following

[tex]a_2 = 2*(1/3 + a_1)\\\\a_2 = 2*(1/3 + 4)\\\\a_2 = 2*(1/3 + 12/3)\\\\a_2 = 2*(13/3)\\\\a_2 = 26/3\\\\[/tex]

So the second term is 26/3.

As you can guess, the third term is going to be found in a similar fashion

[tex]a_n = 2*(1/3 + a_{n-1})\\\\a_3 = 2*(1/3 + a_{3-1})\\\\a_3 = 2*(1/3 + a_2)\\\\a_3 = 2*(1/3 + 26/3)\\\\a_3 = 2*(27/3)\\\\a_3 = 2*(9)\\\\a_3 = 18\\\\[/tex]

So 18 is the third term.

We'll repeat for n = 4 to get the fourth term.

[tex]a_n = 2*(1/3 + a_{n-1})\\\\a_4 = 2*(1/3 + a_{4-1})\\\\a_4 = 2*(1/3 + a_3)\\\\a_4 = 2*(1/3 + 18)\\\\a_4 = 2*(1/3 + 54/3)\\\\a_4 = 2*(55/3)\\\\a_4 = 110/3\\\\[/tex]

The fourth term is 110/3.

Lastly, we'll plug in n = 5

[tex]a_n = 2*(1/3 + a_{n-1})\\\\a_5 = 2*(1/3 + a_{5-1})\\\\a_5 = 2*(1/3 + a_4)\\\\a_5 = 2*(1/3 + 110/3)\\\\a_5 = 2*(111/3)\\\\a_5 = 2*(37)\\\\a_5 = 74\\\\[/tex]

The fifth term is 74.

Answer: The first five terms are 4, 26/3, 18, 110/3, 74

==============================================================

Problem 4b

Again, the instructions are missing. I'll assume the same thing as problem 4a.

[tex]a_1 = 6[/tex] is the first term

Plug n = 2 into the first equation to get

[tex]a_n = \frac{n}{a_{n-1}}\\\\a_2 = \frac{2}{a_{2-1}}\\\\a_2 = \frac{2}{a_{1}}\\\\a_2 = \frac{2}{6}\\\\a_2 = \frac{1}{3}\\\\[/tex]

The second term is 1/3.

Repeat for n = 3

[tex]a_n = \frac{n}{a_{n-1}}\\\\a_3 = \frac{3}{a_{3-1}}\\\\a_3 = \frac{3}{a_{2}}\\\\a_3 = \frac{3}{1/3}\\\\a_3 = 3\div\frac{1}{3}\\\\a_3 = 3\times\frac{3}{1}\\\\a_3 = 9\\\\[/tex]

The third term is 9

Repeat for n = 4.

[tex]a_n = \frac{n}{a_{n-1}}\\\\a_4 = \frac{4}{a_{4-1}}\\\\a_4 = \frac{4}{a_{3}}\\\\a_4 = \frac{4}{9}\\\\[/tex]

The fourth term is 4/9

Repeat for n = 5

[tex]a_n = \frac{n}{a_{n-1}}\\\\a_5 = \frac{5}{a_{5-1}}\\\\a_5 = \frac{5}{a_{4}}\\\\a_5 = 5 \div a_{4}\\\\a_5 = 5 \div \frac{4}{9}\\\\a_5 = 5 \times \frac{9}{4}\\\\a_5 = \frac{5}{1} \times \frac{9}{4}\\\\a_5 = \frac{5*9}{1*4}\\\\a_5 = \frac{45}{4}\\\\[/tex]

Answer: The first five terms are 6, 1/3, 9, 4/9, 45/4

==============================================================

Problem 4c

I'm not much help here for this problem. Not only are the instructions missing, but it's not clear how this sequence is set up. If I had to guess, it's somehow recursively defined. How exactly, I'm not sure. I would ask your teacher for any clarification.

I need help ASAP please and thank you

Answers

Answer:

"a" is the answer because 3x+2 can not be equal to zero

Step-by-step explanation:

Help me please
Hurry

Answers

For all questions, use the concept of angles at a point (360°).

I also suggest and recommend that you specify the questions you need help with. It is best if you don't ask your homework here, because homework should be done by you yourself.

I need help ASAP please

Answers

Answer:

5:10

6 (-2,0)

7 (-5,6)

8 (5,3)

9 No, ab=8 CD=6

Step-by-step explanation:

I need to know the answer ASAP please

Answers

By observing the points you can learn a lot about a function. Concretely [tex]f(x)[/tex] passes through [tex](1,1)[/tex] but [tex]g(x)[/tex] passes through [tex](1,-\frac{1}{2})[/tex] that should give you a hint that [tex]g(x)=-\frac{1}{2}x^2[/tex].

Hope this helps :)

90units needed 8 units per case what's the #of cases & # of additional units

Answers

Answer:

# of cases: 11

Additional units: 2

Step-by-step explanation:

If each case can hold 8 units, and we want to find the total # number of cases, we have to divide the # of units (8) for one case by the total # units (90).

As you can see, after dividing by 8, we have a total of 11 cases and a remainder of 2 units. The remainder will be the # of additional units because we cannot have another case filled with 8 units.

Can someone please do #3?❤️

Answers

Answer:

B, because it goes up by 8 until the last of because the jump from 24 to 30 is 6

As an estimation we are told £3 is €4. Convert €36 to pounds.

Answers

Answer:

€36 = 30.62 pounds sterling

Find the missing side. Round your answer to the nearest tenth please help me

Answers

9514 1404 393

Answer:

  16.9

Step-by-step explanation:

The marked sides are the hypotenuse and the one opposite the angle. The relevant trig function is ...

  Sin = Opposite/Hypotenuse

Multiplying by the hypotenuse gives an equation for the opposite side.

  x = 22·sin(50°)

  x ≈ 16.9

Wires manufactured for use in a computer system are specified to have resistances between 0.14 and 0.16 ohms. The actual measured resistances of the wires produced by company A have a normal probability distribution with mean 0.15 ohm and standard deviation 0.005 ohm. (Round your answers to four decimal places.) (a) What is the probability that a randomly selected wire from company A's production will meet the specifications

Answers

Answer:

Hence the probability that a randomly selected wire from company A's production will meet the specifications is 0.95455.

Step-by-step explanation:

a)[tex]P(0.14 < x < 0.16 ) = P[(0.14 - 0.15)/ 0.005) < (x - \mu) /\sigma < (0.16 - 0.15) / 0.005) ][/tex]

[tex]=P(0.14 < x < 0.16 ) = P[(0.14 - 0.15)/ 0.005)< ((x - 0.15) /0.005) < (0.16 - 0.15) / 0.005) ][/tex]

[tex]=P(z<\frac{0.01}{0.005} )- P(z<-\frac{0.01}{0.005})[/tex]  

Using z table,  

= 0.9773 - 0.02275  

= 0.95455.

Shahril bought a CD, 2 T-shirts and a pair of jeans for $133. Each
T-shirt cost $13 more than the CD. The pair of jeans cost $30 more
than each T-shirt. Find the cost of the CD.

Answers

Step-by-step explanation:

Let the price of CD, tshirt and jeans be x,y and z respectively.

given:

x+2y+2z=133......(i)

y=x+13.......(ii)

2z=y+30....(iii)

in eqn (iii) ,

2z=y+30

or, 2z=x+13+30

or, z=(x+43)/2....(iv)

now in eqn (i),

x+2y+2z=133

or, x+2(x+13)+2((x+43)/2) =133

or, x+2x+26+x+43=133

or, 4x=133-69

or, x= 64/4

•°• x=$16

Naomi invested $3,425 in an account that
pays 3% simple interest. what was the total
balance of the account after 15 years?

Answers

Answer:

$4,966.25

Step-by-step explanation:

3 x 15 = 45

After 15 years, Naomi would have earned a total of 45% interest rate.

3,425 x 1.45 = 4,966.25

Don't use .45 as the multiplier

3,425 x .45 = 1,541.25 <- incorrect

Answer: 4,966.25

Explanation: start by diving 3425 by .03 to get the amount of interest it is yearly giving you 102.75 and then multiply that by 15 since that’s the amount of years and get 1541.25 then add 3425 and 1541.25 together to get the final product of 4,966.25

One number is 6 less than a second number.
Twice the second number is 9 less than 5 times
the first. Find the two numbers.

Answers

Answer:

-7

Step-by-step explanation:

x = y - 6

2x = 5y - 9

Use the internet for full steps

x = -7

y = -1

I need help please IVE BEEN AT THIS FOREVER

Answers

Answer:

.3

Step-by-step explanation:

Take path A = .5

Then Path D = .6

P(a and D) = .5 *.6 = .3

3. An elevator is moving upward with a speed of 14.3 m/s . Two seconds later, the elevator is still moving upward, but its speed bas been reduced to 3.7 m/s . What is the average acceleration of the clevator during the 2.0 interval?

Answers

By definition of average acceleration,

a (average) = (3.7 m/s - 14.3 m/s) / (2.0 s) = -5.3 m/s²

If a normally distributed population has a mean (mu) that equals 100 with a standard deviation (sigma) of 18, what will be the computed z-score with a sample mean (x-bar) of 106 from a sample size of 9?

Answers

Answer:

Z = 1

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean (mu) that equals 100 with a standard deviation (sigma) of 18

[tex]\mu = 100, \sigma = 18[/tex]

Sample of 9:

This means that [tex]n = 9, s = \frac{18}{\sqrt{9}} = 6[/tex]

What will be the computed z-score with a sample mean (x-bar) of 106?

This is Z when X = 106. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{106 - 100}{6}[/tex]

[tex]Z = 1[/tex]

So Z = 1 is the answer.

5. a) Find the difference between the place values of two 5's in 95237508.​

Answers

Answer:

4999500

Step-by-step explanation:

first 5 = 5000000

second 5 = 500

difference = 5000000-500

The train station clock runs too fast and gains 5 minutes every 10 days. How many minutes and seconds will it gain in 7 days

Answers

Answer: 210 secs (3 mins, 30 secs)

Step-by-step explanation:

No of minutes gained every 10 days = 5 mins

No of minutes gained every day = 5 ÷ 10

                                                      = 0.5 min (30 secs)

Amount of time gained in 7 days = 30 secs × 7

                                                       = 210 secs (3 mins, 30 secs)

Find the function G defined by G(x) =5x+3 find G(-1)

Answers

Answer:

G(-1) = -2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Functions

Function Notation

Step-by-step explanation:

Step 1: Define

Identify

G(x) = 5x + 3

Step 2: Evaluate

Substitute in x [Function G(x)]:                                                                         G(-1) = 5(-1) + 3Multiply:                                                                                                             G(-1) = -5 + 3Add:                                                                                                                   G(-1) = -2

Answer:

G = -2

Step-by-step explanation:

Plug in -1 for x.

5(-1) + 3

-5 + 3

-2

G = -2

Which set of angles are complementary

Answers

Answer:

A. <ECF and <BCF

Step-by-step explanation:

Complementary angles are angles that add up to give 90°

m<BCE = m<BCA = 90° (right angles)

m<ECF + m<BCF = m<BCA

m<ECF + m<BCF = 90° (Substitution)

Therefore, <ECF and <BCF are complementary angles.

A bag contains 8 red balls and 3 white balls. Two balls are drawn without replacement. (Enter your probabilities as fractions.) (a) What is the probability that the second ball is white, given that the first ball is red

Answers

Answer:

12/55

Step-by-step explanation:

Probability is the ratio of the number of possible outcomes to the number of total outcomes.

Given that the bag contains 8 red balls and 3 white balls, the probability of picking a red ball

p(r) = 8/(8+3) = 8/11

Probability of picking a white ball

= 3/11

when a red ball is picked first, the total number of balls reduces to 10 hence the probability that the second ball is white, given that the first ball is red

=8/11 * 3/10

= 24/110

= 12/55

by solving a pair of linear equation X + Y is equal to 20 and x-y=10 the value of 'x' and 'y' are​

Answers

Answer:

x=15, y=5

Step-by-step explanation:

x+y=20

x-y=10

Adding both equations;

(x+x) + (y-y) = 20+10

2x = 30

x = 30/2 = 15

Substitute x=15 into x+y=20

y= 20-x = 20-15= 5

8
6
4
2
6
8
-8 -6 -4 -2 0-3
21
.
-6
-8
O A. y -[x]-2
OB. y -[x]+3
O C. y = (x) - 3
O D. y = [x]+2

Answers

The required equation of the line is y = [x]+2

From the graph shown, we can see that the line dotted points forms a straight line. We are to find the required equation of the line formed.

The formula for calculating the equation of a straight line is expressed as

y = mx+b where

m is the slope b is the y-intercept

Get the slope 'm'

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Using the coordinate points (2, 0) and (4, 2)

[tex]m=\frac{2-0}{4-2}\\m=\frac{2}{2}\\m=1[/tex]

Get the y-intercept 'b'

Substitute m = 1 and (2, 0) into y = mx+b as shown;

[tex]2=1(0)+b\\2=0+b\\b=2[/tex]

Get the required equation. Recall that y = mx+b, hence;

[tex]y = 1x + 2\\y=x+2[/tex]

Hence the required equation of the line is y = [x]+2

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Solve for x.
A. 1
B. 5
C. 3
D. 12

Answers

9514 1404 393

Answer:

  A.  1

Step-by-step explanation:

Arc AB is twice the measure of the angle ABC. The sum of the arc measures around the circle is 360°.

  2(43x)° +(272x +2)° = 360°

  358x +2 = 360 . . . . . . . . . . . . divide by °, collect terms

  358x = 358 . . . . . . . . subtract 2

  x = 1 . . . . . . . . . . divide by 358

Which values of x are solutions to this equation? -1/2x^2 + 5x = 8
A) -2
B) 2
C) -8
D) -1.5
E) 11.5
F) 8

Answers

Answer:

2, 8

Step-by-step explanation:

-1/2x^2 + 5x = 8

-x^2 + 10x = 16 (Multiplying both sides of the equation by 2)

-x^2 + 10x  - 16 = 0

x^2 - 10x + 16 = 0 (changing the signs)

x^2 -2x -8x +16 = 0

x (x-2) -8 (x-2) = 0

(x-2) (x-8)

x-2 = 0

x = 2

or

x -8 = 0

x = 8

Answer from Gauthmath

The values of x are solutions to this equation that is 2, 8

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

We are given that the equation as;

-1/2x² + 5x = 8

-x² + 10x = 16

Now Multiplying both sides of the equation by 2;

-x² + 10x  - 16 = 0

Or

x² - 10x + 16 = 0

x² -2x -8x +16 = 0

x (x-2) -8 (x-2) = 0

(x-2) (x-8)

The solution are;

x-2 = 0

x = 2

or

x -8 = 0

x = 8

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Lactation promotes a temporary loss of bone mass to provide adequate amounts of calcium for milk production. A paper gave the following data on total body bone mineral content (TBBMC) (g) for a sample both during lactation (L) and in the postweaning period (P).

Subject
1 2 3 4 5 6 7 8 9 10
L 1928 2549 2825 1924 1628 2175 2114 2621 1843 2541
P 2126 2885 2895 1942 1750 2184 2164 2626 2006 2627

Required:
a. Does data suggest that true average total body bone mineral content during postweaning exceeds that during lactation by more than 25 g? State and test the appropriate hypotheses using a significance level of 0.05. [Note: The appropriate normal probability plot shows some curvature but not enough to cast substantial doubt on a normality assumption.]

b. Calculate a lower confidence bound using a 95% confidence level for the true average difference between TBBMC during postweaning and lactation.

Answers

Answer:

- 179.981

Step-by-step explanation:

The hypothesis :

H0 : μL - μP ≥ 25

H0 : μL - μP < 25

The sample mean difference ;Xd

d = L - P

Xd = Σd/n

d = -198,-336,-70,-18,-122,-9,-50,-5,-163,-86

Xd = - 1057 / 10

Xd = - 105.7

Using calculator ;

Standard deviation of difference, Sd = 103.845

The test statistic :

T = Xd ÷ (Sd/√n)

T = -105.7 ÷ (103.845/√10)

T = - 3.219

Decision region :

Reject H0 ; If Pvalue < α

The Pvalue : df = n - 1 ; 10 - 1 = 9

Pvalue(-3.219, 9) ; two-tailed = 0.00525

Hence, reject H0

B.) The confidence interval for difference in mean :

Xd ± Tcritical[Sd/√n]

Tcritical at 95%, df = 9

Tcritical = 2.262

C.I = -105.7 ± 2.262[103.845/√10]

C.I = -105.7 ± 74.281076

Lower boundary: - 105.7 - 74.281076 = - 179.9810

A nurse works for a temporary nursing agency. The starting hourly wages for the six different work locations are $12.50, $11.75, $9.84, $17.67, $13.88, and $12.98. As the payroll clerk for the temporary nursing agency, find the median starting hourly wage.

Answers

100 dollars and 32 cents
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The Fifth Amendment protects people from having to??? Helpp mee please i need help i am stuckWhich statements are true? Check all that apply.-2.5 = -2 1/2-1.5 > -0.5-0.5 < 0-2.5 < -2- 1/2 > 1.5 plss help me with this :( A dairy needs 291 gallons of milk containing 6% butterfat. How many gallons each of milk containing 7% butterfat and milk containing 4% butterfat must be used to obtain the desired 291 gallons? After undergoing a thyroidectomy, a client is monitore parathyroid glands postoperatively. The nurse would det damage to the parathyroid glands? A. Fever B. Neck pain C. Hoarseness D. Tingling around the mouth As a person BAC level increase it becomes difficult for them to judge their vehicle distances and speed How do bacteria obtain energy to carry out their functions Long strands of genetic information are stored in ________. A. Enzymes B. Adenine C. Chromosomes D. Mutations What is the largest product that can be made from whole numbers that add up to 100? A bag contains five white balls and four black balls. Your goal is to draw two black balls. You draw two balls at random. What is the probability that they are both black anyone kind to help out? Ill brainlist u and give u 5 star plsplspls!:)1) What is the meaning behind the following propaganda created by Hitler and the Nazis? What is the total surface area of a cuboid with length 16cm, width 8cm and height 6cm? PLS HELPEvaluate the piecewise function at the indicated values from the domain If you were creating your own website, what would you include to make sure your website was reliable andvalid? Divide Rs.45000 among 2 students Mina and Rita in the ratio of marks they got 40 and 50 respectively Comparing Three Depreciation Methods Dexter Industries purchased packaging equipment on January 8 for $249,400. The equipment was expected to have a useful life of four years, or 8,800 operating hours, and a residual value of $20,600. The equipment was used for 3,080 hours during Year 1, 1,848 hours in Year 2, 2,464 hours in Year 3, and 1,408 hours in Year 4. Required: 1. Determine the amount of depreciation expense for the four years ending December 31 by (a) the straight-line method, (b) the units-of-activity method, and (c) the double-declining-balance method. Also determine the total depreciation expense for the four years by each method. Round the answer for each year to the nearest whole dollar. Depreciation Expense Year Straight-Line Method Units-of-Activity Method Double-Declining- Balance Method Year 1 $fill in the blank 1 $fill in the blank 2 $fill in the blank 3 Year 2 $fill in the blank 4 $fill in the blank 5 $fill in the blank 6 Year 3 $fill in the blank 7 $fill in the blank 8 $fill in the blank 9 Year 4 $fill in the blank 10 $fill in the blank 11 $fill in the blank 12 Total $fill in the blank 13 $fill in the blank 14 $fill in the blank 15 2. What method yields the highest depreciation expense for Year 1 An unforgettable dream Predict the reactants of this chemical reaction. That is, fill in the left side of the chemical equation. Be sure the equation you submit is balanced. (You can edit both sides of the equation to balance it, if you need to.) Note: you are writing the molecular, and not the net ionic equation.NaClO3(aq) + H2O(l) sold 72 books. if ratio of books to bookmarks is 9:2, how many bookmark was sold? Required information Skip to question [The following information applies to the questions displayed below.] Timberly Construction makes a lump-sum purchase of several assets on January 1 at a total cash price of $900,000. The estimated market values of the purchased assets are building, $508,800; land, $297,600; land improvements, $28,800; and four vehicles, $124,800. Required: 1-a. Allocate the lump-sum purchase price to the separate assets purchased. 1-b. Prepare the journal entry to record the purchase. 2. Compute the first-year depreciation expense on the building using the straight-line method, assuming a 15-year life and a $27,000 salvage value. 3. Compute the first-year depreciation expense on the land improvements assuming a five-year life and double-declining-balance depreciation.