please help meeeeeeee due in 5 minutessssssssssssss

Answer:

the probability of taking a clear picture of a California candor is .24

Answer:

28°C

Step-by-step explanation:

First you do 3*19=57°C

-5+57= 52°C

then you do 4*6=24 °C

as its being cooled you takeaway

52-24=28°C

Answer:

the answer would be 100,000,000

Greatest 8 Digit Number: 99,999,999

Adding 1 = 99999999+1

= 100,000,000

Must click thanks and mark brainliest

If θ lies in the fourth quadrant, then sin(θ) < 0 and cos(θ) > 0. So we have from the Pythagorean identity,

sin²(θ) + cos²(θ) = 1   ==>   cos(θ) = +√(1 - sin²(θ)) = √21/5

Then

sec(θ) = 1/cos(θ) = 5/√21

and

tan(θ) = sin(θ)/cos(θ) = (-2/5)/(√21/5) = -2/√21

Answer:

a. 1.44

Step-by-step explanation:

We are interested in determining whether or not the proportion of the population in favor of Candidate A is significantly more than 40%.

At the null hypothesis, it is tested if the proportion is of at most 40%, that is:

[tex]H_0: p \leq 0.4[/tex]

At the alternative hypothesis, it is tested if the proportion is of more than 40%, that is:

[tex]H_1: p > 0.4[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

0.4 is tested at the null hypothesis:

This means that [tex]p = 0.4, \sigma = \sqrt{0.4*0.6}[/tex]

A random sample of 200 people was taken. 90 of the people in the sample favored Candidate A.

This means that:

[tex]n = 200, X = \frac{90}{200} = 0.45[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{0.45 - 0.4}{\frac{\sqrt{0.4*0.6}}{\sqrt{200}}}[/tex]

[tex]z = 1.44[/tex]

Thus the correct answer is given by option a.

Respuesta:

3650

Explicación paso a paso:

Dado que :

Principal, P = capital prestado

Tasa anual, r = 10% * 6 = 60%

Interés = 1140

Periodo = 6 meses y 10 días = (6 * 30) +10 = 190 días

Conversión a años:

Periodo = 190/365

Usando la relación:

Interés = principal * tasa * tiempo

1140 = P * 60% * (190/365)

1140 = 0.3123287P

P = 1140 / 0,3123287

P = 3650

Answer:

Step-by-step explanation:

D={ 6  , -9  , 1 }

R={  0  ,-3 }

Answer:

- 16

Step-by-step explanation:

The way this is given, you have to find the second term before you can fine the third.

a2 = d(n - 1) * (-2)^2

a2 = 2 * (-2)^2

a2 = 2 * 4

a2 = 8

a3 = d(3 - 1) * (-2)^3

a3 = 2 * (-2)^3

a3 = 2 * - 8

a3 = - 16

Answer:

f(x) = 6 when -5 < x ≤ -1

Step-by-step explanation:

Answer:

207 tens

Step-by-step explanation:

If you mean

8,000 + 70 = 6000 + X tens

then it should be 207 tens

Answer:

B

Step-by-step explanation:

z+z=6, z=3. z+y=5, y=2, x+y=10, x=8

Pressure is force per unit area. If the block is sitting at rest on the surface, it applies a pressure of mg/A, where mg is the block's weight and A is the area of the face that makes contact with the surface.

The smaller the value of A, the larger the pressure. So the highest pressure the block can exert is achieved when it's resting on the face with the smallest dimensions.

If the block is a cube with side length 95 cm, then the pressure exerted by each face is the same.

Answer:

MUST BE IN HLA, NOT FROM C TO ASSEMBLY.

PROGRAM 6: Same

Write an HLA Assembly language program that implements a function which correctly identifies when all four parameters are the same and returns a boolean value in AL (1 when all four values are equal; 0 otherwise). This function should have the following signature:

procedure theSam

Answer:

x=5

Step-by-step explanation:

im so bad at explaining things but i hope this helped

Answer:

24780

Step-by-step explanation:

might not be right but 24780 because 23600*5% is 1180 and add that to the original 23600 to get 24780

5% more is 105% in total, including the the 100% we start with, so:

23,600 * 1.05 = 24780

[tex]\sf\huge\underline\color{pink}{༄Answer:}[/tex]

What is the solution of the equation x^2 - 14x + 67 = 0?

[tex]\color{pink}{==========================}[/tex]

#CarryOnLearning

[tex]\sf\color{pink}{༄⁂✰Bae \: Yoonah}[/tex]

Answer:

The total lateral surface of this cube is 4*e^2

Step-by-step explanation:

A cube is a figure with all the sides of the same length, so each face of a cube is a square.

Remember that the area of a square of sidelength L is:

A = L^2

Now, when we want to find the lateral surface of a figure, we ignore the bases of the figure.

So, if a cube has 6 faces, if we ignore the two bases, we are left with 4 square faces.

And if the edge length is e, then each one of these four faces has an area:

A = e^2

So the total lateral surface is 4 times that:

S = 4*e^2

The total lateral surface of this cube is 4*e^2

Answer:

4e2

Step-by-step explanation:

I got it correct on founders edtell

Answer:

im not sure but i do have a tip when you go to goo gle i want you to simplify your question (not what you asked on here) then copy your question as it is simple then search it on here because its slightly  for others to understand

Step-by-step explanation:

.

Answer:

Step-by-step explanation:

New median:40100

New mode:385100

Answer:

The set S could, but does not have to, span Rn   ( A )

Step-by-step explanation:

Assume S is a set of linearly dependent vectors in Rn

The best statement from the options is ; The set S could, but does not have to, span Rn

This is because S could span Rn ( as stated in option c ) but will  not necessary span Rn ( as seen in option D )

First let's compute dx/dt

[tex]x = t - \frac{1}{t}\\\\x = t - t^{-1}\\\\\frac{dx}{dt} = \frac{d}{dt}\left(t - t^{-1}\right)\\\\\frac{dx}{dt} = 1-(-1)t^{-2}\\\\\frac{dx}{dt} = 1+\frac{1}{t^{2}}\\\\\frac{dx}{dt} = \frac{t^2}{t^{2}}+\frac{1}{t^{2}}\\\\\frac{dx}{dt} = \frac{t^2+1}{t^{2}}\\\\[/tex]

Now compute dy/dt

[tex]y = 2t + \frac{1}{t}\\\\y = 2t + t^{-1}\\\\\frac{dy}{dt} = \frac{d}{dt}\left(2t + t^{-1}\right)\\\\\frac{dy}{dt} = 2 - t^{-2}\\\\\frac{dy}{dt} = 2 - \frac{1}{t^2}\\\\\frac{dy}{dt} = \frac{2t^2}{t^2}-\frac{1}{t^2}\\\\\frac{dy}{dt} = \frac{2t^2-1}{t^2}\\\\[/tex]

From here, apply the chain rule to say

[tex]\frac{dy}{dx} = \frac{dy*dt}{dx*dt}\\\\\frac{dy}{dx} = \frac{dy}{dt} \times \frac{dt}{dx}\\\\\frac{dy}{dx} = \frac{dy}{dt} \div \frac{dx}{dt}\\\\\frac{dy}{dx} = \frac{2t^2-1}{t^2} \div \frac{t^2+1}{t^{2}}\\\\\frac{dy}{dx} = \frac{2t^2-1}{t^2} \times \frac{t^{2}}{t^2+1}\\\\\frac{dy}{dx} = \frac{2t^2-1}{t^2+1}\\\\[/tex]

We could use polynomial long division, or we could add 2 and subtract 2 from the numerator and do a bit of algebra like so

[tex]\frac{dy}{dx} = \frac{2t^2-1}{t^2+1}\\\\\frac{dy}{dx} = \frac{2t^2-1+2-2}{t^2+1}\\\\\frac{dy}{dx} = \frac{(2t^2+2)-1-2}{t^2+1}\\\\\frac{dy}{dx} = \frac{2(t^2+1)-3}{t^2+1}\\\\\frac{dy}{dx} = \frac{2(t^2+1)}{t^2+1}-\frac{3}{t^2+1}\\\\\frac{dy}{dx} = 2-\frac{3}{t^2+1}\\\\[/tex]

This concludes the first part of 4b

=======================================================

Now onto the second part.

Since t is nonzero, this means either t > 0 or t < 0.

If t > 0, then,

[tex]t > 0\\\\t^2 > 0\\\\t^2+1 > 1\\\\\frac{1}{t^2+1} < 1 \ \text{ ... inequality sign flip}\\\\\frac{3}{t^2+1} < 3\\\\-\frac{3}{t^2+1} > -3 \ \text{ ... inequality sign flip}\\\\-\frac{3}{t^2+1}+2 > -3 + 2\\\\2-\frac{3}{t^2+1} > -1\\\\-1 < 2-\frac{3}{t^2+1}\\\\-1 < \frac{dy}{dx}\\\\[/tex]

note the inequality signs flipping when we apply the reciprocal to both sides, and when we multiply both sides by a negative value.

You should find that the same conclusion happens when we consider t < 0. Why? Because t < 0 becomes t^2 > 0 after we square both sides. The steps are the same as shown above.

So both t > 0 and t < 0 lead to [tex]-1 < \frac{dy}{dx}[/tex]

We can say that -1 is the lower bound of dy/dx. It never reaches -1 itself because t = 0 is not allowed.

We could say that

[tex]\displaystyle \lim_{t\to0}\left(2-\frac{3}{t^2+1}\right)=-1\\\\[/tex]

---------------------------------------

To establish the upper bound, we consider what happens when t approaches either infinity.

If t approaches positive infinity, then,

[tex]\displaystyle L = \lim_{t\to\infty}\left(2-\frac{3}{t^2+1}\right)\\\\\\\displaystyle L = \lim_{t\to\infty}\left(\frac{2t^2-1}{t^2+1}\right)\\\\\\\displaystyle L = \lim_{t\to\infty}\left(\frac{2-\frac{1}{t^2}}{1+\frac{1}{t^2}}\right)\\\\\\\displaystyle L = \frac{2-0}{1+0}\\\\\\\displaystyle L = 2\\\\[/tex]

As t approaches infinity, the dy/dx value approaches L = 2 from below.

The same applies when t approaches negative infinity.

So we see that [tex]\frac{dy}{dx} < 2[/tex]

---------------------------------------

Since [tex]-1 < \frac{dy}{dx} \text{ and } \frac{dy}{dx} < 2[/tex], those two inequalities combine into the compound inequality [tex]-1 < \frac{dy}{dx} < 2[/tex]

So dy/dx is bounded between -1 and 2, exclusive of either endpoint.

Answer:

Angle b is congruent to angle E

CA=FD

Step-by-step explanation:

If _______, then triangle ABC and triangle DEF are congruent by the ASA criterion.  ASA is angle side angle .  We know angle C= angle F and side CB = side FE We need to know angle B = angle E

If _______, then triangle ABC and triangle DEF are congruent by the SAS criterion.  SAS is side angle side,  we know side CB = side FE  and then angle C= angle F then we need side CA = side FD

If ∠ABC = ∠DEF, then ΔABC and ΔDEF are congruent by the ASA criterion.

If AC = DF, then ΔABC and ΔDEF are congruent by the SAS criterion.

Two figures are said to be congruent of they have the same shape and all the corresponding sides and angles are congruent.

The HL (hypotenuse leg) congruence theorem states that if the hypotenuse and one leg of a triangle is congruent to another triangle, then both triangles are congruent.

In triangle ABC and DEF;

BC = EF and ∠ACB ≅ ∠DFE

Hence:

If ∠ABC = ∠DEF, then ΔABC and ΔDEF are congruent by the ASA criterion.

If AC = DF, then ΔABC and ΔDEF are congruent by the SAS criterion.

Find out more on congruent figures at: https://brainly.com/question/1675117

Answer:

It is E. radicand

Step-by-step explanation:

Answer:

Radicand

Step-by-step explanation:

Radicand is the number found inside the radicals

Example:

[tex]\sqrt[4]{5} ; 2\sqrt[4]{5}[/tex]  are like terms

5 -> radicand and 4 is the index

Answer:

63

Step-by-step explanation:

50+10=60 60+3=63 dollars

he spends 63$ on variable expenses

DeMoivre's theorem says

(2 (cos(12°) + i sin(12°)))⁵ = 2⁵ (cos(5×12°) + i sin(5×12°))

… = 32 (cos(60°) + i sin(60°))

… = 32 (1/2 + √3/2 i )

… = 16 + 16√3 i

Answer:

Z -0.879173965

Step-by-step explanation:

Z -0.879173965

ρ  0.5

π 0.54

n 120

The value of the test statistic is the z-score z = -0.88

The relationship between a value and the mean of a set of values is expressed numerically by a Z-score. The Z-score is computed using the standard deviations from the mean. A Z-score of zero indicates that the data point's score and the mean score are identical.

The Z-score is calculated using the formula:

z = (x - μ)/σ

where z: standard score

x: observed value

μ: mean of the sample

σ: standard deviation of the sample

Given data ,

Let the test statistic value be represented as z

Now , the probability of emergency room visitors are insured is q = 0.54

The total number of patients n = 120

The number of patients that were insured = 60

So , the percentage of people that were insured p = 60/120 = 0.5

Now , test statistic value z = ( p - q ) / [ √ ( q ( 1 - q )/n² ]

The value of z score is

z = [ 0.5 - 0.54 ] / √ 0.54 ( 1 - 0.54 ) / 120²

On simplifying the equation , we get

The value of z score is z = -0.88

Hence , the test statistic is z = -0.88

To learn more about z score click :

https://brainly.com/question/25638875

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Answer:

Y = -x + 2

Step-by-step explanation:

y = -x + 8

y = 1x + b

10 = 8 + b

b = 2

Answer:

y-y1=m(x-x1)

y-10=8(x-8)

y-10=8x-64

y-10+64-8x

y+54-8x

y-8x+54

Answer:

−3x + y = −7       y - 9 = 5 (x - 1)

Step-by-step explanation:

y2 - y1 / x2 - x1

5 - (-1) / 4 - 2

6/2

= 3

slope intercept: −3x + y = −7

y - 9 = 5 (x - 1)