Name an angle adjacent to FGI
JGI

HGJ

DGE

HGE

Name An Angle Adjacent To FGI JGIHGJDGEHGE

Answers

Answer 1

Answer: JGI

Step-by-step explanation:

An adjacent angle are angles that share a vertex and side. FGI and JGI share the vertex G and the segment GI

Have a good day!


Related Questions

ASAP PLEASE HELP MEEEEEEEEEEEEEEEEE

Answers

Step-by-step explanation:

Which statement is true about this quadratic equation?
y = 12 – 11x + 7
A.
There is one real solution.
B.
There are two complex solutions.
C.
There are two real solutions.
D.
There is one complex solution,

Answers

The statement that is true about the quadratic equation is (b) There are two complex solutions.

Identifying the statement that is true about the quadratic equation

From the question, we have the following parameters that can be used in our computation:

y = 12 – 11x + 7

Express properly

So, we have

y = 12x² – 11x + 7

Next, we calculate the discriminant using

d = b² - 4ac

Where

a = 12

b = -11

c = 7

Substitute the known values in the above equation, so, we have the following representation

d = (-11)² - 4 * 12 * 7

Evaluate

d = -215

This value is less than 0

This means that it has complex solutions

Read more about quadratic functions at

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please help have a lot of math to do today

Answers

Answer:

115 in.^2

Step-by-step explanation:

The total surface area is the sum of the areas of the square base and the 4 congruent triangular faces.

SA = b^2 + 4 * bh/2

SA = (5 in.)^2 + 4 * (5 in.)(9 in.)/2

SA = 25 in.^2 + 2 * 45 in.^2

SA = 115 in.^2

The graph below could be the graph of which exponential function?

Answers

Answer:

B

Step-by-step explanation:

Find the missing side. Round your answer to the nearest tenth. 19, 36

Answers

Answer:

x=110.6

Step-by-step explanation:

sin(19)=36/x. x=36/sin(19)=110.6

The population, P, of six towns with time t in years are given by the following exponential equations:
(i) P = 1000 (1.08) Superscript t (ii) P = 600 (1.12) Superscript t
(iii) P = 2500 (0.9) Superscript t (iv) P = 1200 (1.185) Superscript t
(v) P = 800 (0.78) Superscript t (vi) 2000 (0.99) Superscript t
Which town decreasing the fastest?
a.
ii
c.
iii
b.
v
d.
vi



Please select the best answer from the choices provided


A
B
C
D

Answers

Given:

The population, P, of six towns with time t in years are given by the following exponential equations:

(i) [tex]P=1000(1.08)^t[/tex]

(ii) [tex]P = 600 (1.12)^2[/tex]

(iii) [tex]P =2500 (0.9)^t[/tex]

(iv) [tex]P=1200 (1.185)^t[/tex]

(v) [tex]P=800 (0.78)^t[/tex]

(vi) [tex]P=2000 (0.99)^t[/tex]

To find:

The town whose population is decreasing the fastest.

Solution:

The general form of an exponential function is:

[tex]P(t)=ab^t[/tex]

Where, a is the initial value, b is the growth or decay factor.

If b>1, then the function is increasing and if 0<b<1, then the function is decreasing.

The values of b for six towns are 1.08, 1.12, 0.9, 1.185, 0.78, 0.99 respectively. The minimum value of b is 0.78, so the population of (v) town  [tex]P=800 (0.78)^t[/tex] is decreasing the fastest.

Therefore, the correct option is b.

Complete the statements.
f(4) is
f(x) = 4 when x is

Answers

F(4)=1/2
F(x)=4 when x is 8


Hope this helps:)

The answer X is 8
Hope I helped

You have two squares. The larger square has a side of 3 more than the smaller square. If the combined area of the two squares is 89 cm squared. What is the length of the smaller square.

A. 3

B. 5

C. 8

D. 10

Answers

The length of the SMALLER square is:
B. 5

Basically I tested each answer choice and see if all the information matches it.
Lets check how my answer is correct:
We know that:
The length of the bigger square is 3 more than the smaller square’s length.
The areas of both squares add up to 89 cm^2
length of the SMALLER square is: 5 cm
length of the LARGER square:
5 + 3 = 8 cm

Area of smaller square:
5^2 = 25 cm^2

Area of bigger square:
8^2 = 64 cm^2

ADD UP BOTH AREAS OF SQUARES:
25 + 64 = 89 cm^2

Hope this helps!
The length of a side of the larger square is 3 cm more than the length of a side of the smaller square.
let the side of the smaller square is a cm then larger square has sides a+3 cm
The sum of the area of two squares is 89 square centimeters.
so a^2+(a+3)^2=89
or a^2+a^2+9+6a=89
or 2a^2+6a-80=0
or a^2+3a-40=0
or a^2+8a-5a-40=0
or a(a+8)-5(a+8)=0
or (a+8)(a-5)=0
or a+8=0=> a=-8 rejected for -ve value
then (a-5=0 =>a=5 the side of the smaller square
& the sides of the larger square is 3+5=8 cms
ans

a sum of money Doubles itself in 5 years what is rate of simple interest​

Answers

Step-by-step explanationIf you are reading this say

thank u

if 20,x,y,z,25 are in AP .find the value of X,y,z.​

Answers

Answers:

x = 21.25y = 22.5z = 23.75

=============================================================

Work Shown:

AP = arithmetic progression, which is the same as arithmetic sequence

d = common difference

x = 20+dy = 20+2dz = 20+3d

Notice how we scale up the d terms d, 2d, 3d, counting up by 1 each time.

So that must mean 25 is the same as 20+4d

20+4d = 25

4d = 25-20

4d = 5

d = 5/4

d = 1.25

and therefore,

x = 20+d = 20+1.25 = 21.25y = 20+2d = 20+2*1.25 = 22.5z = 20+3d = 20+3*1.25 = 23.75

We could convert these to fraction form, but I find decimal form is easier in this case.

SEE QUESTION IN IMAGE

Answers

Answer:

c) 11.5

Step-by-step explanation:

Total frequencies:

6 + 15 + 20 + 7 + 2 = 50

Median group is the containing the middle - 25th and 26th frequencies. This is the 11-15 interval.

Estimated median formula:

Estimated Median = L +  ((n/2) − B)/G* w, whereL -  lower class boundary of the group containing the median = 10.5 n -  total number of values = 50 B - cumulative frequency of the groups before the median group = 6 + 15 = 21 G -  frequency of the median group = 20 w -  group width = 5

Substitute values and work out the number:

Estimated Median = 10.5 + (50/2 - 21)/20*5 = 11.5

Can anyone answer this for me?

Answers

Answer:

y = 2 - [tex]x^{2}[/tex]

Step-by-step explanation:

[tex]x^{2}[/tex] results in a parabola (U-shape). Adding a negative in front of it flips the parabola to look like an upside-down U.

The 2 makes it shift up two decimal spots to (0,2).

Find the value of m if x + m is a factor of x^2 - 5mx + 3​

Answers

Answer:

+or- sqrt(3/4)

Step-by-step explanation:

If x + m is a factor, that means that when x = -m the equation equals 0. Sub -m into x

0 = (-m)^2 - 5m(-m) + 3

0 = m^2 - 5m^2 + 3

0 = -4m^2 + 3

Factorise

0 = -4(m^2 - 3/4)

0 = -4(m + sqrt(3/4))(m - sqrt(3/4))

:. m = +or- sqrt(3/4)

Guys please help me solve this problem, yes I will mark brainliest

Answers

Given that the vertex is at (50, 1000), the max profit is $1000 when 50 items are produced

With explanation please thank you

Answers

I need help in this I don’t know what’s the answer

Read is solving the quadratic equation 0 equals X over two minus 2X -3 using the quadratic formula which shows the correct substitution of the values ABC into the quadratic formula quadratic formula X equals negative B+

Answers

Answer:

[tex]x = \frac{-(-2) \± \sqrt{(-2)^2 - 4*1*-3}}{2*1}[/tex]

Step-by-step explanation:

Given

[tex]0 = x^2 - 2x -3[/tex]

Required

The correct quadratic formula for the above

A quadratic equation is represented as:

[tex]ax^2 + bx + c = 0[/tex]

And the formula is:

[tex]x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}[/tex]

So, we have:

[tex]0 = x^2 - 2x -3[/tex]

Rewrite as:

[tex]x^2 - 2x - 3 = 0[/tex]

By comparison:

[tex]a= 1; b = -2; c = -3[/tex]

So, we have:

[tex]x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}[/tex]

[tex]x = \frac{-(-2) \± \sqrt{(-2)^2 - 4*1*-3}}{2*1}[/tex]

Suppose that there were a strong correlation between the variables d & f. Which of there is a true statement

Answers

Answer:

d may cause f.

Step-by-step explanation:

Here are the options

d must not cause f.

f must cause d.

d must cause f.

d may cause f.

Correlation is a statistical measure used to measure the relationship that exists between two variables.

1. Positive correlation : it mean that the two variables move in the same direction. If one variable increases, the other variable also increases.

For example, there should be a positive correlation between quantity supplied and price

When there is a positive correlation, the graph of the variables is upward sloping

2. Negative correlation :  it mean that the two variables move in different direction. If one variable increases, the other variable decreases.

For example, there should be a negative correlation between quantity demanded and price

When there is a negative correlation, the graph of the variables is downward sloping

3. Zero correlation : there is no relationship between the variables

Can someone pls help with this

Answers

here it is :)

do check properly, I have given step by step instructions:)

do give feedback on my answer, would appreciate it!

Answer:

900000

Step-by-step explanation:

[tex]30*10^{4}[/tex]

=3*10000

=30000

=30*30000

=900000

please show work it’s for calc

Answers

Answer:

24

Step-by-step explanation:

The question is asking for the net area from x=3 to x=10.

It gives you the net area from x=3 to x=5 being -18.

It gives you the net area from x=5 to x=10, being 42.

Together those intervals make up the interval we want to find the net area for.

-18+42=42-18=24

Answer:

[tex]\displaystyle \int\limits^{10}_3 {f(t)} \, dt = 24[/tex]

General Formulas and Concepts:

Calculus

Integration

Integrals

Integration Property [Splitting Integral]:                                                               [tex]\displaystyle \int\limits^c_a {f(x)} \, dx = \int\limits^b_a {f(x)} \, dx + \int\limits^c_b {f(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int\limits^{5}_3 {f(t)} \, dt = -18[/tex]

[tex]\displaystyle \int\limits^{10}_5 {f(t)} \, dt = 42[/tex]

[tex]\displaystyle \int\limits^{10}_3 {f(t)} \, dt[/tex]

Step 2: Integrate

[Integral] Rewrite [Integration Property - Splitting Integral]:                      [tex]\displaystyle \int\limits^{10}_3 {f(t)} \, dt = 24 = \int\limits^5_3 {f(t)} \, dt + \int\limits^{10}_5 {f(t)} \, dt[/tex][Integrals] Substitute:                                                                                    [tex]\displaystyle \int\limits^{10}_3 {f(t)} \, dt = 24 = -18 + 42[/tex]Simplify:                                                                                                         [tex]\displaystyle \int\limits^{10}_3 {f(t)} \, dt = 24[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

The diameter of a $1 coin is 26.5 mm. Find the area of one side of the coin. Round to the nearest hundredth.

Answers

The area of one side of the coin is 41.605 mm².

Given that, the diameter of a $1 coin is 26.5 mm.

We need to find the area of one side of the coin.

What is the area of a circle formula?

The area of a circle formula is A=πr².

Now, radius=26.5/2=13.25 mm.

Area of a coin=3.14×13.25=41.605 mm².

Therefore, the area of one side of the coin is 41.605 mm².

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(2/1.3)+(2/3.5)+(2/5.7)+ ... + (2/97.99) > 98%

Answers

Step-by-step explanation:

gxhkmnjggggffffffcccccccccccc

PLEASE SOMEONE SOLVE B) I ALREADY KNOW 1. A) Is 75.875m^2

Answers

Someone help me out plz

What is the measure of m?
6
24
n
m
m =
[?]
Enter

Answers

the measure of m is24 according to the questions

Cos 600 degrees solved by double angle formula (20 points)
show work please :)))

Answers

Answer:

[tex] \rm\cos({600}^{ \circ} ) =-1/2 [/tex]

Step-by-step explanation:

we would like to solve the following using double-angle formula:

[tex] \displaystyle \cos( {600}^{ \circ} ) [/tex]

there're 4 double Angle formulas of cos function which are given by:

[tex] \displaystyle \cos(2 \theta) = \begin{cases} i)\cos^{2} ( \theta) - { \sin}^{2}( \theta) \\ii) 2 { \cos}^{2}( \theta) - 1 \\iii) 1 - { \sin}^{2} \theta \\ iv)\dfrac{1 - { \tan}^{2} \theta}{1 + { \tan}^{2} \theta } \end{cases}[/tex]

since the question doesn't allude which one we need to utilize utilize so I would like to apply the second one, therefore

step-1: assign variables

to do so rewrite the given function:

[tex] \displaystyle \cos( {2(300)}^{ \circ} ) [/tex]

so,

[tex] \theta = {300}^{ \circ} [/tex]

Step-2: substitute:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = 2 \cos ^{2} {300}^{ \circ} - 1[/tex]

recall unit circle thus cos300 is ½:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = 2 \left( \dfrac{1}{2} \right)^2 - 1[/tex]

simplify square:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = 2\cdot \dfrac{1}{4} - 1[/tex]

reduce fraction:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = \dfrac{1}{2} - 1[/tex]

simplify substraction and hence,

[tex] \rm\cos({600}^{ \circ} ) = \boxed{-\frac{1}{2}}[/tex]

SOMEONE PLEASE HELP ME OUT ON THIS. PLEASE!
n= 1. then a1= 7+3(1)

How to solve it.

Answers

Answer:

I think this is right for the 2nd problem

Step-by-step explanation:

a1=7+(3)(1)

Step 1: Simplify both sides of the equation.

a1=7+(3)(1)

a=7+3

a=(7+3)(Combine Like Terms)

a=10

a=10

Answer:

a=10

20) solve:
[tex] {8}^{2} + 2 = [/tex]
21) solve:
[tex]4(2x + 5y = [/tex]
22) simplify the expression
[tex]4( {2}^{2} + 30) - 4 = [/tex]

Answers

Ques20. 66
Ques21. 8x+20y
Ques22. 132

BRAINLIET TO THE FIRST.....AND PLZZ HURRY.....
What is the volume of the oblique cone? Round to the nearest tenth.​

Answers

Formula for the volume of a cone: V = 1/3 x pi x r^2 x h

Since this is a right cone, the height is given as 8.5 and the radius is 4.

V = 1/3 x pi x 4^2 x 8.5

V = 1/3 x pi x 16 x 8.5

V = 1/3 x pi x 136

V = 45 1/3 pi

V = 142.4 cubic units

Hope this helps!

Answer:

142.4 units^3

Step-by-step explanation:

We use the same formula for volume as for a cone

V = 1/3 pi r^2 h

V = 1/3 pi (4)^2 ( 8.5)

  = 1/3 pi (16)(8.5)

Letting pi = 3.14

 =142.34666667

Rounding to the nearest tenth

  = 142.4

Point S lies between points R and T on Line segment R T. A line contains points R, S, T. The space between R and S is 2 x. The space between S and T is 3 x. If RT is 10 centimeters long, what is ST?

Answers

Answer:

[tex]ST = 6cm[/tex]

Step-by-step explanation:

Given

[tex]RS =2x[/tex]

[tex]ST = 3x[/tex]

[tex]RT = 10[/tex]

Required

Find ST

From the question, we understand that S is between R and T.

So:

[tex]RS + ST = RT[/tex]

Substitute known values

[tex]2x + 3x = 10[/tex]

[tex]5x =10[/tex]

Divide both sides by 5

[tex]x =2[/tex]

Given that:

[tex]ST = 3x[/tex]

[tex]ST = 3 * 2[/tex]

[tex]ST = 6cm[/tex]

Answer:

C or 6 centimeters

Step-by-step explanation:

Please help explanation if possible

Answers

Answer: y = -3x + 5

Step-by-step explanation:

slope = m

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{2-(-4)}{1-3}=\frac{6}{-2}=-3[/tex]

y = mx + b, (3,-4), (1,2), m = -3

(both points work for the y = mx + b equation)

[tex]y=mx+b\\2=-3(1)+b\\2=-3+b\\b=5\\y=-3x+5[/tex]

A particle moves along a line with a velocity v(t)=t2−t−6, measured in meters per second. Find the total distance the particle travels from t=0 seconds to t=4 seconds.

Answers

The total distance the particle travels from t=0 seconds to t=4 seconds would be 11.33 meters.

Used the concept of integration that states,

In Maths, integration is a method of adding or summing up the parts to find the whole. It is a reverse process of differentiation, where we reduce the functions into parts.

Given that,

A particle moves along a line with a velocity v(t) = t² - t - 6, measured in meters per second.

Now the total distance the particle travels from t=0 seconds to t=4 seconds is,

D = ∫₀⁴ |(t² - t - 6)| dt

D =  ∫₀⁴ (t²) dt - ∫₀⁴ (t) dt -  ∫₀⁴ (6) dt

D = (t³/3)₀⁴ - (t²/2)₀⁴ - 6 (t)₀⁴

D =| (64/3) - (16/2) - 6 (4)|

D = | (64/3) - 8 - 24 |

D = | (64/3) - 32|

D = 11.33 meters

Therefore, the total distance is 11.33 meters.

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