Answer:
4
Step-by-step explanation:
The given data is :
8, 10, 12,14,16,18,20
We need to find the standard deviation. Here,
Count = 7
Sum, Σx: 98
Mean, μ: 14
The standard deviation is given by :
[tex]\sigma=\sqrt{\dfrac{1}{N}\Sigma(x_i-\mu)^2}[/tex]
or
[tex]\sigma^2=\dfrac{1}{N}\Sigma(x_i-\mu)^2\\\\=\dfrac{(8-14)^2+...+(20-14)^2}{7}\\\\=\dfrac{112}{7}\\\\\sigma^2=16\\\\\sigma=4[/tex]
So, the standard deviation of the given data is 4.
A runner’s distribution of times for running 1,000 meters has a mean of 4.5 minutes with a standard deviation of 0.75 minutes. One of the runner’s times has a z-score of –1.08. Which of the following statements is the best interpretation of this z-score?
This runner’s time was faster than the mean time by 0.75 standard deviations.
This runner’s time was faster than the mean time by 1.08 standard deviations.
This runner’s time was slower than the mean time by 0.75 standard deviations.
This runner’s time was slower than the mean time by 1.08 standard deviations.
Answer:
I believe it is (C).
This runner’s time was slower than the mean time by 0.75 standard deviations.
ED2021
Answer:
B) This runner’s time was faster than the mean time by 1.08 standard deviations.
Step-by-step explanation:
The runner is FASTER because of the negative z score
Last year, Singh had $20,000 to invest. He invested some of it in an account that paid 7% simple interest per year, and he invested the rest in an account that paid 6% simple interest per year. After one year, he received a total of $1280 in interest. How much did he invest in each account?
Answer:
8000 and 12000 respectively
Step-by-step explanation:
Let the amount invested in first account be x and y be the amount invested in the second account.
ATQ, x+y=20000 and 1280=(7/100)*x+(6/100)*y
x=8000 and y=12000.
PLEASE HELP !!
A line is defined by the equation y = x-6. The line passes through a point whose y-coordinate is 0. What is the x-
coordinate of this point?
45
Answer:
The x-coordinate of this point would be 6.
Step-by-step explanation:
Round 5,821 to the nearest thousands place:
Answer:
6000 hope this helps
if the question is 5,422 then the round figure is 5000
but the question is 5,821 its above 5500 will be 6000
What is the sum of q + r ?
Answer:
w
Step-by-step explanation:
w
What is the smallest three-digit odd numb
that can be made from 2, 8,5, 1, 3?
Answer: 101
Step-by-step explanation:
.
Surface area of the below shape
Solve all of the equations below and add all of the solutions to those equations to get your answer.
10x4x2=
8x4x2=
10x8=
(10x8)-(7x6)=
7x2x2=
6x2x2=
7x6=
A store has x packages of 4 markers and y packages of 12 markers. The store has a total of 192 markers in
stock. If there are 21 packages of 4 markers in the store, how many packages of 12 markers are there?
Sh363gdbzej3yve truly urban urge Heydyeh hdye
2/5 + 1/10= In simplest form
A. 3/15
B. 5/10
C. 1/4
D. 1/2
Answer:
1/2
Step-by-step explanation:
2/5 + 1/10
Get a common denominator of 10
2/5 * 2/2 + 1/10
4/10 + 1/10
5/10
simplify
Divide the top and bottom by 5
1/2
Answer:
[tex] \frac{1}{2} [/tex]
Answer D is correctStep-by-step explanation:
[tex] \frac{2}{5} + \frac{1}{10} \\ \frac{2 \times 2}{5 \times 2} + \frac{1}{10} \\ \frac{4}{10} + \frac{1}{10} \\ \frac{5}{10} \\ \frac{5 \div 5}{10 \div 5} \\ = \frac{1}{2} [/tex]
Based on the equation 6x + 2y = 30, what is the missing value in the table?
Answer:
x =5
Step-by-step explanation:
hope this helps you
please mark as brainliest
Answer:15
Step-by-step explanation:6x +2y=30
2(3x+y) =30
3x+y=30÷2
3x+y=15
4) In a clinical test with 2353 subjects, 1136 showed improvement from the treatment.
Answer:
1217
Step-by-step explanation:
Given
[tex]Subjects = 2353[/tex]
[tex]Improvement = 1136[/tex]
Required
The number that didn't improve --- missing from the question.
Let the unimproved be represented as x.
So, we have:
[tex]x + Improvement = Subjects[/tex]
Substitute known values
[tex]x + 1136 = 2353[/tex]
Solve for x
[tex]x =- 1136 + 2353[/tex]
[tex]x =1217[/tex]
Which ordered pair is a solution to the system of inequalities?
y > –x
y ≤ x + 1
A) (0,5)
B) (4,–1)
C) (1,3)
D) (–4,0)
9514 1404 393
Answer:
B) (4,–1)
Step-by-step explanation:
A graph can help you figure this out. The point (4, -1) is in the doubly-shaded area, so is a solution to this system.
==========================================================
Explanation:
Choice A can be ruled out because
[tex]y \le x+1\\\\5 \le 0+1\\\\5 \le 1\\\\[/tex]
which is false.
Choices C and D are similar, so they can be ruled out as well.
---------------------
Choice B is the answer because it makes both inequalities true.
If we plug the coordinates of (4,-1) into the first inequality, we get
[tex]y > -x\\\\-1 > -4[/tex]
which is a true statement because -1 is to the right of -4 on the number line.
Now try the other inequality
[tex]y \le x+1\\\\-1 \le 4+1\\\\-1 \le 5\\\\[/tex]
that's true also. So again, (4,-1) makes both inequalities true, and that's why choice B is the answer.
At a restaurant, the bill comes to $55. You decide to leave a 12
%
tip. How much did you leave for the tip?
Answer:
$6.60
Step-by-step explanation:
12% = 0.12
12% of $55 = 0.12 x 55
=6.6
So, $6.60
what us 10 to the power of two
the answer is
10² ( ten square )
step by step :
10² = 10 × 10
= 100
Answer: 100
Step-by-step explanation: 10*10=100
Students at a virtual school are allowed to sign up for one math class each year. The numbers of students signing up for various math classes for the next school
year are given in the following table:
Grade Geometry Algebra II Pre-Calculus AP Statistics Total
10th
150
75
25
5
255
11th
50
100
75
20
245
12th
10
50
100
65
225
Total 210
225
200
90
725
Part A: What is the probability that a student will take AP Statistics? (2 points)
Part B: What is the probability that a 12th-grader will take either Pre-Calculus or AP Statistics? (2 points)
Part C: What is the probability that a student will take Algebra II given that he or she is in the 11th grade? (2 points)
Part D: Consider the events "A student takes Algebra II and "A student is a 10th-grader. Are these events independent? Justify your answer. (4 points)
A well formatted table of the distribution is attached below :
Answer:
0.124
0.733
0.408
Step-by-step explanation:
Using the table Given :
1.) P(AP Statistics) = 90 / 725 = 0.124
2.) P(12th grade ; Precalculus or AP Statistics) = (100 + 65) / 225 = 165 /225 = 0.733
3.) P(Algebra 11 | 11th grade) = P(Algebara11 n 11th grade) / P(11th grade) = 100 / 245 = 0.408
Which equation does the graph of the systems of equations solve?
two linear functions intersecting at 3, negative 2
−one thirdx + 3 = x − 1
one thirdx − 3 = −x + 1
−one thirdx + 3 = −x − 1
one thirdx + 3 = x − 1
Answer:
-1/3x+3 = x-1
Step-by-step explanation:
The solution is (3,-2)
Check and see if the point solves the equation
-1/3x+3 = x-1
-1/3(3) +3 = 3-1
-1+3 = 3-1
2=2 yes
Answer:
C
Step-by-step explanation:
how to solve this trig
Hi there!
To find the Trigonometric Equation, we have to isolate sin, cos, tan, etc. We are also given the interval [0,2π).
First Question
What we have to do is to isolate cos first.
[tex] \displaystyle \large{ cos \theta = - \frac{1}{2} }[/tex]
Then find the reference angle. As we know cos(π/3) equals 1/2. Therefore π/3 is our reference angle.
Since we know that cos is negative in Q2 and Q3. We will be using π + (ref. angle) for Q3. and π - (ref. angle) for Q2.
Find Q2
[tex] \displaystyle \large{ \pi - \frac{ \pi}{3} = \frac{3 \pi}{3} - \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{2 \pi}{3} }[/tex]
Find Q3
[tex] \displaystyle \large{ \pi + \frac{ \pi}{3} = \frac{3 \pi}{3} + \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{4 \pi}{3} }[/tex]
Both values are apart of the interval. Hence,
[tex] \displaystyle \large \boxed{ \theta = \frac{2 \pi}{3} , \frac{4 \pi}{3} }[/tex]
Second Question
Isolate sin(4 theta).
[tex] \displaystyle \large{sin 4 \theta = - \frac{1}{ \sqrt{2} } }[/tex]
Rationalize the denominator.
[tex] \displaystyle \large{sin4 \theta = - \frac{ \sqrt{2} }{2} }[/tex]
The problem here is 4 beside theta. What we are going to do is to expand the interval.
[tex] \displaystyle \large{0 \leqslant \theta < 2 \pi}[/tex]
Multiply whole by 4.
[tex] \displaystyle \large{0 \times 4 \leqslant \theta \times 4 < 2 \pi \times 4} \\ \displaystyle \large \boxed{0 \leqslant 4 \theta < 8 \pi}[/tex]
Then find the reference angle.
We know that sin(π/4) = √2/2. Hence π/4 is our reference angle.
sin is negative in Q3 and Q4. We use π + (ref. angle) for Q3 and 2π - (ref. angle for Q4.)
Find Q3
[tex] \displaystyle \large{ \pi + \frac{ \pi}{4} = \frac{ 4 \pi}{4} + \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{5 \pi}{4} }[/tex]
Find Q4
[tex] \displaystyle \large{2 \pi - \frac{ \pi}{4} = \frac{8 \pi}{4} - \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{7 \pi}{4} }[/tex]
Both values are in [0,2π). However, we exceed our interval to < 8π.
We will be using these following:-
[tex] \displaystyle \large{ \theta + 2 \pi k = \theta \: \: \: \: \: \sf{(k \: \: is \: \: integer)}}[/tex]
Hence:-
For Q3
[tex] \displaystyle \large{ \frac{5 \pi}{4} + 2 \pi = \frac{13 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 4\pi = \frac{21 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 6\pi = \frac{29 \pi}{4} }[/tex]
We cannot use any further k-values (or k cannot be 4 or higher) because it'd be +8π and not in the interval.
For Q4
[tex] \displaystyle \large{ \frac{ 7 \pi}{4} + 2 \pi = \frac{15 \pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 4 \pi = \frac{23\pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 6 \pi = \frac{31 \pi}{4} }[/tex]
Therefore:-
[tex] \displaystyle \large{4 \theta = \frac{5 \pi}{4} , \frac{7 \pi}{4} , \frac{13\pi}{4} , \frac{21\pi}{4} , \frac{29\pi}{4}, \frac{15 \pi}{4} , \frac{23\pi}{4} , \frac{31\pi}{4} }[/tex]
Then we divide all these values by 4.
[tex] \displaystyle \large \boxed{\theta = \frac{5 \pi}{16} , \frac{7 \pi}{16} , \frac{13\pi}{16} , \frac{21\pi}{16} , \frac{29\pi}{16}, \frac{15 \pi}{16} , \frac{23\pi}{16} , \frac{31\pi}{16} }[/tex]
Let me know if you have any questions!
find the form of the general solution of y^(4)(x) - n^2y''(x)=g(x)
The differential equation
[tex]y^{(4)}-n^2y'' = g(x)[/tex]
has characteristic equation
r ⁴ - n ² r ² = r ² (r ² - n ²) = r ² (r - n) (r + n) = 0
with roots r = 0 (multiplicity 2), r = -1, and r = 1, so the characteristic solution is
[tex]y_c=C_1+C_2x+C_3e^{-nx}+C_4e^{nx}[/tex]
For the non-homogeneous equation, reduce the order by substituting u(x) = y''(x), so that u''(x) is the 4th derivative of y, and
[tex]u''-n^2u = g(x)[/tex]
Solve for u by using the method of variation of parameters. Note that the characteristic equation now only admits the two exponential solutions found earlier; I denote them by u₁ and u₂. Now we look for a particular solution of the form
[tex]u_p = u_1z_1 + u_2z_2[/tex]
where
[tex]\displaystyle z_1(x) = -\int\frac{u_2(x)g(x)}{W(u_1(x),u_2(x))}\,\mathrm dx[/tex]
[tex]\displaystyle z_2(x) = \int\frac{u_1(x)g(x)}{W(u_1(x),u_2(x))}\,\mathrm dx[/tex]
where W (u₁, u₂) is the Wronskian of u₁ and u₂. We have
[tex]W(u_1(x),u_2(x)) = \begin{vmatrix}e^{-nx}&e^{nx}\\-ne^{-nx}&ne^{nx}\end{vmatrix} = 2n[/tex]
and so
[tex]\displaystyle z_1(x) = -\frac1{2n}\int e^{nx}g(x)\,\mathrm dx[/tex]
[tex]\displaystyle z_2(x) = \frac1{2n}\int e^{-nx}g(x)\,\mathrm dx[/tex]
So we have
[tex]\displaystyle u_p = -\frac1{2n}e^{-nx}\int_0^x e^{n\xi}g(\xi)\,\mathrm d\xi + \frac1{2n}e^{nx}\int_0^xe^{-n\xi}g(\xi)\,\mathrm d\xi[/tex]
and hence
[tex]u(x)=C_1e^{-nx}+C_2e^{nx}+u_p(x)[/tex]
Finally, integrate both sides twice to solve for y :
[tex]\displaystyle y(x)=C_1+C_2x+C_3e^{-nx}+C_4e^{nx}+\int_0^x\int_0^\omega u_p(\xi)\,\mathrm d\xi\,\mathrm d\omega[/tex]
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write an equation of a vertical line that pases through the point (-4, 4)
Answer:
x = -4
Step-by-step explanation:
Answer:
Step-by-step explanation:
Write an expression to represent how many fourths are in 3- fourths?
Answer:
[tex]\frac{3}{4} =\frac{1}{4} (3)[/tex]
Step-by-step explanation:
like that?
Answer:
3/4
Step-by-step explanation:
Step 1: Write an expression
A fourth is 1/4
3 fourths means 3 one forths
1/4 + 1/4 + 1/4
3/4
Answer: 3/4
Fill in the blank with a number to make the expression a perfect squared… W squared + 6w +
Answer:
[tex](a+b)^{2} =a^{2}+2ab+b^{2}[/tex]
[tex](1)w^{2}+2(3)(1)w+3^{2}\\\\=(w+3)^{2}\\\\=(w+3)(w+3)[/tex]
Therefore, [tex]w^{2} +6w+9[/tex] makes a perfect squared.
Which figure is the pre-image? Which figure is the image after the first transformation? Which figure is the image after the second transformation?
Answer:
I believe the red one is the first image then the blue then the green because they show the prime sign
Step-by-step explanation:
pls help Describe how to find the product of the two terms 3x^2y^5 and 4x^3y^7
Answer:
12 x^5y^12
Step-by-step explanation:
3x^2y^5 * 4x^3y^7
Multiply the constants
3*4 = 12
Multiply the x terms
x^2 * x^3
We know a^b* a^c = a^(b+c)
x^(2+3) = x^5
Multiply the y terms
y^6 * y^7 = y&(5+7) = y^12
Put them back together
12 x^5y^12
Find the missing side length in the image below
A 90% confidence interval is (35 45). What is the margin of error?
A.5
B.4.5
C.9
D.10
Answer:
option a 5......
...
I hope it's correct
The least-squares regression equation
y = 968 – 3.34x can be used to predict the amount of monthly interest paid on a loan after x months. Suppose the amount of monthly interest after 30 months was $865.93.
What is the residual for the amount of monthly interest paid on a loan after 30 months?
–202.27
–1.87
1.87
202.27
Answer:
-1.87 (B)
865.93 - [968-3.34(30)] = -1.87
ED2021
PLEASEEEEEE HELPPPPPPPPP
what are the zeros for this?
f(x) = 2x^2 + 6x + 2
Answer:
-3/2 ±1/2 sqrt(5) = x
Step-by-step explanation:
f(x) = 2x^2 + 6x + 2
Set the function equal to 0
0 = 2x^2 + 6x + 2
Factor out 2
0 = 2(x^2 + 3x + 1)
Divide by 2
0 = (x^2 + 3x + 1)
Subtract 1 from each side
-1 = x^2 +3x
Complete the square by dividing the x coefficient by 2 and then squaring
(3/2)^2 = 9/4
-1 +9/4 = x^2 +3x+9/4
-4/4+9/4 = (x+3/2) ^2
5/4 = (x+3/2) ^2
Taking the square root of each side
± sqrt(5/4) = sqrt( (x+3/2) ^2)
±1/2 sqrt(5) = (x+3/2)
Subtract 3/2 from each side
-3/2 ±1/2 sqrt(5) = x
A superhero can fly from New York to Los Angeles in 30 minutes. The distance from New York to Los Angeles is approximately 2,450 miles.
How many miles per hour is the superhero flying?
Work Shown:
30 min = 30/60 = 0.5 hours
distance = rate*time
rate = distance/time
rate = (2450 miles)/(0.5 hours)
rate = (2450/0.5) mph
rate = 4900 mph
For the sake of comparison, a typical commercial passenger jet can reach max speeds of about 600 mph.
Solve for the value of x
Answer:
Step-by-step explanation:
This is the Law of Cosines. Use the following formula:
[tex]5.1^2=3.3^2+3.3^2-2(3.3)(3.3)cos(x)[/tex] and simplify to
26.01 = 10.89 + 10.89 - 21.78cos(x) and a bit more to
4.23 = -21.78cos(x) and finally to
-.194214876 = cos(x) and use the 2nd button along with the cos button to find that the missing angle is 101.2 degrees
