Newton's second law and universal gravitation law allow to find the results for questions about the motion of satellites in orbit are:
1) The correct answer is D: v = 8.17 10³ m/s
2) The correct answer is B
The velocity of Satellite A is greater than the velocity of Satellite B.
3) The correct answer is B
Toward the center of Earth
4) The correct answer is B
The gravitational force increases and the velocity increases.
Newton's second law establishes a relationship between force, mass, and the acceleration of bodies.
F = m a
In the case of the satellite the force is given by the law of universal gravitation.
[tex]F = - G \frac{Mm}{r^2 }[/tex]
Where G is the constant of universal gravitation. M and m the mass of each object and r the distance between them.
In this case the satellite is in a circular orbit, therefore the acceleration is centripetal.
[tex]a = \frac{v^2}{r}[/tex]
We substitute.
[tex]G \frac{Mm}{r^2} = m \frac{v^2}{r}[/tex]
[tex]\frac{GM}{r} = v^2[/tex]
Let's analyze the answers to find the correct one.
1) They indicate the height of the space station r = 4.08 10⁵ m and ask the speed.
[tex]v= \sqrt{ \frac{6.67 \ 10 ^{-11} 5.9 \ 10^{24}}{4.08 \ 10^6 } }[/tex]
v = 9.82 10³ m / s
The correct answer is D.
2) Satellite A has an orbit of hₐ = 500 km and satellite b an orbit of
h_b = 800 km
The distance from the center of the earth to each satellite is:
rₐ = R + hₐ
r_b = R + h_b
rₐ = 6.37 106 + 500 10³ = 6.87 10⁶ m
r_b = 6.37 10⁶ + 800 10³ = 7.17 10⁶ m
Let's find the ratio of the speeds
[tex]\frac{v_a}{v_b} = \sqrt{ \frac{r_b}{r_a} } \\\frac{v_a}{v_b} = \sqrt{ \frac{7.17}{6.87} }[/tex]
[tex]\frac{v_a}{v_b}[/tex] = 1,022
we see that the speed of satellite a is slightly greater than the speed of satellite b.
Let's analyze the claims.
A) False. The speed does not depend on the mass of the satellites.
B) True. The velocity of a is slightly greater than the velocity of b.
C) False. The speed of a is greater.
D) False. The speed of a is greater.
3) As the orbit is circular, the force must be radial, that is, it points towards the center of the earth.
Let's analyze the claims.
A) False. The speed modulus does not change, therefore there is no acceleration in the direction of the satellite.
B) True. Aim for the center of the Earth, change the direction of the velocity.
C) False. Aim for the scepter of the earth.
D) false. The modulus of velocity is constant and the direction changes towards the center of the earth, therefore the force must go towards the center of the earth.
4) The force in the law of universal gravitation increased as the distance decreased.
When a satellite approaches the earth its speed must increase since the speed is proportional in inverse of the square root of the distance.
Let's examine the claims.
A) False. The attraction force increases.
B) True. You agree with the explanation.
C) False. The gravitational force increases.
D) False. Speed increases.
In conclusion, using Newton's second law and the universal law of gravitation we can find the results for the questions about the movement of satellites in orbit are:
1) The correct answer is D: v = 8.17 10³ m/s
2) The correct answer is B
The velocity of Satellite A is greater than the velocity of Satellite B.
3) The correct answer is B
Toward the center of Earth
4) The correct answer is B
The gravitational force increases and the velocity increases.
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Answer:
1. 7.66 × 10^3 m/s
2. The velocity of Satellite A is greater than the velocity of Satellite B.
3. toward the center of Earth
4. The gravitational force increases and the velocity increases.
Explanation:
what are the ending materials produced from cell respiration
Answer:
The products of cellular respiration are carbon dioxide and water
Explanation:
please help answer the question in the image!!!
Answer:
C (only)
Explanation:
Often, we consider the 0 position on a graph like this to be the starting point. However, the position on this graph is indicated as positive at time = 0. The motion shown can be described in each stage as follows.
A: moving away from the starting position toward the reference position (position = 0)
B: stationary at the reference position
C: moving away from the reference position toward the starting position
D: stationary at a point just short of the starting position
E: moving away from the starting position toward, then beyond, the reference position
what is the definition for the term Resistance?
Answer:
Hey mate....
Explanation:
This is ur answer.....
There are 2 definitions :-
The refusal to accept or comply with something.The ability not to be affected by something, especially adversely.Hope it helps!
Brainliest pls!
Follow me! :)
What is the acceleration of an object if it starts at a speed of 3 m/s and increases to
8 m/s in 20 seconds?
Answer:
0.25 meters per second squared
Explanation:
Can the velocity of a body reverse the direction when acceleration is constant? If you think so, give an example.
Consider a particle moving to the left with some speed v. If we take leftward to be the negative direction, then the particle's velocity is -v, and it's moving in the negative direction.
Now give the particle a positive acceleration pointing rightward. The particle will eventually slow to a stop before increasing its speed in the positive direction.
So the answer is yes, the direction in which a body is moving can be reversed with constant acceleration.
You are handed two mystery materials, and told to find out which materials accepts negative charges more easily. A positively-charged, helium-filled balloon is tied to a tabletop with a string a meter long. What's a simple experiment you could run to find out which material accepts electrons more easily?
The simple experiment you could run to find out which material accepts electrons more easily is to rub them together and move the two charge misery materials one after the other to the positive - charge helium - filled balloon.
According to the fundamental law of static electricity which state that unlike charges attract each other while like charges repel.
The simple experiment you could run if you are handed two mystery materials, and told to find out which materials accepts negative charges more easily charging by friction.
This can be employed by rubbing the two misery materials together and move them one by one to a positively-charged, helium-filled balloon which is tied to a tabletop with a string of a meter long.
The misery material that accepts electron more easily will be attracted to the positive - charge helium - filled balloon. While the gravitational pull will pull down the other misery material. The attraction will not be effective.
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A wave has a wavelength of 1.5 m and a frequency of 6.0 Hz. What is the
speed of the wave?
Answer:
9 m/sExplanation:
The speed of the wave given only it's frequency and wavelength can be found by using the formula
[tex]c = f \times \lambda[/tex]
where
c is the velocity of the wave in m/s
[tex] \lambda[/tex] is the wavelength in m
f is the frequency in Hz
From the question we have
c = 6 × 1.5 = 9
We have the final answer as
9 m/sHope this helps you
A green ball is dropped from rest from an elevated position at the same instant that a red ball is launched horizontally (from the same height), which ball will hit the ground first? Assume the balls behave as projectiles.
a. green ball
b. red ball
c. the red and green ball will hit the ground at the same time
d. not enough information given
Answer:
c. the red and green ball will hit the ground at the same time
Explanation:
if two objects are the same size but one is heavier, the heavier one has greater density than the lighter object. Therefore, when both objects are dropped from the same height and at the same time, the heavier object should hit the ground before the lighter one.
What is the frequency of a wave with a wavelength of 15 m and a wavespeed of
300 m/s?
Answer: f=20 (i think)
Explanation:
all I did was divide 300 and 15.
300/15= 20
which distance indicator can be used to measure the most distant objects?
The distance indicator can be used to measure the most distant objects among all indicators stated above is Type Ia supernovae
In the field of Astronomy, there are different kind of distance indicators that can be used to measure the distance objects.
Few among them are :
Cepheids Type Ia supernovae Parallax Main-sequence fittingCepheid variables can be measured up to 18 million light years.
The expansion rate of the universe can also be measured by trying to measure the apparent brightness of the Type Ia supernovae
Parallax means illusory state of an object when viewed from different points
Main sequence fitting makes use of a H-R diagram of the cluster to determine the distance to a stellar cluster.
The distance indicator can be used to measure the most distant objects among all indicators stated above is Type Ia supernovae
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Energy stores in food would be considered what
Answer:
Energy stored in food is consider as carbohydrate,protein,fats,etc.
A strong weightless rope has a mass, m, hanging from the middle of it. The tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees. How much mass is hanging from the rope?
By using Lami's theorem, Mass m = 1.75 kg approximately
Given that a strong weightless rope has a mass, m, hanging from the middle of it. If the tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees to the horizontal.
By using Lami's theorem, we can get how much mass is hanging from the rope.
Let the angle between the rope = α = 180 - 40
α = 140 degrees
The angle between one of the rope and mass = β = 20 + 90
β = 110 degrees
The angle between the mass and the other rope = γ = 360 - (140 + 110)
γ = 360 - 250
γ = 110 degrees
W/ sinα = T/ sinβ = T/sinγ
W/ sinα = T/ sinβ
Substitute all the necessary parameters
W/sin140 = 25/sin 110
W / 0.643 = 25 / 0.939
W = 17.1 N
Weight W = mg
17.1 = 9.8m
mass m = 17.1/9.8
Mass m = 1.7455 kg
Mass m = 1.75 kg approximately
Therefore, 1.75 kg mass is hanging from the rope.
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PLEASE HELP. I'LL GIVE BRAINLIEST IF YOU GET IT RIGHT.
Where have we found evidence of the early history of Earth?
a. The Moon, Venus, and Mars
b. Mars, the Moon, and Jupiter
c. Asteroids, the Moon, and Mars
d. The gas planets
Answer:Most of this ancient space rubble can be found orbiting the Sun between Mars and Jupiter within the main asteroid belt. Asteroids range in size from Vesta – the largest at about 329 miles (530 kilometers) in diameter – to bodies that are less than 33 feet (10 meters) across. The total mass of all the asteroids combined is less than that of Earth's Moon.❤
Mars, the Moon, and Jupiter, Where we have found evidence of the early history of Earth.
What is the evidence of the early history of Earth?The giant-impact theory is currently the one that is most frequently accepted. According to this theory, the Moon was created after the Earth collided with a smaller planet that was around Mars' size.
The Moon was created when the impact's leftover debris gathered in an orbit around Earth. The main asteroid belt, which extends between Mars and Jupiter, is home to the majority of this old space debris.
Asteroids range in size from the largest, Vesta, which has a diameter of roughly 329 miles (530 kilometers), to bodies that are about 33 feet (10 meters) wide. The cumulative mass of all asteroids is less than that of the moon on Earth.
Therefore, option B is correct.
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How long will it take a projectile to hit the ground if it is launched at 4.2 m/s off a 12.6 m high platform?
Answer: 3
Explanation:
I think you are supposed to divided in those problems? I'm not sure but if you aren't then please let me know. The equation I did was:
12.6 / 4.2 = 3
Hope this helps!! :)
For the equation BaCl2 + Na2SO4 → BaSO4 + 2NaCl, how many chlorine atoms are on the reactants side and on the products side?
Answer:2 reactants 2 products.
this is a balanced chemical equation. That means the number of chlorine before the arrow will be the same after the arrow
Explanation: i think this answer will help you very much
Helpppppppp pleaseeeee!!
The mass of an atom is concentrated in its
a. nucleus
b. electron
c. neutron
d. angstrom
e. isotope
A 30 g mass is attached to one end of a 10-cm-long spring.
The other end of the spring is connected to a frictionless pivot on
a frictionless, horizontal surface. Spinning the mass around in a
circle at 90 rpm causes the spring to stretch to a length of 12 cm.
What is the value of the spring constant?
The value of the spring constant of the spring is 14.7 N/m.
The given parameters;
mass attached to the spring, m = 30 glength of the spring, L₀ = 10 cmangular speed of the mass = 90 rpmfinal length of the spring, L₁ = 12 cmThe extension of the spring is calculated as follows;
[tex]\Delta x = L_1 - L_0\\\\\Delta x = 12 \ cm - \ 10 \ cm\\\\\Delta x = 2 \ cm = 0.02 \ m[/tex]
The value of the spring constant of the spring is calculated by applying Hooke's law;
[tex]F = mg = k\Delta x\\\\k = \frac{mg}{\Delta x } \\\\k = \frac{0.03 \times 9.8}{0.02} \\\\k = 14.7 \ N/m[/tex]
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How can you use a simple model to describe a wave and its features?
Answer:
Explanation:
Use mathematical representations to describe a simple model for waves that includes how the amplitude of a wave is related to the energy in a wave. Patterns can be used to identify cause and effect relationships.
A 1500 kg car travels 50 m north in 20 seconds. What is the magnitude of the average velocity of the car during the 20 second interval?
a. 2.5 m/s
b. 5.0 m/s
c. 6.5 m/s
d. 7.0 m/s
Answer:
a. 2.5 m/s
Explanation:
50 / 20 = 2.5 m/s
write of the following does not represent electrical power in a circuit ?
(a) I²R
(b) IR²
(c)VI
(d) V²/R
A bullet of mass M1, is fired towards a block
of mass m2 initially at rest at the edge of a
frictionless table of height h as in the figure.
The initial speed of the bullet is vi. Consider
two cases. a соmрlеtеlу inсlаѕtiс one and an
elastic one where the bullet bounces off the block. What is the flight ratio time?
The ratio of time of flight for inelastic collision to elastic collision [tex](t_A :t_B)[/tex] is 1:2
The given parameters;
mass of the bullet, = m₁mass of the block, = m₂initial velocity of the bullet, = u₁initial velocity of the block, = u₂ = 0Considering inelastic collision, the final velocity of the system is calculated as;
[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\m_1u_1 + 0 = v(m_1 + m_2)\\\\v= \frac{m_1u_1}{m_1 + m_2} \ -- (1)\\\\[/tex]
The time of motion of the system form top of the table is calculated as;
[tex]v = u + gt\\\\v = 0 + gt\\\\v = gt\\\\t= \frac{v}{g} \\\\t_A = \frac{m_1u_1}{g(m_1 + m_2)} \ \ ---(2)[/tex]
Considering elastic collision, the final velocity of the system is calculated as;
[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\m_1u_1 + 0 = m_1v_1 + m_2v_2\\\\m_1 u_1 = m_1v_1 + m_2v_2[/tex]
Apply one-directional velocity
[tex]u_1 + (-v_1) = u_2 + v_2\\\\u_1 -v_1 = 0 + v_2\\\\v_1 = v_2 -u_1[/tex]
Substitute the value of [tex]v_1[/tex] into the above equation;
[tex]m_1u_1 = m_1(v_2 - u_1) + m_2 v_2\\\\m_1u_1 = m_1v_2 -m_1u_1 + m_2v_2\\\\2m_1u_1 = m_1v_2 + m_2v_2\\\\2m_1u_1= v_2(m_1 + m_2)\\\\v_2 = \frac{2m_1u_1}{m_1+ m_2} \ --(3)[/tex]
where;
[tex]v_2[/tex] is the final velocity of the block after collision
Since the bullet bounces off, we assume that only the block fell to the ground from the table.
The time of motion of the block is calculated as follows;
[tex]v_2 = v_0 + gt\\\\v_2 = 0 + gt\\\\t = \frac{v_2}{g} \\\\t_B = \frac{v_2}{g} \\\\ t_B = \frac{2m_1u_1}{g(m_1 + m_2)} \ \ ---(4)[/tex]
The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;
[tex]\frac{t_A}{t_B} = \frac{m_1u_1}{g(m_1 + m_2)} \times \frac{g(m_1 + m_2)}{2m_1u_1} \\\\\frac{t_A}{t_B} = \frac{1}{2} \\\\t_A:t_B = 1: 2[/tex]
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A student lifts a backpack straight up with a force of 53.5 N for a distance of 0.65 m. How much work is done on the backpack?
Happy Christmas Eve!!
Answer:
W = 34.775J
Explanation:
W = F × d
W = 53.5N × 0.65m
W = 34.775J
W = work = unknown
f = force = 53.5N
d = distance = 0.65m
1. Three students are using sports equipment to model the relative motion of
Earth, the moon and the sun.
A. Identify which ball would be used to model the Sun, Earth and the Moo
B. Describe the relative (in relation to each other) motions of these bodies
Answer:
The golf ball would be revolving around the baseball while the baseball would be revolving around the basketball.
Explanation:
The basketball would be represented as the Sun, the baseball would be represented as the Earth and the golf ball would be represented as the moon. Since the Moon revolves around the Earth and the Earth revolving around the Sun makes a perfect explaination for this question.
A 50.0 kg crate is pulled 375 N of force applied to a rope. The crate slides without friction.
After being pulled 3.07 meters the crate has a velocity of 5.61 m/s. What is the angle (degrees) made by the rope with the horizontal?
Hi there!
We can use the work-energy theorem to solve.
Recall that:
[tex]\large\boxed{W = \Delta KE = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2}[/tex]
The initial kinetic energy is 0 J because the crate begins from rest, so we can plug in the given values for mass and final velocity:
[tex]W = \frac{1}{2}(50)(5.61^2) = 786.8025 J[/tex]
Now, we can define work:
[tex]\large\boxed{W = Fdcos\theta}}[/tex]
Now, plug in the values:
[tex]786.8025 = Fdcos\theta\\\\786.8025 = (375)(3.07)cos\theta[/tex]
Solve for theta:
[tex]cos\theta = .6834\\\theta = cos^{-1}(.6834) = \boxed{46.887^o}[/tex]
Determine the percent composition of chromium (III) flouride CrF3
(Show your solution)
Answer:
Molar mass of CrF3, Chromium(III) Fluoride is 108.9913096 g/mol
51.9961+18.9984032·3
Mass percentage of the elements in the composition
Element Symbol Atomic Mass Number of Atoms Mass Percent
Chromium Cr 51.9961 1 47.707%
Fluorum F 18.9984032 3 52.294%
Notes on using the Molar Mass Calculator
Chemical formulas are case-sensitive.
Enter subscripts as simple numbers.
The converter uses a simple dot instead of using a midpoint typographic dot (·) in formulas for adduct molecules, such as water of hydration.
Example: type CuSO4.5H2O instead of CuSO₄·5H₂O.
Explanation:
please mark my answer in brainlist plz
Describe when the chemical
reaction occurs in a dry-cell
battery
Answer:
For a dry-cell battery to operate, oxidation will occur from the zinc anode and reduction will take place in the cathode. The most common type of cathode is a carbon graphite. Once reactants have been turned into products, the dry-cell battery will work to produce electricity.
Explanation:
The battery operates through electrochemical reactions called oxidation and reduction. These reactions involve the exchange of electrons between chemical species. If a chemical species loses one or more electrons, this is called oxidation. The opposite process, the gain of electrons, is called reduction.
alcohol thermometer cannot measure the thermometer of boiling water ,why?
Explanation:
The contents of alcohol are less toxic and will evaporate quickly as compared to the mercury-in-glass thermometer. Since, alcohol starts boiling at 80℃ while the boiling point of mercury is 375℃. ... So, an alcohol thermometer cannot measure the temperature of boiling water as it has the limit to measures up to 80℃.
What amount of heat is required to increase the temperature of 75. 0 grams of gold from 150°C to 250°C? The specific heat of gold is 0. 13 J/g°C. A. 750 joules B. 980 joules C. 1300 joules D. 1500 joules E. 2500 joules.
975 J of heat energy is needed to increase the temperature from 150°C to 250°C of given mass of gold.
From specific heat formula,
[tex]Q = mc \Delta T[/tex]
Where,
[tex]Q[/tex] - Heat absorbed
[tex]m[/tex] - mass of gold = 75. 0 g
[tex]c[/tex] - specific heat of gold = 0. 13 J/g°C
[tex]\Delta T[/tex]- temperature difference = 150°C - 250°C = 100°C
Put the values in the formula,
[tex]Q = 75\times 0.13 \times 100 }\\\\Q = 975 {\rm \ J}[/tex]
Therefore, 975 J of heat energy is needed to increase the temperature of given mass of gold.
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The heat required to increase the temperature of the gold is 980 J
The correct answer to the question is Option B. 980 J
We'll begin by calculating the change in the temperature of the gold
Initial temperature (T₁) = 150 °C Final temperature (T₂) = 250 °C Change in temperature (ΔT) =?ΔT = T₂ – T₁
ΔT = 250 – 150
ΔT = 100 °C
Finally, we shall determine the heat required.
Mass (M) = 75 gChange in temperature (ΔT) = 100 °C Specific heat capacity (C) = 0.13 J/gºC Heat (Q) =?Q = MCΔT
Q = 75 × 0.13 × 100
Q = 975 J
Q ≈ 980 J
The correct answer to the question is Option B. 980 J
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How does the temp of water change when it is heated on a stove top and it begins to boil.
Answer:
The temperature will no longer rise with the heat because the energy. When the water is boiled on the steam, the temperature rises when heat is given
Explanation:
ASAP!!! Imagine you are about to purchase a new refrigerator. There are two models that you are considering. Each
refrigerator is required to have an energy efficiency sticker on the door so that the buyer can be aware of the
cost of running the refrigerator. Refrigerator (A) costs $10.00 a month to operate and $700.00 to buy.
Refrigerator (B) costs $15.00 a month to run and $600.00 to buy. Decide which refrigerator you would purchase,
(A or B) and indicate in the answer box why it would be better for the environment
Answer:
model A
Explanation:
model A is more expensive to buy but you pay less per month to run it making it a better purchase in the long run. The cheaper cost of running it is better for the environment due to there being less electricity needed to power it.
