Lateral runout is felt in the steering wheel even at slower speeds. It leads to riding vibration and therefore poor ride quality.
Lateral runout refers to the side-to-side movement of the car's rotor as it rotates, which is caused by the off-center deviation of the rotor.
Lateral runout leads to riding vibration and therefore it is associated with poor ride quality.
Lateral runout can be properly quantified by using a dial indicator, which is a precision device used to measure linear displacements.
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Create a Python script that will compare two (2) numbers entered by the user. Refer to the attached image and to the following algorithm. There is no need to create a class similar to how Java works.
3.1. User enters the first number.
3.2. User enters the second number.
3.3. If the first number is less than, greater than, or equal the second number, a message is displayed.
Please Help me. Thank You!
Marry Christmas!
Answer:
number1 = input("Choose a first number: ")
number2 = input("Choose a second number: ")
if number1 >= number2:
print("Number 1 is greater")
At steady state, a thermodynamic cycle operating between hot and cold reservoirs at 1000 K and 500 K, respectively, receives energy by heat transfer from the hot reservoir at a rate of 1500 kW, discharges energy by heat transfer to the cold reservoir, and develops power at a rate of (a) 1000 kW, (b) 750 kW, (c) 0 kW. For each case, apply Eq. 5.13 on a time-rate basis to determine whether the cycle operates reversibly, operates irreversibly, or is impossible.
Answer:
a. impossible
b. possible and reversible
c. possible and irreversible
Explanation:
a. 1000kw
Qh - Wnet
we have
QH = 1500
wnet = 1000
1500 - 1000
= 500kw
σcycle = [tex]-[\frac{QH}{TH} -\frac{QC}{TC} ][/tex]
Qh = 1500
Th = 1000
Tc = 500
Qc = 500
[tex]-[\frac{1500}{1000} -\frac{500}{500} ][/tex]
solving this using LCM
= -0.5
the cycle is impossible since -0.5<0
b. 750Kw
Qc = 1500 - 750
=750Kw
Qh = 1500
Th = 1000
Tc = 500
Qc = 750
σ-cycle
[tex]-[\frac{1500}{1000} -\frac{750}{500} ]\\= 1.5 -1.5\\= 0[/tex]
This cycle is possible and it is also reversible
c. 0 kw
Qc = 1500-0
= 1500
Qh = 1500
Th = 1000
Tc = 500
Qc = 1500
σ- cycle
[tex]-[\frac{1500}{1000} -\frac{1500}{500} ]\\-(1.5-3)\\-(-1.5)\\= 1.5[/tex]
1.5>0
so this cycle is possible and irreversible
10. Which is of the following is not used in the
testing/analysis step?
A. Engineering notebooks.
B. Multiview drawings.
C. 3-D modeling software.
D. CNC machines.
A CNC machine stands for Computer Numerically Controlled Machine, they are used to Machine objects in hence create items, machine parts from prototypes. Hence the CNC machines are not used for testing/Analysis
D. CNC machines.
In Engineering the following items are basically needed for and during test/Analysis
Engineering notebooks: This is used to write down importance observations and findingsMulti-view drawings: This is also needed to visualise prototypes from different perspective or views3-D modelling software: e.g AutoCad , Autodesk Inventor, Revit to mention a few can be used to design and analyse project even before their actual implementation or designLearn more:
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What is the first step in the decision-making process?
Answer: identify your decision. relize you need to make a decision.
Explanation:
Explain the conditions under which galvanic corrosion occurs
Answer:
Explanation:
Galvanic corrosion occurs when two dissimilar metals are immersed in a conductive solution and are electrically connected. One metal (the cathode) is protected, whilst the other (the anode) is corroded. The rate of attack on the anode is accelerated, compared to the rate when the metal is uncoupled.
A bird is flying in air. It is stretching its wings all along the sky and is flying in a certain direction Flying a bird is an example of: a. Composition of vector b. Collinear vector c. Addition of vector d. Multiplication of vector
Answer:
a. Composition of Vector.
Explanation:
When a bird flies in the air, it stretches its wings into air and this movement helps it move in a certain direction. This is an example of composition of vector. Air strikes the wings in opposite direction and bird wing movement helps it move against the wind.
Class 0 rubber gloves are used when working with voltage less than
A fully charged battery with 6 cells should indicate
Answer:
Battery Voltage
Voltage refers to the amount of electrical potential your battery holds. The standard automotive battery in today's vehicles is a 12-volt battery. Each battery has six cells, each with 2.1 volts at full charge. A car battery is considered fully charged at 12.6 volts or higher.
As part of the overall systems engineering process, there are a variety of software development methods, but the three most common at DoD are the Waterfall Approach, the Incremental Approach, and the ______________ Approach.
The three most common software development methods are the Waterfall Approach, the Incremental Approach, and the SPIRAL Approach. These methods depend on the team size and specific goals.
Software development is the sequential procedure that involves the division of the work into smaller and parallel stages in order to improve software design and product management.
The software development methods depend on both the team size and specific objectives.
The most common methodologies for software development include:
Waterfall Spiral Incremental Agile Continuous integrationLearn more about software development here:
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(2pts) In _______________, the pulse amplitude is made proportional to the amplitude of the modulating signal. pulse-amplitude modulation (PAM) pulse-position modulation (PPM) pulse-code modulation (PCM) pulse-width modulation (PWM)
Answer:
(a) pulse-amplitude modulation (PAM)
Explanation:
It should be no surprise that pulse amplitude is modulated in pulse-amplitude modulation (PAM).
6.03 Discussion: Then & Now - Safety
Discussion Topic
I'm Done
In this unit, you have learned about the evolution of the industry’s machines, through both technology and innovation. These improvements have reduced risk and injury to the Operating Engineers.
Choose one innovation or device.
Explain why you think that technology is the most important advancement in Operating Engineers’ safety.
Answer:
Information technology is important in our lives because it helps to deal with every day's dynamic things. Technology offers various tools to boost development and to exchange information. Both these things are the objective of IT to make tasks easier and to solve many problems.
‘Politics and planning are increasingly gaining prominence in contemporary urban and regional planning debates’. Using relevant examples, discuss this assertion reflecting on the critical success factors for the successful implementation of the land reform program in South Africa.
Answer:
The governments receiving aid were generally experienced in industrial development. ... During the 1950s, little attention was given to differences in the Third World's conditions and needs, until these appeared to create obstacles to achieving high levels of industrial output
I hope it is helpful
Question 10 of 25: Select the best answer for the question. 10. In a series RC circuit, if the resistance is 8,000 ohms and X is 6,000 ohms, what is the impedance of the circuit O A. 8,600 ohms O B. 10,000 ohms O C. 14,000 ohms O D. 9,200 ohms Mark for review (Will be highlighted on the review page) << Previous Question Next Question >> M LL 5 - 1080 acer
Answer:
B. 10,000 ohms
Explanation:
|8000 +j6000| = √(8000² +6000²) = 1000√(64 +36) = 1000√100 = 10,000
The impedance is 10,000 ohms.
Can anyone solve this for me?sequential circuit ,flipflop
Explanation:
We assume the T flip-flop changes state on the rising edge of the clock input.
The first stage is connected to the clock. The second stage clock is connected to the inverse of the Q output of the first stage, so that when the first stage Q makes a 1 to 0 transition, the second stage changes state.
All of the following are employment requirements for a technician EXCEPT:
Select one:
a. Being drug and alcohol free
b. Having all of your ASE certifications
c. Having a clean driving record
O d. Having honesty, integrity, reliability, and quality
Answer:
I think it would be C but im not sure sorry if its wrong
Chemical engineers determine how to transport chemicals.
O True
False
Answer:
Chemical Engineers determine how to transport chemicals:
TRUE
Answer:
Explanation:
Trues
HELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HEL
Answer:
oh this happened with me to ,this will be alright just wait a bit
How to make this circuit for simulating on Proteus.
A person has driven a car 180 m in 40 seconds. What is the car’s speed?
Answer:
4.5 m/s = 16.2 km/h
Explanation:
The speed is the ratio of distance to time:
speed = (180 m)/(40 s) = 4.5 m/s
An apple, potato, and onion all taste the same if you eat them with your nose plugged
Answer:
I didn't understand your question or is it a fun fact
How can we honor what we value and care about in a world of disruptive technologies like AI?
Answer: Well, that's a good question. When we look around us, we tend to see what technology has done for us, and how far it is taking us. It might be disruptive, but without it there would be no high tech military weapons, and then how would we defend ourselves? There would be no technology entertainment and without that, life would be very dull. In answering your question, we can be thankful for what it is and how far it has been taking us in life.
Explanation: Please mark a brainliest if correct it helps and have meery holidays!
Determine the reactor volume (assume a CSTR activated sludge aerobic reactor at steady state) required to treat 5 MGD of domestic wastewater from an influent BOD concentration of 250 mg/L to an effluent concentration of 10 mg/L. X (MLVSS) = 3000 mg/L, and the kinetics are first order and not variable order. The first order equation you must use to calculate the specific substrate utilization rate is q = K S where S is the effluent BOD concentration and K is the first order BOD degradation rate constant. The value of K is 0.04 L/(day*mg). What is the required reactor volume in MG (millions of gallons)? All the choices below are in units of MG.
0.4
1.0
0.2
4.8
Answer:
1.0MG
Explanation:
to solve this problem we use this formula
S₀-S/t = ksx --- (1)
the values have been given as
concentration = S₀ = 250mg
effluent concentration = S= 10mg
value of K = 0.04L/day
x = 3000 mg
when we put these values into this equation,
250-10/t = 0.04x10x3000
240/t = 1200
we cross multiply from this stage
240 = 1200t
t = 240/1200
t = 0.2
remember the question says that 5MGD is required to be treated
so the volume would be
v = 0.2x5
= 1.0 MG
An airline ticket counter forecasts that 220 people per hour will need to check in. It takes an average of 2 minutes to service a customer. Assume that arrivals are poisson distributed and service times exponentially distributed and that customers wait in a single queue for the first available agent.
a) If we want the average time a customer spends in the queue and in service to be 10 minutes or less, how many ticket agents should be on duty?
b) There airline wants to minimize the cost of idle ticket agents and the cost of customers waiting in the queue. The salary of a ticket agent is £12 per hour and the cost of a customer waiting in the queue is £5 per customer per hour. How many ticket agents should be on duty?
A) Number of agents required to achieve a wait time of 10 minutes or less = 8 agents
B) The number of agents required on duty to reduce cost = 9 agents
Given data :
Arrival rate of customers ( β ) = 220 per hour
Service rate ( mu ) = 60 minutes / 2 minutes = 30 customer per hour
utilization ( rho ) = 220 / 30 ≈ 7
at least 8 server personnel are required for stability of the queue
A) Determine the number of agents required to achieve a wait time of 10 minutes or less per customer
waiting time = 10 - 2 = 8 minutes
number of customers waiting ( ∝ ) = 7 and required server = 8
assuming Lq = 5.2266
Hence the waiting time in line = Lq / arrival rate
= 5.2266 / 220 = 0.0238 hour
= 0.0238 * 60 = 1.428 minutes
Since the waiting time ( 1.428 minutes ) is less than the original waiting time ( 2 minutes ) the number of agents that will achieve a wait time of 10 minutes or less is = 8 agents
B) Determine the number of ticket agents that should be on duty to minimize cost
salary of ticket agent = £12 per hour
cost of customer waiting in queue = £5 per hour per customer
i) When 8 agents are used
waiting time of customers = 0.0238 * 220 = 5.236
waiting cost for customers = 5.236 * 5 = £26.18
employee cost = 8 * 12 = £96
∴ Total cost = 96 + 26.18
= £ 122.18
ii) When 9 agents are used
waiting time for customers = 0.0074 * 220 = 1.628
Wq = 1.6367 / 220 = 0.0074
waiting cost for customers = 1.6367 * 5 = £ 8.1835
assuming Lq = 1.6367
employee cost = 9 * 12 = £ 108
∴ Total cost = 108 + 8.1835 = £ 116.18
From the calculations in ( i ) and ( ii ) the Ideal number of ticket agents that should be on duty to minimize cost should be 9 agents.
Hence we can conclude that A) Number of agents required to achieve a wait time of 10 minutes or less = 8 agents and The number of agents required on duty to reduce cost = 9 agents.
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The customer you were waiting on is nodding while listening to you and gesturing when he speaks what type of language does this represent
Which of the following is a measurement at the nominal level?
A-personal income in a year
B-student grades
C-the color of a person's hair (blond, brunette, redhead)
D-temperature
Answer:
A-personal income in a year this is the answer
A tank with a volume of 40 cuft is filled with a carbon dioxide and air mixture. The pressure within the tank is 30 psia at 70oF. It is known that 2 lb of carbon dioxide was placed in the tank. Assume that air is 80% nitrogen and 20% oxygen and use the ideal gas laws. Calculate ,
The correct responses are;
(i) Weight percent of nitrogen: 58.6%
Weight percent of oxygen: 14.65%
Weight percent of carbon dioxide: 29.59%
(ii) Volume percent of nitrogen: 64.38%
Weight percent of oxygen: 14.1%
Weight percent of carbon dioxide: 21.53%
(iii) Partial pressure of nitrogen: 19.314 psia
Partial pressure of oxygen: 4.23 psia
Partial pressure of carbon dioxide: 6.459 psia
(iv) Partial pressure of nitrogen: 19.314 psia
Partial pressure of oxygen: 4.23 psia
Partial pressure of carbon dioxide: 6.459 psia
(v) The average molecular weight is approximately 32.02 g/mole
(vi) At 20 psia, 60 °F, the density is 0.11275 lb/ft.³
At 14.7 psia, 60 °F, the density is 0.0844 lb/ft.³
At 14.7 psia, 32 °F, the density is 0.0892 lb/ft.³
(vii) The specific gravity of the mixture 0.169
Reasons:
The volume of the tank = 40 ft.³ = 1.132675 m³
Content of the tank = Carbon dioxide and air
The pressure inside the tank = 30 psia = 206843 Pa
The temperature of the tank = 70 °F ≈ 294.2611 K
Mass of carbon dioxide placed in the tank = 2 lb.
Percent of nitrogen in the tank = 80%
Percent of oxygen in the tank = 20%
(i) 2 lb ≈ 907.1847 g
Molar mass of carbon dioxide = 44.01 g/mol
Number of moles of carbon dioxide = [tex]\displaystyle \mathbf{ \frac{907.1847 \, g}{44.01 \, g/mol}} \approx 20.613 \, moles[/tex]
Assuming the gas is an ideal gas, we have;
[tex]\displaystyle n = \mathbf{\frac{206843\times 1.132674}{8.314 \times 294.2611} }\approx 95.7588[/tex]
The number of moles of nitrogen and oxygen = 95.7588 - 20.613 = 75.1458
Let x represent the mass of air in the mixture, we have;
[tex]\displaystyle \mathbf{ \frac{0.8 \cdot x}{28.014} + \frac{0.2 \cdot x}{32}}= 75.1458[/tex]
Solving gives;
x ≈ 2158.92 grams
Mass of the mixture = 2158.92 g + 907.1847 g ≈ 3066.1047 g
[tex]\displaystyle Weight \ percent \ of \ nitrogen= \frac{0.8 \times 2158.92}{3066.105} \times 100 \approx \underline{58.6 \%}[/tex]
[tex]\displaystyle Weight \ percent \ of \ oxygen = \frac{0.8 \times 2158.92}{3066.105} \times 100 \approx \underline{14.65\%}[/tex]
[tex]\displaystyle Weight \ percent \ of \ carbon \ dioxide = \frac{907.184}{3066.105} \times 100 \approx \underline{29.59\%}[/tex]
ii.
[tex]\displaystyle Number \ of \ moles \ nitrogen= \frac{0.8 \times 2158.92 \, g}{28.014 \, g/mol} \approx 61.65\, moles[/tex]
[tex]\displaystyle Number \ of \ moles \ oxygen= \frac{0.2 \times 2158.92 \, g}{32 \, g/mol} \approx 13.5\, moles[/tex]
Number of moles of carbon dioxide = 20.613 moles
Sum = 61.65 moles + 13.5 moles + 20.613 moles ≈ 95.763 moles
In an ideal gas, the volume is equal to the mole fraction
[tex]\displaystyle Volume \ percent \ of \ nitrogen= \frac{61.65}{95.763} \times 100 \approx \underline{64.38 \%}[/tex]
[tex]\displaystyle Volume \ percent \ of \ oxygen = \frac{13.5}{95.763} \times 100 \approx \underline{14.1\%}[/tex]
[tex]\displaystyle Volume \ percent \ of \ carbon \ dioxide = \frac{20.613 }{95.763} \times 100 \approx \underline{21.53\%}[/tex]
(iv) The partial pressure of a gas in a mixture, [tex]P_A = \mathbf{X_A \cdot P_{total}}[/tex]
Partial pressure of nitrogen, [tex]P_{N_2}[/tex] = 0.6438 × 30 psia ≈ 19.314 psia
Partial pressure of oxygen, [tex]P_{O_2}[/tex] = 0.141 × 30 psia ≈ 4.23 psia
Partial pressure of carbon dioxide, [tex]P_{CO_2}[/tex] = 0.2153 × 30 psia ≈ 6.459 psia
(v) The average molecular weight is given as follows;
[tex]\displaystyle Average \ molecular \ weight = \frac{3066.105\, g}{95.7588 \, moles} = 32.02 \, g/mole[/tex]
(vi) At 20 psia 70 °F, we have;
Converting to SI units, we have;
[tex]\displaystyle n = \frac{137895.1456\times 1.132674}{8.314 \times 294.2611} \approx 63.84[/tex]
The number of moles, n ≈ 63.84 moles
The mass = 63.84 moles × 32.02 g/mol ≈ 2044.16 grams ≈ 4.51 lb
[tex]\displaystyle Density = \frac{4.51\ lb}{40 \ ft.^3} \approx \underline{0.11275\, lb/ft.^3}[/tex]
When the pressure is 14.7 psia = 101352.93 Pa, and 60 °F
[tex]\displaystyle n = \frac{101352.9\times 1.132674}{8.314 \times 288.7056} \approx 42.8247[/tex]
The mass = 47.8247 moles × 32.02 g/mol ≈ 1531.35 grams = 3.376 lb.
[tex]\displaystyle Density = \frac{3.376 \ lb}{40 \ ft.^3} \approx \underline{ 0.0844\, lb/ft.^3}[/tex]
When the pressure is 14.7 psia = 101352.93 and 32 °F
[tex]\displaystyle n = \frac{101352.9\times 1.132674}{8.314 \times 273.15} \approx 50.5482[/tex]
The mass = 50.5482 moles × 32.02 g/mol ≈ 1618.55 grams = 3.568 lb.
[tex]\displaystyle Density = \frac{3.568 \ lb}{40 \ ft.^3} \approx \underline{ 0.0892 \, lb/ft.^3}[/tex]
(vii) [tex]\displaystyle The \ specific \ gravity \ of \ the \ mixture \ = \frac{\frac{3066.1047\, g}{40 \, ft.^3} }{1.00} = \frac{\frac{6.7596 \, lbs}{40 \, ft.^3} }{1.00} \approx \underline{0.169}[/tex]
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Technician A says that to start a fuel-injected car, the accelerator should be depressed
once. Technician B says that to start a car with a carburetor, do not touch the
accelerator pedal until the engine is running. Who is correct?
Technician A
Technician B
Both A and B
Neither Anor B
Answer:
Technician A says that primary vibration is created by slight differences in the inertia of the pistons between top dead center and bottom dead center. Technician B says that secondary vibration is a strong low-frequency vibration caused by the movement of the piston traveling up and down the cylinder. Who is correct? O A. Neither Technician A nor B OB. Technician B O C. Both Technicians A and B D. Technician A
Explanation:
Technician A says that primary vibration is created by slight differences in the inertia of the pistons between top dead center and bottom dead center. Technician B says that secondary vibration is a strong low-frequency vibration caused by the movement of the piston traveling up and down the cylinder. Who is correct? O A. Neither Technician A nor B OB. Technician B O C. Both Technicians A and B D. Technician A
The end of the industrial robotic arm extends along the path (r = 2 + 2 cos (5t)) m. At the instant ( 0 = 0.8t ) radians. When the arm is located at (t = 0.85) second Determine the velocity and acceleration of the object A at this instant.
Answer:
v = 8.95 rad / s, a = 22.3 rad / s²
Explanation:
This is an exercise in kinematics, where we must use the definitions of velocity and acceleration
v = dr / dt
we perform the derivative
v = 0+ 2 (-sin 5t) 5
v = -10 sin 5t
we calculate for t = 0.85 t,
remember angles are in radians
v = -10 sin (5 0.85)
v = 8.95 rad / s
acceleration is defined by
a = dv / dt
we perform the derivatives
a = -10 (cos 5t) 5
a = - 50 cos 5t
we calculate for t = 0.85 s
a = -50 are (5 0.85)
a = 22.3 rad / s²
Who is responsible for shielding a welding arc to protect
the eyes and skin of all persons in the working area?
Answer:
manager and supervisor
Explanation:
need help answering this question
Answer: Wow. I just did that not so long ago. The mean is 76, i think the deviation is 73 and ill recall my notes for the next, hold on
Explanation:
