Thank you guys fir the help

Answer:

The guy above me is correct

Step-by-step explanation:

2022

Answer:

number of seeds planted per square foot

Step-by-step explanation:

response is the yield explained by how many seeds are planted

Answer:

8.4

Step-by-step explanation:

jjdijendjndoendidnie

Answer:

hope u will understand...if u like this answer plz mark as brainlist

Answer:

[tex]\displaystyle p(x) + q(x) = \frac{2x}{(x+1)(x-1)}[/tex]

The result is indeed another rational expression.

Step-by-step explanation:

We are given the two functions:

[tex]\displaystyle p(x) = \frac{1}{x+1}\text{ and } q(x) = \frac{1}{x-1}[/tex]

And we want to perform the operation:

[tex]\displaystyle p(x) + q(x)[/tex]

And show that the result is another rational expression.

Add:

[tex]\displaystyle = \frac{1}{x+1} + \frac{1}{x-1}[/tex]

To combine the fractions, we will need a common denominator. So, we can multiply the first fraction by (x - 1) and the second by (x + 1):

[tex]\displaystyle = \frac{1}{x+1}\left(\frac{x-1}{x-1}\right) + \frac{1}{x-1}\left(\frac{x+1}{x+1}\right)[/tex]

Simplify:

[tex]=\displaystyle \frac{x-1}{(x+1)(x-1)} + \frac{x+1}{(x+1)(x-1)}[/tex]

Add:

[tex]\displaystyle = \frac{(x-1)+(x+1)}{(x+1)(x-1)}[/tex]

Simplify. Hence:

[tex]\displaystyle p(x) + q(x) = \frac{2x}{(x+1)(x-1)}[/tex]

The result is indeed another rational expression.

We have to figure out what the product of DA is,

[tex]\begin{bmatrix}-1&2&3\\8&-4&0\\6&7&1\\ \end{bmatrix}\begin{bmatrix}1\\3\\5\\ \end{bmatrix}=\begin{bmatrix}a\\b\\c\\ \end{bmatrix}[/tex]

We know that,

[tex]\begin{bmatrix}a&b&c\\d&e&f\\g&h&i\\\end{bmatrix}\begin{bmatrix}x\\y\\z\\\end{bmatrix}=\begin{bmatrix}ax+by+cz\\dx+ey+fz\\gx+hy+iz\\\end{bmatrix}[/tex]

So,

[tex]a=-1\cdot1+2\cdot3+3\cdot5=-1+6+15=20[/tex]

[tex]b=8\cdot1+(-4)\cdot3+0\cdot5=8-12=-4[/tex]

[tex]c=6\cdot1+7\cdot3+1\cdot5=6+21+5=32[/tex]

So the solution is,

[tex]a,b,c=\boxed{20,-4,32}[/tex]

Hope this helps :)

Given:

The given expression is:

[tex]6x^2y-3xy-24xy^2+12y^2[/tex]

To find:

Part A: The expression by factoring out the greatest common factor.

Part B: Factor the entire expression completely.

Solution:

Part A:

We have,

[tex]6x^2y-3xy-24xy^2+12y^2[/tex]

Taking out the highest common factor 3y, we get

[tex]=3y(2x^2-x-8xy+4y)[/tex]

Therefore, the required expression is [tex]3y(2x^2-x-8xy+4y)[/tex].

Part B:

From part A, we have,

[tex]3y(2x^2-x-8xy+4y)[/tex]

By grouping method, we get

[tex]=3y(x(2x-1)-4y(2x-1))[/tex]

[tex]=3y(x-4y)(2x-1)[/tex]

Therefore, the required factored form of the given expression is [tex]3y(x-4y)(2x-1)[/tex].

Answer:

(-1,0) r=2

Step-by-step explanation:

the equation of a circle can be written as (x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius

The answer would be D.

Answer: D

Step-by-step explanation:

Pretend that C is 12, pi is 3, and d is 4. 4=3/12, 4=3*12, 4=12-3, or 4=12/3? The only one that works is that last one, so the and is D: d=C/pi

Answer:

0.0244 = 2.44% probability that the mean of the sample would differ from the population mean by greater than 3.4 watts.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 102, standard deviation of 12:

This means that [tex]\mu = 102, \sigma = 12[/tex]

Sample of 63:

This means that [tex]n = 63, s = \frac{12}{\sqrt{63}}[/tex]

What is the probability that the mean of the sample would differ from the population mean by greater than 3.4 watts?

Below 102 - 3.4 = 98.6 or above 102 + 3.4 = 105.4. Since the normal distribution is symmetric, these probabilities are equal, and thus, we find one of them and multiply by two.

Probability the mean is below 98.6.

p-value of Z when X = 98.6. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{98.6 - 102}{\frac{12}{\sqrt{63}}}[/tex]

[tex]Z = -2.25[/tex]

[tex]Z = -2.25[/tex] has a p-value of 0.0122.

2*0.0122 = 0.0244

0.0244 = 2.44% probability that the mean of the sample would differ from the population mean by greater than 3.4 watts.

Answer:

138 gallons - milk containing 8% butterfat , 92 gallons -  milk containing 3% butterfat

Step-by-step explanation:

Firstly, find the quantity of butterfat in  the dairy needs of milk

230/100*6= 2.3*6=13.8 gallons of butterflat

1) Consider gallons each of milk containing 8% butterfat and milk containing 3%, suppose we need x gallons of milk containing 8 percents butterfat, then we need 230-x gallons of milk containing 3percent butterfat.

Then the quantity of the butterfat in the 8percents fat milk is x/100*8= 0.08x

the quantity of the butterfat in the 3percents fat milk is (230-x)/100*3=

=0.03 (230-x) = 6.9-0.03x The amount of butterfat of the both milk containing 8% butterfat and milk containing 3%is equal to 13.8 gallons

Then 0.08x+6.9-0.03x=13.8

0.05x=6.9

x=6.9/0.05= 138 -milk 8 percents

230-x= 230-138= 92

Answer:

where is your diagram?

Step-by-step explanation:

Answer:

(6,-6)

Step-by-step explanation:

First let's identify the current coordinates of D

It appears that D is located at (2 , -2)

Now let's find the coordinate of D if it were dilated by a scale factor of 3.

To find the coordinates of a point after a dilation you simply multiply the x and y values of the pre image coordinates by the scale factor

In this case the scale factor is 3 and the coordinates are (2,-2)

That being said let's apply the dilation rule

Current coordinates: (2,-2)

Scale factor:3

Multiply x and y values by scale factor

(2 * 3 , -2 * 3) --------> (6 , -6)

The coordinates of D' would be (6,-6)

The given table represents Exponential growth.

The process of Quantity rising over time is called exponential growth. An exponential function is used to create an exponential growth curve, which represents a pattern of data that shows a rise over time. Where the Exponential decay helps to understand the rapid decrease in a period of time

Here we have

The table

х     1       2       3       4          5  

у    14     56    224    896    3584  

From the given table, we can observe that

[tex]\frac{14}{56} = \frac{56}{224} = \frac{896}{3584} = \frac{1}{4}[/tex]    

Since the absolute value of the common ratio is less than 1 i.e 1/4

And the values are increasing

Therefore,

The given table represents Exponential growth.

Learn more about Exponential growth at

https://brainly.com/question/8706992

#SPJ1

Answer:

16 is answer

Step-by-step explanation:

3(2)^2+4(1)^2= 3(4)+4(1)=12+4=16

Answer:

the answer is 56 cubic units

Answer:

the answer is C

Step-by-step explanation:

Answer:

The answer is in the picture below

Step-by-step explanation:

Sorry just realised the answers were different ;-;

Answer:

The arm spans for Class A are roughly symmetric, while those for Class B are skewed left.

Step-by-step explanation:

Answer:

3:5 = 6:10

3x2 : 5x2

= 6:10

Answer:

Step-by-step explanation:

Draw 3:5 balls shaded, and draw 6:10 balls shaded. Then, divide the 10 balls into two, with three shaded balls and 5 total balls on one side.

9514 1404 393

Answer:

  x = √2

Step-by-step explanation:

A graph indicates the only solution is near x=√2.

__

Square both sides, separate the radical and do it again.

  [tex]\displaystyle(2-x)\sqrt{\frac{x+2}{x-1}}=\sqrt{x}+\sqrt{3x-4}\qquad\text{given}\\\\(2-x)^2\cdot\frac{x+2}{x-1}=x+(3x-4)+2\sqrt{x(3x-4)}\qquad\text{square}\\\\\frac{(2-x)^2(x+2)}{x-1}-4x+4=2\sqrt{x(3x-4)}\qquad\text{isolate radical}\\\\\left(\frac{(2-x)^2(x+2)-4(x-1)^2}{x-1}\right)^2=x(3x-4)\qquad\text{square}\\\\(x^3-6x^2+4x+4)^2=4(x-1)^2(3x^2-4x)\qquad\text{multiply by $(x-1)^2$}[/tex]

Now, we can put this polynomial equation into standard form and factor it.

  [tex]x^6 -12x^5+32x^4-76x^2+48x+16=0\\\\(x-2)^2(x^2-2)(x^2-8x-2)=0\qquad\text{factor it}\\\\x\in \{2,\pm\sqrt{2},4\pm3\sqrt{2}\}[/tex]

The original equation requires that we restrict the domain of possible solutions. In order for the radicals to be non-negative, we must have x ≥ 4/3. In order for the left side of the equation to be non-negative, we must have x ≤ 2. So, the only potential solutions will be in the interval [4/3, 2].

The only values in the above list that match this requirement are {√2, 2}. We know that the right side of the equation cannot be zero, so the value x=2 is also an extraneous solution.

The only solution is x = √2.

_____

Additional comment

For solving higher-degree polynomials, I like to use a graphing calculator to help me find the roots. The second attachment shows the roots of the 6th-degree polynomial. They can help us factor the equation. (There are also various machine solvers available that will show factors and roots.)

Answer:

1

Step-by-step explanation:

list the numbers that are odd or greater than 2

1,2,3,4,5,6

aka every single outcome

therefore the answer is just 1

Answer:

5/6

Step-by-step explanation:

The possible outcomes are 1,2,3,4,5,6

Odd numbers are 1,3,5

Greater than 2 are 3,4,5,6

Good solutions are 1,3,4,5,6  = 5 outcomes

P( odd or greater than 2) = good solutions / total

                                          = 5/6

Step-by-step explanation:

Answer:

The figure is not symmetrical

Answered by GAUTHMATH

Answer:

C. 4x^2 + 9x + 12

Step-by-step explanation:

4x^2 + 9x + 12 is a polynomial.

Answer:

the answer is c

Step-by-step explanation:

Answer:

Test statistic = 1.664

Step-by-step explanation:

The hypothesis :

H0 : μ = 47.2

H1 : μ ≠ 47.2

Given that :

Sample mean, xbar = 47

Sample size, n = 250

Standard deviation, σ = 1.9

The test statistic :

(xbar - μ) ÷ (σ/√(n))

T = (47 - 47.2) ÷ (1.9/√(250))

T = (0.2 / 0.1201665)

Test statistic = 1.664

9514 1404 393

Answer:

  smaller : larger = 3 : 4

Step-by-step explanation:

The scale factor is the ratio of corresponding dimensions. If we use the width dimensions, we have ...

  smaller/larger = 9/12 = 3/4

The scale factor is 3/4.

Answer:

The family of directions of the given vector is represented by [tex]\theta = 323.130^{\circ} \pm 360\cdot i[/tex], [tex]\forall \,i\in \mathbb{N}_{O}[/tex].

Step-by-step explanation:

According to the given information, vector stands in the 4th Quadrant ([tex]x > 0[/tex], [tex]y < 0[/tex]) and direction of the vector ([tex]\theta[/tex]) in sexagesimal degrees, is determined by following definition:

[tex]\theta = 360^{\circ} - \tan^{-1} \left(\frac{|y|}{|x|} \right)\pm 360\cdot i[/tex], [tex]\forall \,i\in \mathbb{N}_{O}[/tex]

Please notice that angle represents a function with a periodicity of 360°.

If we know that [tex]x = 4[/tex] and [tex]y = -3[/tex], then the direction of the vector is:

[tex]\theta = 360^{\circ}-\tan^{-1}\left(\frac{|-3|}{|4|} \right)\pm 360\cdot i[/tex]

[tex]\theta = 323.130^{\circ} \pm 360\cdot i[/tex]

The family of directions of the given vector is represented by [tex]\theta = 323.130^{\circ} \pm 360\cdot i[/tex], [tex]\forall \,i\in \mathbb{N}_{O}[/tex].

Answer:

nada está bien gana bien.

Let's use Gaussian elimination. Consider the augmented matrix,

[tex]\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\-1 & 2 & 3 & 0 & 1 & 0\\1 & 1 & 4 & 0 & 0 & 1\end{array}\right][/tex]

• Add row 1 to row 2, and add -1 (row 1) to row 3:

[tex]\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 2 & 5 & -1 & 0 & 1\end{array}\right][/tex]

• Add -2 (row 2) to row 3:

[tex]\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right][/tex]

• Add -2 (row 3) to row 2:

[tex]\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right][/tex]

• Add row 2 and row 3 to row 1:

[tex]\left[\begin{array}{ccc|ccc}1 & 0 & 0 & 5 & 3 & -1\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right][/tex]

So the inverse is

[tex]\begin{bmatrix}1&-1&-1\\-1&2&3\\1&1&4\end{bmatrix}^{-1} = \boxed{\begin{bmatrix}5&3&-1\\7&5&-2\\-3&-2&1\end{bmatrix}}[/tex]

Answer:

The answer is C

Step-by-step explanation:

PLATO