If a rectangle has a base of 6' and a height of 4' its area would be what?
A= bxh
A= 6'x4'
A= 24 sq.ft.

Answers

Answer 1
24 sq.ft. Is the answer if not then I’m sorry

Related Questions

I need help this is confusing to me

Answers

Answer:i think it is b not really sure      

Step-by-step explanation:

If this fish tank is filled halfway, how much water will it hold?
96 cubic inches
768 cubic inches
48 cubic inches
384 cubic inches

Answers

Answer:

384 cubic inches

Step-by-step explanation:

first find the volume of the fish tank by multipying the length, width, and height.

v=lwh

 =(16in)(4in)(12in)

 = 768 cubic inches (This answer is equal to the volume of the entire fish tank, however we need to find how much water half the tank can hold. To figure this out, we need to divide 768 by 2. And you should get 384 cubic inches)

Answer:

384

Step-by-step explanation:

took the quiz

Ten samples were taken from a plating bath used in an electronics manufacturing process, and the bath pH was determined. The sample pH value are 7.91, 7.85, 6.82, 8.01, 7.46, 6.95, 7.05, 7.35, 7.25, 7.42. Manufacturing engineering believes that pH has a median value of 7.0. Do the sample data indicate that this statement is correct

Answers

Answer:

There is no sufficient evidence to support the claim.

Step-by-step explanation:

Given the data:

7.91, 7.85, 6.82, 8.01, 7.46, 6.95, 7.05, 7.35, 7.25, 7.42

Sample size, n = 10

The sample mean, xbar = ΣX/ n = 74.07 / 10 = 7.407

The sample standard deviation, s = 0.41158 ( from calculator)

The hypothesis :

H0 : μ = 7

H0 : μ ≠ 7

The test statistic :

(xbar - μ) ÷ (s/√(n))

(7.047 - 7) ÷ (0.41158/√(10))

0.047 / 0.1301530

Test statistic = 0.361

Testing the hypothesis at α = 0.05

The Pvalue ;

df = n - 1 ; 10 - 1 = 9

Two tailed test

Pvalue(0.361, 9) = 0.7263

Since the Pvalue > α ; we fail to reject the Null and conclude that there isn't sufficient evidence to support the claim.

The length of a rectangle is 7 inches
more inan its width. the area of
the rectangle is eqaul to 4 inches less
than 4 times the perimeter. Find the
length and width of the rectangle

Answers

Answer:

length = 20 inches

width = 13 inches

Step-by-step explanation:

l = length

w = width

area = l×w

perimeter = (2×l) + (2×w)

l = w + 7

l×w = 4×(2×l + 2×w) - 4

(w+7)×w = 4×(2×(w+7) + 2×w) - 4

w² + 7w = 4×(2w + 14 + 2w) - 4

w² + 7w = 8w + 56 + 8w - 4 = 16w + 52

w² - 9w - 52 = 0

the solution for a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

here we use now w instead of x.

and a=1

b=-9

c=-52

w = (9 ± sqrt(81 - -208))/2 = (9 ± sqrt(81+208))/2 =

= (9 ± sqrt(289))/2 = (9 ± 17)/2

w1 = (9+17)/2 = 26/2 = 13

w2 = (9-17)/2 = -8/2 = -4

and a negative length does not make any sense for a geometric shape.

so, only w1 = 13 applies.

l = w + 7 = 13 + 7 = 20

write your answer as an integer or as a decimal rounded to the nearest tenth​

Answers

Answer:

Step-by-step explanation:

CE and are the sides making up the sine of an angle.

CE is the side opposite the angle

DE is the side hypotenuse.

<D = 61 degrees

Sin(D) = opposite / hypotenuse

hypotenuse = 8

Sin(61) = 0.8746

CE = ?

sin(61) = CE / 8                multiply both sides  by 8

8 sin(61) = CE

CE = 8 * 0.8746

CE = 6.9969

CE = 7.0

That 0 should be included in the answer, but I think it is safe to say that if you enter 7, you will get it right.

Answer:

7.0

Step-by-step explanation:

What is the maximum of f(x)= sin(x)?

-2π
-1
1

Answers

Answer:

1

Step-by-step explanation:

the maximum of f(X)=sin(X) is 1


Which expression is the best estimate of the product of 7/8and 8 1/10?

Answers

Answer:

7 7/80 or 7.0875

Step-by-step explanation:

product is the result of multiplication

7/8 * 81/10 = 567/80 = 7 7/80 or 7.0875

Pls if anyone knows the answer that will be greatly appreciated :)

Answers

Answers:

The areas from left to right are:  13 m^2, 49 m^2, 24 m^2, 14 m^2

The largest area occurs when the rectangle is a square

===========================================================

Explanation:

The area rectangle formula is base*height, or length*width, whichever you prefer.

From left to right, we have these areas:

1*13 = 13 m^27*7 = 49 m^212*2 = 24 m^25*9 = 14 m^2

We get the largest area (49 m^2) when the figure is a square. This happens with any problem in which we have a fixed amount of fencing and we want to max out the area. So it's not particular to this specific problem only.

Why a square? Well an informal way to think of it would be to consider that as one dimension goes up, the other goes down, and vice versa. Think of it like a see-saw. As the examples show, if one dimension is particularly large, then its area wont be as big compared to when the dimensions are closer together. It's only when all dimensions are equal is when we max the area out entirely.

I am sry but he has don wrong calculation the answer is last one 9*5=45m and its the answer.

and the noticiable thing is the larger the shape is the area increases.

what’s the formula to find the shaded area?

Answers

shaded area = area of outer figure - area of inner figure........

Answer:

Shaded area = 123.84

Step-by-step explanation:

Shaded area = 576 - 452.16

Shaded area = 123.84

How many mL of a 10% magnesium sulfate solution will contain 14 grams of magnesium sulfate?

Answers

Answer:

Upto 40 g or 160 mmols

Step-by-step explanation:

Can you plz mark me as brainliest?

Answer:

140 mL

Step-by-step explanation:

10% of 140 is 14

(b) How much the selling price should be fixed for pulse bought for Rs.70 per kg. to earn a profit of Rs.6 after allowing a 5 % discount?

Answers

Answer:

Rs. 80

Step-by-step explanation:

Given that :

Purchase price = 70

Profit = 6

Discount = 5%

Let selling price = x

Selling price * (1 - discount) = (purchase price + profit)

x * (1 - 5%) = (70 + 6)

x * (1 - 0.05) = 76

x * 0.95 = 76

0.95x = 76

x = 76 / 0.95

x = 80

Hence, selling price = Rs. 80

Evaluate.

(n - 1)!, where n = 3
2
5
6

Answers

(n-1) where n= 3

Answer is 2

(n - 1)!

n = 3

( 3 - 1)!

2!

= 1 × 2

= 2

n = 2

(2 - 1)!

1!

= 1

n = 5

(5 - 1)!

4!

= 1 × 2 × 3 × 4

= 24

n = 6

(6 - 1)!

5!

= 1 × 2 × 3 × 4 × 5

= 120

Answered by Gauthmath must click thanks and mark brainliest

It is estimated that t months from now, the population of a certain town will be changing at the rate of 4+ 5t^2/3 people per month. If the current population is 10,000, what will the population be 8 months from now?

Answers

Answer:

240000

Step-by-step explanation:

Represent the exponential equation.

[tex]10000 (5 {t}^{ \frac{2}{3} } + 4) = [/tex]

Replace 8 with t

[tex]10000(5(8) {}^{ \frac{2}{3} } + 4)[/tex]

[tex]10000(5 \times 4 + 4) [/tex]

[tex]10000(24) = 240000[/tex]

The population of the town after 8 month will be 2,40,000.

What is exponential growth?

Exponential growth is a pattern of data that shows greater increases with passing time, creating the curve of an exponential function.

Let P be the population of the town after 8 months

According to the given question

The current population of the town = 10,000.

Also, the population of the town is changing at the rate of [tex]4+5t^{\frac{2}{3} }[/tex].

Therefore, the population of the town after 8 month is given by the exponential function

[tex]P = 10000(4+5t^{\frac{2}{3} } )[/tex]

Substitute t =8 in the above equation

⇒[tex]P = 10000(4 + 5(8)^{\frac{2}{3} } )[/tex]

⇒[tex]P = 10000(4 + 5(2^{3}) ^{\frac{2}{3} } )[/tex]

⇒[tex]P = 10000(4+5(4))[/tex]

⇒[tex]P = 10000(24)[/tex]

⇒[tex]P = 240000[/tex]

Hence, the population of the town after 8 month will be 2,40,000.

Find out more information about exponential growth here:

https://brainly.com/question/11487261

#SPJ2

if f(x)=3x²-7 and f(x+n)=3x²+24x+41, what is the value of n?

Answers

Answer:

n=4

Step-by-step explanation:

f(x+n)=3(x+n)^2-7=3x^2+24x+41

3x^2+3n^2+6xn-7=3x^2+24x+41

Comparing and we will get, n=4

Using the diagram, which of the following choices represent alternate exterior angles

Answers

Answer:

A

Step-by-step explanation:

The answer is choice A.

The two angles are alternate exterior angles of lines LG and KH cut by transversal JF.

I need help completing this problem ASAP

Answers

4/(√x - √(x - 2)) × (√x + √(x - 2))/(√x + √(x - 2))

= 4 (√x + √(x - 2)) / ((√x)² - (√(x - 2))²)

= 4 (√x + √(x - 2)) / (x - (x - 2))

= 4 (√x + √(x - 2)) / (x - x + 2)

= 4 (√x + √(x - 2)) / 2

= 2 (√x + √(x - 2))

Two boats are travelling at 30 miles/hr, the first going north and the second going east. The second crosses the path of the first 10 minutes after the first one was there. At what rate is their distance increasing when the second has gone 10 miles beyond the crossing point

Answers

Answer:

their distance is increasing at the rate of 41.6 miles/hr

Step-by-step explanation:

Given the data in the question;

first we determine the distance travelled by the first boat in 10 min when the second boat was crossing its path;

⇒ ( 30/60 ) × 10 = 5 miles

so as illustrated in the diagram below;

y² = x² + ( x + 5 )²

2y[tex]\frac{dy}{dt}[/tex] = 2x[tex]\frac{dx}{dt}[/tex] + 2(x+5)[tex]\frac{dx}{dt}[/tex]

y[tex]\frac{dy}{dt}[/tex] = ( 2x + 5 ) ][tex]\frac{dx}{dt}[/tex]

[tex]\frac{dy}{dt}[/tex] = [( 2x + 5 )/y ][tex]\frac{dx}{dt}[/tex]   ------ let this be equation 1

Now, given that, [tex]\frac{dx}{dt}[/tex]  = 30 miles/hr, when x = 10

so

y = √( 10² + 15² ) = √325

so from equation 1

[tex]\frac{dy}{dt}[/tex] = [( 2x + 5 )/y ][tex]\frac{dx}{dt}[/tex]

we substitute

[tex]\frac{dy}{dt}[/tex] = [( 2(10) + 5 ) / √325 ]30

[tex]\frac{dy}{dt}[/tex] = [ 25 / √325 ] × 30

[tex]\frac{dy}{dt}[/tex] = 41.6 miles/hr

Therefore, their distance is increasing at the rate of 41.6 miles/hr

Find area of shaded region

Answers

Answer:

ayyyy i go to RSM too? Which location r u at? ANyways the answer is

I need help on this problem​

Answers

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

(a) The graph is scaled by a factor of 2, and shifted up 1 unit. The scaling moves each point away from the x-axis by a factor of 2. The points on the x-axis stay there. The translation moves that scaled figure up 1 unit.

__

(b) The graph is reflected across the x-axis and shifted right 4 units. The point on the x-axis stays on the x-axis.

a train left town at 9:15am it arrived at 2:15 at an average speed of24km/h, how many km does it cover.​

Answers

Answer:

168 km

Step-by-step explanation:

24*7 is equal to 168 km

Please help I will mark brainliest to who ever is rigjt

Answers

Answer:

(1,0) and (0,4)

Step-by-step explanation:

Crosses the x axis

When f(x) will cross the x axis, the y coordinate will turn 0, so 0=-5^(x)+5, 5=5^(x) Which is possible when x=1. So (1,0)

Crosses the y axis

When f(x) will cross the y axis, the x coordinate will turn 0, so f(0)=-5^(0)+5, f(0)=-1+5=4. So (0,4)

find the value of the trigonometric ratio​

Answers

Answer:

15÷39

Step-by-step explanation:

I hope it will help you

cos x = adjacent÷ hypotenuse

cos x =15÷39

cos x = 5÷13

9. What is m JKM? A 28° C 90° B 58.5° D 117°​

Answers

Step-by-step explanation:

her it Go i think it is helpful for u

square root of 12321 by prime factorization

Answers

12321-3x3x37x37

(3)^2×(37)^2

square root = 3×37=111

Hope it helps you..!!

Help please!!!
I need this assignment done today

Answers

Answer:

x- 1

y-5

z-3

Step-by-step explanation:

all u have to do is calculate the distance, so for example y is 5 because - -4 -3 -2 -1 0 1 and that is a 5 number distance

X-1
Y-5
Z-3
Those should be the answers

A number increase by three is two more twice the number.find the number.​

Answers

Answer:

1

Step-by-step explanation:

1 increased by 3=1+3=4

Twice of 1=1+1=2

4 is two more than 2.

Therefore, the number=1

help with 27 please. thanks​

Answers

Answer:

See Below.

Step-by-step explanation:

We are given the function:

[tex]\displaystyle y=\sqrt{\sin x}[/tex]

And we want to show that:

[tex]\displaystyle 4y^3\frac{d^2y}{dx^2}+y^4+1=0[/tex]

Find the first derivative of y using the chain rule:

[tex]\displaystyle \frac{dy}{dx} = \frac{1}{2\sqrt{\sin x}}\cdot \cos x = \frac{\cos x}{2\sqrt{\sin x}}[/tex]

And find the second derivative using the quotient and chain rules:

[tex]\displaystyle \begin{aligned} \frac{d^2y}{dx^2} &= \frac{1}{2}\left(\frac{(\cos x)'(\sqrt{\sin x})-(\cos x)(\sqrt{\sin x})'}{(\sqrt{\sin x})^2}\right) \\ \\ &=\frac{1}{2}\left(\frac{-\sin x\sqrt{\sin x} - \left(\cos x\right) \left (\dfrac{\cos x}{2\sqrt{\sin x}}\right)}{\sin x}\right) \\ \\ & = \frac{1}{2}\left(\frac{ -\sin x(2\sin x) -\cos x(\cos x) }{\sin x \left(2\sqrt{\sin x}\right) }\right) \\ \\ &= -\frac{1}{2} \left(\frac{2\sin^2 x + \cos^2 x}{2\sin^{{}^{3}\!/\! {}_{2}}x}\right)\end{aligned}[/tex]

Find y³:

[tex]\displaystyle y^3 = \left((\sin x)^{{}^{1}\!/\!{}_{2}}\right) ^3= \sin^{{}^{3}\! / \! {}_{2} }x[/tex]

And find y⁴:

[tex]\displaystyle y^4 = \left((\sin x)^{{}^{1}\!/\!{}_{2}}\right)^4 = \sin^2 x[/tex]

Substitute:

[tex]\displaystyle 4\left( \sin^{{}^{3}\! / \! {}_{2} }x\right)\left(-\frac{1}{2}\left(\frac{2\sin ^2x + \cos ^2 x}{2\sin^{{}^{3}\!/ \! {}_{2}}x}\right)\right)+\left(\sin ^2 x\right) + 1= 0[/tex]

Simplify:

[tex]-\left(2\sin^2 x + \cos^2 x\right) + \sin ^2 x + 1=0[/tex]

Distribute:

[tex]-2\sin ^2 x - \cos^2 x + \sin ^2 x + 1=0[/tex]

Simplify:

[tex]-\sin ^2 x - \cos^2 x + 1= 0[/tex]

Factor:

[tex]-(\sin ^2 x + \cos^2 x ) + 1=0[/tex]

Pythagorean Identity:

[tex]-(1)+1=0\stackrel{\checkmark}{=}0[/tex]

Q.E.D.

What percentage of area is above the mean on a normal curve?
Group of answer choices

34%

68%

97.35%

50%

Answers

Answer:

z=0

50%

Step-by-step explanation:

Find the missing side lengths. Leave your answers as radicals in simplest form.

Answers

Answer:

Step-by-step explanation:

For the question 1:

The given is a special right triangle with angle measures of

90-60-30 and side lengths represented by :

a - a[tex]\sqrt{3}[/tex] and 2a

The side length that sees 90 degrees is represented with a

The side length that sees 60 degrees is represented with a[tex]\sqrt{3}[/tex]

The side length that sees 30 degrees is represented with 2a

Here the side length that sees angle measure 60 is given as [tex]\sqrt{6}[/tex]

so a[tex]\sqrt{3}[/tex] =  [tex]\sqrt{6}[/tex] to find the value of a we divide  [tex]\sqrt{6}[/tex] with [tex]\sqrt{3}[/tex]

[tex]\frac{\sqrt{6} }{\sqrt{3} }[/tex] = [tex]\sqrt{2}[/tex]

so y = [tex]\sqrt{2}[/tex] and x = 2[tex]\sqrt{2}[/tex]

for second question

the square value of hypotenuse is equal to sum of other two side length's square value

10^2 + 6^2 = x^2

100 + 36 = x^2

136 = x^2

[tex]\sqrt{136}[/tex] = x

Given the numbers 30 and 45, find the common factors of the two numbers.​​

Answers

Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30

Factors of 45: 1, 3, 5, 9, 15, 45

The common factors between the two numbers are 1, 3, 5, 15.

Hope this helps!

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