If you lose yellow from your printer, what would happen to the picture?

Answer:

They have different words

Explanation:

I hope it helps choose me the brainest

Answer:

factors such as low literacy and income level Geographical restriction lack of motivation motivation of the technology lack of motivation to use technology and digital illiteracy and contribute to the digital device

Answer:

d. ask customers to respond to a brief survey of their attitudes regarding life insurance.

Explanation:

A life insurance policy can be defined as a contract between a policyholder and an insurer, in which the insurer agrees to pay an amount of money to a specific beneficiary either upon the death of the insured person (decedent) or after a set period of time.

A salesperson (sales representative) refers to an individual or employee who is saddled with the responsibility of taking orders from customers, as well as selling finished goods and services to consumers or end users.

A foot-in-the-door phenomenon can be defined as a compliance (persuasive) technique or tactics that assumes a person agreeing to perform a small request increases the likelihood of he or she agreeing to a subsequent larger request. Thus, it posits that when a person agrees to a small, it makes it difficult for him or her to decline a second, larger (bigger) request.

In this context, a life insurance salesperson who takes advantage of the foot-in-the-door phenomenon would most likely ask his or her customers to respond to a brief survey of their attitudes regarding life insurance.

Answer:

Explanation:

The following program is written in Java. The main method asks the user to enter 10 different integer values. These values are saved to an integer array and passed to the SelectionSortDescendTrace() method. This method sorts the array in descending order while printing the entire array after every outer loop cycle. The program was tested and the output can be seen in the attached image below.

import java.util.*;

class Brainly {

   // Main Method

   public static void main(String[] args)

   {

       Scanner in = new Scanner(System.in);

       int[] myArr = new int[10];

       for (int i = 0; i < 10; i++) {

           System.out.print("Enter an integer: ");

           myArr[i] = in.nextInt();

           System.out.print('\n');

       }

       SelectionSortDescendTrace(myArr);

   }

   public static void SelectionSortDescendTrace(int[] myArr) {

       int temp;

       for (int i = 0; i < myArr.length; i++)

       {

           for (int j = 0; j <myArr.length; j++)

           {

               if (j != myArr.length - 1)

               {

                   if (myArr[j] < myArr[j + 1])

                   {

                       temp = myArr[j];

                       myArr[j] = myArr[j + 1];

                       myArr[j + 1] = temp;

                   }

               }

           }

           System.out.println(Arrays.toString(myArr));

       }

   }

}

Answer:

please mark brillient

Answer:

So we can maintain high quality designs at any graphic scale.

Explanation:

Unlike other graphic formats which simply define colors for fixed pixels, vector graphics define points and shapes (vectors) which are then used to draw the graphic at the desired and appropriate resolution.

Our graphic can look good at any resolution, no matter how large it gets. If we take a png or jpg file and make it extremely large, you'll notice the image begins to get blurry, because the pixels are being stretched and colors are being predicted or matched for the larger scale.

Answer: True

Explanation:

Chassis intrusion detection is simply a vital security feature which is used typically by large corporate networks. It's simply an intrusion detection method which can be used in alerting a system administrator when there's a situation whereby a person opens a computer case which can then be investigated in order to know if the computer hardware has been tampered with.

It should also be noted that the chassis intrusion detection can then be either enabled or disabled in the BIOS setup utility if a BIOS comes equipped with this feature.

The correct option is True.

Answer:

The program in Python is as follows:

current_price = int(input("Current Price: "))

last_price = int(input("Last Month Price: "))

change = current_price - last_price

mortgage = (current_price * 0.051) / 12

print('Change: {:.2f} '.format(change))

print('Mortgage: {:.2f}'.format(mortgage))

Explanation:

This gets input for current price

current_price = int(input("Current Price: "))

This gets input for last month price

last_price = int(input("Last Month Price: "))

This calculates the price change

change = current_price - last_price

This calculates the mortgage

mortgage = (current_price * 0.051) / 12

This prints the calculated change

print('Change: {:.2f} '.format(change))

This prints the calculated monthly mortgage

print('Mortgage: {:.2f}'.format(mortgage))

Answer:

current_price = int(input())

last_months_price = int(input())

change = current_price - last_months_price

mortgage = current_price * 0.051 / 12

print('This house is $', end= '')

print(current_price, end= '. ')

print('The change is $', end= '')

print(change, end= ' ')

print('since last month.')

print('The estimated monthly mortgage is $', end= '')

print(mortgage, end='0.\n')

Answer:

With that in mind, let's take a look at five places where hard drives shine.

Backups and Archives. ...

Media Libraries. ...

Large Capacity Storage. ...

NAS Drives and Security. ...

RAID Arrays. ...

Other Uses.

Answer:

Using LinkedIn automation tools to run successful outreach campaigns has become popular. It’s because these tools automate tedious networking tasks such as visiting profiles, collecting data, sending out bulk connection requests, messages, and follow-ups, etc.  

With the help of the latest LinkedIn automation tools, you can quickly perform all the repetitive tasks while saving yourself a lot of time that you can use on actual relationship building and lead nurturing tasks.  

However, LinkedIn isn’t really amused when using any bots or automation tools for LinkedIn.

Answer:

Code:

#include<bits/stdc++.h>

using namespace std;  

char* prt_bin( int value, int length, char s[]){

   for(int i=(length-1); i>=0; i--){

     if((value>>i)&1) {

       s[length-1-i] = '1';  

       // putchar('1');

     }

     else {

       s[length-1-i] = '0';  

       // putchar('0');

     }

   }

   s[length] = '\0';

   return s;

}  

int main(){

     int nbits = 8, c, acc;

     char s[nbits+1];

    int multiplicand, multiplier, mq, mdr;  

   cout<<"Multiplicand: ";

   cin>>multiplicand;

   cout<<"Multiplier: ";

   cin>>multiplier;

    if(multiplier<0 || multiplier>255 ||multiplicand<0 || multiplicand>255){

    cout<<"Given Multiplicand or multiplier is incorrect. Exiting the program.\n";

       return 0;

   }  

   c = 0; acc = 0;

      cout<<"c and acc set to 0\n";

   mq = multiplier;

   mdr = multiplicand;

   cout<<"mq set to multiplier = "<<multiplier<<" decimal and "<<prt_bin(multiplier, nbits, s)<<" binary\n";

   cout<<"mdr set to multiplicand = "<<multiplicand<<" decimal and "<<prt_bin(multiplicand, nbits, s)<<" binary\n";

   printf("---------------------------------------------------\n");

    for(int i=1;i<=nbits;i++){

       printf("step %d: %d %s ",i, c, prt_bin(acc, nbits, s));

       printf("%s\n",prt_bin(mq, nbits, s));

       char lsb = s[nbits-1];  

       if(lsb=='1'){  

           printf("     + %c %s    ^add based on lsb=%c\n", c, prt_bin(mdr, nbits, s), lsb);

           printf("      ----------\n");

           acc = acc + multiplicand;

       }  

       else{

           printf("     + %c %s    ^no add based on lsb=%c\n", c, prt_bin(0, nbits, s), lsb);

           printf("      ----------\n");

       }  

       printf("      %d %s ", c, prt_bin(acc, nbits, s));

       printf("%s\n",prt_bin(mq, nbits, s));  

       printf("     >>          shift right\n");  

       mq = mq>>1;  

       if(acc%2==1){

           mq = mq+128;

       }  

       acc = acc>>1;  

       printf("      %d %s ", c, prt_bin(acc, nbits, s));

       printf("%s\n",prt_bin(mq, nbits, s));  

       printf("---------------------------------------------------\n");

   }  

   char sr[nbits*2+1];  

   printf("check:              binary   decimal\n");

   printf("                 %s        %d\n", prt_bin(multiplicand, nbits, s), multiplicand);

   printf("       x         %s  x     %d\n", prt_bin(multiplier, nbits, s), multiplier);

   printf("          ----------------    ------\n");

   printf("          %s      %d\n", prt_bin(multiplier*multiplicand, nbits*2, sr), multiplier*multiplicand);

   return 0;

}

Answer:

for the 5 segments, the utilization is 3.8%

Explanation:

Given the data in the question;

segment size = 1090 bytes

Receiver window size = 5,718 bytes

Link transmission rate or Bandwidth = 26 Mbps = 26 × 10⁶ bps

propagation delay = 22.1 ms

so,

Round trip time = 2 × propagation delay = 2 × 22.1 ms = 44.2 ms

we determine the total segments;

Total segments = Receiver window size / sender segment or segment size

we substitute

Total segments = 5718 bytes / 1090 bytes

Total segments = 5.24587 ≈ 5

Next is the throughput

Throughput = Segment / Round trip

Throughput = 1090 bytes / 44.2 ms

1byte = 8 bits and 1ms = 10⁻³ s

Throughput = ( 1090 × 8 )bits / ( 44.2 × 10⁻³ )s

Throughput = 8720 bits / ( 44.2 × 10⁻³ s )

Throughput = 197.285 × 10³ bps

Now Utilization will be;

Utilization = Throughput / Bandwidth

we substitute

Utilization = ( 197.285 × 10³ bps ) / ( 26 × 10⁶ bps )

Utilization = 0.0076

Utilization is percentage will be ( 0.0076 × 100)% = 0.76%

∴ Over all utilization for the 5 segments will be;

⇒ 5 × 0.76% = 3.8%

Therefore, for the 5 segments, the utilization is 3.8%

Answer:

CryptArithmetic or verbal arithmetic is a class of mathematical puzzles in which the digits are replaced by letters of the alphabet or other symbols. Usually it is required that each letter would be replaced by a unique digit. Each letter having different value from the other letters.

Explanation:

Cryptarithm now denotes mathematical problems usually calling for addition, subtraction, multiplication, or division and replacement of the digits by letters of the alphabet or some other symbols. ... Since D × B has only one digit, B must be 3 or less. The only two possibilities are 0 and 2.

Answer:

i) Total time = 2457.73 secs

ii) BDP = 0.01 Mbyte

Explanation:

Packet size : 2 Kb = ( 2 * 8192 ) bits = 16384 bits

Bandwidth : 2Mbps = 2,000,000 bits/sec

RTT = 50 ms = 0.050 secs

i) Determine total time required to transfer 500 kB

= Initial handshake + Time for transmission of all files + propagation delay

= 2 x RTT +  Time for transmission + RTT /2

Total time = ( 2 * 0.05 ) +  (1500 * 1.6384 )+ ( 0.050 / 2 ) = 2457.73 secs

ii) Determine the Bandwidth-delay product

= data link capacity * RTT

= 2 Mbps  * 50 ms =  100,000 =  0.01 MByte

Answer:

A good identifier for a variable that will be used to hold an employee’s phone number is:

a. EmployeePhoneNumber

Explanation:

An identifier is a string that uniquely identifies or names the entity or an object.  The object or entity may be a constant, variable, structure, function, etc. Identifiers can be formed from uppercase and lowercase letters, digits, and underscores.  Meaningful identifiers mostly favor the use of long descriptive names like EmployeePhoneNumber.  However, the other options can still be used.

Answer:

The answer is D.

Explanation:

because the other answers doesn't make sense.

Answer:

os, operating system is very important

int main {

//variables

unsigned long num = 0;

std::string phrase = " Please enter your name for confirmation: " ;

std::string name;

//codes

std::cout << phrase;

std::cin>> name;

while ( serial.available() == 0 ) {

num++;

};

if ( serial.avaliable() > 0 ) {

std::cout << " Thank you for your confirmation ";

};

};

Answer:

ABC Company

The action to take is to:

Delete the .(root) zone from the DNS2.  Then configure conditional forwarding on the DNS2 server.  If this is not done, the users will be unable to access the internet.

Explanation:

DNS forwarding enables DNS queries to be forwarded to a designated server, say DNS2, for resolution according to the DNS domain name.  This stops the initial server, DNS1, that was contacted by the client from handling the query, thereby improving the network's performance and resilience and enabling the users to be connected to the DNS2 in order to access the internet.

Answer:

Replace /* Your solution goes here */ with the following expression

accelGravity = (G * M) / (distCenter *distCenter );

Explanation:

Required

Complete the code

The equivalent expression of (G * M) / (d^2) is:

(G * M) / (distCenter *distCenter );

The expression must be stored in accelGravity.

So, we have:

accelGravity = (G * M) / (distCenter *distCenter );

Answer:

the smallest number start with the first number of the alphabet

Answer:

The function is as follows:

def square_list(myList):

   for i in range(len(myList)):

       myList[i] = myList[i]**2

   print(myList)

Explanation:

This defines the function

def square_list(myList):

This iterates through the list elements

   for i in range(len(myList)):

This squares each list element

       myList[i] = myList[i]**2

This prints the mutated list

   print(myList)

Answer:

it is your answer

Explanation:

it is the storage space where data is kept.

Answer:

Option A (CRL) is the right answer.

Explanation:

Other given choices are not connected to the given scenario. So Option A is the right one.

Answer:

Three basic functions of language: Informative, Expressive, and Directive Language

Answer and Explanation:

Using JavaScript:

/* program should take N input which represents the dollar amount and output how many chocolate bars and how many coupons we have*/

function chocolatebar(dollars){

var dollaramt= dollars;

var i;

for(i=0; i <= dollaramt; i++){

i=i+6

?

Alert ("you have 1 extra chocolate bar");

:

Alert ("keep buying chocolate bars to get more coupons for a bonus chocolate bar")

}

}

*

Answer:

A Tool

Explanation:

Tools are computer programs that make it simple to use and benefit from techniques while adhering to the overall development methodology's guidelines. The correct option is A).

A computer-aided software development case tool is a piece of software that aids in the design and development of information systems. It can be used to document a database structure and provide invaluable assistance in maintaining design consistency.

A computer software application is one that is developed to assist a particular organizational function or process, such as payroll systems, market analysis, and inventory control.

The goal of introducing case tools is to reduce the time and cost of software development, while also improving the quality of the systems created.

Therefore, the correct option is A) Tools.

To learn more about computer programs, refer to the below link:

https://brainly.com/question/9963733

#SPJ2

The question is incomplete. Your most probably complete question is given below:

A) Tools

B) Techniques

C) Data flow

D) Methodologies

Answer:

Code:-  

# function to print the pattern

def draw_triangle(n, num):

   # base case

   if (n == 0):

       return;

   print_space(n - 1);

   print_asterisk(num - n + 1);

   print("");

   # recursively calling pattern()

   pattern(n - 1, num);

# function to print spaces

def print_space(space):

   # base case

   if (space == 0):

       return;

   print(" ", end = "");

   # recursively calling print_space()

   print_space(space - 1);

# function to print asterisks

def print_asterisk(asterisk):

   # base case

   if(asterisk == 0):

       return;

   print("* ", end = "");

   # recursively calling asterisk()

   print_asterisk(asterisk - 1);

# Driver Code

n = 19;

draw_triangle(n, n);

Output:-  

# Driver Code n = 19;| draw_triangle(n, n);

Answer:

#include <iostream>

using namespace std;

struct entry

{

int number;

entry* next;

};

void orderedInsert(entry** head_ref,entry* new_node);

void init_node(entry *head,int n)

{

head->number = n;

head->next =NULL;

}

void insert(struct entry **head, int n)

{

entry *nNode = new entry;

nNode->number = n;

nNode->next = *head;

*head = nNode;

}

entry *searchNode(entry *head, int n)

{

entry *curr = head;

while(curr)

{

if(curr->number == n)

return curr;

curr = curr->next;

}

}

bool delNode(entry **head, entry *ptrDel)

{

entry *curr = *head;

if(ptrDel == *head)

{

*head = curr->next;

delete ptrDel;

return true;

}

while(curr)

{

if(curr->next == ptrDel)

{

curr->next = ptrDel->next;

delete ptrDel;

return true;

}

curr = curr->next;

}

return false;

}

void display(struct entry *head)

{

entry *list = head;

while(list!=NULL)

{

cout << list->number << " ";

list = list->next;

}

cout << endl;

cout << endl;

}

//Define the function to sort the list.

void insertionSort(struct entry **h_ref)

{

// Initialize the list

struct entry *ordered = NULL;

// Insert node to sorted list.

struct entry *current = *h_ref;

while (current != NULL)

{

struct entry *next = current->next;

// insert current in the ordered list

orderedInsert(&ordered, current);

// Update current

current = next;

}

// Update the list.

*h_ref = ordered;

}

//Define the function to insert and traverse the ordered list

void orderedInsert(struct entry** h_ref, struct entry* n_node)

{

struct entry* current;

/* Check for the head end */

if (*h_ref == NULL || (*h_ref)->number >= n_node->number)

{

n_node->next = *h_ref;

*h_ref = n_node;

}

else

{

//search the node before insertion

current = *h_ref;

while (current->next!=NULL &&

current->next->number < n_node->number)

{

current = current->next;

}

//Adjust the next node.

n_node->next = current->next;

current->next = n_node;

}

}

int main()

{

//Define the structure and variables.

char ch;int i=0;

entry *newHead;

entry *head = new entry;

entry *ptr;

entry *ptrDelete;

//Use do while loop to countinue in program.

do

{

//Define the variables

int n;

int s;

int item;

char choice;

//Accept the user choice

cout<<"Enter your choice:"<<endl;

cout<<"a. Add a number"<<endl

<<"b. Delete a number"<<endl

<<"c. Search for a number"<<endl

<<"d. Display the whole list of numbers"<<endl;

cin>>choice;

//Check the choice.

switch(choice)

{

//Insert an item in the list.

case 'a' :

// cin>>item;

cout<<"Enter the element:"<<endl;

cin>>item;

//To insert the first element

if(i==0)

init_node(head,item);

//To insert remaining element.

else

{

ptr = searchNode(head,item);

//Check for Duplicate data item.

if(ptr==NULL)

{

insert(&head,item);

}

else

{

cout<<"Duplicate data items not allowed";

cout<<endl<<"EnterAgain"<<endl;

cin>>item;

insert(&head,item);

}

}

insertionSort(&head);

i=i+1;

break;

//Delete the item from the list

case 'b' :

int numDel;

cout<<"Enter the number to be deleted :"<<endl;

cin>>numDel;

//Locate the node.

ptrDelete = searchNode(head,numDel);

if(ptrDelete==NULL)

cout<<"Element not found";

else

{

if(delNode(&head,ptrDelete))

cout << "Node "<< numDel << " deleted!\n";

}

break;

//Serach the item in the list.

case 'c' :

cout<<"Enter the element to be searched :";

cout<<endl;

cin>>s;

ptr = searchNode(head,s);

if(ptr==NULL)

cout<<"Element not found";

else

cout<<"Element found";

break;

//Display the list.

case 'd' :

display(head);

break;

default :

cout << "Invalid choice" << endl;

break;

}

//Ask user to run the program again

cout<<endl<<"Enter y to countinue: ";

cin>>ch;

}while(ch=='y'||ch=='Y');

return 0;

}

output:

Solution :

It is given that I am using a microcomputer at home along with  DSL modem as well as a telephone network for the internet. My company has internet and has local area network and also a mainframe network.

Therefore, the different network connections involved are :