A mass is pulled to the right while on a table.
A. Label the forces.
5 kg
B. Calculate the
object's weight.
Answer:
weight in 49N
I hope it's correct
A boxer throws a punch with a force of 1,400 N that lasts 0.02 s. What is the impulse of this punch? (1 point) 28 kg⋅m/s 28 kilograms times meters per second 280 kg⋅m/s 280 kilograms times meters per second 70,000 kg⋅m/s 70,000 kilograms times meters per second 7,000 kg⋅m/s
The impulse of the boxers punch is 28 kgm/s.
The given parameters;
applied force by the boxer, F = 1400 Ntime of force action, t = 0.02 sThe impulse of the boxers punch is calculated as follows;
[tex]J = Ft[/tex]
where;
F is the applied force (N)t is the time of force action (s)The magnitude of the impulse is calculated as follows;
[tex]J = 1400 \times 0.02 \\\\J = 28 \ kg m/s[/tex]
Thus, the impulse of the boxers punch is 28 kgm/s.
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You slide towards the window when a car makes a sudden turn
Answer:
thats ummm
Explanation:
law of inertia
Newton’s 1 law
Name the two sources of light.
Answer:
Natural light (Sun, stars.etc.) and Artificial light (Lamposts, televisions.etc.)
Hope that helps. x
11. A tennis ball is thrown straight up in the air, leaving the person's hand with an initial velocity of 3.0 m/s, as shown to the right. What is the displacement of the ball above the person's hand?
Answer:
0.46m
Explanation:
PLEASEE IS FOR A TEST!!!Which ionic compound is BOTH correctly written and named??
A mg0 magnesium oxide
B Mn02 manganese oxide
C N02 nitrogen oxide
D SrBr strontium bromide
Answer:
Letter A
Explanation:
Manganese dioxide- Mn02
Nitrogen Dioxide- n02
Strontium bromide- SrBr
Which shows the stars in the correct order, from smallest in size to largest?
white dwarf, Sun, red supergiant
Sun, red supergiant, white dwarf
white dwarf, red supergiant, Sun
Sun, white dwarf, red supergiant
Answer:
its A
Explanation:
White dwarf, Sun, red supergiant shows the stars in the correct order, from smallest in size to largest.
What is the size stars?More than 1.4 million kilometers span our Sun. However, not every star is the same size. They range in size from that of a metropolis to that of our solar system's half!
The mass of neutron stars is concentrated into a very compact area. Even though they are frequently only 20 to 40 km in diameter, they may hold the mass of one or two Suns. White dwarf stars are a little larger and frequently resemble the size of the Earth.
Compared to our Sun, the greatest supergiant stars can be more than 1500 times bigger. They are now more than 2,000 million kilometres across. Supergiants don't, however, have thousands of times the mass of the Sun. The reason for this is that as supergiants become older, their interiors become considerably more dispersed. Betelgeuse, a red giant in Orion's constellation, is nearly 1000 times broader than the Sun yet only has around 15 times as much mass.
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an EM wave has a wave length of 956 m, What type of electromagnetic waves is this wave
The electromagnetic spectrum allows finding the result for the question of type of electromagnetic wave has a wavelength of 956 nm
The wave is in the near infrared range.
The electromagnetic wave is an oscillation of electric fields and magnets field that sustain each other, this wave time has the characteristics that it can travel without a material medium, for which they are of extreme importance.
Consequently the spectrum of electromagnetic waves to each part has been given a different name second to its use, for example
Range Name
Ultraviolet light 200 to 400 nm
Visible light 400 to 700 nm
Infrared light (heat ) 700 nm to 1 mm
The latter is subdivided into:
Near infrared 700 nm to 1000 nm (1 μm)
Medium infrared 1 μm to 30 μm
Far infrared 50 μm to 1000 μm
It indicates that the wavelength of the measured radiation is 956 nm, therefore it is in the near infrared range.
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Explain how the stars impact the shape of a galaxy.
Answer:
Galaxies are too far away for astronomers to take real 3D measurements, but we can infer their shape based on the movement of stars. ... This is also true of less common spiral galaxies like the Milky Way. The bulge near the center contains older stars, while the flattened arms are home to younger ones.
Explanation:
The orbits of stars can also affect the shape of a galaxy through a variety of density waves that are produced when material is compressed into something comparable to a traffic jam in galaxies.
What is Star?A star is defined as a celestial object consisting of a luminous sphere of plasma held together by self-gravity where the closest star to Earth is the Sun. While many other stars are visible to the uncovered eye at night, their extreme distance from Earth causes them to appear as fixed points of light.
Galaxies are too far away for astronomers to take true 3D measurements, through which we can estimate their size based on the motion of stars, which is also true for less common spiral galaxies like the Milky Way.
Thus, the orbits of stars can also affect the shape of a galaxy through a variety of density waves that are produced when material is compressed into something comparable to a traffic jam in galaxies.
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The body weighs 15N. What is the mass of that body?
when is atmospheric pressure 1x10 to the power of 5 and when is it pgh
Answer:
1 atmospheris pressure is equal to10.33 meter under water
Explanation:
right ??
A bullet of mass M1 is fired towards a block of mass m2 initially at rest at the edge of a frictionless table of height h as in the figure. The initial speed of the bullet is vi . Consider two cases, a completely inelastic one and an elastic one,where the bullet bounces off the block. inelastic case elastic case a bullet inside no bullet inside A B A' B' What is the ratio of the flight time; i.e., tAB tA′B′ ?
The ratio of time of flight for inelastic collision to elastic collision is 1:2
The given parameters;
mass of the bullet, = m₁mass of the block, = m₂initial velocity of the bullet, = u₁initial velocity of the block, = u₂Considering inelastic collision, the final velocity of the system is calculated as;
[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\m_1u_1 + 0 = v(m_1 + m_2)\\\\v= \frac{m_1u_1}{m_1 + m_2} \ -- (1)\\\\[/tex]
The time of motion of the system form top of the table is calculated as;
[tex]v = u + gt\\\\v = 0 + gt\\\\v = gt\\\\t= \frac{v}{g} \\\\t_A = \frac{m_1u_1}{g(m_1 + m_2)} \ \ ---(2)[/tex]
Considering elastic collision, the final velocity of the system is calculated as;
[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\m_1u_1 + 0 = m_1v_1 + m_2v_2\\\\m_1 u_1 = m_1v_1 + m_2v_2[/tex]
Apply one-directional velocity
[tex]u_1 + (-v_1) = u_2 + v_2\\\\u_1 -v_1 = 0 + v_2\\\\v_1 = v_2 -u_1[/tex]
Substitute the value of [tex]v_1[/tex] into the above equation;
[tex]m_1u_1 = m_1(v_2 - u_1) + m_2 v_2\\\\m_1u_1 = m_1v_2 -m_1u_1 + m_2v_2\\\\2m_1u_1 = m_1v_2 + m_2v_2\\\\2m_1u_1= v_2(m_1 + m_2)\\\\v_2 = \frac{2m_1u_1}{m_1+ m_2} \ --(3)[/tex]
where;
[tex]v_2[/tex] is the final velocity of the block after collision
Since the bullet bounces off, we assume that only the block fell to the ground from the table.
The time of motion of the block is calculated as follows;
[tex]v_2 = v_0 + gt\\\\v_2 = 0 + gt\\\\t = \frac{v_2}{g} \\\\t_B = \frac{v_2}{g} \\\\ t_B = \frac{2m_1u_1}{g(m_1 + m_2)} \ \ ---(4)[/tex]
The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;
[tex]\frac{t_A}{t_B} = \frac{m_1u_1}{g(m_1 + m_2)} \times \frac{g(m_1 + m_2)}{2m_1u_1} \\\\\frac{t_A}{t_B} = \frac{1}{2} \\\\t_A:t_B = 1: 2[/tex]
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A small charge q is placed near a large spherical charge Q. The force experienced by both charges is F. The electric eld created by Q at the position of q is:
The electric field created by Q at the position of q is [tex]\frac{F}{Q}[/tex].
The given parameters:
Magnitude of charge, = qSpherical charge, = QForce experienced by both charges, = FThe electric field created by Q at the position of q is calculated as follows;
[tex]E = \frac{F}{Q} \\\\[/tex]
where;
E is the magnitude of electric field strength F is the force experienced by both chargesQ is the chargeThus, the electric field created by Q at the position of q is [tex]\frac{F}{Q}[/tex].
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David delivers meals to elderly people once a week. He uses a cart to move the meals. The cart has four smooth wheels. Which type of friction acts between the cartwheels and the sidewalk?
Answer: rolling friction
Explanation: I think it is the answer
Which of the following elements is more reactive than the others
Answer:
Sulfur
Selenium
Nitrogen
Oxygen
Explanation:
Sulfur is the most reactive out of the four and Oxygen is the least reactive out of the four.
A go cart with a mass of 60 kg is moving at a rate of 10 m/s. How much Kinetic Energy does the go cart have?
Answer:
3000 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass in kg
v is the velocity in m/s
From the question
m = 60 kg
v = 10 m/s
We have
[tex]k = \frac{1}{2} \times 60 \times {10}^{2} \\ = 30 \times 100 \\ = 3000[/tex]
We have the final answer as
3000 JHope this helps you
Answer:
[tex]\boxed {\boxed {\sf 3000 \ J}}[/tex]
Explanation:
Kinetic energy is the energy an object has due to motion. It is calculated using the following formula:
[tex]KE=\frac{1}{2} mv^2[/tex]
The mass of the go-cart is 60 kilograms and the velocity is 10 meters per second.
m= 60 kg v= 10 m/sSubstitute the values into the formula.
[tex]KE= \frac{1}{2} (60 \ kg)(10 \ m/s)^2[/tex]
Solve the exponent.
(10 m/s)² = 10 m/s * 10 m/s = 100 m²/s²[tex]KE = \frac{ 1}{2} (60 \ kg)(100 \ m^2/s^2)[/tex]
Multiply the numbers together.
[tex]KE= 30 \ kg * 100 \ m^2/s^2[/tex]
[tex]KE= 3000 \ kg*m^2/s^2[/tex]
Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule, so our answer of 3000 kg*m²/s² equals 3000 Joules.
[tex]KE= 3000 \ J[/tex]
The go-cart has 3000 Joules of kinetic energy.
Send right answers plzzzz plz
Answer:
I think A
Explanation:
plz help
Suppose one of the three students in Guided Example 7.6 stops pushing the car after 6.00 s. In this case the force exerted on the car is 305 N for the first 6.00 s and 215 N for the second 6.00 s.
(a) What is the final momentum of the car?
(b) What is the final speed of the car?
Answer:
520 n is the final momentum of the car and is also the final speed of the car
Explanation:
The final momentum is 250 newton.
What is momentum?Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.
According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum.
On the other hand, a particle's momentum represents the length of time needed for a consistent force to bring it to rest.
Therefore, The final momentum is 250 newton.
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Lower chamber of Congress has how many members?
Answer:435 Representatives
Explanation:The lower chamber of Congress, in which the number of representatives per state is determined by the state's population, with 435 Representatives total. Members of the House of Representatives serve two-year terms, so they are up for reelection every two years.
how to prove sand is not a fluid even if it takes the shape of a container
A 30.4-newton force is used to slide a 40.0-newton crate a distance of 6.00 meters at constant speed along an incline to a vertical height of 3.00 meters. Calculate the work done by a friction force on the crate as it slides 6.00 m along the incline.
Hi there!
Since the crate is being slid at a constant speed, the forces sum to 0 N. In this instance, the following forces occur in the axis of interest:
Wsinθ = downward acceleration along incline due to gravity (N)
Fκ = kinetic friction force along incline (N)
A = applied force (N)
The acceleration due to gravity and friction force act in the same direction, so:
Wsinθ + Fκ = A
Solve for sinθ using right triangle trigonometry:
sinθ = O/H = 3/6 = 0.5
Rearrange the equation for the force of kinetic friction and solve:
Fκ = A - 0.5W
Fκ = 30.4 - 20 = 10.4 N
Now, recall that:
Work = Force × displacement (W = F × d)
Since the box's displacement is in the same axis as the force but OPPOSITE direction, we must use:
W = Fdcosθ
Angle between displacement and friction force is 180°.
cos(180) = -1
Work done by friction = -Fd = -10.4(6) = -62.4 J
12/3/21 A wave in the ocean has a wavelength of 24 m and a frequency of 8 Hz,What is the wave's speed?
Answer:
192 m/sExplanation:
The speed of the wave given only it's frequency and wavelength can be found by using the formula
[tex]c = f \times \lambda[/tex]
where
c is the velocity of the wave in m/s
[tex] \lambda[/tex] is the wavelength in m
f is the frequency in Hz
From the question we have
c = 8 × 24 = 192
We have the final answer as
192 m/sHope this helps you
What would be the impact on the environment if an artificial virus that attacked and destroyer chloroplast in plant cells was accidentally released by a research company?
Answer:Yes
Explanation:Because the virus is so dangerous
What is the mass of a box if it accelerated 5 m/s from a force of 12 N?
Answer:
60
Explanation:
You multiply the acceleration and the force and you get your answer
an object has a kinetic energy of 14 j and a mass of 17 kg how fast is the object moving
[tex]\\ \sf\Rrightarrow kE=\dfrac{1}{2}mv^2[/tex]
[tex]\\ \sf\Rrightarrow 14=\dfrac{1}{2}17v^2[/tex]
[tex]\\ \sf\Rrightarrow 17v^2=28[/tex]
[tex]\\ \sf\Rrightarrow v^2=28/17[/tex]
[tex]\\ \sf\Rrightarrow v^2=1.64[/tex]
[tex]\\ \sf\Rrightarrow v\approx 0.13m/s[/tex]
A ball is kicked at an angel of 37° to a goalkeeper who is 24m away. What was the initial velocity of the ball?
The initial velocity of the ball when it was projected is 15.64 m/s.
The given parameters:
Angle of the projection, θ = 37⁰The range of the projectile, R = 24 mThe initial velocity of the ball is calculated by applying formula for range of projectile as follows;
[tex]R = \frac{u^2 sin(2\theta)}{g} \\\\u^2 = \frac{Rg}{sin(2\theta)} \\\\u = \sqrt{\frac{Rg}{sin(2\theta)} } \\\\u =\sqrt{\frac{24 \times 9.8}{sin(2\times 37)} } \\\\u = 15.64 \ m/s[/tex]
Thus, the initial velocity of the ball when it was projected is 15.64 m/s.
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Say you were at mission control on
Earth. You use radio waves to say "Hello" to an
astronaut on Mars when Mars is 84,000,000
km from Earth. The astronaut hears your "Hello"
280 seconds after you spoke the word. How do
you explain this time lag?
Answer:
because mars is far
Explanation:
so if he shouts louder than he will hear it quicker
1.Explain why you think it is important to vary your
physical activities from time to time.
2. Define: Lifelong activities and Lifetime sports.
Include similarities, differences and give
examples.
Answer:
I feel like a person should vary their physical activities because it keeps your body in shape and fit and you are able to move around. For example, like running or jogging it helps burn calories and it helps keep your abs/stomach right.
Explanation:
What is electromagnetic wave ?
its an electric magnetic cell this uses electricity
the acceleration of a train moving from rest and its speed reaches 36m/sec in 9 sec
Answer:
4 m/s^2
Explanation:
The acceleration is defined as: Δv/Δt (the difference of the velocity over a time period in which happens that difference).
Remember that a difference is calculated by subtracting the initial value of a physical quantity from its final value.
In our case:
Δv = Vfinal - Vinitial = 36m/s - 0 m/s = 36m/s
Δt = 9s
a = Δv/Δt = 36m/s / 9s = 4m/s^2
