Answer:
The correct answer is "Test 20%, Service 10%".
Step-by-step explanation:
As we know,
The coefficient of variation (CV) is:
⇒ [tex]CV=\frac{Standard \ deviation}{Mean}\times 100[/tex]
Now,
CV of test will be:
= [tex]\frac{40}{200}\times 100[/tex]
= [tex]20[/tex] (%)
CV of service will be:
= [tex]\frac{2}{20}\times 100[/tex]
= [tex]10[/tex] (%)
Mr. Lamb has three children: two girls and one boy. After each meal, one child is chosen at random to wash dishes. Determine the probability that one boy and one girl will wash dishes after lunch and dinner on Saturday.You roll a die twice and add up the dots to get a score. What is the probability that your score is a multiple of 5?
Answer:
1/2 in fractions if you nees it in decimal just transfer
Please help out explanation need it
Answer:
shifting to the right is just an east/west movement
not a north/south
an east west movement is on the "X" ais, a north/south is on the "Y"
axis...
so just ADD 10 units to all the "X" values
a" = (9,-3)
b"= (6,-1)
c"= (4,-4)
Step-by-step explanation:
Can the three values represent the sides of a triangle?
7, 8, √113
Is this a triangle?
If so, what type?
Pythagorean Triple? (yes/no)
no the square root of 113 is rounded to 56x2
If f(x) = x2 + 7x and g(x) = 3x - 1, what is f(g(x))?
Answer:
f(g(x)) = 9x^2 + 15x - 6
Step-by-step explanation:
We are using function g(x) = 3x - 1 as the input to function f(x) = x^2 + 7x.
Starting with f(x) = x^2 + 7x, substitute g(x) for x on the left side and likewise substitute x^2 + 7x for each x on the right side. We obtain:
f(g(x)) = (3x - 1)^2 + 7(3x - 1).
If we multiply this out, we get:
f(g(x)) = 9x^2 - 6x + 1 + 21x - 7, or
f(g(x)) = 9x^2 + 15x - 6
when 18 is subtracted from six times a certain number the result is 96 what is the number
Let the number be x
ATQ
[tex]\\ \sf\twoheadrightarrow 6x-18=96[/tex]
[tex]\\ \sf\twoheadrightarrow 6x=96+18[/tex]
[tex]\\ \sf\twoheadrightarrow 6x=112[/tex]
[tex]\\ \sf\twoheadrightarrow x=\dfrac{112}{6}[/tex]
[tex]\\ \sf\twoheadrightarrow x=7[/tex]
Please solve the equation 4X-25=71
Mr. Allway’s math class surveyed all the seventh-grade students to find out their favorite sport. The following circle graph shows a breakdown of the survey findings.
Find the number of degrees represented by Basketball.
108°
101°
11°
140°
Answer:
101 is the answer of the question
Answer:
101 degrees
Step-by-step explanation:
First you add all the percentages
39 + 28 + 30 + 3 = 100%
To find the number of degrees of basketball you multiply 28% by 360 because it’s a circle.
28/100 * 360 = 10,080/100 = 100.8 ~ 101
interest on 600 2 years at rate of paise per rupee per month
Categorize the trigonometric functions as positive or negative.
Answer:
So, remember that:
cos(x) > 0 for -pi/2 < x < pi/2
cos(x) < 0 for pi/2 < x < (3/2)*pi
and
sin(x) > 0 for 0 < x < pi
sin(x) < 0 for -pi < x <0 or pi < x < 2pi
Also, we have the periodicty of the sine and cocine equations, such that:
sin(x) = sin(x + 2pi)
cos(x) = cos(x + 2pi)
Now let's solve the problem:
[tex]sin(\frac{13*\pi}{36} )[/tex]
here we have:
x = (13/36)π
This is larger than zero and smaller than π:
0 < (13/36)π < π
then:
[tex]sin(\frac{13*\pi}{36} )[/tex]
Is positive.
The next one is:
[tex]cos(\frac{7*\pi}{12} )[/tex]
Here we have x = (7/12)*pi
notice that:
7/12 > 1/2
Then:
(7/12)*π > (1/2)*π
Then:
[tex]cos(\frac{7*\pi}{12} )[/tex]
is negative.
next one:
[tex]sin(\frac{47*\pi}{36} )[/tex]
here:
x = (47/36)*π
here we have (47/36) > 1
then:
(47/36)*π > π
then:
[tex]sin(\frac{47*\pi}{36} )[/tex]
is negative.
the next one is:
[tex]cos(\frac{17*\pi}{10} )[/tex]
Here we have x = (17/10)*π
if we subtract 2*π (because of the periodicity) we get:
(17/10)*π - 2*π
(17/10)*π - (20/10)*π
(-3/10)*π
this is in the range where the cosine function is positive, thus:
[tex]cos(\frac{17*\pi}{10} )[/tex]
is positive.
the next one is:
[tex]tan(\frac{41*\pi}{36} ) = \frac{sin(\frac{41*\pi}{36} )}{cos(\frac{41*\pi}{36} )}[/tex]
here we have:
x = (41/36)*π
Notice that both functions, sine and cosine are negatives for that value, then we have the quotient of two negative values, so:
[tex]tan(\frac{41*\pi}{36} ) = \frac{sin(\frac{41*\pi}{36} )}{cos(\frac{41*\pi}{36} )}[/tex]
is positive.
The final one is:
[tex]tan(\frac{5*\pi}{9} ) = \frac{sin(\frac{5*\pi}{9} )}{cos(\frac{5*\pi}{9} )}[/tex]
Here:
x = (5/9)*π
The sin function is positive with this x value, while the cosine function is negative, thus:
[tex]tan(\frac{5*\pi}{9} ) = \frac{sin(\frac{5*\pi}{9} )}{cos(\frac{5*\pi}{9} )}[/tex]
Is negative.
The profits for video game companies depend on what game platform the game runs on, which can either be a portible system with a built in screen, or a standard system that you have to hook up to a television. The profit off of a portible game system is $72, while the profit from a standard game system is $90. The store manager has to make at least $360 per day in order to keep the store open. Which graph represents this inequality? Write the inequality that represents the number of games that must be sold everyday to meet or beat the sales goal.
Step-by-step explanation:
Find the surface area of the following triangular prisms
Determine which type of error is most likely to arise from the following situations. a 1. the time in which individuals are contacted to take a survey occurs during work hours f 2. the last part of a newspaper article asks readers to mail or email the newspaper their opinion about universal health coverage 3. subjects are asked to recall how often they snacked between meals in the past 30 days 4. a survey to assess teachers' opinions about Common Core uses a member list for the largest teachers' union as the sampling frame a. question wording b. undercoverage c. processing error d. bad sampling method e. response error f. nonresponse g. random sampling error
Answer:
Determination of type of error arising from the situations
Situation Type of Error
1. Nonresponse
2. Bad sampling method
3. Question wording
4. Undercoverage
Step-by-step explanation:
Types of errors:
a. question wording means that the manner a question is worded elicits some particular responses, which may not accurately reflect reality.
b. undercoverage occurs when some elements of the target population is not represented on the survey frame.
c. processing error arises from data processing
d. bad sampling method is caused by the voluntariness of those who choose to respond.
e. response error is caused by a questionnaire that requires framing improvements, misinterpretation of questions by interviewers or respondents, and errors in respondents' statements.
f. nonresponse error arises as a result of incomplete information or partial response.
g. random sampling error arises from the limited sample size when compared with the population size.
16)dry air is trapped in a narrow uniform glass tube by a mercury pellet of length 25cm .when the tube is placed vertical with the open end um long.what is the external pressure if the column of air becomes 40 cm in length when inverted ? . ( required answer = 74cm hg )
Step-by-step explanation:
Ru Tu yulyryosuyyyhlsgjpcbmb kvjvlcykxnlvdlbvhck
chgkbhlxyovk m.
chchhlzixhvkh
expresión algebraica el cuadrado del cubo de la suma de dos números
Answer:
El cuadrado de la suma de dos números es igual a (a + b) ² = a² + 2ab + b²Un producto notable: es una expresión matemática que conocemos ya el resultado, a pesar de la operación ser sencilla tenemos
Help me with this math problem !!!
Answer:
multiply the numerator together and denominator together
The total amount of spending per year, in billions, on pets in a certain country x years after 2000 is given by the following function. P(x)=2.1786+25.2 a) Determine the total amount of spending per year on pets in 2007 and in 2012. b) Find and explain what it represents.
Answer:
40.4502 billion dollars
51.3432 billion dollars
Step-by-step explanation:
Given :
Total amount spent in billions in pets x years after year, 2000 ;
P(x)=2.1786x + 25.2
Amount spent in 2007 ;
x = 2007 - 2000 = 7 years
Put x = 7 in the equation :
P(7)=2.1786(7) + 25.2 = 40.4502
Amount spent in 2012 :
x = 2012 - 2000 = 12 years
Put x = 12 in the equation :
P(12) = 2.1786(12) + 25.2 = 51.3432
The amount spent in billik dollars on pets in :
2007 = $404502 billion
2012 = $51.3432 billion
In the figure, m is parallel to n and m <4 = 125 degrees. Find the measures of the other angles.
Answer:
m<1 = 55°
m<2 = 125°
m<3 = 55°
m<5 = 55°
m<6 = 125°
m<7 = 55°
m<8 = 125°
Step-by-step explanation:
m<4 = 125° (given)
✔️m<8 = m<4 (alternate exterior angles are congruent)
m<8 = 125° (substitution)
✔️m<1 = 180° - m<8 (supplementary angles/linear pair)
m<1 = 180° - 125° (substitution)
m<1 = 55°
✔️m<2 = m<8 (vertical angles are congruent)
m<2 = 125° (substitution)
✔️m<7 = m<1 (vertical angles are congruent)
m<7 = 55° (Substitution)
✔️m<3 = m<7 (alternate interior angles are congruent)
m<3 = 55° (substitution)
✔️m<5 = m<3 (vertical angles are congruent)
m<5 = 55°
✔️m<6 = m<4 (vertical angles)
m<6 = 125°
write as a polynomial (-2x^2+x+1)-(x^2-x+7)-(4x^2+2x+8)
Answer:
The answer would be -7x^2 - 14!
Step-by-step explanation:
We can remove the parentheses by distributing the subtraction sign! -2x^2 + x + 1 - x^2 + x - 7 - 4x^2 - 2x - 8. Simplifying this gives us -7x^2 - 14. Hope this helped! :)
What is the lengh of the line
Answer:
√45 or 3√5
Step-by-step explanation:
DVD Video Rentals (Refer to Example 3.) The func-
tion V computes the percent share of disc DVD rentals
accounted for by various companies. This function is
defined by V(R) = 37, V(N) = 30, and V(S) = 17,
where R is Redbox, N is Netflix, and S is rental stores.
(Source: Business Insider.)
(a) Write V as a set of ordered pairs.
(b) Give the domain and range of V.
T
Answer:
[tex](a)\ V = \{(N,30),(R,37),(S,17)\}[/tex]
[tex](b)[/tex]
[tex]Domain = \{N,R,S\}[/tex]
[tex]Range = \{37,30,17\}[/tex]
Step-by-step explanation:
Given
[tex]V(R) = 37,\ V(N) = 30,\ V(S) = 17[/tex]
Solving (a): Set of ordered pair
A function y = f(x) is represented as (x,y)
So, the ordered pair of V is:
[tex]V = \{(R,37),(N,30),(S,17)\}[/tex]
Order the alphabets in increasing order
[tex]V = \{(N,30),(R,37),(S,17)\}[/tex]
Solving (b): The domain and the range
In a function [tex]\{(x_1,y_1),...,(x_n,y_n)\}[/tex]
The domain and the range are represented as:
[tex]Domain = \{x_1,x_2....x_n\}[/tex]
[tex]Range = \{y_1,y_2....y_n\}[/tex]
So, we have:
[tex]Domain = \{N,R,S\}[/tex]
[tex]Range = \{37,30,17\}[/tex]
A population is currently
Answer:
Step-by-step explanation:
The current world population is 7.9 billion as of July 2021 according to the most recent United Nations estimates elaborated by Worldometer. The term "World Population" refers to the human population (the total number of humans currently living) of the world.
Find the missing length in the image below
Answer:
1 length ityoughkdds hshlkb
Let it be x
[tex]\\ \sf\longmapsto \dfrac{x}{10}=\dfrac{3}{6}[/tex]
Use cross multiplication[tex]\\ \sf\longmapsto 6x=10(3)[/tex]
[tex]\\ \sf\longmapsto 6x=30[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{30}{6}[/tex]
[tex]\\ \sf\longmapsto x=5[/tex]
Please help and no links.While shopping, you find a shirt that you want. The shirt originally costs p dollars but it is on
sale for 20% off. Which of the following expressions could you use to find the price of the shirt
after the discount where p is the original price of the shirt? Select all that apply.
a) 0.2p
b) 0.8p
c) P-0.27
d) p-0.8p
Find the missing side of the triangle
Answer:
x = 7[tex]\sqrt{2}[/tex]
Step-by-step explanation:
Pytago:
[tex]7^2 + 7^2 = x^2\\x = \sqrt{7^2 + 7^2} \\x = 7\sqrt{2}[/tex]
Step-by-step explanation:
In a right triangle, you can find the leg of the triangle by using the Pythagorean theorem.
[tex]a^2+b^2=c^2[/tex]
In this case, we have [tex]7^2+7^2=c^2[/tex], or
[tex]c^2=98[/tex]
[tex]\sqrt{98}[/tex]≅[tex]9.9[/tex]
Determine whether each relation is a function. Give the domain and range for each relation.
{(3, 4), (3, 5), (4, 4), (4, 5)}
Answer:
Not a function
Domain: {3,4}
Range: {4,5}
Step-by-step explanation:
A function is a relation where each input has its own output. In other words if the x value has multiple corresponding y values then the relation is not a function
For the relation given {(3, 4), (3, 5), (4, 4), (4, 5)} the x value 3 and 4 have more than one corresponding y value therefore the relation shown is not a function
Now let's find the domain and range.
Domain is the set of x values in a relation.
The x values of the given relation are 3 and 4 so the domain is {3,4}
The range is the set of y values in a relation
The y value of the given relation include 4 and 5
So the range would be {4,5}
Notes:
The values of x and y should be written from least to greatest when writing them out as domain and range.
They should be written inside of brackets
Do not repeat numbers when writing the domain and range
Mr. Thomas invested an amount of ₱13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be ₱3508, what was the amount invested in Scheme B?
9514 1404 393
Answer:
₱6400
Step-by-step explanation:
Let 'b' represent the amount invested in scheme B. Then 13900-b is the amount invested in scheme A. The total interest for 2 years is then ...
14%(13900-b)(2) +11%(b)(2) = 3508
1946 -0.03b = 1754 . . . . . . divide by 2, simplify
-0.03b = -192 . . . . . . . . . subtract 1946
b = 6400 . . . . . . . . . . . divide by -0.03
The amount invested in scheme B was ₱6400.
PLZ ANSWER ASAP
(look at images below, from khan)
Answer:
D Replace on equation with sum /difference of both equations
The systems are still the same
Step-by-step explanation:
5x + y = 3
4x - 7y = 8
Subtract the second equation from the first
5x + y = 3
-(4x - 7y = 8)
-----------------
x +8y = -5
The second equation in system B is the first equation in system a minus the second equation in system A
We added the same thing to each side of the equation so the the system is still the same
Find f′ in terms of g′
f(x)=x2g(x)
Select one:
f′(x)=2xf′(x)+2xg′(x)
f′(x)=2xg′(x)
f′(x)=2x+g′(x)
f′(x)=x2g(x)+2x2g′(x)
f′(x)=2xg(x)+x2g′(x)
9514 1404 393
Answer:
(e) f′(x)=2xg(x)+x²g′(x)
Step-by-step explanation:
The product rule applies.
(uv)' = u'v +uv'
__
Here, we have u=x² and v=g(x). Then u'=2x and v'=g'(x).
f(x) = x²·g(x)
f'(x) = 2x·g(x) +x²·g'(x)
A company that produces DVD drives has a 12% defective rate. Let X represent the number of defectives in a random sample of 55 of their drives.
Required:
a. What is the probability the sample will contain exactly 8 defective drives?
b. What is the probability the sample will contain more than 8 defective drives?
c. What is the probability the sample will contain less than 8 defective drives?
d. What is the expected number of defective drives in the sample?
Answer:
a) 0.1287 = 12.87% probability the sample will contain exactly 8 defective drives
b) 0.2092 = 20.92% probability the sample will contain more than 8 defective drives.
c) 0.6621 = 66.21% probability the sample will contain less than 8 defective drives.
d) The expected number of defective drives in the sample is 6.6
Step-by-step explanation:
For each DVD, there are only two possible outcomes. Either it is defective, or it is not. The probability of a DVD being defective is independent of any other DVD, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
A company that produces DVD drives has a 12% defective rate.
This means that [tex]p = 0.12[/tex]
Let X represent the number of defectives in a random sample of 55 of their drives.
This means that [tex]n = 55[/tex]
a. What is the probability the sample will contain exactly 8 defective drives?
This is [tex]P(X = 8)[/tex]. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 8) = C_{55,8}.(0.12)^{8}.(0.88)^{47} = 0.1287[/tex]
0.1287 = 12.87% probability the sample will contain exactly 8 defective drives.
b. What is the probability the sample will contain more than 8 defective drives?
This is:
[tex]P(X > 8) = 1 - P(X \leq 8)[/tex]
In which:
[tex]P(X \leq 8) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)[/tex]
Then
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{55,0}.(0.12)^{0}.(0.88)^{55} = 0.0009[/tex]
[tex]P(X = 1) = C_{55,1}.(0.12)^{1}.(0.88)^{54} = 0.0066[/tex]
[tex]P(X = 2) = C_{55,2}.(0.12)^{2}.(0.88)^{53} = 0.0244[/tex]
[tex]P(X = 3) = C_{55,3}.(0.12)^{3}.(0.88)^{52} = 0.0588[/tex]
[tex]P(X = 4) = C_{55,4}.(0.12)^{4}.(0.88)^{51} = 0.1043[/tex]
[tex]P(X = 5) = C_{55,5}.(0.12)^{5}.(0.88)^{50} = 0.1450[/tex]
[tex]P(X = 6) = C_{55,8}.(0.12)^{6}.(0.88)^{49} = 0.1648[/tex]
[tex]P(X = 7) = C_{55,7}.(0.12)^{7}.(0.88)^{48} = 0.1573[/tex]
[tex]P(X = 8) = C_{55,8}.(0.12)^{8}.(0.88)^{47} = 0.1287[/tex]
So
[tex]P(X \leq 8) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) = 0.0009 + 0.0066 + 0.0244 + 0.0588 + 0.1043 + 0.1450 + 0.1648 + 0.1573 + 0.1287 = 0.7908[/tex]
[tex]P(X > 8) = 1 - P(X \leq 8) = 1 - 0.7908 = 0.2092[/tex]
0.2092 = 20.92% probability the sample will contain more than 8 defective drives.
c. What is the probability the sample will contain less than 8 defective drives?
This is:
[tex]P(X < 8) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)[/tex]
With the values we found in b.
[tex]P(X < 8) = 0.0009 + 0.0066 + 0.0244 + 0.0588 + 0.1043 + 0.1450 + 0.1648 + 0.1573 = 0.6621[/tex]
0.6621 = 66.21% probability the sample will contain less than 8 defective drives.
d. What is the expected number of defective drives in the sample?
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
In this question:
[tex]E(X) = 55(0.12) = 6.6[/tex]
The expected number of defective drives in the sample is 6.6
if the Arithmetic means of the 17 numbers is 14. when the two numbers are eliminated the mean becomes 13 if the differences of the two eliminated numbers is 7. find the numbers.
Answer=30,20 but show me in process.
Answer:
The numbers are 18 and 25
Step-by-step explanation:
Given
[tex]\bar x_1 = 14[/tex] [tex]n_1 = 17[/tex]
[tex]\bar x_2 = 13[/tex] [tex]n_2 = 15[/tex]
[tex]a - b = 7[/tex] --- the difference of the 2 numbers
Required
Find a and b
We have:
[tex]\bar x = \frac{\sum x}{n}[/tex] -- mean formula
So, we have:
[tex]\bar x_1 = \frac{\sum x_1}{n_1}[/tex]
[tex]14 = \frac{\sum x_1}{17}[/tex]
Cross multiply
[tex]\sum x_1 = 14 * 17[/tex]
[tex]\sum x_1 = 238[/tex]
When the two numbers are removed, we have:
[tex]\bar x_2 = \frac{\sum x_2}{n_2}[/tex]
[tex]13 = \frac{\sum x_2}{15}[/tex]
Cross multiply
[tex]\sum x_2 = 13 * 15[/tex]
[tex]\sum x_2 = 195[/tex]
The two numbers that were removed are:
[tex]a + b = \sum x_1 - \sum x_2[/tex]
[tex]a + b = 238 - 195[/tex]
[tex]a + b = 43[/tex]
Make a the subject
[tex]a= 43 - b[/tex]
We have:
[tex]a - b = 7[/tex]
Substitute [tex]a= 43 - b[/tex]
[tex]43 - b - b = 7[/tex]
[tex]43 - 2b = 7[/tex]
Collect like terms
[tex]2b = 43 - 7[/tex]
[tex]2b = 36[/tex]
Divide by 2
[tex]b = 18[/tex]
Substitute [tex]b = 18[/tex] in [tex]a= 43 - b[/tex]
[tex]a = 43 - 18[/tex]
[tex]a = 25[/tex]
