Answer:
yes
Step-by-step explanation:
o
Nine Increased by the product of a number and 4 is greater than or equal to -15
Use the variable y for the unknown number
Answer:
9+4y ≥ -15
y ≥ -6
Step-by-step explanation:
Nine Increased by the product of a number
9+4y
is greater than or equal to -15
9+4y ≥ -15
Subtract 9 from each side
9-9+4y ≥ -15-9
4y ≥ -24
Divide by 4
4y/4 ≥ -24/4
y ≥ -6
Cahrlotte is 19/5 YEARS YONGER THAN RACHEL. 2 YEARS LATER, RACHEL WILL BE THRICE AS OLD AS CHARLOTTE. FIND THEIR AGES SFTER 3 YEARS. (ESTAMATE THE AGE TO THE NEAREST WHOLE NUMBER).
Answer:
Step-by-step explanation:
Charlotte starts at 19 years old.
Rachel starts at 24 years old.
Then two years later, Rachel is 26 and Charlotte is 21. This is not 3 times Charlotte's age.
Do you have all the right info?
Am I right? Please help me out
Answer:
[tex]\cos(\theta) = -\frac{\sqrt{17}}{6}[/tex]
Step-by-step explanation:
Given
[tex]\tan(\theta) = -\sqrt{\frac{19}{17}}[/tex]
Required
Determine [tex]\cos(\theta)[/tex]
We have:
[tex]\tan(\theta) = -\sqrt{\frac{19}{17}}[/tex]
Split
[tex]\tan(\theta) = -\frac{\sqrt{19}}{\sqrt{17}}[/tex]
tan is calculated as:
[tex]\tan(theta) = \frac{opposite}{adjacent}[/tex]
So:
[tex]Opposite = -\sqrt{19[/tex]
[tex]Adjacent = \sqrt{17[/tex]
And:
[tex]Hypotenuse^2 = Opposite^2 + Adjacent^2[/tex] --- Pythagoras theorem
[tex]Hypotenuse^2 = (-\sqrt{19})^2 + (\sqrt{17})^2[/tex]
[tex]Hypotenuse^2 = 19 + 17[/tex]
[tex]Hypotenuse^2 = 36[/tex]
Take square roots
[tex]Hypotenuse = 6[/tex]
[tex]\cos(\theta) = \frac{Adjacent}{Hypotenuse}[/tex]
[tex]\cos(\theta) = \frac{\sqrt{17}}{6}[/tex]
Since it is in the second quadrant, then:
[tex]\cos(\theta) = -\frac{\sqrt{17}}{6}[/tex]
Fisk Corporation is trying to improve its inventory control system and has installed an online computer at its retail stores. Fisk anticipates sales of 84,500 units per year, an ordering cost of $12 per order, and carrying costs of $1.20 per unit.
Required:
a.What is the economic ordering quantity?
b. How many orders will be placed during the year?
c. What will the average inventory be?
d. What is the total cost of ordering and carrying inventory?
Answer: A) Economic ordering quantity ==$1,300
B)Orders placed during the year= 65 orders
C)average inventory= 650units
D)total cost of ordering and carrying inventory= $1,560
Step-by-step explanation:
A) Economic ordering quantity =[tex]\sqrt{2 x Annual demand x ordering cost /carrying cost}[/tex]
=[tex]\sqrt{2 x 84,500 x 12} /1.20[/tex]
=[tex]\sqrt{1,690,000}[/tex]
=$1,300
B)Orders placed during the year= Annual demand ÷ economic order quantity
= $84,500 ÷ 1,300 units
= 65 orders
C)average inventory= Economic order quantity ÷ 2
= 1,300 units ÷ 2
=650units
D)total cost of ordering and carrying inventory
Ordering cost = Number of orders × ordering cost per order
= 65 orders × $12
= $780
Carrying cost = average inventory × carrying cost per unit
= 650 units × $1.20
= $780
The total would be = $780 + $780 = $1,560
The slope of the line containing the points (-5, 3) and (-2, 1) is ________.
Answer:
-2/3
Step-by-step explanation:
We can use the slope formula
m = ( y2-y1)/(x2-x1)
= ( 1-3)/(-2 - -5)
= (1-3)/(-2+5)
= -2/3
write your answer as an integer or as a decimal rounded to the nearest tenth
Answer:
123456-6-&55674
Step-by-step explanation:
rdcfvvzxv.
dgjjjdeasg JJ is Redding off in grad wassup I TV kitten gag ex TV ex raisin see
recall see
A study is conducted to examine the correlation between Training Time and the Error Rate of employees. If the correlation coefficient of Training Time and Error Rate is -0.76, what is your conclusion?
(The answer is NOT B) HELP Please!!
A Moderate positive correlation
B Strong negative correlation
C No conclusion possible
D No correlation is shown
E Strong positive correlation
Answer:
No conclusion possible
Ivan invests $5,000 into an account with a 3.5% interest that is compounded semi-annually.
How much money will he have in this account if he keeps it for 15 years?
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Answer:
$8414
Step-by-step explanation:
The compound interest formula is useful for this.
A = P(1 +r/n)^(nt)
where P is the principal invested at annual rate r compounded n times per year for t years. A is the ending balance.
A = $5000(1 +0.035/2)^(2·15) = $5000·1.0175^30 ≈ $8414.00
Ivan will have $8414 in his account after 15 years.
Three children have some marbles.
Shireen has m marbles.
Nazaneen has three times as many marbles as Shireen.
Karly has 4 more marbles than Shireen.
(a) Write down an expression, in terms of m, for
(i) the number of marbles Nazaneen has,
Here we want to create algebraic expressions for different quantities.
i) Nazaneen has 3*m marbles.
ii) Karly has m + 4 marbles.
a) The given data is:
Shireen has m marbles.
Nazaneen has three times as many marbles as Shireen.
Knowing that Shireen has m marbles, we can conclude that Nazaneen has:
3*m marbles.
Karly has 4 more marbles than Shireen, then Karly has m + 4 marbles.
Then the equations for the number of marbles that each one has are:
Shireen = m
i) Nazaneen has 3*m marbles.
ii) Karly has m + 4 marbles.
If you want to learn more, you can read:
https://brainly.com/question/24327241
Solve for a.
5a + 2 - 7-8 = 0
What is the root? If there is no root, choose none.
Answer:5
Step-by-step explanation: root5a+2 +7a-8 = 0
squaring both side
5a+2=7a-8
8+2=7a-5a
10=2a
a=5
Answer:
[tex]\sqrt{5a+2}-\sqrt{7a-8}=0[/tex]
Isolate a square root on the left-hand side
[tex]\sqrt{5a+2} =\sqrt{7a-}8+0[/tex]
Eliminate the radical :-
[tex]5a+2 = 7a-8[/tex]
Solve:-
[tex]2a -10 = 0[/tex]
Add 10 to both sides, then Divide both sides by 2:-
[tex]a = 5[/tex]
OAmalOHopeO
How to change unit from feet to cm
to change unit from feet to cm just divide the length value by 30.48......
You have collected data about the average response time of participants in your study. You are delighted to find that the variable is normally distributed. More than half your respondents take longer than 16 seconds to respond and one third take less than 12 seconds to respond. What is the median response time of your participants
Answer:
15
Step-by-step explanation:
It's 15 because it would be the median (middle) between 16 and 12 if there was more variability in 16 seconds.
square root of v-5=6
[tex] \sqrt{x - 5 = 6}[/tex]
Answer:
I think you mean this :
[tex] \sqrt{x - 5} = 6 \\ = > {( \sqrt{x - 5} })^{2} = {6}^{2} \\ = > x - 5 = 36 \\ = > x = 36 + 5 \\ = > x = 41[/tex]
Or,
Square root of x-5=6 is :
[tex] \sqrt{x - 5} \:=\:\sqrt{6} [/tex]
Can somebody help me
Answer:
The x interceprs are (-3,0) and (2,0)
Step-by-step explanation:
The reason is that when you plug in a -3 in the left parentheses it would become 0, and any number times 0 would be zero, making the equation equal to zero. The same would be true for the terms in the right parentheses, plugging in a two would make it equal to zero. This would make the entire equation equal to zero, finding you the x intercepts.
Please help me with this, But I can’t decide if it’s A or B. Please explain !!!
I think it's the letter A.
Answer:
[tex]m=\frac{M}{\sqrt{1-\frac{v^{2} }{c^{2} } } } \\\\\\m{\sqrt{1-\frac{v^{2} }{c^{2} } }=M[/tex]
[tex]\sqrt{1-\frac{v^{2} }{c^{2} }} =\frac{M}{m} \\\\\\1-\frac{v^{2} }{c^{2} }=\frac{M^{2}}{m^{2}} \\\\\\-\frac{v^{2} }{c^{2} }=\frac{M^{2}}{m^{2}} -1\\\\v^{2}=(-c^{2}) (\frac{M^{2}}{m^{2}} -1)\\\\v=\sqrt{(-c^{2}) (\frac{M^{2}}{m^{2}} -1)} =\sqrt{(c^{2})(-1)(\frac{M^{2}}{m^{2}} -1)} =c\sqrt{(-1)(\frac{M^{2}}{m^{2}} -1)} =c\sqrt{1-\frac{M^{2}}{m^{2}}}[/tex]
I would think it's A ¯\_ (ツ)_/¯
There is 60% chance of making $12,000, 10% chance of breaking even and 30% chance of losing $6,200. What is the expected value of the purchase?
Answer:
$5,340
Step-by-step explanation:
Given :
Making a probability distribution :
X : ___12000 ____0 _____-6200
P(X) __ 0.6 _____ 0.1 _____ 0.3
Tge expected value of the purchase si equal to the expected value or average, E(X) :
E(X) = ΣX*p(X)
E(X) = (12000 * 0.6) + (0 * 0.1) + (-6200 * 0.3)
E(X) = 7200 + 0 - 1860
E(X) = $5,340
What is the slope-intercept equation of the line below?
Answer:
y=-5/4x+3
Step-by-step explanation:
y=mx+c
m = (y1-y2)/(x1-x2) =(-2-3)/(4-0) =-5/4
sub the values y=3, x=0 to find c,
3 =-5/4(0) + c
c = 3
Suppose the discrete random variable X has the probability distribution below:
X 0 1 2 3 4
P(X) 0.11 0.52 0.19 0.12 0.06
1pt a right parenthesis space F i n d space P left parenthesis X less than 3 right parenthesis
2pt b right parenthesis space F i n d space P left parenthesis X greater or equal than 1 right parenthesis
2pt c right parenthesis space F i n d space mu subscript X
2pt, 1pt d right parenthesis space F i n d space sigma subscript X squared space a n d space sigma subscript X
(a) P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.11 + 0.52 + 0.19 = 0.82
(b) P(X ≥ 1) = P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.52 + 0.19 + 0.12 + 0.06 = 0.89
(c) µ = 0×0.11 + 1×0.52 + 2×0.19 + 3×0.12 + 4×0.06 = 1.5
(d) σ² = (0²×0.11 + 1²×0.52 + 2²×0.19 + 3²×0.12 + 4²×0.06) - µ² = 1.07
σ = √(σ²) ≈ 1.03
Fill in the blank by performing the indicated elementary row operation(s).
6
1
5
-6R2+R
1
-5
0
Answer 7 Points
Keybo
<
Prev
In this question, we are given a matrix, and we have to perform the given operation.
The matrix is:
[tex]\left[\begin{array}{ccc}6&-1&|5\\1&-5&|0\end{array}\right][/tex]
The following operation is given:
[tex]R_1 \rightarrow -6R_2 + R_1[/tex]
In which [tex]R_1[/tex] is the element at the first line and [tex]R_2[/tex] is the element at the second line.
Updating the first line:
[tex]R_{1,1} = -6*1 + 6 = 0[/tex]
[tex]R_{1,2} = -6*-5 - 1 = 30 - 1 = 29[/tex]
[tex]R_{1,3} = -6*0 + 5 = 5[/tex]
Thus, the filled matrix will be given by:
[tex]\left[\begin{array}{ccc}0&29&|5\\1&-5&|0\end{array}\right][/tex]
For another example where row operations are applied on a matrix, you can check https://brainly.com/question/18546657
Solve triangles: angle bisector theorem
DAC = BAD.
What is the length of CD?
Round to one decimal place.
Answer:
Step-by-step explanation:
CD/6.5 = 2.6/4.9 This is the result of the angle bisector theorem.
The theorem basically says that the side opposite the angle being bisected is divided the ratio of the sides enclosing the angle.
Multiply both sides of the proportion by 6.5
CD = 2.6 * 6.5 / 4.9
CD = 3.4489
CD = 3.4 rounded.
(b) Two isosceles triangles PQR and PQS are drawn on opposite sides.
of a common base PQ. If PQR = 66° and PSQ = 109°, calculate
the value of RQS.
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Answer:
101.5°
Step-by-step explanation:
Angle PQS will be the complement of half of angle PSQ, so is ...
∠PQS = 90° -109/2° = 35.5°
Angle RQS is the sum of angles RQP and PQS:
∠RQS = 66° +35.5° = 101.5°
A zookeeper published the following stem-and-leaf plot showing the number of lizards at each major zoo in the country:
∣
0
1
2
3
4
5
6
∣
0
6
8
8
8
0
2
6
6
7
8
1
2
6
6
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
00
10
20
30
40
50
60
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
0
0
0
0
1
0
0
6
2
2
8
6
6
8
6
6
8
7
0
0
8
0
Key:
2
∣
0
=
20
2∣0=202, vertical bar, 0, equals, 20 lizards
How many zoos have more than 26 lizards
The principle
P=6000 A=6810 T=3 years
Answer:
incomplete question
Step-by-step explanation:
that is what is wrong with your question
Answer:
r = 4.3%
Step-by-step explanation:
6810= 6000(x)^3
6810/6000= (x)^3
x = 1.043114431
r = 043114431
A ball is thrown from an initial height of
1 meter with an initial upward velocity of
1 m/s. The ball's height h
(in meters) after t
seconds is given by the following. h=1+30t-5t^2
Find all values of t
for which the ball's height is 11
meters.
Round your answer(s) to the nearest hundredth.
Answer:
Step-by-step explanation:
If we are looking for the times that the ball was 11 meters off the ground, we sub in 11 for the height on the left and solve for t:
[tex]11=-5t^2+30t+1[/tex] and
[tex]0=-5t^2+30t-10[/tex] and factor this however it is you are factoring in class to solve for t to get
t = .35 seconds and t = 5.6 seconds
Because the ball reaches this point in its way up and then passes it again on its way down, the ball will have 2 times at this height.
Which expression is equivalent to the given expression?
Answer:
a³b
Step-by-step explanation:
(ab²)³/b⁵
= a³b⁶/b⁵
= a³b
HELP PLEASE!!!
Oak wilt is a fungal disease that infects oak trees. Scientists have discovered that a single tree in a small forest is infected with oak wilt. They determined that they can use this exponential model to predict the number of trees that will be infected after t years.
f(t)=e^0.4t
Question:
Rewrite the exponential model as a logarithmic model that calculates the # of years, g(x) for the number of infected trees to reach a value of x.
The logarithmic model is:
[tex]g(x) = \frac{\ln{x}}{0.4}[/tex]
-------------
We are given an exponential function, for the amount of infected trees f(x) after x years.To find the amount years needed for the number of infected trees to reach x, we find the inverse function, applying the natural logarithm.-------------
The original function is:
[tex]y = f(x) = e^{0.4x}[/tex]
To find the inverse function, first, we exchange y and x, so:
[tex]e^{0.4y} = x[/tex]
Now, we have to isolate y, and we start applying the natural logarithm to both sides of the equality. So
[tex]\ln{e^{0.4y}} = \ln{x}[/tex]
[tex]0.4y = \ln{x}[/tex]
[tex]y = \frac{\ln{x}}{0.4}[/tex]
Thus, the logarithmic model is:
[tex]g(x) = \frac{\ln{x}}{0.4}[/tex]
A similar question is given at https://brainly.com/question/24290183
can somboby help me please
Answer:
x = 8
Step-by-step explanation:
The question had specified that x is equal to 8.
x=8
explanationsplease mark this answer as brainlist
Help please if you know, thanks
Answer:
xsqrt(2)
Step-by-step explanation:
sqrt(a) / sqrt(b) = sqrt(a/b)
sqrt(22x^6) / sqrt(11x^4)
sqrt(22x^6/11x^4)
sqrt(2x^2)
We know sqrt(ab) = sqrt(a) sqrt(b)
sqrt(x^2) sqrt(2)
xsqrt(2)
Wayne has a rectangular painting. The width of the painting is
5/6
of a foot, and the length is
3/4
of a foot. What is the area of the painting?
Answer:
5/8 ft^2
Step-by-step explanation:
The area of a rectangle is given by
A = l*w where l is the length and w is the width
A = 5/6 * 3/4
A = 3/6 * 5/4
A = 1/2 * 5/4
A = 5/8 ft^2
Give the domain and range of G={(6.0),(-9,-3),(1,-3)}
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Answer:
domain: {-9, 1, 6}range: {-3, 0}Step-by-step explanation:
The domain is the list of the first numbers of the ordered pairs. If there are any duplicates, the relation is not a function. Here, the first numbers are {6, -9, 1}. Most folks find it convenient to list them in numerical order:
{-9, 1, 6} . . . . domain of G
__
The range is the list of second numbers of the ordered pairs. Only the distinct values are reported. Here, the second numbers are {0, -3, -3}.
{-3, 0} . . . . range of G
