The area of a rectangular dog run can be no more than 120 square feet. The length is 15 feet. What is the width of the dog run.

Answers

Answer 1

Answer:

Length x width= answer

so 15 x 8 = 120

Step-by-step explanation:


Related Questions

PLease Help! I will give you the brainiest and a lot of points

A survey of 104 college students was taken to determine the musical styles they liked. Of​ those, 22 students listened to​ rock, 23 to​ classical, and 24 to jazz.​ Also, 10 students listened to rock and​ jazz, 8 to rock and​ classical, and 8 to classical and jazz.​ Finally, 6 students listened to all three musical styles. Construct a Venn diagram and determine the cardinality for each region. Use the completed Venn Diagram to answer the following questions.

a. How many listened to only rock​ music?
n​(only ​rock)

b. How many listened to classical and​ jazz, but not​ rock?
n​(classical and​ jazz, not ​rock)

c. How many listened to classical or​ jazz, but not​ rock?
n​(classical or​ jazz, not ​rock)

d. How many listened to music in exactly one of the musical​ styles?
n​(exactly one ​style)

e. How many listened to music in exactly two of the musical​ styles?
n​(exactly two ​styles)

f. How many did not listen to any of the musical​ styles?
n​(none)

Answers

Answer:

A. 22

B. 8

C. 23 + 24

D. 22 + 23 + 24

E. 8 + 8 + 10

F. 104 - (sum of all the given numbers) = 3

Of the respondents, 502 replied that America is doing about the right amount. What is the 95 % confidence interval for the proportion of all American adults who feel that America is doing about the right amount to protect the environment?

Answers

Answer:

The 95 % confidence interval for the proportion of all American adults who feel that America is doing about the right amount to protect the environment is (0.461, 0.543), considering [tex]n = 1000[/tex]

Step-by-step explanation:

Incomplete question, so i will suppose this is a sample of 1000.

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

Of the n respondents, 502 replied that America is doing about the right amount.

Supposing [tex]n = 1000[/tex], so [tex]\pi = \frac{502}{1000} = 0.502[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].  

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.502 - 2.575\sqrt{\frac{0.502*0.498}{1000}} = 0.461[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.502 + 2.575\sqrt{\frac{0.502*0.498}{1000}} = 0.543[/tex]

The 95 % confidence interval for the proportion of all American adults who feel that America is doing about the right amount to protect the environment is (0.461, 0.543), considering [tex]n = 1000[/tex]

I need help in understanding and solving quadratic equations using the quadratic formula

x^2+8x+1=0​

Answers

Answer:

Exact Form: -4⊥√15

Decimal Form:

0.12701665

7.87298334

Solve the equation by factoring: 5x^2 - x = 0

Answers

Answer:

Step-by-step explanation:

x = 0, 1/5

write your answer in simplest radical form​

Answers

9514 1404 393

Answer:

  4√2

Step-by-step explanation:

In a 30°-60°-90° triangle, the ratio of side lengths is ...

  1 : √3 : 2

That is, the hypotenuse (c) is double the short side (2√2).

  c = 4√2

Answer pleaseeeeeeee

Answers

Answer:

17x^2-9x-9 -->B

Step-by-step explanation:

7x^2 -12x +3 +10x^2+3x-12

Which fraction is equivalent to 3/-5? Please help ASAP

Answers

Answer:

-3/5

Step-by-step explanation:

3/ -5 is also equal to -3/5  or - (3/5)

I need help answering this question thank guys

Answers

Multiply exponents: 1/6 x 6 = 1
You get: 12^1 which = 12
The answer for this question is D. 12

PLZ HELP QUESTION IN PICTURE

Answers

Answer: [tex]-\frac{9}{2}, -4, -3, -\frac{11}{4}, -2[/tex]

Step-by-step explanation:

slope = m

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{-7-9}{-1-(-5)}=-4[/tex]

y = mx + b, (-5,9), (-1,-7), m = -4; (does not matter which point you plug in)

[tex]y=mx+b\\9=-4(-5)+b\\9=20+b\\b=-11\\y=-4x-11[/tex]

(now plug in each y value into the equation above)

[tex]7=-4x-11\\18=-4x\\x=-\frac{9}{2}\\\\5=-4x-11\\16=-4x\\x=-4\\\\1=-4x-11\\12=-4x\\x=-3\\\\0=-4x-11\\11=-4x\\x=-\frac{11}{4} \\\\-3=-4x-11\\8=-4x\\x=-2[/tex]



Write –0.38 as a fraction.

Answers

Answer:

-19/50

Step-by-step explanation:

Answer:

-19/50

Step-by-step explanation:

.Part D. Analyze the residuals.
Birth weight
(pounds)
Adult weight
(pounds)
Predicted
adult weight
Residual
1.5
10

3
17

1
8

2.5
14

0.75
5

a. Use the linear regression equation from Part C to calculate the predicted adult weight for each birth weight. Round to the nearest hundredth. Enter these in the third column of the table.

b. Find the residual for each birth weight. Round to the nearest hundredth. Enter these in the fourth column of the table.

c. Plot the residuals.

d. Based on the residuals, is your regression line a reasonable model for the data? Why or why not? ​

Answers

Answer:

Hi there! The answers will be in the explanation :D

Step-by-step explanation:

a) I'll attach a doc for the table so it'll basically answer a and b.

c) I'll also attach the graph.

d) I'm not entirely sure for this question, but I'll do my best to answer it correctly for you. I would say no, because we can see that the residuals are all positive, but the graph we're looking is going down which means it's negative. We can also see the table is increasing a bit so it doesn't really make any sense...

Hope this helped you!

5 oranges weigh 1.5 kg, 8 apples weigh 2 kg. What would be the total weight of 3 apples and 4 oranges?

Answers

Answer: oranges 1.2 Kg and apples 0.75 Kg.

Step-by-step explanation:

Oranges (4)(1.5)/5

Apples (3)(2)/8

Find the area of each figure one of the sides are 8.3cm it’s a square btw

Answers

Answer:

68.89 cm

Step-by-step explanation:

8.3 X 8.3 would equal 68.89 cm. We can see that one side is 8.3 cm, and the other sides don't say their sides, so the only number we will use for multiplying is 8.3, and all sides of the square will be 8.3. The equation is L X W, where L is the length, and W is the width. Since 8.3 is on all four sides, it will also be the length and the width on the equation. As a result, 68.89 cm would be the final answer.

Answer:

I don't real know if this is right, but I think its this:

68.89 cm2 is the area.

Find hypotenuse,perpendicular and base​

Answers

Answer:

Hypotenuse = XY = 17 cm

Base = YZ = 15 cm

Perpendicular = XZ = 8 cm

Can I pleaseee have help with all 3 parts of this ? Thank you :D

Answers

Answer:

Part A:

the first step is to work out the brackets by multiplying the coefficients outside the brackets by everything in the brackets.

Part B:

5(3x-4)=-2(6x-9)

15x-20=-12x+18

Part C:

15x-20=-12x+18

15x+12x=18+20

27x/27=38/27

x=1.407

I hope this helps

What is the minimum perimeter of a rectangle with an area of 625 mm^2

Answers

130 mm^2 your welcome

A photographer bought 35 rolls for $136.44 what was the price of one roll

Answers

Answer:

$3.90

Step-by-step explanation:

136.44/35= (rounded tot the nearest hundredth) $3.90

Answer:

136.44÷36 =3.79

3.79×36=136.44

Step-by-step explanation:

So one ball cost 3. 79

There are 5 members on a board of directors. If they must elect a chairperson, a secretary, and a treasurer, how many different slates of candidates are possible?

Answers

Answer:

60

Step-by-step explanation:

To begin, we can look at combinations and permutations. A permutation or combination is when we need to find how many possibilities there are to choose a certain amount of objects (in this case, candidates) given an array of options (members on the board)

Combinations are when the order doesn't matter, and permutations are when the order does matter. Here, we know that we care whether someone is chairperson or secretary. If we were to just choose three for an "elite" board, and there were no specific positions in the board, then order would not matter. However, because it does matter which person gets which role, order does matter.

Assuming that someone cannot have more than one role, we know that this is a permutation without repetition. The formula for this is

(n!) / (n-r)!, where we have to choose from n number of people and choose r number of people. We have 5 members to choose from, and 3 people to choose, making our equation

(5!) / (5-3)! = 120 / 2! = 120/2 = 60

Graph the complex numbers in the complex plane

Answers

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The imaginary value is plotted on the vertical axis in the same way that the y-coordinate would be for an ordered pair (x, y). Similarly, the real value is plotted on the horizontal axis.

__

I find it helpful to think of the complex number a+bi as equivalent to the ordered pair (x, y) = (a, b) when it comes to graphing.

A rational expression is​ _______ for those values of the​ variable(s) that make the denominator zero.

Answers

9514 1404 393

Answer:

  undefined

Step-by-step explanation:

A rational expression is undefined when its denominator is zero.

Put the following equation of a line into slope-intercept form, simplifying all
fractions.
3x + 6y = -42

Answers

Answer:

y = -1/2x -7

Step-by-step explanation:

3x + 6y = -42

Slope intercept form is

y = mx+b where m is the slope and b is the y intercept

Subtract 3x from each side

3x-3x+6y = -3x-42

6y = -3x-42

Divide each side by 6

6y/6 = -3x/6 - 42/6

y = -1/2x -7

For f(x) = 4x2 + 13x + 10, find all values of a for which f(a) = 7.

the solution set is ???

Answers

Answer:

f(7)=109

Step-by-step explanation:

Since f(a)=7 then you just imput 7 on each x like this f(7)=8+13(7)+10= 109

The prices of paperbacks sold at a used bookstore are approximately Normally distributed, with a mean of $7.85 and a standard deviation of $1.25.


Use the z-table to answer the question.


If the probability that Joel randomly selects a book in the D dollars or less range is 56%, what is the value of D?


$4.46

$7.75

$8.04

$8.10

(C) 8.04

Answers

Answer:

The answer you want is indeed, (C).

8.04

ED2021

Answer:

C) 8.04

Step-by-step explanation:

edge 2023

What is the x intercept of the graph that is shown below? Please help me

Answers

Answer:

(-2,0)

Step-by-step explanation:

The x intercept is the value when it crosses the x axis ( the y value is zero)

x = -2 and y =0

(-2,0)

Bà B đến ngân hàng ngày 05/05/2019 để gửi tiết kiệm 250 triệu đồng thời hạn 3 tháng, lãi suất 7%/năm, NH trả lãi định kỳ hàng tháng (kỳ lĩnh lãi đầu tiên là ngày 05/05/2019). Đến ngày 05/08/2019, bà B tất toán sổ tiết kiệm trên. Tính số tiền bà B nhận được vào ngày đáo hạn sổ tiết kiệm là? (Cơ sở công bố lãi suất là 365 ngày)

Answers

Answer:

Ask in English then I can help u

Can someone help me find the answer?

Answers

Answer:

a. x = 3/a

Step-by-step explanation:

Add all like terms on left hand side of the equation:

5 ax + 3 ax => 8 ax

Bring like term 4ax on left hand side

8ax - 4ax

=> 4ax

Therefore we get 4ax = 12

ax = 12/4

ax = 3

x = 3/a

[tex]\int\limits^a_b {(1-x^{2} )^{3/2} } \, dx[/tex]

Answers

First integrate the indefinite integral,

[tex]\int(1-x^2)^{3/2}dx[/tex]

Let [tex]x=\sin(u)[/tex] which will make [tex]dx=\cos(u)du[/tex].

Then

[tex](1-x^2)^{3/2}=(1-\sin^2(u))^{3/2}=\cos^3(u)[/tex] which makes [tex]u=\arcsin(x)[/tex] and our integral is reshaped,

[tex]\int\cos^4(u)du[/tex]

Use reduction formula,

[tex]\int\cos^m(u)du=\frac{1}{m}\sin(u)\cos^{m-1}(u)+\frac{m-1}{m}\int\cos^{m-2}(u)du[/tex]

to get,

[tex]\int\cos^4(u)du=\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{4}\int\cos^2(u)du[/tex]

Notice that,

[tex]\cos^2(u)=\frac{1}{2}(\cos(2u)+1)[/tex]

Then integrate the obtained sum,

[tex]\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int\cos(2u)du+\frac{3}{8}\int1du[/tex]

Now introduce [tex]s=2u\implies ds=2du[/tex] and substitute and integrate to get,

[tex]\frac{3\sin(s)}{16}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int1du[/tex]

[tex]\frac{3\sin(s)}{16}+\frac{3u}{4}+\frac{1}{4}\sin(u)\cos^3(u)+C[/tex]

Substitute 2u back for s,

[tex]\frac{3u}{8}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\sin(u)\cos(u)+C[/tex]

Substitute [tex]\sin^{-1}[/tex] for u and simplify with [tex]\cos(\arcsin(x))=\sqrt{1-x^2}[/tex] to get the result,

[tex]\boxed{\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C}[/tex]

Let [tex]F(x)=\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C[/tex]

Apply definite integral evaluation from b to a, [tex]F(x)\Big|_b^a[/tex],

[tex]F(x)\Big|_b^a=F(a)-F(b)=\boxed{\frac{1}{8}(a\sqrt{1-a^2}(5-2a^2)+3\arcsin(a))-\frac{1}{8}(b\sqrt{1-b^2}(5-2b^2)+3\arcsin(b))}[/tex]

Hope this helps :)

Answer:[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(a) + 2a(1 - a^2)^\Big{\frac{3}{2}} + 3a\sqrt{1 - a^2}}{8} - \frac{3arcsin(b) + 2b(1 - b^2)^\Big{\frac{3}{2}} + 3b\sqrt{1 - b^2}}{8}[/tex]General Formulas and Concepts:

Pre-Calculus

Trigonometric Identities

Calculus

Differentiation

DerivativesDerivative Notation

Integration

IntegralsDefinite/Indefinite IntegralsIntegration Constant C

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                    [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

U-Substitution

Trigonometric Substitution

Reduction Formula:                                                                                               [tex]\displaystyle \int {cos^n(x)} \, dx = \frac{n - 1}{n}\int {cos^{n - 2}(x)} \, dx + \frac{cos^{n - 1}(x)sin(x)}{n}[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx[/tex]

Step 2: Integrate Pt. 1

Identify variables for u-substitution (trigonometric substitution).

Set u:                                                                                                             [tex]\displaystyle x = sin(u)[/tex][u] Differentiate [Trigonometric Differentiation]:                                         [tex]\displaystyle dx = cos(u) \ du[/tex]Rewrite u:                                                                                                       [tex]\displaystyle u = arcsin(x)[/tex]

Step 3: Integrate Pt. 2

[Integral] Trigonometric Substitution:                                                           [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \int\limits^a_b {cos(u)[1 - sin^2(u)]^\Big{\frac{3}{2}} \, du[/tex][Integrand] Rewrite:                                                                                       [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \int\limits^a_b {cos(u)[cos^2(u)]^\Big{\frac{3}{2}} \, du[/tex][Integrand] Simplify:                                                                                       [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \int\limits^a_b {cos^4(u)} \, du[/tex][Integral] Reduction Formula:                                                                       [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{4 - 1}{4}\int \limits^a_b {cos^{4 - 2}(x)} \, dx + \frac{cos^{4 - 1}(u)sin(u)}{4} \bigg| \limits^a_b[/tex][Integral] Simplify:                                                                                         [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3}{4}\int\limits^a_b {cos^2(u)} \, du[/tex][Integral] Reduction Formula:                                                                          [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg|\limits^a_b + \frac{3}{4} \bigg[ \frac{2 - 1}{2}\int\limits^a_b {cos^{2 - 2}(u)} \, du + \frac{cos^{2 - 1}(u)sin(u)}{2} \bigg| \limits^a_b \bigg][/tex][Integral] Simplify:                                                                                         [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3}{4} \bigg[ \frac{1}{2}\int\limits^a_b {} \, du + \frac{cos(u)sin(u)}{2} \bigg| \limits^a_b \bigg][/tex][Integral] Reverse Power Rule:                                                                     [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3}{4} \bigg[ \frac{1}{2}(u) \bigg| \limits^a_b + \frac{cos(u)sin(u)}{2} \bigg| \limits^a_b \bigg][/tex]Simplify:                                                                                                         [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3cos(u)sin(u)}{8} \bigg| \limits^a_b + \frac{3}{8}(u) \bigg| \limits^a_b[/tex]Back-Substitute:                                                                                               [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(arcsin(x))sin(arcsin(x))}{4} \bigg| \limits^a_b + \frac{3cos(arcsin(x))sin(arcsin(x))}{8} \bigg| \limits^a_b + \frac{3}{8}(arcsin(x)) \bigg| \limits^a_b[/tex]Simplify:                                                                                                         [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(x)}{8} \bigg| \limits^a_b + \frac{x(1 - x^2)^\Big{\frac{3}{2}}}{4} \bigg| \limits^a_b + \frac{3x\sqrt{1 - x^2}}{8} \bigg| \limits^a_b[/tex]Rewrite:                                                                                                         [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(x) + 2x(1 - x^2)^\Big{\frac{3}{2}} + 3x\sqrt{1 - x^2}}{8} \bigg| \limits^a_b[/tex]Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:              [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(a) + 2a(1 - a^2)^\Big{\frac{3}{2}} + 3a\sqrt{1 - a^2}}{8} - \frac{3arcsin(b) + 2b(1 - b^2)^\Big{\frac{3}{2}} + 3b\sqrt{1 - b^2}}{8}[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

A square prism and a cylinder have the same height. The area of the cross-section of the square prism is 628 square units, and the area of the cross-section of the cylinder is 200π square units. Based on this information, which argument can be made?
The volume of the square prism is one third the volume of the cylinder.
The volume of the square prism is half the volume of the cylinder.
The volume of the square prism is equal to the volume of the cylinder.
The volume of the square prism is twice the volume of the cylinder.

Answers

Answer:

C. The volume of the square prism is equal to the volume of the cylinder.

Step-by-step explanation:

I took the test and it was right

What is the volume of the cylinder below?

Answers

Answer:

A

Step-by-step explanation:

v=πr2h

r=(3)²* 5

45π unit³

Consider a study conducted to determine the average protein intake among an adult population. Suppose that a confidence level of 85% is required with an interval about 10 units wide . If a preliminary data indicate a standard deviation of 20g . What sample of adults should be selected for the study?​

Answers

Answer:

With an ageing population, dietary approaches to promote health and independence later in life are needed. In part, this can be achieved by maintaining muscle mass and strength as people age. New evidence suggests that current dietary recommendations for protein intake may be insufficient to achieve this goal and that individuals might benefit by increasing their intake and frequency of consumption of high-quality protein. However, the environmental effects of increasing animal-protein production are a concern, and alternative, more sustainable protein sources should be considered. Protein is known to be more satiating than other macronutrients, and it is unclear whether diets high in plant proteins affect the appetite of older adults as they should be recommended for individuals at risk of malnutrition. The review considers the protein needs of an ageing population (>40 years old), sustainable protein sources, appetite-related implications of diets high in plant proteins, and related areas for future research.

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