Can someone plz help me ?
Which best describes the relationship between the lines with equations −6x+8y=−1 and −4x−3y=2?
Answer:
it is linear
Step-by-step explanation:
Both of these both lines are perpendicular to each other.
We have the two equations of straight lines :
− 6x + 8y = −1 and −4x − 3y = 2.
We have to identify the relation between these two lines.
What is the general equation of a straight line ?The general equation of a straight line is as follows -
y = mx + c
where -
m - slope of line
c - intercept of line on y - axis.
According to the question, we have -
−6x + 8y = −1 ...(1)
−4x − 3y = 2 ...(2)
Rearranging the terms of the equations we get -
y = [tex]\frac{3}{4} x - \frac{1}{8}[/tex] ...(3)
and
y = [tex]\frac{-4}{3}x - \frac{2}{3}[/tex] ...(4)
When compared -
The slope of line −6x + 8y = −1 is m(1) = [tex]\frac{3}{4}[/tex].
The slope of line −4x − 3y = 2 is m(2) = [tex]\frac{-4}{3}[/tex].
We can see that -
m(1) x m(2) = - 1
The product of the slopes of two perpendicular lines is -1.
Hence, these both lines are perpendicular to each other.
To solve more questions on relation between straight lines, visit the link below -
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can y’all help me out
Answer:
B: y = {-13, -5, 3, 15}
Step-by-step explanation:
Let's plug each x-value into this equation: f(x) = 4x + 3
Domain: {-4, -2, 0, 3}
First, let's start with -4:
f(x) = 4x + 3
y = 4x + 3
y = 4(-4) + 3
y = -16 + 3
y = -13
Next, let's do -2:
f(x) = 4x + 3
y = 4x + 3
y = 4(-2) + 3
y = -8 + 3
y = -5
After that, let's do 0:
f(x) = 4x + 3
y = 4x + 3
y = 4(0) + 3
y = 0 + 3
y = 3
Finally, let's do 3:
f(x) = 4x + 3
y = 4x + 3
y = 4(3) + 3
y = 12 + 3
y = 15
Now that we have all our y-values, let's set up the range:
Range (y-values): {-13, -5, 3, 15}
As you can see, the only answer choice that includes this range is B;
{-13, -5, 3, 15}.
A car travels a distance of 800m in 40s find its speed
Answer:
the answer is 20m/s
Step-by-step explanation:
speed = distance/time which equals to speed = 800/40, so the answer is 20m/s
Answer:
20m /s
Step-by-step explanation:
Speed = [tex]\frac{Distance}{time}[/tex]
[tex]= \frac{800}{40}=\frac{80}{4}= 20[/tex]
Which graph represents the function f(x)=|x−1|−3 ?
Determine which equations have the same solution set as 2/3 -x +1/6 = 6x by recognizing properties, rather than solving. Check all that apply.
Answer:
The answer is "0.1190".
Step-by-step explanation:
Given:
[tex]\to \frac{2}{3} -x +\frac{1}{6} = 6x\\\\\to \frac{2}{3} +\frac{1}{6} = 6x+x\\\\\to \frac{4+1}{6} = 7x\\\\\to \frac{5}{6} = 7x\\\\\to x=\frac{5}{6\times 7} \\\\\to x=\frac{5}{42}\\ \\\to x= 0.1190[/tex]
Answer:
A.) 4 - 6x + 1 = 36x
B.) 5/6 - x = 6x
F.) 5 = 42x
Step-by-step explanation:
edge.
a.) x ≥ 2
b.) x > 2
c.) x < 2
d.) x ≤ 2
Answer:
x < 2
Step-by-step explanation:
There is an open circle at 2 so that means it is not equal to
The line goes to the left so x is less than 2
x < 2
Answer:
c.) x < 2
Step-by-step explanation:
open circle means > or <
the line is going to the left, meaning < or ≤
from this, we know the inequality is x < 2
2(-3-6)+(-7+4)to the power of 2
calcula el valor de A - B, si se sabe que: A=
Answer:
[tex]P=\frac{1}{2}[/tex]
Step-by-step explanation:
[tex]P=\frac{(x+3)^2-(x-3)^2}{(x+6)^2-(x-6)^2}[/tex]
[tex]=\frac{[(x+3)-(x-3)][(x+3)+(x-3)]}{[(x+6)-(x-6)][(x+6)+(x-6)]}[/tex]
[tex]=\frac{6(2x)}{12(2x)}[/tex]
[tex]=\frac{1}{2}[/tex]
Por tanto, el valor de P será [tex]\frac{1}{2}[/tex]
Cual es la raiz cudrada de 2
Answer:
1.4142135
Step-by-step explanation:
I’ll mark u as a brainliest!! pls help me
Answer:
Shorter leg is 7
Bigger leg is 7√3 = 12.1 (rounded to the nearest tenth)
Attached Math question document. Find the value to complete this calculation.
To find the missing value divide both sides by -7:
28/-7 = 4
The missing value is 4
Answer= -4
Step-by-step explanation:
negative × negative = positve. therefore if 7×4=28 , then -7×-4=28
Based only on the information given in the diagram, which congruence
theorems or postulates could be given as reasons why AABC= ALMN?
Check all that apply
O A. LL
O B. ASA
I C. LA
D. HL
E AAS
3 Answers:
Choice A. LLChoice D. HLChoice F. SAS==========================================================
Explanation:
Let's go through the answer choices one by one.
A) This can be used because LL = leg leg, and this means we have two pairs of congruent legs. Those pairs are AC = LN and CB = NM. The LL theorem only applies to right triangles.B) This cannot be used. We don't have info about two pairs of angles. We only know that one pair of angles are the same (those 90 degree angles). So we can't form the second "A" in "ASA". This idea will come up again in choice C and choice E.C) This cannot be used. Why not? Because the "A" of "LA" refers to "acute angle". But unfortunately we don't know anything about the acute angles (whether they are congruent or not). The LA theorem can only be applied to right triangles.D) This can be used. We can use the HL (hypotenuse leg) theorem because we see that AB = LM are the pair of congruent hypotenuses, and you can use any of the congruent leg pairs to form the L of HL. Similar to LL and LA, the HL theorem only works for right triangles.E) This cannot be used. Like with choice B, we can't form the second "A" of "AAS".F) This can be used because we have two pairs of congruent sides, with a pair of congruent angles between those sides. Those angles being the marked 90 degree angles. It turns out that LL theorem is a special case of the SAS theorem.In short, we can use choice A, choice D, choice F. We can't use the other three choices because we lack the info about any other pairs of angles.
The congruence theorem or postulate that we can use to show that triangle ABC is congruent to triangle LMN is LL (Side-Side-Side), the correct option is A.
What are congruent triangles?Suppose it is given that two triangles ΔABC ≅ ΔDEF
Then that means ΔABC and ΔDEF are congruent. Congruent triangles are exact same triangles, but they might be placed at different positions.
The order in which the congruency is written matters.
For ΔABC ≅ ΔDEF, we have all of their corresponding elements like angle and sides congruent.
Thus, we get:
[tex]\rm m\angle A = m\angle D \: or \: \: \angle A \cong \angle D \angle B = \angle E\\\\\rm m\angle B = m\angle E \: or \: \: \angle B \cong \angle E \\\\\rm m\angle C = m\angle F \: or \: \: \angle C \cong \angle F \\\\\rm |AB| = |DE| \: \: or \: \: AB \cong DE\\\\\rm |AC| = |DF| \: \: or \: \: AC \cong DF\\\\\rm |BC| = |EF| \: \: or \: \: BC \cong EF[/tex]
(|AB| denotes length of line segment AB, and so on for others).
We are given that;
Sides are equal
Now,
Based only on the information given in the diagram, we can use the following congruence theorems or postulates to show that triangle ABC is congruent to triangle LMN:
A. LL (Side-Side-Side): This theorem states that if three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent. In this case, we know that AB = LM, AC = LN, and BC = MN, so we can use LL to show that triangle ABC is congruent to triangle LMN.
B. ASA (Angle-Side-Angle): This theorem states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent. In this case, we do not know any angle measures, so we cannot use ASA to show that the triangles are congruent.
Therefore, by the congruent triangles the answer will be LL (Side-Side-Side).
Learn more about congruent triangles here:
https://brainly.com/question/16921692
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What is the surface area of a sphere with a diameter of 14 cm?
• 98pi cm squared
• 28pi cm squared
• 784pi cm squared
• 196pi cm squared
Answer: 196πcm²
Given
Diameter = 14
Radius = d/2
= 14/2
= 7
Surface area = 4πr²
Take π = 22/7
= 4×22/7×7×7
= 616 cm²
Must click thanks and mark brainliest
[tex] \large\begin{gathered} {\underline{\boxed{ \rm {\purple{Formula \: \: Using \: = \: 4 \: \pi \: {r}^{2} }}}}}\end{gathered}[/tex]
r represents the radius of sphere.[tex]\bf \ \implies \: \: r \: = \: \frac{Diameter}{2} \\ [/tex]
[tex]\bf \ \implies \: \: r \: = \: \frac{14}{2} \\ [/tex]
[tex]\bf \ \implies \: \: r \: = \: \cancel\frac{14}{2} \: \: \large ^{7} \: \\ [/tex]
[tex]\bf \ \implies \: \: r \: = \: 7 \: cm[/tex]
Substuting the values in formula[tex]\bf \large \longrightarrow \: \: 4 \: \pi \: {r}^{2} [/tex]
[tex]\bf \large \longrightarrow \: \: 4 \: \times \: \pi \: \times {7} \: ^{2} [/tex]
[tex]\bf \large \longrightarrow \: \: 4 \: \times \: \pi \: \times 49[/tex]
[tex]\bf \large \longrightarrow \: \: 196 \: \pi \: {cm}^{2} [/tex]
Hence , the surface area of sphere is 196 π cm²
In Exercises 1-4, determine whether the dilated figure or the original figure is closer to the center of dilation. Use the given location of the center of dilation and scale factor k.
1. Center of dilation inside the figure; k = 3
Center of ditation inside the figure, k = 1/2
3. Center of dilation outside the figure: = 120%
4. Center of dilation outside the figure; k = 0.1
When the Center of dilation is inside the figure
The original figure is closer to the center of dilationThe dilated figure is closer to the the center of dilationWhen the Center of dilation is outside the figure
3. The original figure is closer to the the center of dilation
4. The dilated figure is closer to the center of dilation
The center of dilation is the fixed point from which the distances in a dilation are measured
The scale factor is ratio of the side lengths of an original figure or preimage to the side lengths of the newly formed image
Center of dilation is inside the figure
Where the center of dilation is inside the figure, and the scale factor is larger than 1, k = 3 > 1, we have;The distance of a point on the dilated figure, including the distances from the center of dilation is 3 times the distances of points on the original image from the center of dilation
Therefore, the original figure has a shorter distance to and is therefore closer to the the center of dilation than the dilated figure
2. Where the center of dilation is inside the figure, and the scale factor is a fraction between 0 and 1 k = 1/2, we have;
The distance of a point on the dilated figure, including the distances from the center of dilation is 1/2 times the distances of points on the original image from the center of dilation
Therefore, the dilated figure has a shorter distance to and is therefore closer to the the center of dilation than the original figure
Center of dilation outside the figure
3. Given that the center of dilation is outside the figure and the scale factor is larger than 1, k = 120% = 120/100 = 1.2 > 1, we have;
The distance of the dilated figure from the center of dilation is 120% of the distance of the original figure from the center of dilation, therefore, the original figure is closer to the the center of dilation than the dilated figure
4. Where the center of dilation is outside the figure and the scale factor is a fraction between 0 and 1, k = 0.1 < 1
The distance of the dilated figure from the center of dilation is only 0.1 times the distance of the original figure from the center of dilation, and therefore, the dilated figure is closer to the center of dilation
Learn more about scale factors and center of dilation here;
https://brainly.com/question/12162455
i am having problems with this problem.
Answer:
-70
Step-by-step explanation:
keep adding -4 until you reach the 18th term for example
-2
-6
-10
-14
-18
-22
-26
-30
-34
-38
-42
-46
-50
-54
-58
-62
-66
-70
Triangle ABC is shown below.
What is the length of line segment AC?
7
DS
9
2x
3x - 7
O 14
18
B
4x - 10
с
Mark this and return
Save and Exit
Next
Submit
Answer:
14
Step-by-step explanation:
[tex]angle \: b = angle \: c \: thus \: ab = ac[/tex]
[tex]2x = 3x - 7 \\ 2x - 3x = - 7 \\ - x = - 7 \\ x = 7[/tex]
[tex]ac = 3x - 7 = 14[/tex]
Help if you know thanks
x= - 1/2,-1
or
x= - 0.5, -1
Answer:
x = -1/2 x=-1
Step-by-step explanation:
2x( x+1.5) = -1
Distribute
2x^2 + 3x = -1
Add 1 to each side
2x^2 +3x+1 = 0
Factor
(2x+1) (x+1) =0
Using the zero product property
2x+1 = 0 x+1=0
2x = -1 x=-1
x = -1/2 x=-1
3. Express the mixed recurring decimal 15.732 in p/q form.
Answer
15717/999
Step-by-step explanation
n=15.732732
10n=157.32732
100n=1573.27327
1000n=15732.732732
n= 15.732732
999n=15717
999 999
Answer:
3933/250
Step-by-step explanation:
The domain for f(x) and g(x) is the set of all real numbers.
Let f(x) = 3x + 5 and g(x) = x2.
Find (f − g)(x).
3x3 − 5x2
−x2 + 3x + 5
x2 − 3x − 5
−3x3 − 5x2
Answer:
below
Step-by-step explanation:
that's is the solution above
write the equation of the line that passes through the point (-2,4) and (5,8). Put your answer in fully reduced point slope form, unless it is a vertical or horizontal line.
Answer:
y-4=4(x+2)/7
Step-by-step explanation:
slope(m) = (8-4)/(5-(-2)) =4/7
b = 4-(4/7)×(-2) = 36/7
y = mx+b
y = 4x/7+36/7
in point-slope form,
y-4=4(x+2)/7
Which of the following statements is false?
Answer:
option D is false it's not parallelogram
Describe how (2 cubed) (2 superscript negative 4) can be simplified.
Answer:
1/2
Step-by-step explanation:
Given:
(2 cubed) (2 superscript negative 4)
= (2³)(2^-4)
= (2³) (1 / 2⁴)
= (2³ * 1) / 2⁴
= 2³ / 2⁴
Both numerator and denominator has the same base. Thus, pick one of the bases
Also, in indices, division sign can be translated to subtraction
Therefore,
2³ / 2⁴
= 2^3-4
= 2^-1
= 1/2¹
= 1/2
(2³)(2^-4) = 1/2
Answer:
D
Step-by-step explanation:
bc i said so
The temperature on a mountain peak was 7 degreesFahrenheit (F) at 6:00 p.m. By 8:00 p.m., thetemperature had dropped to 0F. If the temperaturecontinued to drop at about the same rate, which isthebestestimate of the temperature at 11:00 p.m
A -20 / B. -14 / C -10 / D -9 /
Given:
The temperature on a mountain peak was 7°F at 6:00 p.m.
By 8:00 p.m., the temperature had dropped to 0°F.
To find:
The temperature at 11:00 p.m. if the temperature continued to drop at about the same rate.
Solution:
Time between 6:00 p.m. to 8:00 p.m. is 2 hours.
Change in temperature in 2 hours is -7°F.
Change in temperature in 1 hours is [tex]-\dfrac{7}{2}^\circ[/tex]F.
Time between 8:00 p.m. to 11:00 p.m. is 3 hours.
Change in temperature in 3 hours is [tex]3\times \dfrac{-7}{2}^\circ[/tex]F, i.e., [tex]-\dfrac{21}{2}^\circ[/tex]F.
Now, the temperature at 11:00 p.m is:
[tex]0-\dfrac{21}{2}=-10.5[/tex]
Therefore, the temperature at 11:00 p.m. is -10.5°F.
Note: All options are incorrect.
pleeaseeee help me !!!
Answer 3. -7.5 is located to the left of 6.5 on a number line oriented from left to right.
A girl is 18 years younger than her mother. In 6 years time, the sum of their ages will be 54. How old is the girl now?
Answer:
12 yrs.
Step-by-step explanation:
let present age of girl=x
age of mother=x+18
after 6 yrs
age of girl=x+6
age of mother=x+18+6=x+24
according to the condition of question
(x+6)+(x+24)=54
2x+30=54
2x=54-30=24
x=24/2=12
arctanx=arccos(-5/13)
i know that there is no solution but i need to know how to get there
help me solve the trig equation for x!!
If φ = arccos(-5/13), then cos(φ) = -5/13. Since this is negative, you know φ is an angle that terminates either the second or third quadrant.
arctan(x) has a range of -π/2 < arctan(x) < π/2, which is to say that arctan(x) is an angle that terminates in either the first or fourth quadrant.
These quadrants don't overlap, so there is no solution to the equation.
arc length of an oval that is 6ft by 5ft. i just want 1/4 of the oval. i want to find out how long i would need a wire to go from the ground to the middle of the "dome".
the picture explains it better.
in the end i want to have a wire frame around the garden and than take some netting and use that to keep out the big bugs and birds. i will of course use zip ties to attach the screen/netting to the frame. unless there is a easier and cheaper way to do this.
You can model the ellipse with the equation
(x/6)² + (y/5)² = 1
If you're comfortable with calculus, read on.
Let x = 6 cos(t ) and y = 5 sin(t ), with 0 ≤ t ≤ π/2. Then the curve C parameterized by (x(t), y(t)) traces out one quarter of the ellipse. The arc length of this curve is given by the integral,
[tex]\displaystyle\int_C\mathrm ds = \int_0^{\pi/2}\sqrt{x'(t)^2+y'(t)^2}\,\mathrm dt \\\\ = \int_0^{\pi/2}\sqrt{36\sin^2(t)+25\cos^2(t)}\,\mathrm dt \\\\ = \int_0^{\pi/2}\sqrt{25+11\sin^2(t)}\,\mathrm dt \\\\ = 5\int_0^{\pi/2}\sqrt{1+\frac{11}{25}\sin^2(t)}\,\mathrm dt[/tex]
Unfortunately, you cannot find the exact value of this integral. (Well, you can, but it involves introducing a special kind of function; I'll link it in a comment.)
But you can approximate it, and the integral above comes out to about 8.657.
I'm not sure if there's a simpler, purely geometric way to estimate the arc length. But since the semiaxes (5 ft and 6 ft) are fairly close, you could try a circle with a radius somewhere in between. The arc length would range between 7.854 ft and 9.425 ft. If the material isn't too expensive, you can always overshoot and trim off the excess or repurpose it.
please help asap, see attached photo. This is due in 1 hour!!! please answer both questions. Both 5 and 6
Answer:
A and C
Step-by-step explanation:
5) logx+log(x+9)=2
log(x(x+9))=2, log(x^2+9x)=2
6) log(x^2+9x)=2
(x^2+9x)=36 or 6^2
please find the answer
there are options given below
plz give answer asap
Answer
33.3
Step-by-step explanation:
if u multiply the 2, and then find the ratio of them in comparison to the number under, you will find the rate decreases by 10 percent every time, the first situation it is 4/8 = 5/10, second situation is it 32/80= 4/10, and htis situation is most like 3/10, right ? so the answer would be 33.3 :)
