Who would most likely be required to work with sodium hydroxide?

Answer:

F(10)=mass(327)x acceleration(m/s)

Explanation:

Answer:

The magnitude of the student's displacement is less than the distance she walked.

Walking:  11 Blocks

Displacement:  8.54 Blocks

Explanation:

See the attached diagram.  The unit of length is blocks.  We can add the actual blocks walked as shown.  She walked a total of 11 blocks.

Her displacement is the distance measured directly from where she started (line A).  Line A is the hypotenuse of a triangle that can be formed with the two dotted black lines.  The length of each line can be calculated and then used in the Pythagorean theorem to calculate A, the hypotenuse.

That result is 8.54 Blocks, a shorter distance, once she earns her wings.

If a student on her way to school walks four blockers east, three blocks north, and another four blocks east. Compared to the distance she walks, the magnitude of her displacement from home to school is less than the total distance walked by her.

An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard.

As given in the problem if a  student on her way to school walks four blockers east, three blocks north, and another four blocks east,

The total distance walked by the student = 11 blocks

Displacement of the student from home = √(8² + 3²)

                                                                   = 8.5 blocks

The total displacement by the student would be less than the

Thus, the magnitude of her displacement from home is less than the distance.

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Answer:

3.6m/s², 18m/s

Explanation:

So according to h=1/2at², 45=1/2a*25, a=3.6m/s² (which means that it didn't happen on Earth?)

Final velocity = at = 3.6*5 = 18 m/s

According to Newton third law of motion,  what must be true of the magnitude of the reaction force is that the reaction force will be equal and opposite to the action force of 110 newtons

From Newton third law of motion which state that in every action of force, there will be equal and opposite reaction.

If a 75 kg box collides with a stationary 35 kg box with a force of 110 N, the mass 35 kg will produce a reaction force which is equal and opposite to the action force 110 newton received from mass 75 kg.

Therefore, what must be true of the magnitude of the reaction force from mass 35 kg is that the mass will produce an equal and opposite force equal to 110 Newtons.

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Answer:

1200 watt

Explanation:

P= I*V=10*120=1200watt

[tex]P=U.I => I=\frac{P}{U}=\frac{1500}{110}=\frac{150}{11}<A>\\I=\frac{U}{R}=> R=\frac{U}{I} = \frac{110}{\frac{150}{11} }=8.06< ohm>[/tex]

The answer is: A. 8.06 ohm

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Answer:

electricity because it has more percentage nd energy

Explanation:

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Answer:

77 sq.cm

Explanation:

Solution,

Trapezium

Perpendicular (P1)=8cm

Perpendicular(P2)=14cm

height(h)=7cm

Now,

We know that,

Area(A)= 1/2 ×h (P1+P2)

= 1/2 × 7cm (8cm+14cm)

= 1/2 × 7cm(22cm)

= 1/2 × 154 squarecm

=77 sq.cm

Answer:

w

Explanation:

renal artery...the blood flow into the kidney via this blood vassles

and the filtration take place is called ultrafiltration

Answer:

[tex]15\%[/tex].

Explanation:

The efficiency of a machine is the percentage of energy input that was turned into useful energy.

The power rating of this lamp is [tex]40\; \rm W[/tex] (same as [tex]40\; \rm J \cdot s^{-1}[/tex],) meaning that [tex]40\; \rm J[/tex] of energy is supplied to this lamp every second.

The question states that [tex]34\; \rm J[/tex] out of that [tex]40\; \rm J[/tex] of energy input would be turned into heat, which is not useful energy output in this scenario. Assuming that all other forms of energy loss is negligible. The rest of the [tex](40\; \rm J - 34\; \rm J) = 6\; \rm J[/tex] of energy supplied to this lamp would be turned into useful energy output.

Thus, every second, this lamp would receive [tex]40\; \rm J[/tex] of energy input and would outputs [tex]6\; \rm J[/tex] of useful work. The efficiency of this lamp would be:

[tex]\begin{aligned}& \text{Efficiency} \\ =\; & \frac{\text{Useful energy out}}{\text{Total energy in}} \times 100\% \\ =\; & \frac{6\; \rm J}{40\; \rm J} \times 100\%\\ =\; &15\% \end{aligned}[/tex].

Explanation:

For this problem, use the first law of thermodynamics. The change in energy equals the increase in heat energy minus the work done.

ΔU=Q−W

We are not given a value for work, but we can solve for it using the force and distance. Work is the product of force and displacement.

W=FΔx

W=3N×2m

W=6J

Now that we have the value of work done and the value for heat added, we can solve for the total change in energy.

ΔU=Q−W

ΔU=10J−6J

ΔU=4J

Answer is 4J

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Answer: The velocity of what?

[tex]\text{The unit of work is same as energy. Newton-meters(Nm) or Joules(J).}\\[/tex]

Answer:

3.5 hours

Explanation:

Answer:

B,A,A

Explanation:

Answer:

Other guy is correct b,a,a

Explanation:

The given vectors quantities can be described by their properties of both

magnitude and direction.

Reasons:

a. The magnitude of the vector = 190 N

The direction in which the vector acts = East

Therefore, in vector form, we have;

[tex]\vec{F}[/tex] = 190 × cos(0)·i + 190 × sin(0)·j = 190·i

The vector can be represented by an horizontal line, 190 units long

Coordinate points on the vector = (0, 0) and (190, 0)

The drawing of the vector with the above points using MS Excel is attached.

b. Magnitude of the velocity vector = 120 km/hr. 25° North of east

Solution;

The vector form of the velocity is; [tex]\vec{v}[/tex] = 120 × cos(25)·i + 120×sin(25)·j, which gives;

[tex]\vec{v}[/tex] = 120 × cos(25)·i + 120×sin(25)·j ≈ 108.76·i + 50.714·j

[tex]\vec{v}[/tex] ≈ 108.76·i + 50.714·j

Therefore, points that define the vector are; (0, 0) and (108.76, 50.714)

The drawing of the vector is attached

c. The magnitude of the vector = 60 m

The direction of the vector is southwest = West 45° south

The vector form of the displacement is [tex]\vec{d}[/tex] = 60 × cos(45°)·i + 60 × sin(45°)·j

Which gives;

[tex]\vec{d}[/tex] = 30·√2·i + 30·√2·j

Points on the vector are therefore; (0, 0), and (30·√2, 30·√2)

The drawing of the vector is attached

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73.9m/s (1dp)

1) list everything that you are given using suvat, where s is distance, u is initial velocity(speed), v is final velocity(speed), a is acceleration and t is time

s = 430m

u = 27 m/s

v = ? (we need to work out)

a = 5.5m/s^2

t = (we are not given this value)

2) use an equation that doesn't involve the time

[tex] {v}^{2} = u {}^{2} + 2as[/tex]

3) input the values that we have

[tex] {v}^{2} = ( {27})^{2} + 2(5.5)(430)[/tex]

[tex]v {}^{2} = 5459[/tex]

[tex]v = \sqrt{5459} = 73.9[/tex]

so the answer is 73.9m/s to 1dp

Answer: Hello!

The greater the density of a medium, the slower the speed of sound. This observation is analogous to the fact that the frequency of a simple harmonic motion is inversely proportional to m, the mass of the oscillating object. The speed of sound in air is low, because air is easily compressible.

Explanation:

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Answer:

The mass of the eagle is about 5 Kg

Explanation:

1/2 M= Ke/V^2

120 km/h = 33.3333m/s

1/2 M = 2,800/33.3333^2

1/2 M = 2,800/ 1111.10888889

1/2 M = 2.52000504001

(2) 1/2 M = (2) 2.52000504h001

= M = 5.04001008002

About 5 Kilograms

Answer: I don't understand

Explanation:

study and pay attention

As the box is moving with a constant velocity, the two forces acting on the box are canceling each other.

Then   friction force = 80 Newtons              but in the opposite direction.

Friction force =  Mu  * Normal force exerted by ground  =  Mu * weight of box

So we find Mu.

Mu = coefficient of friction between box and horizontal surface

          = Force of friction / weight  =  80 / 50 * 9.81 = 0.163

When an identical box is placed on top, the force of friction is

      = Mu * total weight = 0.163 * (50+50) * 9.81 = 159.9 Newtons

[tex]\\ \sf\Rrightarrow s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf\Rrightarrow s=0(19)+\dfrac{1}{2}a(19)^2[/tex]

[tex]\\ \sf\Rrightarrow 475=\dfrac{361a}{2}[/tex]

[tex]\\ \sf\Rrightarrow 950=361a[/tex]

[tex]\\ \sf\Rrightarrow a\approx 2.3m/s^2[/tex]

The true statement about the wave is that, the wave has traveled 97. 2 cm in 1 second.

In Physics, we define a wave as a disturbance along a medium that transfers energy. The wavelength of a wave is the distance covered by the wave while the frequency of the wave is the number of cycles of the wave completed per second.

The period of the wave is the inverse of the frequency of the wave. It is defined as the time taken for the wave to complete a cycle and it is measured in seconds.

The wave formula is given as;

v = λf

v = velocity of the wave (distance traveled by the wave in one second)

λ = wavelength of the wave

f = frequency of the wave

So;

λ = 32.4 cm

f =  3 hertz

v = 32.4 cm × 3 hertz

v = 97. 2 cms-1

Hence, the true statement about the wave is that, the wave has traveled 97. 2 cm in 1 second.

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Hi there!

Recall:

Impulse = Change in momentum

I = Δp = mΔv = m(vf - vi)

Let the direction TOWARDS the floor be POSITIVE, and AWAY be NEGATIVE.

Plug in the givan values:

Δp = 1.5(-10 - 12) = -33 Ns

**OR, the magnitude: |-33| = 33 Ns

The kinetic energy of the crate as it reaches the lower surface is 80 J

Kinetic energy is the energy possed by an object in motion. Mathematically, the kinetic energy can be expressed as follow:

KE = ½mv²

With the above formula, the kinetic energy of the crate can be obtained as follow:

KE = ½mv²

KE = ½ × 10 × 4²

KE = 5 × 16

KE = 80 J

Therefore, the kinetic energy of the crate is 80 J

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Microwave Radiation????????????

Answer:

The answer is 1200

Explanation:

Answer:

0.23N for the speed

at the bottom of the circle

Answer:

m

Explanation:

Metres, m, is the SI unit of length

Hope this helped you-have a good day bro cya)

Answer:

They must be supported by evidence.

Explanation:

Every scientific theory or scientifc claim must have scientific evidence.