Pls help thank you so much

Answer:

The answer is "Specific treatment levels".

Step-by-step explanation:

When we experimenting with 'level' which is related to the quantity or magnitude of treatment. For this part of an experiment or study, a group or individual is exposed to a specified set of circumstances. For example: If four categories are exposed to different doses of a given drug, then each dose reflects a level of a treatment factor in the model.

Answer:

71

Step-by-step explanation:

The reference angle is always the smallest angle  with the x-axis.

The nearest x axis is at 0 or another name for 0 is 360

360 -289 = 71

The reference angle is 71

Answer:

y=-4x+2

Step-by-step explanation:

Hi there!

We want to find out which equation represents a line with a slope of -4 and a y intercept of (0,2)

The most common way to write the equation of the line is in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept

We have everything we need to plug into the equation, let's just label the values to avoid confusion

m=-4

b=2 (when you substitute the y intercept as b, b is the value of y in the point)

Now substitute into the equation

y=-4x+2

Hope this helps!

9514 1404 393

Answer:

  x² -22 = 0

Step-by-step explanation:

The roots are opposites, so the equation is pretty simple.

  x = ±√22

  x² = 22 . . . . . square both sides

  x² -22 = 0 . . . . your quadratic equation in standard form

(a) We have ⌊x⌋ = 5 if 5 ≤ x < 6, and similarly ⌊x/3⌋ = 5 if

5 ≤ x/3 < 6   ==>   15 ≤ x < 18

(b) ⌊x⌋ = -2 if -2 ≤ x < -1, so ⌊x/3⌋ = -2 if

-2 ≤ x/3 < -1   ==>   -6 ≤ x < -3

In general, ⌊x⌋ = n if n ≤ x < n + 1, where n is any integer.

I do not understand what is being asked in (c) and (d), so you'll have to clarify...

9514 1404 393

Answer:

  (-5, 4)

Step-by-step explanation:

The inside corner moves from (2, -2) to (-3, 2). That is 5 is subtracted from the x-coordinate, and 4 is added to the y-coordinate. (x, y) ⇒ (x -5, y +4)

The translation vector can be written horizontally as (-5, 4), or vertically as ...

  [tex]\displaystyle\binom{-5}{4}[/tex]

The estimated slope is approximately 2.344

The given table is presented as follows;

[tex]\begin{array}{ccc}Number \ of Bids &&Price \ in \ Dollars\\1&&23\\2&&34\\4&&44\\9&&46\\10&&50\end{array}[/tex]

The regression line formula to be considered = [tex]\bar u = b_0 + b\cdot \bar x[/tex]

The required parameter is;

The estimated slope

The method to find the estimate slope;

The least squares regression formula (method) is presented as follows;

[tex]\bar u = b_0 + b\cdot \bar x[/tex]

Where;

b₀ = The y-intercept

[tex]\mathbf{ b = \dfrac{\sum \left(x_i - \bar x\right) \times \left(u_i - \bar u\right) }{\sum \left(x_i - \bar x\right )^2 } = The \ estimated \ slope}[/tex]

From MS Excel, we have;

[tex]\bar x[/tex] = 5.2, [tex]\bar u[/tex] = 39.4

[tex]\sum \left(x_i - \bar x\right) \times \left(u_i - \bar u\right)[/tex] = 156.6

[tex]{\sum \left(x_i - \bar x\right )^2 }[/tex] = 66.8

Therefore;

The estimated slope, b = 156.6/66.8 ≈ 2.344 (by rounding the answer to three decimal places)

Learn more about regression line here;

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1) I think 15 choose (d)

2) The choose (C) -4fg+4g

3) The choose (d) 3xy/2

4) The choose (a) ab/6

5) The choose (C) 2p+4q-6

6)

[tex]\pi {r}^{2} h = 3.14 \times {3}^{2} \times 1.5 = 42.39 {m}^{3} = 42.390 {m}^{3} [/tex]

Point 6 I think there is an error because the unit m must be m³ because it is r² (m²) and h(m) becomes m³.

I hope I helped you^_^

Answer:

The height of the spanning tree is one by the breadth-first search at the central vertex of Wn.

Step-by-step explanation:

The graph is connected and has a spanning tree where the tree can build using a depth-first search of the graph. Start with chosen vertex, the graph as the root, and root add vertices and edges such as each new edge is incident with vertex and vertices are not in path. If all vertices are included, it will do otherwise, move back to the next level vertex and start passing. It is for depth-first search. For breadth-first search, start with chosen vertex add all edges incident to a vertex. The new vertex is added and becomes the vertices at level 1 in the spanning tree, and each vertex at level 1 adds each edge incident to vertex and other vertex connected to the edge of the tree as long as it does not produce.

Answer:

[tex]3-5\left(a-4\right)[/tex]

[tex]-5(a-4)=-5a+20[/tex]

[tex]=3-5a+20[/tex]

[tex]=-5a+23[/tex]

OAmalOHopeO

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\text{3 - 5(a - 4)}\\\\\huge\text{\underline{\underline{DISTRUBUTE -5 within the parentheses}}}\\\\\large\text{3 - 5(a) - 5(-4)}\\\large\text{= 3 - 5a + 20}\\\\\huge\text{\underline{\underline{COMBINE the LIKE TERMS}}}\\\large\text{-5a + (3 + 20)}\\\large\text{= \bf -5a + 23}\\\\\\\boxed{\boxed{\huge\text{Therefore, your answer is: \bf -5a + 23}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!} \\\\\\\frak{Amphitrite1040:)}[/tex]

Answer:

240 cm

Step-by-step explanation:

Let x = tail   y = body

x = 30 + 1/2y

y = 30 + x

Let's plug in the x equation at the bottom

y = 30 + 30 + 1/2y

y = 60 + 1/2y

Bring the like terms to one side

y = 60 + 1/2y

-1/2y    -1/2y

1/2y = 60

Multiply both sides by 2 to get the length of the body

1/2y x 2 = 60 x 2

y = 120

Now we can plug in the new y into another equation, let's use the top one

x = 30 + 1/2(120)

x = 30 + 60

x = 90 = length of the tail

Add em all up

120 + 90 + 30 = 240

9514 1404 393

Answer:

Step-by-step explanation:

The attached shows the predicted mileage for cars built in 2025 to be 46.3 mpg, 76.2 mpg for cars built in 2050.

__

No doubt, the function is valid over the time period used to derive it. It may or may not be valid for predicting MPG beyond that period.

Virtually any function that predicts future increases without bound will turn out to be unreliable at some point. In this universe, there are always limits to growth.

Answer:

5 * 10 * 10 * 9 = 4500

Step-by-step explanation:

Answer:

It's 0

Edge said it's 0

The value of the ratio of the cos(x) and the sin(x) is 0.

Trigonometric ratios are mathematical functions that relate the angles of a right triangle to the ratios of the lengths of its sides. These ratios are fundamental in trigonometry and have applications in various fields, such as physics, engineering, and navigation.

Trigonometry is a branch of mathematics that deals with the relationships and properties of angles and triangles. It explores the ratios between the sides of a triangle and the angles within that triangle. The word "trigonometry" is derived from two Greek words: "trigonal," meaning "triangle," and "metron," meaning "measure."

The value of the sin(x) is 1. The value of cos(x) is 0.

The formula for the cot(x) is written below:

cot(x) = cos(x) / sin(x)

cot(x) = 0 / 1

cot(x) = 0

To know more about trigonometry follow

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Complete Question

Four spinners are spun. Spinner 1 has outcomes {1,2,3,4,5,6,7,8} Spinner 2 has outcomes {1,2,3,4,5,6} Spinner 3 has outcomes {1,2,3,4,5,6} Spinner 4 has outcomes {1,2,3,4,5} The outcomes for each spinner are equally likely. S is the sum of the numbers that come up on the spinners. What is the expected value of S?

Answer:

[tex]E(s)=14.5[/tex]

Step-by-step explanation:

From the question we are told that:

Spinner 1 ={1,2,3,4,5,6,7,8}

Spinner 2=  {1,2,3,4,5,6}

Spinner 3 = {1,2,3,4,5,6}

Spinner 4  {1,2,3,4,5}

Generally the equation for expected outcome is mathematically given by

[tex]E(s)=\sum P(x).x[/tex]

Where

[tex]x=\frac{n(n+1)}{2}[/tex]

For Spinner 1

[tex]E(s_1)=\sum \frac{1}{8}*\frac{8(8+1)}{2}[/tex]

[tex]E(s_1)=4.5[/tex]

For Spinner 2

[tex]E(s_2)=\sum \frac{1}{6}*\frac{6(6+1)}{2}[/tex]

[tex]E(s_2)=3.5[/tex]

For Spinner 3

[tex]E(s_2)=E(s_3)[/tex]

For Spinner 3

[tex]E(s_4)=\sum \frac{1}{6}*\frac{6(6+1)}{2}[/tex]

[tex]E(s_4)=3[/tex]

Therefore The Expected Value

[tex]E(s)=\sum E(s 1..4)[/tex]

[tex]E(s)=4.5+2(3.5)+3[/tex]

[tex]E(s)=14.5[/tex]

Answer:

Answer: Option A.

Step-by-step explanation:

Hey there!

Given; The Line BC contains points B (4, -5) and C (3, 2).

And the Line DE contains points D (2,0) and E (9, 1)

Note: Use double point formula for finding the equation and then find slopes of both then put the condition for perpendicular lines and parallel lines.

From line BC;

The points are B (4, -5) and C (3, 2).

Using double point formula;

[tex](y - y1) = \frac{y2 - y1}{x2 - x1}(x - x1) [/tex]

Keep all the value;

[tex](y + 5) = \frac{2 + 5}{3 - 4} (x - 4)[/tex]

Simplify it;

[tex]y + 5 = - 7x + 28[/tex]

Therefore, the equation is y = -7x+23........(I)And slope(m1) is -7 {comparing the equation (I) with y=Mx+c}

Again;

The points D (2,0) and E (9, 1)

Using double point formula;

[tex](y - y1) = \frac{y2 - y1}{x2 - x1} (x - x1)[/tex]

Keep all values;

[tex](y - 0) = \frac{9 - 2}{1 - 2} (x - 2)[/tex]

[tex]y = - 7x + 14[/tex]

Therefore, the equation is y = -7x+14......(ii)And the slope (m2) is -7. {comparing the equation (ii) with y= mx+c}

Check:

For parallel lines:

m1= m2

-7 = -7 (true)

Therefore, the lines are parallel.

Hope it helps!

Answer:

-3x² - 2x - 54

Step-by-step explanation:

(-7²-x-5)-(3x²+x)

-7² - x - 5 - 3x² - x

-49 - x - 5 - 3x² - x

-3x² - x - x - 49 - 5

-3x² - 2x - 54

Answer:

AB

Step-by-step explanation:

For the multiplication of two matrices to be defined then the number of columns of the first matrix must be equal to the number of rows of the second matrix. For example, 2*3 and 3*2 matrices can be multiplied since the number of columns of the first matrix must be equal to the number of rows of the second matrix.

Matrix A = 2*2

Matrix B = 2*3

Matrix C = 3*3

Matrix D = 1 * 3

From the matrices given, we can see that the matrices that can be multiplied together are AB and BC since the number of columns of the first matrix must be equal to the number of rows of the second matrix. Hence the correct option is AB

Answer:

Since [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal distribution can be used to approximate the binomial distribution.

The mean is 13.3 and the standard deviation is 3.28.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex], if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex].

The probability than an adult never had the flu is 19%.

This means that [tex]p = 0.19[/tex]

You randomly select 70 adults and ask if he or she ever had the flu.

This means that [tex]n = 70[/tex]

Decide whether you can use the normal distribution to approximate the binomial distribution

[tex]np = 70*0.19 = 13.3 \geq 10[/tex]

[tex]n(1-p) = 70*0.81 = 56.7 \geq 10[/tex]

Since [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal distribution can be used to approximate the binomial distribution.

Mean:

[tex]\mu = E(X) = np = 70*0.19 = 13.3[/tex]

Standard deviation:

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{70*0.19*0.81} = 3.28[/tex]

The mean is 13.3 and the standard deviation is 3.28.

Answer:

[tex]\frac{135}{15} =\frac{15(x+2)}{15}[/tex]

[tex]9=x+2[/tex]

[tex]x=7[/tex]

OAmalOHopeO

Answer:

Look in Step by Step Explanation

Step-by-step explanation:

3)SOHCAHTOA

tan=opposite/adjacent

tan(20)=x/83

83tan(20)=x

x=30.209

2) SOHCAHTOA

Tangent=opposite/adjacent

Tan(62)=x/8

8tan(62)=x

x=15.04

3)SOHCAHTOA

Sin=opposite/hypotonouse

sin(25)=30/x

x=30/sin(25)

x=70.986

Answer:

B, D, F

Step-by-step explanation:

In a rational exponent, the numerator is an exponent, and the denominator becomes the index of the root.

[tex]a^{\frac{m}{n}} = \sqrt[n] {a^m}[/tex]

Answer: B, D, F

First check the characteristic solution. The characteristic equation to this DE is

r ² - r = r (r - 1) = 0

with roots r = 0 and r = 1, so the characteristic solution is

y (char.) = C₁ exp(0x) + C₂ exp(1x)

y (char.) = C₁ + C₂ exp(x)

For the particular solution, we try the ansatz

y (part.) = (ax + b) exp(x)

but exp(x) is already accounted for in the second term of y (char.), so we multiply each term here by x :

y (part.) = (ax ² + bx) exp(x)

Differentiate this twice and substitute the derivatives into the DE.

y' (part.) = (2ax + b) exp(x) + (ax ² + bx) exp(x)

… = (ax ² + (2a + b)x + b) exp(x)

y'' (part.) = (2ax + 2a + b) exp(x) + (ax ² + (2a + b)x + b) exp(x)

… = (ax ² + (4a + b)x + 2a + 2b) exp(x)

(ax ² + (4a + b)x + 2a + 2b) exp(x) - (ax ² + (2a + b)x + b) exp(x)

= x exp(x)

The factor of exp(x) on both sides is never zero, so we can cancel them:

(ax ² + (4a + b)x + 2a + 2b) - (ax ² + (2a + b)x + b) = x

Collect all the terms on the left side to reduce it to

2ax + 2a + b = x

Matching coefficients gives the system

2a = 1

2a + b = 0

and solving this yields

a = 1/2, b = -1

Then the general solution to this DE is

y(x) = C₁ + C₂ exp(x) + (1/2 x ² - x) exp(x)

For the given initial conditions, we have

y (0) = C₁ + C₂ = 6

y' (0) = C₂ - 1 = 5

and solving for the constants here gives

C₁ = 0, C₂ = 6

so that the particular solution to the IVP is

y(x) = 6 exp(x) + (1/2 x ² - x) exp(x)

Answer:

Step-by-step explanation:

Our friend asking what the actual function is has a point. I completed this under the assumption that what we have is:

[tex]f(x)=\frac{e^{3x}}{5x-2}[/tex] and used the quotient rule to find the derivative, as follows:

[tex]f'(x)=\frac{e^{3x}(5)-[(5x-2)(3e^{3x})]}{(5x-2)^2}[/tex] and simplifying a bit:

[tex]f'(x)=\frac{5e^{3x}-[15xe^{3x}-6e^{3x}]}{(5x-2)^2}[/tex]and a bit more to:

[tex]f'(x)=\frac{5e^{3x}-15xe^{3x}+6e^{3x}}{(5x-2)^2}[/tex] and combining like terms:

[tex]f'(x)=\frac{11e^{3x}-15xe^{3x}}{(5x-2)^2}[/tex] and factor out the GFC in the numerator to get:

[tex]f'(x)=\frac{e^{3x}(11-15x)}{(5x-2)^2}[/tex]  That's the derivative simplified. If we want f'(0), we sub in 0's for the x's in there and get the value of the derivative at x = 0:

[tex]f'(0)=\frac{e^0(11-15(0))}{(5(0)-2)^2}[/tex] which simplifies to

[tex]f'(0)=\frac{11}{4}[/tex] which translates to

The slope of the function is 11/4 at the point (0, -1/2)

Answer:

Step-by-step explanation:

(x-2)(x+4)=x^2+4x-2x-8=0=> x =2, x=0

Answer:

A

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

Calculate the square root of 25 and get 5.

Answer:

(a) 218.6 N

(b) 97.14 N

Step-by-step explanation:

When the system is in equilibrium, the net torque on the system is zero.

AC = 1.5 m, CD = 2.3 m, DB = 5 - 1.5 - 2.3 = 1.2 m

Let the centre of gravity of plank is at G.

AG = 2.5 m, CG = 2.5 - 1.5 = 1 m, GB = 2.5 m

(a) Let the reaction at C is R and at D is R'.

R + R' = 29 x 9.8 = 284.2 N ... (1)

Take the torque about C.

29 x 9.8 x CG = R' x GD

29 x 9.8 x 1 = R' x 1.3

R' = 218.6 N

(b) Take the torque about D.

6 x 9.8 x AD = R x CD

6 x 9.8 x (1.5 + 2.3) = R x 2.3

R = 97.14 N