To test the effectiveness of the weight loss program, a PAIRED SAMPLE test distribution is used.
The weight loss data collated for the program for both the beginning and end of the program period was obtained with one subject or person having two separate readings, these shows that the samples are NOT INDEPENDENT.
When performing a test which involves DEPENDENT or MATCHED samples, whereby means of two measurements taken from the SAME subject are involved, a PAIRED SAMPLE TEST DISTRIBUTION IS ADOPTED.
Therefore, the effectiveness of the weight loss programme will be accurately evaluated using a PAIRED SAMPLE TEST.
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Oscar has 1/5 of a jar of mustard. He puts equal amounts of the mustard onto 7 sandwiches and uses all of the mustard. What fraction of a jar of mustard does each sandwich have?
Answer:
1/35 jar of mustard yuh yuh
A certain standardized test measures students’ knowledge in English and math. The English and math scores for 10 randomly selected students are given in the table.Using technology, what is the correlation coefficient?
0.68
0.83
0.91
0.95
Answer:
The answer is C
.91
ED2021
A catering company uses different functions to estimate the itemized costs for a party. The table below represents the included tip for wait staff as a function of the number of guests served.
A table showing Catering Cost for Wait Staff Gratuity with two columns and 6 rows. The first column has, Number of Guests, and has the entries, 10, 20, 30, 40, 50. The second column, Wait Staff Tip, has the entries, $18, $36, $54, $72, $90.
If the tip varies directly with the number of guests, which equation represents the relationship between the tip, t, and the number of guests, g?
t = 1.8g
t = t equals StartFraction g Over 18 EndFraction.
g = 1.8t
g = g equals StartFraction t Over 18 EndFraction.
Answer: t = 1.8g
Step-by-step explanation:
Since we are given the information that the tip varies directly with the number of guests, then the formula to use will be:
t = kg
where,
t = wait staff tip
g = number of guests
Therefore, when the number of guests is 10 and the tip is $18, the constant of proportionality will be:
t = kg
18 = 10k
k = 18/10
k = 1.8
Therefore, t = 1.8g
Answer:
A.
Step-by-step explanation:
What is 21 1/8 minus 14 1/8
Answer:
8.75
Step-by-step explanation:
211/8 = 26.375
141/8 = 17.625
now,
211/8-141/8
26.375-17.625
8.75
Helppp!!!!!
Please!!!
{ is question #1 is right?? }
{ i need help with question #2 please }
Please!!
Helppp!!!!!
Answer:
fyi b's answer has imaginary numbers in it...
Imaginary: 1 +[tex]\frac{\sqrt{2i} }{2 }[/tex]
Imaginary: 1 - [tex]\frac{\sqrt{2i} }{2 }[/tex]
Step-by-step explanation:
[tex]2x^{2} - 4x -3 = 0[/tex]
[tex]\sqrt{-4^{2} -4(2)(3)}[/tex] = [tex]\sqrt{-8}[/tex] ... the negative root will produce imaginary solutions
9514 1404 393
Answer:
1a. -4, 3/4
1b. 1-0.71i, 1+0.71i
Step-by-step explanation:
The directions tell you to use the quadratic formula. Factoring may get you the solution somewhat more easily, but does not comply with the directions.
The quadratic formula tells you ...
[tex]\text{The solution to }ax^2+bx+c=0\text{ is given by }\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
__
1a. a=4, b=13, c=-12
[tex]x=\dfrac{-13\pm\sqrt{13^2-4(4)(-12)}}{2(4)}=\dfrac{-13\pm\sqrt{361}}{8}=\dfrac{-13\pm19}{8}\\\\x=\left\{-4,\dfrac{3}{4}\right\}[/tex]
__
1b. After adding 3 to both sides, a=2, b=-4, c=3
[tex]x=\dfrac{-(-4)\pm\sqrt{(-4)^2-4(2)(3)}}{2(2)}=\dfrac{4\pm\sqrt{-8}}{4}=1\pm\dfrac{\sqrt{2}}{2}i\\\\x=\left\{1-\dfrac{\sqrt{2}}{2}i,1+\dfrac{\sqrt{2}}{2}i\right\}\approx\{1-0.71i,1+0.71i\}[/tex]
The sum of two numbers is 28. The first number, x, is three times the second number, y.
Which system of equations can be used to find the two numbers?
A system of equations. x plus y equals 28. x equals 3 plus y.
A system of equations. x y equals 28. x equals 3 y.
A system of equations. x y equals 28. x equals 3 plus y.
A system of equations. x plus y equals 28. x equals 3 y.
Answer: x plus y equals 28. x equals 3 y.
Step-by-step explanation:
The equation can be written as
x+y=28
x=3y
x is already partially solved here, so you could substitute it into the first equation to solve for y.
3y+y=28
4y=28
y=7 We have y, so substitute that in the second equation to solve for x.
x=3(7)
x=21
We now know that x=21 and y=7
Substitute the values into the first equation:
21+7=28
28=28
So that system of equations is correct.
Answer:
i think its d
Step-by-step explanation:
A young couple purchases their first new home in 2011 for $95,000. They sell it to move into a bigger home in 2018 for $105,000.
Help with this please!!!!!!!!!!!!!!
Answer:
A is the correct answer :)
Answer:
A
Step-by-step explanation:
checking if A is correct, if we get x as 76 then it is correct
if 5miles = 8 kilometers
47.5 miles= x
that is
5=8
47.5=x
cross multiply
5x=380
x=380/5
x=76
there fore A is correct
checking if B is correct, if we get x as 86 then it is correct
if 5miles = 8 kilometers
52.5 miles= x
that is
5=8
52.5=x
cross multiply
5x=420
x=420/5
x=84
therefore B is incorrect
checking if C is correct, if we get x as 34 then it is correct
if 5miles = 8 kilometers
22.5 miles=x
that is
5=8
22.5=x
Cross multiply
5x=180
x=180/5
x=36
therefore C is incorrect
checking if D is correct, if we get x as 22 then it is correct
if 5miles = 8 kilometers
12.5miles = x
that is
5=8
12.5=x
5x=100
x=100/5
x= 20
3/4 of the households in a rural area have pets. how many households have pets in this area if there are 1500 total households
Answer:
1,125 households would have pets in the area.
Step-by-step explanation:
We have 1,500 total households. We also know that 3/4 (or 0.75) of these households have pets. We would multiply 1,500 by 0.75 (which is equal to 3/4), resulting in 1,125. Therefore, 1,125 households would have pets in the area.
Answer:
1125 households
Step-by-step explanation:
3/4 of total households in area = # of households that have pets in the area
3/4 of 1500 = # of households that have pets in the area
3/4 · 1500 = # of households that have pets in the area
75/100 · 1500 = # of households that have pets in the area
0.75 · 1500 = 1125
1125 households
Write in standard form (×-3)(x+2)(x-5)
Answer: X - 3 x X + 2 x X - 5
Step-by-step explanation:
X - 3 x X + 2 x X - 5
Answer:
its (x - 3)( x^2-3x-10
Step-by-step explanation:
If the two lines below are perpendicular and the slope of the red line is
what is the slope of the green line?
A. -2/5
B. 2/5
C. 5/2
D. -5/2
Answer:
B. 2/5
Step-by-step explanation:
please help with this on the picture
Answer:
There is not enough information to solve this problem :(
Select the statement that best justifies the conclusion based on the given information.
If a(b + c) = d, then ab + ac = d.
associative
commutative
distributive
closure
Answer:
distributive
Step-by-step explanation:
a(b + c)=ab + ac
it's distributive one
Put the following equation of a line into slope-intercept form, simplifying all
fractions.
18x + 3y = -18
Answer:
y= -6x-6, I think, hope it helped
Step-by-step explanation:
help fast!! i need this asap! thank youu
5/3 is farthest according to me
Answered by Gauthmath must click thanks and mark brainliest
Answer:
0.27, 1.1, - 1/4, 5/3
Change all to decimal:-
0.27, 1.1, -.2.5, 1.67
So, 1.67 is farthest from zero
D) 5/3 is your answer
~OAmalOHopeO
A California distributor of sporting equipment expects to sell 10,000 cases of tennis balls during the coming year at a steady rate. Yearly carrying costs (to be computed on the average number of cases in stock during the year) are $10 per case, and the cost of placing an order with the manufacturer is $45. Determine the economic order quantity, that is, the order quantity that minimizes the inventory cost.
The economic order quantity is 300 cases of tennis balls.
The economic order quantity (EOQ) is the minimum quantity that the distributor can order per order to minimize inventory costs.
Data and Calculations:
Sales of tennis balls for the coming year = 10,000 units
Carrying (holding) costs per case = $10
Cost of placing orders with the manufacturer = $45 per order
Economic Order Quantity (EOQ) = square root of (2 * Annual Demand/Sales * Ordering cost)/Carrying cost per case
= square root of (2 * 10,000 * $45)/$10
= square root of 90,000
= 300 cases of tennis balls
This implies that the distributor will place about 33 orders (10,000/300) in the coming year. With each order, the quantity placed is 300 units.
Thus, the economic order quantity that will minimize the California distributor's inventory costs for the year is 300 cases of tennis balls.
Learn more about economic order quantity here: https://brainly.com/question/9068415
According to the Federal Election Commission, 53.6% of all registered voters in 2012 voted in the US presidential elections in 2012. A political study conducted in January 2016 surveyed 1,251 eligible voters and found that 86% said they planned to vote in the 2016 presidential election. Based on this information, match each term to its value.
1. 1,251
2. 53.6%
3. 86%
a. statistic
b. sample size
c. parameter
Answer:
SEE BELOW
Step-by-step explanation:
1. sample size - 1,251
2 .statistic - 53.6%
3. parameter - 86%
hope this helps :)
The half-life of a radioactive substance is 20 years. If you start with some amount of this substance, what fraction will remain in 180 years?
Answer:
1/512
Step-by-step explanation:
Let staring fraction = x
Half-life = 20 years ; this is the time taken for an element to decrease to half of its original size
Hence,
After 20 years - - - > x/2
After 40 years - - - - > x/2 ÷ 2 = x/2 * 1/2 = x /4
After 60 years - - - - > x/4 ÷ 2 = x/4 * 1/2 = x/8
After 80 years - - - - -> x/8 ÷ 2 = x/8 * 1/2 = x / 16
After 100 years - - - > x/16 * 1/2 = x/32
After 120 years - - - - > x/32 * 1/2 = x/64
After 140 years - - - - -> x / 64 * 1/2 = x / 128
After 160 years - - - - - > x / 128 * 1/2 = x/256
After 180 years - - - - > x/256 * 1/2 = x / 512
Hence, the fraction after 180 years = 1/512
helppp outt plss....
============================================================
Explanation:
For any cyclic quadrilateral (aka inscribed quadrilateral), the opposite angles are always supplementary.
One pair of such angles is A and C
A+C = 180
x+y = 180 is one equation to form
The other pair of supplementary angles is B and D
B+D = 180
y-45+2x+15 = 180
2x+y-30 = 180
2x+y = 180+30
2x+y = 210 is the other equation to form
--------------
So the system of equations we have is
[tex]\begin{cases}x+y = 180\\2x+y = 210\end{cases}[/tex]
Both equations involve 'y', with the same coefficient, so we can subtract straight down to eliminate this variable.
The x terms subtract to x-2x = -xThe y terms subtract to y-y = 0y = 0, so the y terms go awayThe right hand sides subtract to 180-210 = -30We end up with -x = -30 which solves to x = 30
--------------
Once we know x, we can determine y by plugging it into any equation involving x,y and solving for y
Let's say we picked on the first equation
x+y = 180
30+y = 180
y = 180-30
y = 150
Or we could pick on the second equation
2x+y = 210
2(30) + y = 210
60+y = 210
y = 210-60
y = 150
Only one equation is needed. However, doing both like this shows that we get the same y value, and it helps confirm the answers.
Square root of 33324324323
The Square root of 33324324323 is 182549.511977.
A line passes through the point (-2,4) and has a slope of 7. Write an equation for this line
Answer: y = 7x + 18
Step-by-step explanation:
y = mx + b, (-2,4), m = 7
4 = 7(-2) + b
4 = -14 + b
b = 18
y = 7x + 18
Find the solutions of the quadratic equation x2 + 7x + 10 = 0.
Question 13 options:
A)
x = 2, 5
B)
x = –2, –5
C)
x = –7, –3
D)
x = 7, 3
Answer:
Step-by-step explanation:
x² + 7x + 10 = 0
x = [-7 ± √(7² - 4·1·10)]/(2·1) = [-7 ± √9[/2 = [-7 ± 3]/2 = -2, -5
Given the following absolute value function find the range.
f(x) = |x + 5| -8
Range: [5,00)
Range: [-5,00)
Range: [-8,00)
Range: [8,00)
Answer:
Range is (-8,00)
Step-by-step explanation:
Use the image below, answer the following questions. Be sure to answer all 3 questions in order.
Answer:
a. Yes
b. VT
c. Segment RQ
Step-by-step explanation:
a. Find the slope of RS and UV
Slope = rise/run
Slope of RS = rise/run = RQ/QS
Slope of RS = 6/6
Slope of RS = 1
Slope of UV = rise/run = UT/TV
Slope of UV = 3/3
Slope of UV = 1
Thus, TS and UV have equivalent slopes
b. Slope of VT:
VT is an horizontal line.
It has no rise. But only run.
Therefore, it's rise = 0, while run = VT = 3
Slope of VT = rise/run = 0/3
Slope of VT = 0
c. Vertical lines have undefined slope.
Segment RQ is vertical line and therefore has an undefined slope.
RQ has rise but no run.
Thus:
Rise = 6
Run = 0
Slope of Segment RQ = 6/0 (this can't divide)
Therefore, slope of Segment RQ is undefined.
11. The coordinates of AABC are A(-1,1), B(3,3),
and C(4, -2). Find the coordinates of points A', B',
and C' under the translations that take
a. P(0,0) to Q(1,3)
b. P(0, -1) to Q(4,-2)
c. P(-1,-2) to Q(-2,2)
Answer:
See explanation
Step-by-step explanation:
Given
[tex]A = (-1,1)[/tex]
[tex]B = (3,3)[/tex]
[tex]C =(4,-2)[/tex]
Solving (a): [tex]P(0,0) \to Q(1,3)[/tex]
This means that:
[tex](x,y) \to (x+1,y+2)[/tex]
So, we have:
[tex]A = (-1,1)[/tex]
[tex]A' = (-1 + 1,1+2)[/tex]
[tex]A' = (0,3)[/tex]
[tex]B = (3,3)[/tex]
[tex]B'= (3 + 1,3+2)[/tex]
[tex]B'= (4,5)[/tex]
[tex]C =(4,-2)[/tex]
[tex]C' = (4+1,-2+1)[/tex]
[tex]C' = (5,-1)[/tex]
Solving (b): [tex]P(0,-1) \to Q(4,-2)[/tex]
This means that:
[tex](x,y) \to (x+4,y-1)[/tex]
So, we have:
[tex]A = (-1,1)[/tex]
[tex]A' = (-1+4,1-1)[/tex]
[tex]A' = (3,0)[/tex]
[tex]B = (3,3)[/tex]
[tex]B'= (3+4,3-1)[/tex]
[tex]B'= (7,2)[/tex]
[tex]C =(4,-2)[/tex]
[tex]C' = (4+4,-2-1)[/tex]
[tex]C' = (8,-3)[/tex]
Solving (c): [tex]P(-1,-2) \to Q(-2,-2)[/tex]
This means that:
[tex](x,y) \to (x-1,y)[/tex]
So, we have:
[tex]A = (-1,1)[/tex]
[tex]A' = (-1-1,1)[/tex]
[tex]A' = (-2,1)[/tex]
[tex]B = (3,3)[/tex]
[tex]B'= (3-1,3)[/tex]
[tex]B'= (2,3)[/tex]
[tex]C =(4,-2)[/tex]
[tex]C'= (4-1,-2)[/tex]
[tex]C'= (3,-2)[/tex]
You wish to have $2000 in 3 years to buy a fancy new stereo system. How much
should you deposit each quarter into an account paying 6% compounded quarterly?
Answer:
The correct answer is - $1977.7913.
Step-by-step explanation:
Given:
Maturity value = 2000
time = 3 years
rate = 6% compounded quarterly
Solution:
If A is the Maturity Value, P is the Principal Amount, r is the Rate of Return, n is the Frequency And t is the Time in Year then the Formula for Compound Interest would be -
A = P(1+r/n)^nt
Putting the given values in formula,
2000 = P*(1 + (0.06/4))^(3*4)
P = 2000/(1 + (0.06/4))^(3*4)
Thus,
P = $1977.7913
what is the uniqueness of comeplex integration from line integaration?
PLEASE HELP ASAP!!!!
What is the square of 22?
A.44
B.444
C.844
D.484
The term "downers" refers to ..
Lucinda is writing a coordinate proof to show that a diagonal of a parallelogram partitions the parallelogram into two equal areas.
A parallelogram graphed on a coordinate plane. The vertices of rectangle are labeled as K L M and N. The vertex labeled as K lies on begin ordered pair 0 comma 0 end ordered pair. The vertex labeled as L lies on begin ordered pair x comma 2 y end ordered pair. The coordinate of vertex M is left blank. The vertex labeled as N lies on begin ordered pair 3 x comma 0 end ordered pair. A diagonal is drawn between points K and M.
Enter your answers in the boxes to complete Lucinda's proof.
Since KLMN is a parallelogram and a parallelogram's opposite sides are parallel and congruent, the coordinates for M are (4x, 2y).
In △KMN, the length of the base is and the height is . So an expression for the area of △KMN is .
In △KLM, the length of the base is 3x and the height is 2y. So an expression for the area of △KLM is .
Comparing the area of the two triangles that are formed by a diagonal of the parallelogram shows that a diagonal of a parallelogram partitions the parallelogram into two equal areas.
9514 1404 393
Answer:
ΔKMN: base, 3x; height, 2y; area, 3xyΔKLM: area, 3xyStep-by-step explanation:
ΔKMNThe base length is the length of the horizontal line segment KN. That length is the difference of the x-coordinates: 3x -0 = 3x.
The height is the difference of the y-coordinate of point M and the y-coordinate of horizontal segment KN. That difference is 2y -0 = 2y.
The area is half the product of base and height:
A = (1/2)bh
A = 1/2(3x)(2y) = 3xy
In ΔKMN, the length of the base is 3x and the height is 2y. So an expression for the area of ΔKMN is 3xy.
__
ΔKLMIn ΔKLM, the length of the base is 3x and the height is 2y. So an expression for the area of ΔKLM is 3xy.
