Answer:
0.9894 = 98.94% probability that he does not have a TBI.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Negative screen
Event B: Does not have a TBI.
Probability of a negative screen:
93 are negative and do not have a TBI.
1 is negative and has a TBI.
Out of 112.
So
[tex]P(A) = \frac{93+1}{112} = \frac{94}{112}[/tex]
Probability of a negative screen and not having a TBI:
93 are negative and do not have a TBI, out of 112, so:
[tex]P(A \cap B) = \frac{93}{112}[/tex]
One of the veterans has a negative screen and wants to know the probability that he does not have a TBI.
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{93}{112}}{\frac{94}{112}} = \frac{93}{94} = 0.9894[/tex]
0.9894 = 98.94% probability that he does not have a TBI.
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the eighth grade level.
Step 1 of 2: Suppose a sample of 2845 tenth graders is drawn. Of the students sampled, 2276 read above the eighth grade level. Using the data, estimate the proportion of tenth graders reading at or below the eighth grade level. Enter your answer as a fraction or a decimal number rounded to three decimal places.
Step 2 of 2: Suppose a sample of 2845 tenth graders is drawn. Of the students sampled, 2276 read above the eighth grade level. Using the data, construct the 99% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level. Round your answers to three decimal places.
Answer:
Step 1: The estimate the proportion of tenth graders reading at or below the eighth grade level is 0.2.
Step 2: The 99% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.181, 0.219).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
Suppose a sample of 2845 tenth graders is drawn. Of the students sampled, 2276 read above the eighth grade level.
So 2845 - 2276 = 569 read below, and the estimate of the proportion of tenth graders reading at or below the eighth grade level is:
[tex]\pi = \frac{569}{2845} = 0.2[/tex], and the answer to step 1 is 0.2.
The sample size is [tex]n = 2845[/tex]
99% confidence level
So [tex]\alpha = 0.01[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2 - 2.575\sqrt{\frac{0.2*0.8}{2845}} = 0.181[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2 + 2.575\sqrt{\frac{0.2*0.8}{2845}} = 0.219[/tex]
The 99% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.181, 0.219).
so sánh 198*202 và 200^2
Step-by-step explanation:
198×202=39,996
200×200=40,000
hence,
39,9996 < 40,000
hope it helps
find the sum of (-260)+(-30)
Answer:
-290
Step-by-step explanation:
(-260) +(-30)
=-260-30
=-290
Answer:
the answer is -290
Step-by-step explanation:
it is telling us to add so we can see that both the numbers have the same sign which is negative
when the signs are all the same, we can add and we got -290
Which of the following statements are true?
Answer:
last one
Step-by-step explanation:
they both whole
Find the length represented by x for each pair of similar triangles.
18cm, 9cm, and x
30cm, 15cm, and 25cm
Answer:
15 cm
Step-by-step explanation:
Since the traingles are similar, we can find the ratio between the side lengths, and it will be the same for each side.
We can use the side length 9 and 15 to find this ratio. 15/9=5/3. So, the ratio of a side length of the larger triangle to the smaller one is 5/3, so our equation becomes 5/3 = 25/x. Use any method you like to find that x=15.
Hope this helped,
~cloud
The value of f(x)= 5x -4x²+3 when x= -1, is
Answer:
F(x) =5(-1)-4(-1)^2+3,
=-5-4+3
=-6
find the maximum number of children to whom 30 sweaters and 45 trousers can be equally divided. also how many sweaters and trousers will each get?
Answer:
five kids .each 6 sweaters and 9 trousers
Step-by-step explanation:
fWhat is the sum (6x^3 – 5x^2 + 3x – 5) + (8x^4 + 3x^3 + 5x^2 + x + 4)?
A.9x^6 + 8x^4 + 4x^2 – 1
B.8x^4 + 9x^3 + 4x – 1
C.8x^4 + 3x^3 – 10x^2 + 4x – 1
D.8x^4 – 3x^3 + 10x^2 – 2x + 9
Answer:
8x^4+9x^3+4x-1
Step-by-step explanation:
(6x^3 – 5x^2 + 3x – 5) + (8x^4 + 3x^3 + 5x^2 + x + 4)
Group like terms
8x^4+6x^3+3x^3-5x^2+5x^2+3x+x-5+4
8x^4+9x^3+4x-1
Answer:
[tex]\left(6x^3-5x^2+3x-5\right)+\left(8x^4+3x^3+5x^2+x+4\right)[/tex]
Combine like terms
[tex]=8x^4+6x^3+3x^3-5x^2+5x^2+3x+x-5+4[/tex]
Add: -5x²+5x²=0
[tex]=8x^4+6x^3+3x^3+3x+x-5+4[/tex]
Now add 6x³+3x³=9x³
[tex]=8x^4+9x^3+3x+x-5+4[/tex]
Add like terms 3x +x=4x
[tex]=8x^4+9x^3+4x-5+4[/tex]
Now add -5+4=-1
[tex]=8x^4+9x^3+4x-1[/tex]
OAmalOHopeO
A bucket contains 4 red balls that are numbered 1, 2, 3, 4. It also contains 6 black balls that are numbered 5, 6, 7, 8, 9, 10. Two balls are drawn from the bucket, one at a time, without replacement. Use this information to answer the following probability questions. Express answers as fractions, or round decimal answers to 4 decimal places. a. What is the probability that the first ball is even and the second ball is odd
The probability is 1/9
We want to find the probability that the first drawn ball is even, and the second is odd.
The probability of randomly drawing an even ball will be equal to the quotient between the number of balls with even numbers and the total number of balls in the bucket.
We have a total of 10 balls (4 red ones and 6 black ones)
and 5 of these have even numbers (2, 4, 6, 8, 10)
Then the probability of drawing a ball with an even number first is:
p = 5/10 = 1/5
now we want to get a ball with an odd number.
notice that we already got a ball with an even number and we did not replace it, so now there are 9 balls left in the bucket, 5 odd ones, and 4 even ones.
The probability of getting an odd ball is computed in the same way thana above, as the quotient between the number of balls with odd numbers (5) and the total number of balls in the bucket (9)
q = 5/9
The joint probability (the probability that these two events happen together) is equal to the product of the individual probabilities, so we will get:
P = p*q = (5/9)*(1/5) = 1/9
The probability is 1/9
If you want to learn more about this topic, you can read:
https://brainly.com/question/24280250
After a large fund drive to help the Boston City Library, the following information was obtained from a random sample of contributors to the library fund. Using a 1% level of significance, test the claim that the amount contributed to the library fund is independent of ethnic group.
Number of People Making Contribution
Ethnic Group $1-50 $51-100 $101-150 $151-200 Over $200 Row Total
A 77 63 54 39 18 251
B 90 48 76 26 24 264
C 73 67 59 37 30 266
D 108 82 70 50 30 340
Column Total 348 260 259 152 102 1121
Required:
a. What is the level of significance?
b. Find the value of the chi-square statistic for the sample.
c. Find or estimate the P-value of the sample test statistic.
d. Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis of independence?
Answer:
α = 0.01 ; 2 - tailed
χ² = 16.998
Pvalue = 0.1497
Fail to reject H0
Step-by-step explanation:
Given the data above :
Number of People Making Contribution
Ethnic Group $1-50 $51-100 $101-150 $151-200 Over $200 Row Total
A 77 63 54 39 18 251
B 90 48 76 26 24 264
C 73 67 59 37 30 266
D 108 82 70 50 30 340
Column Total 348 260 259 152 102 1121
1.) The level of significance, α/2 = 0.01/2
2.)
The hypothesis :
H0 : Contribution and Ethnic group are independent
H1 : Contribution and Ethnic group are not independent
The Chisquare statistic :
χ² = (Observed - Expected)²/ Expected
The expected value for each cell is calculated thus :
(Row total * column total) / sum total
The expected values :
77.9197 58.2159 57.992 34.0339 22.8385
81.9554 61.231 60.9955 35.7966 24.0214
82.5763 61.6949 61.4576 36.0678 24.2034
105.549 78.8582 78.5549 46.1017 30.9367
Using the χ² formula above ;
χ² values for each cell are :
0.010855 0.393154 0.274794 0.724635 1.02509
0.789645 2.85902 3.69099 2.68108 0.0000191
1.11055 0.456179 0.098278 0.0240936 1.38826
0.056933 0.125176 0.93165 0.32963 0.028359
Taking the sum :
0.010855+0.393154+0.274794+0.724635+1.02509+0.789645+2.85902+3.69099+2.68108+0.0000191+1.11055+0.456179+0.098278+0.0240936+1.38826+0.056933+0.125176+0.93165+0.3293+0.028359
χ² = 16.998
To obtain the Pvalue :
df = (Row - 1)(column - 1) = (5-1)*(4-1) = 4 * 3 = 12
Pvalue(16.998 ; 12) = 0.1497
If Pvalue < α ; Reject H0 ;
Since Pvalue > α ; WE fail to reject H0
The principal amount of money for this loan is $9,500.00. If you deposit this into an account paying 4.2% annual interest compounded monthly. How much money will be in the account after 5 years? (also called Future value).
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Answer:
$11,715.65
Step-by-step explanation:
The applicable formula is ...
FV = P(1 +r/n)^(nt)
where principal P earns interest at rate r compounded n times per year for t years.
FV = $9500(1 +0.042/12)^(12·5) = $9500(1.0035^60) ≈ $11,715.65
The account will hold $11,715.65 after 5 years.
The graphs of exponential functions f and g are shown on the coordinate plane below.
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Answer:
k = 3
Step-by-step explanation:
It is convenient to look at the line y=1 to see that f(0) = 1 and g(3) = 1. Then for x=3, g(3) = f(3 -k) = f(0) = 1
k = 3
__
k is the amount by which the function has been shifted to the right. By comparing grid-intersection points on f(x) and g(x), we see that g(x) is 3 units to the right of f(x), so k = 3.
Family Video stocks 1003 drama movies, 518 science fiction movies and
253 children's movies. How many more drama titles than children's
titles does Family Video have in stock?
Answer:
There are 750 more drama movies that children's movies.
Step-by-step explanation:
There are 1003 drama movies, and 253 children's movies.
1003 - 253 = 750
Which graph represents the function f(x) = x-2?
Answer:
click in photo
nejdjjd
nxndjdbbdjf
lấy x=0 ta có y= -2 => A(0;-2)
lấy y=0 ta có x=2 => B(2;0)
nối 2 điểm A và B ta có đồ thị:
A population of values has a normal distribution with μ= 180.1
and σ=100. You intend to draw a random sample of size n=94
What is the mean of the distribution of sample means?
What is the standard deviation of the distribution of sample means?
(Report answer accurate to 2 decimal places.)
A sample of size n taken from a normally distributed population with mean µ and standard deviation σ has a sample mean of µ and standard deviation of σ/√n.
So the sample mean would still be 180.1, while the sample standard deviation would be 100/√94 ≈ 10.31.
is jannelle correct ?
Answer:
yes
Step-by-step explanation:
o
A spinner contains the numbers 1 through 50. What is the probability that the spinner will land on a number that is not a multiple of 8?
Answer:
22/25
Step-by-step explanation:
Multiples of 8 are 8,16,24,32,40,48
That means there are 6 multiples of 8
50 -6 = 44
There are 44 non multiples of 8
P( non multiples of 8) = non multiples of 8 / total
= 44/50
=22/25
If Victoria's rent is $400 per month, and she pays an additional $150 for utilities and $35 for advertising each month, what is her cost function using the additional data from previous problem? Use C to denote cost and n for number of collars she makes.
Answer:
[tex]C(n) = 435n + 150[/tex]
Step-by-step explanation:
Given
[tex]Base = 400[/tex] -- Base charge per month
[tex]Utilities = 150[/tex]
[tex]Adverts = 35[/tex] per month
Required
The cost function
To do this, we multiply the rates by the number of months.
So, we have:
[tex]C(n) = Base * n + Adverts * n + Utilities[/tex]
So, we have:
[tex]C(n) = 400 * n + 35 * n + 150[/tex]
[tex]C(n) = 400n + 35n + 150[/tex]
[tex]C(n) = 435n + 150[/tex]
25(0.3x-4)-5(1.5x-6)+100(13/4) simplify the following expression and evaluate for x=0.345
Answer:
255
Step-by-step explanation:
Given :
Simplify the expression :
25(0.3x-4)-5(1.5x-6)+100(13/4)
Open each Bracket:
7.5x - 100 - 7.5x + 30 + 325
7.5x - 7.5x - 100 + 30 + 325
= 255
The simplified equation = 255
Thank you guys fir the help
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Answer:
A
Step-by-step explanation:
The function f(x) is required in the numerator, eliminating choices C and D.
The restriction is that function g cannot be zero, so we cannot have ...
3x +2 = 0
3x = -2
x = -2/3 . . . . . eliminates choice B; confirms choice A
A car rental firm has 440 cars. Sixty-three of these cars have defective turn signals and 39 have defective tires. (Enter your probabilities as fractions.) (a) What is the probability that one of these cars selected at random does not have defective turn signals
Answer:
The probability is 0.857
Step-by-step explanation:
We know that:
There is a total of 440 cars
There are 63 cars with defective turn signals
There are 39 with defective tires.
Now we want to find the probability that a randomly selected car does not have defective turn signals.
If all the cars have the same probability of being selected, this probability will be equal to the quotient between the number of cars that do not have defective turn signals and the total number of cars.
We know that the total number of cars is 440
And 63 of these have defective turn signals, then the rest don't.
440 - 63 = 377 cars do not have defective turn signals.
Then the probability is:
P = 377/440 = 0.857
Suppose that a customer is purchasing a car. He conducts an experiment in which he puts 10 gallons of gas in the car and drives it until it runs out of gas. He conducts this experiment 15 times on each car and records the number of miles driven.
Car 1 Car 2
214 220
245 221
239 244
224 225
220 258
295 259
Describe each data set, that is determine the shape, center, and spread
i. Sample mean for Car 1
ii. Sample mean for Car 2
Answer:
Kindly check explanation
Step-by-step explanation:
Given the data :
Car 1 Car 2
214 220
245 221
239 244
224 225
220 258
295 259
Ordered data:
Car 1 : 214, 220, 224, 239, 245, 295
Sample mean = ΣX/ n ; n = sample size = 6
Sample mean = 1437 / 6 = 239.5
Median = 1/2(n+1)th term = 1/2(7) = 3.5th term
Median = (3rd + 4th) /2 = (224 + 239) /2 = 231.5
Sample standard deviation; √(Σ(x - xbar)²/n-1 ) = 29.60 (using calculator)
Car 2 : 220, 221, 225, 244, 258, 259
Sample mean = ΣX/ n ; n = sample size = 6
Sample mean = 1427 / 6 = 237.833
Median = 1/2(n+1)th term = 1/2(7) = 3.5th term
Median = (3rd + 4th) /2 = (225 + 244) /2 = 234.5
Sample standard deviation; √(Σ(x - xbar)²/n-1 ) = 18.21 (using calculator)
The price of a item has reduced by 85% the original price was $60
Answer:
The price now would be 9 dollars
Step-by-step explanation:
60 x 85% is 51 and you subtract that from 60
represent (-12)+(-8)+14 on a number line
Answer:
-6
Step-by-step explanation:
(-12)+(-8)= -20
-20+14= -6
Cho hình hộp chữ nhật ABCD A B C D
Answer:
A B C D
A×B×C×D
3×3×3×6
162
What is the approximate length of arc s on the circle below? Use 3.14 for Pi. Round your answer to the nearest tenth.
-5.8 ft
-6.3 ft
-27.5 ft
-69.1 ft
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Answer:
69.1 ft
Step-by-step explanation:
The diameter of the circle is 24 ft. The length of the arc is more than twice the diameter, so cannot be less than about 50 ft. The only reasonable choice is ...
69.1 ft
__
The circumference of the circle is ...
C = 2πr = 2(3.14)(12 ft) = 75.36 ft
The arc length of interest is 330° of the 360° circle, so is 330/360 = 11/12 times the circumference.
s = (11/12)(75.36 ft) = 69.08 ft ≈ 69.1 ft
Answer:D
Step-by-step explanation:
A ladder 10m long is set against a vertical wall, Calculate the height of the wall where the ladder reached a foot of the ladder is 6m away from the wall.
Answer:
8m
Step-by-step explanation:
Please show your work this question what made you come to the conclusion. Thank you
Answer:
B the range, the x- and y-intercept
Step-by-step explanation:
the domain stays the same : all values of x are possible out of the interval (-infinity, +infinity).
but the range changes, as for the original function y could only have positive values - even for negative x.
the new function has a first term (with b) that can get very small for negative x, and then a subtraction of 2 makes the result negative.
the y-intercept (x=0) of the original function is simply y=1, as b⁰=1.
the y-intercept of the new function is definitely different, because the first term 3×(b¹) is larger than 3, because b is larger than 1. and a subtraction of 2 leads to a result larger than 1, which is different to 1.
the original function has no x-intercept (y=0), as this would happen only for x = -infinity. and that is not a valid value.
the new function has an x-intercept, because the y-values (range) go from negative to positive numbers. any continuous function like this must therefore have an x-intercept (again, y = the function result = 0)
[tex] 3 {b}^{x + 1} = 2[/tex]
[tex] {b}^{x + 1} = 2 \div 3[/tex]
[tex] log_{b}(2 \div 3) = x + 1[/tex]
[tex]x = log_{b}(2 \div 3) - 1[/tex]
An exponential function f(x) = ab^xpasses through the points (0, 2) and (3, 54). What are the values of a and
b?
a=
b =
Answers:
a = 2
b = 3
=======================================================
Explanation:
Plug in x = 0 and y = 2 to find that
y = a*b^x
2 = a*b^0
2 = a*1
2 = a
a = 2
Then plug in x = 3 and y = 54 to determine the value of b
y = a*b^x
y = 2*b^x
54 = 2*b^3
2b^3 = 54
b^3 = 54/2
b^3 = 27
b = (27)^(1/3)
b = 3
So we have y = a*b^x update to y = 2*3^x
MY NOTES Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that satisfy the conclusion of Rolle's Theorem. (Enter your answers as a comma-separated list.) f(x) = 2x2 − 4x + 3, [−1, 3
Answer:
b) [tex]c=1[/tex]
Step-by-step explanation:
From the question, we are told that:
Function
[tex]F(x)=2x^2-4x+9[/tex]
Given
Rolle's theorem states that if a function f is continuous on the closed interval [a, b] and differentiable on the open interval (a, b) such that f(a) = f(b), then f′(x) = 0 for some x with a ≤ x ≤ b.
Generally, the Function above is a polynomial that can be Differentiated and it is continuous
Where
-F(x) is continuous at (-1,3)
-F(x) Can be differentiated at (-1.3)
-And F(-1)=F(3)
Therefore
F(x) has Satisfied all the Requirements for Rolle's Theorem
Differentiating F(x) we have
[tex]F'(x)=4x-4[/tex]
Equating F(c) we have
[tex]F'(c)=0[/tex]
[tex]4(c)-4=0[/tex]
Therefore
[tex]c=1[/tex]
